How to find second,third,etc maximum peak of list

up vote
2
down vote

favorite

I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here

Then I tried to find peaks:

tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]

Here tbl my Table with Data
And get:

0.15

8.751

So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .

I also tried to use FindPeaks but it's wrong:

peakpositions = FindPeaks[tbl[[All, 2]]]

peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions

ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]

enter image description here

edited Nov 27 at 0:50

asked Nov 27 at 0:30

John

1996

1

Did you try FindPeaks?
– J42161217
Nov 27 at 0:33

Yes, I did. I added the result above.
– John
Nov 27 at 0:45

add a comment |

up vote
2
down vote

favorite

I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here

Then I tried to find peaks:

tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]

Here tbl my Table with Data
And get:

0.15

8.751

So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .

I also tried to use FindPeaks but it's wrong:

peakpositions = FindPeaks[tbl[[All, 2]]]

peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions

ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]

enter image description here

edited Nov 27 at 0:50

asked Nov 27 at 0:30

John

1996

1

Did you try FindPeaks?
– J42161217
Nov 27 at 0:33

Yes, I did. I added the result above.
– John
Nov 27 at 0:45

add a comment |

up vote
2
down vote

favorite

I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here

Then I tried to find peaks:

tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]

Here tbl my Table with Data
And get:

0.15

8.751

So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .

I also tried to use FindPeaks but it's wrong:

peakpositions = FindPeaks[tbl[[All, 2]]]

peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions

ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]

enter image description here

edited Nov 27 at 0:50

asked Nov 27 at 0:30

John

1996

I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here

Then I tried to find peaks:

tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]

Here tbl my Table with Data
And get:

0.15

8.751

So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .

I also tried to use FindPeaks but it's wrong:

peakpositions = FindPeaks[tbl[[All, 2]]]

peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions

ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]

enter image description here

plotting list-manipulation mathematical-optimization peak-detection

edited Nov 27 at 0:50

asked Nov 27 at 0:30

John

1996

edited Nov 27 at 0:50

asked Nov 27 at 0:30

John

1996

edited Nov 27 at 0:50

asked Nov 27 at 0:30

John

1996

asked Nov 27 at 0:30

John

1996

asked Nov 27 at 0:30

John

1996

1

Did you try FindPeaks?
– J42161217
Nov 27 at 0:33

Yes, I did. I added the result above.
– John
Nov 27 at 0:45

add a comment |

1

Did you try FindPeaks?
– J42161217
Nov 27 at 0:33

Yes, I did. I added the result above.
– John
Nov 27 at 0:45

Did you try FindPeaks?
– J42161217
Nov 27 at 0:33

Yes, I did. I added the result above.
– John
Nov 27 at 0:45

add a comment |

2 Answers
2

active

oldest

votes

up vote
5
down vote

accepted

jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]

ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 

 GridLines -> Transpose[jumps]]

enter image description here

answered Nov 27 at 0:53

kglr

174k9196402

add a comment |

up vote
4
down vote

Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]

answered Nov 27 at 1:15

J42161217

3,552220

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
5
down vote

accepted

jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]

ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 

 GridLines -> Transpose[jumps]]

enter image description here

answered Nov 27 at 0:53

kglr

174k9196402

add a comment |

up vote
5
down vote

accepted

jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]

ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 

 GridLines -> Transpose[jumps]]

enter image description here

answered Nov 27 at 0:53

kglr

174k9196402

add a comment |

up vote
5
down vote

accepted

jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]

ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 

 GridLines -> Transpose[jumps]]

enter image description here

answered Nov 27 at 0:53

kglr

174k9196402

jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]

ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 

 GridLines -> Transpose[jumps]]

enter image description here

answered Nov 27 at 0:53

kglr

174k9196402

answered Nov 27 at 0:53

kglr

174k9196402

answered Nov 27 at 0:53

kglr

174k9196402

answered Nov 27 at 0:53

kglr

174k9196402

add a comment |

up vote
4
down vote

Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]

answered Nov 27 at 1:15

J42161217

3,552220

add a comment |

up vote
4
down vote

Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]

answered Nov 27 at 1:15

J42161217

3,552220

add a comment |

up vote
4
down vote

Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]

answered Nov 27 at 1:15

J42161217

3,552220

Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]

answered Nov 27 at 1:15

J42161217

3,552220

answered Nov 27 at 1:15

J42161217

3,552220

answered Nov 27 at 1:15

J42161217

3,552220

answered Nov 27 at 1:15

J42161217

3,552220

add a comment |

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