continuous derivatives of all orders on $mathbb{R}$











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Prove that there is exists a function $fin C^infty(mathbb{R})$ such that $f(x)=0$ for $xleq 0$ and $f(x)>0$ for $x>0$.



I know that there exists many examples. But have no idea, how to prove the existence such a function.










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  • See en.wikipedia.org/wiki/Bump_function.
    – gj255
    Nov 16 at 14:12










  • I know that there exists many examples. But have no idea, how to show that such a function exists. What have I just read?
    – freakish
    Nov 16 at 14:14










  • @freakish The OP means that he is aware of the existence of many examples, but is not acquainted with any of them, and does not know how to produce one.
    – saulspatz
    Nov 16 at 14:19






  • 1




    See en.wikipedia.org/wiki/Non-analytic_smooth_function. The first example is one that you want.
    – edm
    Nov 16 at 14:20










  • @freakish Well, that's what the statement seems to mean to me. I guess it's possible that he knows of a purported example, but can't demonstrate that it satisfies the conditions, but then I feel certain he'd have told us what the function is.
    – saulspatz
    Nov 16 at 14:23















up vote
-3
down vote

favorite












Prove that there is exists a function $fin C^infty(mathbb{R})$ such that $f(x)=0$ for $xleq 0$ and $f(x)>0$ for $x>0$.



I know that there exists many examples. But have no idea, how to prove the existence such a function.










share|cite|improve this question
























  • See en.wikipedia.org/wiki/Bump_function.
    – gj255
    Nov 16 at 14:12










  • I know that there exists many examples. But have no idea, how to show that such a function exists. What have I just read?
    – freakish
    Nov 16 at 14:14










  • @freakish The OP means that he is aware of the existence of many examples, but is not acquainted with any of them, and does not know how to produce one.
    – saulspatz
    Nov 16 at 14:19






  • 1




    See en.wikipedia.org/wiki/Non-analytic_smooth_function. The first example is one that you want.
    – edm
    Nov 16 at 14:20










  • @freakish Well, that's what the statement seems to mean to me. I guess it's possible that he knows of a purported example, but can't demonstrate that it satisfies the conditions, but then I feel certain he'd have told us what the function is.
    – saulspatz
    Nov 16 at 14:23













up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











Prove that there is exists a function $fin C^infty(mathbb{R})$ such that $f(x)=0$ for $xleq 0$ and $f(x)>0$ for $x>0$.



I know that there exists many examples. But have no idea, how to prove the existence such a function.










share|cite|improve this question















Prove that there is exists a function $fin C^infty(mathbb{R})$ such that $f(x)=0$ for $xleq 0$ and $f(x)>0$ for $x>0$.



I know that there exists many examples. But have no idea, how to prove the existence such a function.







integration sequences-and-series functions






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 16 at 14:25

























asked Nov 16 at 14:06









HindShah

74




74












  • See en.wikipedia.org/wiki/Bump_function.
    – gj255
    Nov 16 at 14:12










  • I know that there exists many examples. But have no idea, how to show that such a function exists. What have I just read?
    – freakish
    Nov 16 at 14:14










  • @freakish The OP means that he is aware of the existence of many examples, but is not acquainted with any of them, and does not know how to produce one.
    – saulspatz
    Nov 16 at 14:19






  • 1




    See en.wikipedia.org/wiki/Non-analytic_smooth_function. The first example is one that you want.
    – edm
    Nov 16 at 14:20










  • @freakish Well, that's what the statement seems to mean to me. I guess it's possible that he knows of a purported example, but can't demonstrate that it satisfies the conditions, but then I feel certain he'd have told us what the function is.
    – saulspatz
    Nov 16 at 14:23


















  • See en.wikipedia.org/wiki/Bump_function.
    – gj255
    Nov 16 at 14:12










  • I know that there exists many examples. But have no idea, how to show that such a function exists. What have I just read?
    – freakish
    Nov 16 at 14:14










  • @freakish The OP means that he is aware of the existence of many examples, but is not acquainted with any of them, and does not know how to produce one.
    – saulspatz
    Nov 16 at 14:19






  • 1




    See en.wikipedia.org/wiki/Non-analytic_smooth_function. The first example is one that you want.
    – edm
    Nov 16 at 14:20










  • @freakish Well, that's what the statement seems to mean to me. I guess it's possible that he knows of a purported example, but can't demonstrate that it satisfies the conditions, but then I feel certain he'd have told us what the function is.
    – saulspatz
    Nov 16 at 14:23
















See en.wikipedia.org/wiki/Bump_function.
– gj255
Nov 16 at 14:12




See en.wikipedia.org/wiki/Bump_function.
– gj255
Nov 16 at 14:12












I know that there exists many examples. But have no idea, how to show that such a function exists. What have I just read?
– freakish
Nov 16 at 14:14




I know that there exists many examples. But have no idea, how to show that such a function exists. What have I just read?
– freakish
Nov 16 at 14:14












@freakish The OP means that he is aware of the existence of many examples, but is not acquainted with any of them, and does not know how to produce one.
– saulspatz
Nov 16 at 14:19




@freakish The OP means that he is aware of the existence of many examples, but is not acquainted with any of them, and does not know how to produce one.
– saulspatz
Nov 16 at 14:19




1




1




See en.wikipedia.org/wiki/Non-analytic_smooth_function. The first example is one that you want.
– edm
Nov 16 at 14:20




See en.wikipedia.org/wiki/Non-analytic_smooth_function. The first example is one that you want.
– edm
Nov 16 at 14:20












@freakish Well, that's what the statement seems to mean to me. I guess it's possible that he knows of a purported example, but can't demonstrate that it satisfies the conditions, but then I feel certain he'd have told us what the function is.
– saulspatz
Nov 16 at 14:23




@freakish Well, that's what the statement seems to mean to me. I guess it's possible that he knows of a purported example, but can't demonstrate that it satisfies the conditions, but then I feel certain he'd have told us what the function is.
– saulspatz
Nov 16 at 14:23















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