Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the...
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Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the sample ratio is between 0.20 and 0.30.
I don't have a clear idea of how solve this exercise:
Can someone help me?
probability
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Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the sample ratio is between 0.20 and 0.30.
I don't have a clear idea of how solve this exercise:
Can someone help me?
probability
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the sample ratio is between 0.20 and 0.30.
I don't have a clear idea of how solve this exercise:
Can someone help me?
probability
Given a random sample size 40 from a binomial population, where p = 0.25 calculate the probability that the sample ratio is between 0.20 and 0.30.
I don't have a clear idea of how solve this exercise:
Can someone help me?
probability
probability
asked Nov 19 at 2:17
Bvss12
1,729617
1,729617
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It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
add a comment |
up vote
0
down vote
It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
add a comment |
up vote
0
down vote
up vote
0
down vote
It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
It looks like you need to use the binomial distribution. The specific answer is $sum_{k=8}^{12}binom{40}{k}.25^k.75^{40-k}$. $k=8$ to $ 12$ comes from $.20,.30$ times $40$.
answered Nov 19 at 2:31
herb steinberg
2,3682310
2,3682310
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