Confusion with simple probability concepts












1












$begingroup$


There is a problem which goes, there are 6 red balls and $4$ green balls and a sample of $7$ balls are chosen.



Show that the probability such that all the balls chosen are red.



My answer is $0$, because there are only $6$ red balls, how can we choose $7$ sample balls when there are only $6$ red balls?



Is this correct?










share|cite|improve this question









$endgroup$












  • $begingroup$
    With replacement or without?
    $endgroup$
    – Did
    Jan 7 at 15:18










  • $begingroup$
    "Show that the probability such that all the balls chosen are red." That should read "Find the probability that all the balls chosen are red. "
    $endgroup$
    – zhw.
    Jan 7 at 23:44
















1












$begingroup$


There is a problem which goes, there are 6 red balls and $4$ green balls and a sample of $7$ balls are chosen.



Show that the probability such that all the balls chosen are red.



My answer is $0$, because there are only $6$ red balls, how can we choose $7$ sample balls when there are only $6$ red balls?



Is this correct?










share|cite|improve this question









$endgroup$












  • $begingroup$
    With replacement or without?
    $endgroup$
    – Did
    Jan 7 at 15:18










  • $begingroup$
    "Show that the probability such that all the balls chosen are red." That should read "Find the probability that all the balls chosen are red. "
    $endgroup$
    – zhw.
    Jan 7 at 23:44














1












1








1





$begingroup$


There is a problem which goes, there are 6 red balls and $4$ green balls and a sample of $7$ balls are chosen.



Show that the probability such that all the balls chosen are red.



My answer is $0$, because there are only $6$ red balls, how can we choose $7$ sample balls when there are only $6$ red balls?



Is this correct?










share|cite|improve this question









$endgroup$




There is a problem which goes, there are 6 red balls and $4$ green balls and a sample of $7$ balls are chosen.



Show that the probability such that all the balls chosen are red.



My answer is $0$, because there are only $6$ red balls, how can we choose $7$ sample balls when there are only $6$ red balls?



Is this correct?







probability






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 14 '18 at 3:47









Aurora BorealisAurora Borealis

866414




866414












  • $begingroup$
    With replacement or without?
    $endgroup$
    – Did
    Jan 7 at 15:18










  • $begingroup$
    "Show that the probability such that all the balls chosen are red." That should read "Find the probability that all the balls chosen are red. "
    $endgroup$
    – zhw.
    Jan 7 at 23:44


















  • $begingroup$
    With replacement or without?
    $endgroup$
    – Did
    Jan 7 at 15:18










  • $begingroup$
    "Show that the probability such that all the balls chosen are red." That should read "Find the probability that all the balls chosen are red. "
    $endgroup$
    – zhw.
    Jan 7 at 23:44
















$begingroup$
With replacement or without?
$endgroup$
– Did
Jan 7 at 15:18




$begingroup$
With replacement or without?
$endgroup$
– Did
Jan 7 at 15:18












$begingroup$
"Show that the probability such that all the balls chosen are red." That should read "Find the probability that all the balls chosen are red. "
$endgroup$
– zhw.
Jan 7 at 23:44




$begingroup$
"Show that the probability such that all the balls chosen are red." That should read "Find the probability that all the balls chosen are red. "
$endgroup$
– zhw.
Jan 7 at 23:44










1 Answer
1






active

oldest

votes


















2












$begingroup$

Yup, that's correct. Since it's impossible for all $7$ balls to be red - because there aren't $7$ or more red balls to begin with - the probability of that would be $0$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thank you I guess I was just over thinking this.
    $endgroup$
    – Aurora Borealis
    Dec 14 '18 at 3:50










  • $begingroup$
    lol that's perfectly normal, I'm the same way with probability. But at least it shows you're thinking about the material, which is a good thing. :P
    $endgroup$
    – Eevee Trainer
    Dec 14 '18 at 3:54












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

Yup, that's correct. Since it's impossible for all $7$ balls to be red - because there aren't $7$ or more red balls to begin with - the probability of that would be $0$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thank you I guess I was just over thinking this.
    $endgroup$
    – Aurora Borealis
    Dec 14 '18 at 3:50










  • $begingroup$
    lol that's perfectly normal, I'm the same way with probability. But at least it shows you're thinking about the material, which is a good thing. :P
    $endgroup$
    – Eevee Trainer
    Dec 14 '18 at 3:54
















2












$begingroup$

Yup, that's correct. Since it's impossible for all $7$ balls to be red - because there aren't $7$ or more red balls to begin with - the probability of that would be $0$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thank you I guess I was just over thinking this.
    $endgroup$
    – Aurora Borealis
    Dec 14 '18 at 3:50










  • $begingroup$
    lol that's perfectly normal, I'm the same way with probability. But at least it shows you're thinking about the material, which is a good thing. :P
    $endgroup$
    – Eevee Trainer
    Dec 14 '18 at 3:54














2












2








2





$begingroup$

Yup, that's correct. Since it's impossible for all $7$ balls to be red - because there aren't $7$ or more red balls to begin with - the probability of that would be $0$.






share|cite|improve this answer









$endgroup$



Yup, that's correct. Since it's impossible for all $7$ balls to be red - because there aren't $7$ or more red balls to begin with - the probability of that would be $0$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 14 '18 at 3:50









Eevee TrainerEevee Trainer

10.2k31742




10.2k31742












  • $begingroup$
    Thank you I guess I was just over thinking this.
    $endgroup$
    – Aurora Borealis
    Dec 14 '18 at 3:50










  • $begingroup$
    lol that's perfectly normal, I'm the same way with probability. But at least it shows you're thinking about the material, which is a good thing. :P
    $endgroup$
    – Eevee Trainer
    Dec 14 '18 at 3:54


















  • $begingroup$
    Thank you I guess I was just over thinking this.
    $endgroup$
    – Aurora Borealis
    Dec 14 '18 at 3:50










  • $begingroup$
    lol that's perfectly normal, I'm the same way with probability. But at least it shows you're thinking about the material, which is a good thing. :P
    $endgroup$
    – Eevee Trainer
    Dec 14 '18 at 3:54
















$begingroup$
Thank you I guess I was just over thinking this.
$endgroup$
– Aurora Borealis
Dec 14 '18 at 3:50




$begingroup$
Thank you I guess I was just over thinking this.
$endgroup$
– Aurora Borealis
Dec 14 '18 at 3:50












$begingroup$
lol that's perfectly normal, I'm the same way with probability. But at least it shows you're thinking about the material, which is a good thing. :P
$endgroup$
– Eevee Trainer
Dec 14 '18 at 3:54




$begingroup$
lol that's perfectly normal, I'm the same way with probability. But at least it shows you're thinking about the material, which is a good thing. :P
$endgroup$
– Eevee Trainer
Dec 14 '18 at 3:54


















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