Given X ~ N(0,1).Find P(X>0) and P(X<0)
$begingroup$
All I understand here is that it is a question of binomial deviation where the particular case is of standard deviation i.e ( I familiarise it with the bell curve.an image has been attached.) .I am aware that there is a table to calculate for particular values of X.But what about the following two cases?
... consider me as 'not so well versed person' in this topic and explain me as simplified as you could. Thank you.
P.s if someone could post a detailed solutions,you could leave the understanding part on me..
Just in case this question feels incomplete or has some ambiguity please let me know.
statistics binomial-distribution standard-deviation
$endgroup$
add a comment |
$begingroup$
All I understand here is that it is a question of binomial deviation where the particular case is of standard deviation i.e ( I familiarise it with the bell curve.an image has been attached.) .I am aware that there is a table to calculate for particular values of X.But what about the following two cases?
... consider me as 'not so well versed person' in this topic and explain me as simplified as you could. Thank you.
P.s if someone could post a detailed solutions,you could leave the understanding part on me..
Just in case this question feels incomplete or has some ambiguity please let me know.
statistics binomial-distribution standard-deviation
$endgroup$
1
$begingroup$
You've drawn the picture for P(X<z) for some positive z. Did you try drawing the corresponding picture for 0? The answer will smack you in the face.
$endgroup$
– zoidberg
Dec 8 '18 at 6:45
$begingroup$
Do you know that $int_{mathbb{R}}f(z)dz=1$ and $f(z)=f(-z)$?
$endgroup$
– Fakemistake
Dec 8 '18 at 8:47
add a comment |
$begingroup$
All I understand here is that it is a question of binomial deviation where the particular case is of standard deviation i.e ( I familiarise it with the bell curve.an image has been attached.) .I am aware that there is a table to calculate for particular values of X.But what about the following two cases?
... consider me as 'not so well versed person' in this topic and explain me as simplified as you could. Thank you.
P.s if someone could post a detailed solutions,you could leave the understanding part on me..
Just in case this question feels incomplete or has some ambiguity please let me know.
statistics binomial-distribution standard-deviation
$endgroup$
All I understand here is that it is a question of binomial deviation where the particular case is of standard deviation i.e ( I familiarise it with the bell curve.an image has been attached.) .I am aware that there is a table to calculate for particular values of X.But what about the following two cases?
... consider me as 'not so well versed person' in this topic and explain me as simplified as you could. Thank you.
P.s if someone could post a detailed solutions,you could leave the understanding part on me..
Just in case this question feels incomplete or has some ambiguity please let me know.
statistics binomial-distribution standard-deviation
statistics binomial-distribution standard-deviation
edited Dec 8 '18 at 5:51
user611339
asked Dec 8 '18 at 5:44
user611339user611339
183
183
1
$begingroup$
You've drawn the picture for P(X<z) for some positive z. Did you try drawing the corresponding picture for 0? The answer will smack you in the face.
$endgroup$
– zoidberg
Dec 8 '18 at 6:45
$begingroup$
Do you know that $int_{mathbb{R}}f(z)dz=1$ and $f(z)=f(-z)$?
$endgroup$
– Fakemistake
Dec 8 '18 at 8:47
add a comment |
1
$begingroup$
You've drawn the picture for P(X<z) for some positive z. Did you try drawing the corresponding picture for 0? The answer will smack you in the face.
$endgroup$
– zoidberg
Dec 8 '18 at 6:45
$begingroup$
Do you know that $int_{mathbb{R}}f(z)dz=1$ and $f(z)=f(-z)$?
$endgroup$
– Fakemistake
Dec 8 '18 at 8:47
1
1
$begingroup$
You've drawn the picture for P(X<z) for some positive z. Did you try drawing the corresponding picture for 0? The answer will smack you in the face.
$endgroup$
– zoidberg
Dec 8 '18 at 6:45
$begingroup$
You've drawn the picture for P(X<z) for some positive z. Did you try drawing the corresponding picture for 0? The answer will smack you in the face.
$endgroup$
– zoidberg
Dec 8 '18 at 6:45
$begingroup$
Do you know that $int_{mathbb{R}}f(z)dz=1$ and $f(z)=f(-z)$?
$endgroup$
– Fakemistake
Dec 8 '18 at 8:47
$begingroup$
Do you know that $int_{mathbb{R}}f(z)dz=1$ and $f(z)=f(-z)$?
$endgroup$
– Fakemistake
Dec 8 '18 at 8:47
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3030734%2fgiven-x-n0-1-find-px0-and-px0%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3030734%2fgiven-x-n0-1-find-px0-and-px0%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
You've drawn the picture for P(X<z) for some positive z. Did you try drawing the corresponding picture for 0? The answer will smack you in the face.
$endgroup$
– zoidberg
Dec 8 '18 at 6:45
$begingroup$
Do you know that $int_{mathbb{R}}f(z)dz=1$ and $f(z)=f(-z)$?
$endgroup$
– Fakemistake
Dec 8 '18 at 8:47