1+AB=1 using boolean algebra ? Am I right or not?
$begingroup$
As 1+AB
Now if I put A=0 & B=1 then the above expression gives the answer 1
Conversely if I put A=1 & B=0 then again the answer of above expression is 1
I've seen manly rules or laws to solve boolean algebra problems but I didn't see anyone like this so I'm not sure wether I'm right or wrong please guide me thanks in advance
boolean-algebra
asked Dec 8 '18 at 5:37
Diana JosephDiana Joseph
11
$endgroup$
add a comment |
$begingroup$
As 1+AB
Now if I put A=0 & B=1 then the above expression gives the answer 1
Conversely if I put A=1 & B=0 then again the answer of above expression is 1
I've seen manly rules or laws to solve boolean algebra problems but I didn't see anyone like this so I'm not sure wether I'm right or wrong please guide me thanks in advance
boolean-algebra
asked Dec 8 '18 at 5:37
Diana JosephDiana Joseph
11
$endgroup$
3
$begingroup$
Note that $True$ $or$ $something = True$.
$endgroup$
– trancelocation
Dec 8 '18 at 5:44
1
$begingroup$
Since $1+1 = 1$ and $1+0 = 1$ we must have $1+X = 1$ regardless of $X$.
$endgroup$
– copper.hat
Dec 8 '18 at 5:46
$begingroup$
$1+A=1$ is called Annihilation or Dominance
$endgroup$
– Bram28
Dec 8 '18 at 5:48
$begingroup$
The law you are looking for is Annulment Law
$endgroup$
– Shubham Johri
Dec 8 '18 at 10:00
add a comment |
$begingroup$
As 1+AB
Now if I put A=0 & B=1 then the above expression gives the answer 1
Conversely if I put A=1 & B=0 then again the answer of above expression is 1
I've seen manly rules or laws to solve boolean algebra problems but I didn't see anyone like this so I'm not sure wether I'm right or wrong please guide me thanks in advance
boolean-algebra
asked Dec 8 '18 at 5:37
Diana JosephDiana Joseph
11
$endgroup$
As 1+AB
Now if I put A=0 & B=1 then the above expression gives the answer 1
Conversely if I put A=1 & B=0 then again the answer of above expression is 1
I've seen manly rules or laws to solve boolean algebra problems but I didn't see anyone like this so I'm not sure wether I'm right or wrong please guide me thanks in advance
boolean-algebra
boolean-algebra
asked Dec 8 '18 at 5:37
Diana JosephDiana Joseph
11
asked Dec 8 '18 at 5:37
Diana JosephDiana Joseph
11
asked Dec 8 '18 at 5:37
Diana JosephDiana Joseph
11
asked Dec 8 '18 at 5:37
Diana JosephDiana Joseph
11
asked Dec 8 '18 at 5:37
Diana JosephDiana Joseph
11
11
3
$begingroup$
Note that $True$ $or$ $something = True$.
$endgroup$
– trancelocation
Dec 8 '18 at 5:44
1
$begingroup$
Since $1+1 = 1$ and $1+0 = 1$ we must have $1+X = 1$ regardless of $X$.
$endgroup$
– copper.hat
Dec 8 '18 at 5:46
$begingroup$
$1+A=1$ is called Annihilation or Dominance
$endgroup$
– Bram28
Dec 8 '18 at 5:48
$begingroup$
The law you are looking for is Annulment Law
$endgroup$
– Shubham Johri
Dec 8 '18 at 10:00
add a comment |
3
$begingroup$
Note that $True$ $or$ $something = True$.
$endgroup$
– trancelocation
Dec 8 '18 at 5:44
1
$begingroup$
Since $1+1 = 1$ and $1+0 = 1$ we must have $1+X = 1$ regardless of $X$.
$endgroup$
– copper.hat
Dec 8 '18 at 5:46
$begingroup$
$1+A=1$ is called Annihilation or Dominance
$endgroup$
– Bram28
Dec 8 '18 at 5:48
$begingroup$
The law you are looking for is Annulment Law
$endgroup$
– Shubham Johri
Dec 8 '18 at 10:00
3
3
$begingroup$
Note that $True$ $or$ $something = True$.
$endgroup$
– trancelocation
Dec 8 '18 at 5:44
$begingroup$
Note that $True$ $or$ $something = True$.
$endgroup$
– trancelocation
Dec 8 '18 at 5:44
1
1
$begingroup$
Since $1+1 = 1$ and $1+0 = 1$ we must have $1+X = 1$ regardless of $X$.
$endgroup$
– copper.hat
Dec 8 '18 at 5:46
$begingroup$
Since $1+1 = 1$ and $1+0 = 1$ we must have $1+X = 1$ regardless of $X$.
$endgroup$
– copper.hat
Dec 8 '18 at 5:46
$begingroup$
$1+A=1$ is called Annihilation or Dominance
$endgroup$
– Bram28
Dec 8 '18 at 5:48
$begingroup$
$1+A=1$ is called Annihilation or Dominance
$endgroup$
– Bram28
Dec 8 '18 at 5:48
$begingroup$
The law you are looking for is Annulment Law
$endgroup$
– Shubham Johri
Dec 8 '18 at 10:00
$begingroup$
The law you are looking for is Annulment Law
$endgroup$
– Shubham Johri
Dec 8 '18 at 10:00
add a comment |
0
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3
$begingroup$
Note that $True$ $or$ $something = True$.
$endgroup$
– trancelocation
Dec 8 '18 at 5:44
1
$begingroup$
Since $1+1 = 1$ and $1+0 = 1$ we must have $1+X = 1$ regardless of $X$.
$endgroup$
– copper.hat
Dec 8 '18 at 5:46
$begingroup$
$1+A=1$ is called Annihilation or Dominance
$endgroup$
– Bram28
Dec 8 '18 at 5:48
$begingroup$
The law you are looking for is Annulment Law
$endgroup$
– Shubham Johri
Dec 8 '18 at 10:00