Remove math mode in macro defined text
3
I would like to remove the math mode in a text that is not defined directly, but in a macro. Here is my code:
documentclass{book}
begingroup
lccode`~=`$
lowercase{endgroup
def~#1~{ignorespaces}%
}
defremovemath{%
begingroup
catcode`$=active
removemathX
}
defremovemathX#1{%
#1
endgroup
}
edefnomath#1{
removemath{#1}
}
begin{document}
chapter{XXXXXX}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
removemath{aaaa}
nomath{aaaa}
end{document}
In this example, the first removemath works, but the second removemath and nomath does not work.
I am not sure why. Is it an expansion problem? Maybe something else?
Can someone suggest a solution?
math-mode expansion
asked Jan 25 at 22:12
Peter IvanyiPeter Ivanyi
273
add a comment |
3
I would like to remove the math mode in a text that is not defined directly, but in a macro. Here is my code:
documentclass{book}
begingroup
lccode`~=`$
lowercase{endgroup
def~#1~{ignorespaces}%
}
defremovemath{%
begingroup
catcode`$=active
removemathX
}
defremovemathX#1{%
#1
endgroup
}
edefnomath#1{
removemath{#1}
}
begin{document}
chapter{XXXXXX}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
removemath{aaaa}
nomath{aaaa}
end{document}
In this example, the first removemath works, but the second removemath and nomath does not work.
I am not sure why. Is it an expansion problem? Maybe something else?
Can someone suggest a solution?
math-mode expansion
asked Jan 25 at 22:12
Peter IvanyiPeter Ivanyi
273
1
removemath is using catcode changes so will only work at the top level, the characters inaaaahave already been tokenised so catcode changes have no effect. However it isn't clear why you are using catcode changes, you copuld use a delimited argument on a normal catcode$.
– David Carlisle
Jan 25 at 22:15
add a comment |
3
3
3
I would like to remove the math mode in a text that is not defined directly, but in a macro. Here is my code:
documentclass{book}
begingroup
lccode`~=`$
lowercase{endgroup
def~#1~{ignorespaces}%
}
defremovemath{%
begingroup
catcode`$=active
removemathX
}
defremovemathX#1{%
#1
endgroup
}
edefnomath#1{
removemath{#1}
}
begin{document}
chapter{XXXXXX}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
removemath{aaaa}
nomath{aaaa}
end{document}
In this example, the first removemath works, but the second removemath and nomath does not work.
I am not sure why. Is it an expansion problem? Maybe something else?
Can someone suggest a solution?
math-mode expansion
asked Jan 25 at 22:12
Peter IvanyiPeter Ivanyi
273
I would like to remove the math mode in a text that is not defined directly, but in a macro. Here is my code:
documentclass{book}
begingroup
lccode`~=`$
lowercase{endgroup
def~#1~{ignorespaces}%
}
defremovemath{%
begingroup
catcode`$=active
removemathX
}
defremovemathX#1{%
#1
endgroup
}
edefnomath#1{
removemath{#1}
}
begin{document}
chapter{XXXXXX}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
removemath{aaaa}
nomath{aaaa}
end{document}
In this example, the first removemath works, but the second removemath and nomath does not work.
I am not sure why. Is it an expansion problem? Maybe something else?
Can someone suggest a solution?
math-mode expansion
math-mode expansion
asked Jan 25 at 22:12
Peter IvanyiPeter Ivanyi
273
asked Jan 25 at 22:12
Peter IvanyiPeter Ivanyi
273
asked Jan 25 at 22:12
Peter IvanyiPeter Ivanyi
273
asked Jan 25 at 22:12
Peter IvanyiPeter Ivanyi
273
asked Jan 25 at 22:12
Peter IvanyiPeter Ivanyi
273
273
1
removemath is using catcode changes so will only work at the top level, the characters inaaaahave already been tokenised so catcode changes have no effect. However it isn't clear why you are using catcode changes, you copuld use a delimited argument on a normal catcode$.
– David Carlisle
Jan 25 at 22:15
add a comment |
1
removemath is using catcode changes so will only work at the top level, the characters inaaaahave already been tokenised so catcode changes have no effect. However it isn't clear why you are using catcode changes, you copuld use a delimited argument on a normal catcode$.
– David Carlisle
Jan 25 at 22:15
1
1
removemath is using catcode changes so will only work at the top level, the characters in
aaaa have already been tokenised so catcode changes have no effect. However it isn't clear why you are using catcode changes, you copuld use a delimited argument on a normal catcode $.– David Carlisle
Jan 25 at 22:15
removemath is using catcode changes so will only work at the top level, the characters in
aaaa have already been tokenised so catcode changes have no effect. However it isn't clear why you are using catcode changes, you copuld use a delimited argument on a normal catcode $.– David Carlisle
Jan 25 at 22:15
add a comment |
1 Answer
1
active
oldest
votes
3
You can remove one formula at a time:
documentclass{book}
makeatletter
newcommand{removemath}[1]{%
expandafterremovemath@#1$$@nil
}
defremovemath@#1$#2$#3@nil{%
#1%
ifrelaxdetokenize{#3}relax
expandafter@gobble
else
expandafter@firstofone
fi
{removemath@#3@nil}%
}
makeatother
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
The same with a regular expression approach:
documentclass{book}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{removemath}{m}
{
peter_removemath:o { #1 }
}
cs_new_protected:Nn peter_removemath:n
{
tl_set:Nn l__peter_removemath_tl { #1 }
regex_replace_all:nnN { $ [^$]* $ } {} l__peter_removemath_tl
l__peter_removemath_tl
}
cs_generate_variant:Nn peter_removemath:n { o }
tl_new:N l__peter_removemath_tl
ExplSyntaxOff
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
answered Jan 25 at 23:13
egregegreg
717k8619023191
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You can remove one formula at a time:
documentclass{book}
makeatletter
newcommand{removemath}[1]{%
expandafterremovemath@#1$$@nil
}
defremovemath@#1$#2$#3@nil{%
#1%
ifrelaxdetokenize{#3}relax
expandafter@gobble
else
expandafter@firstofone
fi
{removemath@#3@nil}%
}
makeatother
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
The same with a regular expression approach:
documentclass{book}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{removemath}{m}
{
peter_removemath:o { #1 }
}
cs_new_protected:Nn peter_removemath:n
{
tl_set:Nn l__peter_removemath_tl { #1 }
regex_replace_all:nnN { $ [^$]* $ } {} l__peter_removemath_tl
l__peter_removemath_tl
}
cs_generate_variant:Nn peter_removemath:n { o }
tl_new:N l__peter_removemath_tl
ExplSyntaxOff
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
answered Jan 25 at 23:13
egregegreg
717k8619023191
add a comment |
3
You can remove one formula at a time:
documentclass{book}
makeatletter
newcommand{removemath}[1]{%
expandafterremovemath@#1$$@nil
}
defremovemath@#1$#2$#3@nil{%
#1%
ifrelaxdetokenize{#3}relax
expandafter@gobble
else
expandafter@firstofone
fi
{removemath@#3@nil}%
}
makeatother
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
The same with a regular expression approach:
documentclass{book}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{removemath}{m}
{
peter_removemath:o { #1 }
}
cs_new_protected:Nn peter_removemath:n
{
tl_set:Nn l__peter_removemath_tl { #1 }
regex_replace_all:nnN { $ [^$]* $ } {} l__peter_removemath_tl
l__peter_removemath_tl
}
cs_generate_variant:Nn peter_removemath:n { o }
tl_new:N l__peter_removemath_tl
ExplSyntaxOff
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
answered Jan 25 at 23:13
egregegreg
717k8619023191
add a comment |
3
3
3
You can remove one formula at a time:
documentclass{book}
makeatletter
newcommand{removemath}[1]{%
expandafterremovemath@#1$$@nil
}
defremovemath@#1$#2$#3@nil{%
#1%
ifrelaxdetokenize{#3}relax
expandafter@gobble
else
expandafter@firstofone
fi
{removemath@#3@nil}%
}
makeatother
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
The same with a regular expression approach:
documentclass{book}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{removemath}{m}
{
peter_removemath:o { #1 }
}
cs_new_protected:Nn peter_removemath:n
{
tl_set:Nn l__peter_removemath_tl { #1 }
regex_replace_all:nnN { $ [^$]* $ } {} l__peter_removemath_tl
l__peter_removemath_tl
}
cs_generate_variant:Nn peter_removemath:n { o }
tl_new:N l__peter_removemath_tl
ExplSyntaxOff
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
answered Jan 25 at 23:13
egregegreg
717k8619023191
You can remove one formula at a time:
documentclass{book}
makeatletter
newcommand{removemath}[1]{%
expandafterremovemath@#1$$@nil
}
defremovemath@#1$#2$#3@nil{%
#1%
ifrelaxdetokenize{#3}relax
expandafter@gobble
else
expandafter@firstofone
fi
{removemath@#3@nil}%
}
makeatother
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
The same with a regular expression approach:
documentclass{book}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{removemath}{m}
{
peter_removemath:o { #1 }
}
cs_new_protected:Nn peter_removemath:n
{
tl_set:Nn l__peter_removemath_tl { #1 }
regex_replace_all:nnN { $ [^$]* $ } {} l__peter_removemath_tl
l__peter_removemath_tl
}
cs_generate_variant:Nn peter_removemath:n { o }
tl_new:N l__peter_removemath_tl
ExplSyntaxOff
begin{document}
newcommandaaaa{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD$^{4}$}--
--removemath{AAA$^{1}$, BBB$^{2}$, CCC$^{3}$, DDD}--
--removemath{AAA$^{1}$, BBB, CCC$^{3}$, DDD}--
--removemath{aaaa}--
end{document}
answered Jan 25 at 23:13
egregegreg
717k8619023191
edited Jan 25 at 23:18
answered Jan 25 at 23:13
egregegreg
717k8619023191
answered Jan 25 at 23:13
egregegreg
717k8619023191
answered Jan 25 at 23:13
egregegreg
717k8619023191
717k8619023191
add a comment |
add a comment |
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1
removemath is using catcode changes so will only work at the top level, the characters in
aaaahave already been tokenised so catcode changes have no effect. However it isn't clear why you are using catcode changes, you copuld use a delimited argument on a normal catcode$.– David Carlisle
Jan 25 at 22:15