Stored Procedure with two raiserrors
I use SQL Server.
I want to write a stored procedure that looks if a questionid
and employeeid
exists (questionid
is in the table question
, same for employeeid
, is in the table employee
) AND looks if they not already existing in the table (you don't get a duplicate in the table contentment
). I want raiserror's for the user if so.
In my case it is possible to have a duplicate but not on the same DATE
!
Contentment table has columns:
employeeid, questionid, date, score
employeeid
, questionid
, date
make up the primary key.
So I want something like this:
1,1, 18-11-2018, null
1,1, 19-11-2018, null
and not something like this:
1,1, 18-11-2018, null
1,1, 18-11-2018, null
I already made something but it is not working (1-1-1900 is a standard date, because it is primary key
it needs to be inserted, score
is not inserted because the user needs to do this):
@employeeid int,
@questionid int
as
begin
if exists (select * from question where questionid = @questionid)
and exists (select * from employee where employeeid= @employeeid)
begin
insert into contentment (employeeid, questionid, date, score)
values (@employeeid, @questionid, '1-1-1900', null)
end
if (select count(*)
from contentment
where employeeid = @employeeid
and questionid = @questionid
and date = date) = 0
raiserror ('@employeeid or @questionid already existing', 16, 1)
else
raiserror ('@employeeid or @questionid are not existing', 16, 1, null)
end
sql-server tsql
add a comment |
I use SQL Server.
I want to write a stored procedure that looks if a questionid
and employeeid
exists (questionid
is in the table question
, same for employeeid
, is in the table employee
) AND looks if they not already existing in the table (you don't get a duplicate in the table contentment
). I want raiserror's for the user if so.
In my case it is possible to have a duplicate but not on the same DATE
!
Contentment table has columns:
employeeid, questionid, date, score
employeeid
, questionid
, date
make up the primary key.
So I want something like this:
1,1, 18-11-2018, null
1,1, 19-11-2018, null
and not something like this:
1,1, 18-11-2018, null
1,1, 18-11-2018, null
I already made something but it is not working (1-1-1900 is a standard date, because it is primary key
it needs to be inserted, score
is not inserted because the user needs to do this):
@employeeid int,
@questionid int
as
begin
if exists (select * from question where questionid = @questionid)
and exists (select * from employee where employeeid= @employeeid)
begin
insert into contentment (employeeid, questionid, date, score)
values (@employeeid, @questionid, '1-1-1900', null)
end
if (select count(*)
from contentment
where employeeid = @employeeid
and questionid = @questionid
and date = date) = 0
raiserror ('@employeeid or @questionid already existing', 16, 1)
else
raiserror ('@employeeid or @questionid are not existing', 16, 1, null)
end
sql-server tsql
1
Hi there, tag your database to get proper attention. Different RDBMs have different syntax and even commands
– Jorge Campos
Nov 19 '18 at 17:49
1
@JorgeCampos Sorry I forgot to mention, just did.
– DutchFatBoys
Nov 19 '18 at 17:53
add a comment |
I use SQL Server.
I want to write a stored procedure that looks if a questionid
and employeeid
exists (questionid
is in the table question
, same for employeeid
, is in the table employee
) AND looks if they not already existing in the table (you don't get a duplicate in the table contentment
). I want raiserror's for the user if so.
In my case it is possible to have a duplicate but not on the same DATE
!
Contentment table has columns:
employeeid, questionid, date, score
employeeid
, questionid
, date
make up the primary key.
So I want something like this:
1,1, 18-11-2018, null
1,1, 19-11-2018, null
and not something like this:
1,1, 18-11-2018, null
1,1, 18-11-2018, null
I already made something but it is not working (1-1-1900 is a standard date, because it is primary key
it needs to be inserted, score
is not inserted because the user needs to do this):
@employeeid int,
@questionid int
as
begin
if exists (select * from question where questionid = @questionid)
and exists (select * from employee where employeeid= @employeeid)
begin
insert into contentment (employeeid, questionid, date, score)
values (@employeeid, @questionid, '1-1-1900', null)
end
if (select count(*)
from contentment
where employeeid = @employeeid
and questionid = @questionid
and date = date) = 0
raiserror ('@employeeid or @questionid already existing', 16, 1)
else
raiserror ('@employeeid or @questionid are not existing', 16, 1, null)
end
sql-server tsql
I use SQL Server.
I want to write a stored procedure that looks if a questionid
and employeeid
exists (questionid
is in the table question
, same for employeeid
, is in the table employee
) AND looks if they not already existing in the table (you don't get a duplicate in the table contentment
). I want raiserror's for the user if so.
In my case it is possible to have a duplicate but not on the same DATE
!
Contentment table has columns:
employeeid, questionid, date, score
employeeid
, questionid
, date
make up the primary key.
So I want something like this:
1,1, 18-11-2018, null
1,1, 19-11-2018, null
and not something like this:
1,1, 18-11-2018, null
1,1, 18-11-2018, null
I already made something but it is not working (1-1-1900 is a standard date, because it is primary key
it needs to be inserted, score
is not inserted because the user needs to do this):
@employeeid int,
@questionid int
as
begin
if exists (select * from question where questionid = @questionid)
and exists (select * from employee where employeeid= @employeeid)
begin
insert into contentment (employeeid, questionid, date, score)
values (@employeeid, @questionid, '1-1-1900', null)
end
if (select count(*)
from contentment
where employeeid = @employeeid
and questionid = @questionid
and date = date) = 0
raiserror ('@employeeid or @questionid already existing', 16, 1)
else
raiserror ('@employeeid or @questionid are not existing', 16, 1, null)
end
sql-server tsql
sql-server tsql
edited Nov 19 '18 at 19:44
marc_s
574k12811091256
574k12811091256
asked Nov 19 '18 at 17:42
DutchFatBoysDutchFatBoys
487
487
1
Hi there, tag your database to get proper attention. Different RDBMs have different syntax and even commands
– Jorge Campos
Nov 19 '18 at 17:49
1
@JorgeCampos Sorry I forgot to mention, just did.
– DutchFatBoys
Nov 19 '18 at 17:53
add a comment |
1
Hi there, tag your database to get proper attention. Different RDBMs have different syntax and even commands
– Jorge Campos
Nov 19 '18 at 17:49
1
@JorgeCampos Sorry I forgot to mention, just did.
– DutchFatBoys
Nov 19 '18 at 17:53
1
1
Hi there, tag your database to get proper attention. Different RDBMs have different syntax and even commands
– Jorge Campos
Nov 19 '18 at 17:49
Hi there, tag your database to get proper attention. Different RDBMs have different syntax and even commands
– Jorge Campos
Nov 19 '18 at 17:49
1
1
@JorgeCampos Sorry I forgot to mention, just did.
– DutchFatBoys
Nov 19 '18 at 17:53
@JorgeCampos Sorry I forgot to mention, just did.
– DutchFatBoys
Nov 19 '18 at 17:53
add a comment |
1 Answer
1
active
oldest
votes
If you want to date validation you need to provide @date as well. I have created a sample stored procedure with detail that you provide:
DROP PROCEDURE P_ContentmentInsert
GO
CREATE PROCEDURE P_ContentmentInsert
@employeeid int,
@questionid int,
@date DATE
AS
BEGIN
--Check if exists Employee, Question and Contentment
DECLARE @IsEmployeeExists INT=ISNULL((SELECT COUNT(1) FROM employee WHERE employeeid= @employeeid),0)
DECLARE @IsQuestionExists INT=ISNULL((SELECT COUNT(1) FROM question WHERE questionid = @questionid),0)
DECLARE @IsContentmentExists INT=ISNULL((SELECT COUNT(1) FROM contentment WHERE questionid = @questionid and employeeid= @employeeid and [date]=@date),0)
DECLARE @ErrorMessage VARCHAR(1000)=''
--If one of the validation not passed give error message
IF (@IsEmployeeExists=0 OR @IsQuestionExists=0 OR @IsContentmentExists=0)
BEGIN
IF @IsEmployeeExists=0
SET @ErrorMessage='-EmployeeId Not exists'
IF @IsQuestionExists=0
SET @ErrorMessage=@ErrorMessage+'-QuesitonId Not exists'
IF @IsContentmentExists=0
SET @ErrorMessage=@ErrorMessage+'-Contentment already exists'
RETURN
END
--If there is no problem insert it.
IF @IsEmployeeExists>0 and @IsQuestionExists>0 and @IsContentmentExists>0
BEGIN
INSERT INTO contentment (employeeid, questionid, date, score)
VALUES (@employeeid, @questionid, @date, null)
END
END
Why I need to provide date as well then?
– DutchFatBoys
Nov 19 '18 at 19:02
Because you want to validate date as well. You said you have three primary key QuestionId, EmployeeId and Date in contentment table. You need to provide Date to validate it.
– Zeki Gumus
Nov 19 '18 at 19:11
See my example, can I do it that way?
– DutchFatBoys
Nov 19 '18 at 19:20
You'd need to clarify under what circumstances you enter an actual date, because the code you show always uses the same date, and therefore will always cause an error the second time around. You can do the check after the insert, but then you need to rollback the transaction as well. Much better to test first if you can.
– Dale Burrell
Nov 19 '18 at 20:42
Some more questions: why do you do INT=ISNULL (Select Count(1) ...... )? And @ErrorMessage = @ErrorMessage+ ..... ? Thanks!
– DutchFatBoys
Nov 20 '18 at 8:27
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you want to date validation you need to provide @date as well. I have created a sample stored procedure with detail that you provide:
DROP PROCEDURE P_ContentmentInsert
GO
CREATE PROCEDURE P_ContentmentInsert
@employeeid int,
@questionid int,
@date DATE
AS
BEGIN
--Check if exists Employee, Question and Contentment
DECLARE @IsEmployeeExists INT=ISNULL((SELECT COUNT(1) FROM employee WHERE employeeid= @employeeid),0)
DECLARE @IsQuestionExists INT=ISNULL((SELECT COUNT(1) FROM question WHERE questionid = @questionid),0)
DECLARE @IsContentmentExists INT=ISNULL((SELECT COUNT(1) FROM contentment WHERE questionid = @questionid and employeeid= @employeeid and [date]=@date),0)
DECLARE @ErrorMessage VARCHAR(1000)=''
--If one of the validation not passed give error message
IF (@IsEmployeeExists=0 OR @IsQuestionExists=0 OR @IsContentmentExists=0)
BEGIN
IF @IsEmployeeExists=0
SET @ErrorMessage='-EmployeeId Not exists'
IF @IsQuestionExists=0
SET @ErrorMessage=@ErrorMessage+'-QuesitonId Not exists'
IF @IsContentmentExists=0
SET @ErrorMessage=@ErrorMessage+'-Contentment already exists'
RETURN
END
--If there is no problem insert it.
IF @IsEmployeeExists>0 and @IsQuestionExists>0 and @IsContentmentExists>0
BEGIN
INSERT INTO contentment (employeeid, questionid, date, score)
VALUES (@employeeid, @questionid, @date, null)
END
END
Why I need to provide date as well then?
– DutchFatBoys
Nov 19 '18 at 19:02
Because you want to validate date as well. You said you have three primary key QuestionId, EmployeeId and Date in contentment table. You need to provide Date to validate it.
– Zeki Gumus
Nov 19 '18 at 19:11
See my example, can I do it that way?
– DutchFatBoys
Nov 19 '18 at 19:20
You'd need to clarify under what circumstances you enter an actual date, because the code you show always uses the same date, and therefore will always cause an error the second time around. You can do the check after the insert, but then you need to rollback the transaction as well. Much better to test first if you can.
– Dale Burrell
Nov 19 '18 at 20:42
Some more questions: why do you do INT=ISNULL (Select Count(1) ...... )? And @ErrorMessage = @ErrorMessage+ ..... ? Thanks!
– DutchFatBoys
Nov 20 '18 at 8:27
add a comment |
If you want to date validation you need to provide @date as well. I have created a sample stored procedure with detail that you provide:
DROP PROCEDURE P_ContentmentInsert
GO
CREATE PROCEDURE P_ContentmentInsert
@employeeid int,
@questionid int,
@date DATE
AS
BEGIN
--Check if exists Employee, Question and Contentment
DECLARE @IsEmployeeExists INT=ISNULL((SELECT COUNT(1) FROM employee WHERE employeeid= @employeeid),0)
DECLARE @IsQuestionExists INT=ISNULL((SELECT COUNT(1) FROM question WHERE questionid = @questionid),0)
DECLARE @IsContentmentExists INT=ISNULL((SELECT COUNT(1) FROM contentment WHERE questionid = @questionid and employeeid= @employeeid and [date]=@date),0)
DECLARE @ErrorMessage VARCHAR(1000)=''
--If one of the validation not passed give error message
IF (@IsEmployeeExists=0 OR @IsQuestionExists=0 OR @IsContentmentExists=0)
BEGIN
IF @IsEmployeeExists=0
SET @ErrorMessage='-EmployeeId Not exists'
IF @IsQuestionExists=0
SET @ErrorMessage=@ErrorMessage+'-QuesitonId Not exists'
IF @IsContentmentExists=0
SET @ErrorMessage=@ErrorMessage+'-Contentment already exists'
RETURN
END
--If there is no problem insert it.
IF @IsEmployeeExists>0 and @IsQuestionExists>0 and @IsContentmentExists>0
BEGIN
INSERT INTO contentment (employeeid, questionid, date, score)
VALUES (@employeeid, @questionid, @date, null)
END
END
Why I need to provide date as well then?
– DutchFatBoys
Nov 19 '18 at 19:02
Because you want to validate date as well. You said you have three primary key QuestionId, EmployeeId and Date in contentment table. You need to provide Date to validate it.
– Zeki Gumus
Nov 19 '18 at 19:11
See my example, can I do it that way?
– DutchFatBoys
Nov 19 '18 at 19:20
You'd need to clarify under what circumstances you enter an actual date, because the code you show always uses the same date, and therefore will always cause an error the second time around. You can do the check after the insert, but then you need to rollback the transaction as well. Much better to test first if you can.
– Dale Burrell
Nov 19 '18 at 20:42
Some more questions: why do you do INT=ISNULL (Select Count(1) ...... )? And @ErrorMessage = @ErrorMessage+ ..... ? Thanks!
– DutchFatBoys
Nov 20 '18 at 8:27
add a comment |
If you want to date validation you need to provide @date as well. I have created a sample stored procedure with detail that you provide:
DROP PROCEDURE P_ContentmentInsert
GO
CREATE PROCEDURE P_ContentmentInsert
@employeeid int,
@questionid int,
@date DATE
AS
BEGIN
--Check if exists Employee, Question and Contentment
DECLARE @IsEmployeeExists INT=ISNULL((SELECT COUNT(1) FROM employee WHERE employeeid= @employeeid),0)
DECLARE @IsQuestionExists INT=ISNULL((SELECT COUNT(1) FROM question WHERE questionid = @questionid),0)
DECLARE @IsContentmentExists INT=ISNULL((SELECT COUNT(1) FROM contentment WHERE questionid = @questionid and employeeid= @employeeid and [date]=@date),0)
DECLARE @ErrorMessage VARCHAR(1000)=''
--If one of the validation not passed give error message
IF (@IsEmployeeExists=0 OR @IsQuestionExists=0 OR @IsContentmentExists=0)
BEGIN
IF @IsEmployeeExists=0
SET @ErrorMessage='-EmployeeId Not exists'
IF @IsQuestionExists=0
SET @ErrorMessage=@ErrorMessage+'-QuesitonId Not exists'
IF @IsContentmentExists=0
SET @ErrorMessage=@ErrorMessage+'-Contentment already exists'
RETURN
END
--If there is no problem insert it.
IF @IsEmployeeExists>0 and @IsQuestionExists>0 and @IsContentmentExists>0
BEGIN
INSERT INTO contentment (employeeid, questionid, date, score)
VALUES (@employeeid, @questionid, @date, null)
END
END
If you want to date validation you need to provide @date as well. I have created a sample stored procedure with detail that you provide:
DROP PROCEDURE P_ContentmentInsert
GO
CREATE PROCEDURE P_ContentmentInsert
@employeeid int,
@questionid int,
@date DATE
AS
BEGIN
--Check if exists Employee, Question and Contentment
DECLARE @IsEmployeeExists INT=ISNULL((SELECT COUNT(1) FROM employee WHERE employeeid= @employeeid),0)
DECLARE @IsQuestionExists INT=ISNULL((SELECT COUNT(1) FROM question WHERE questionid = @questionid),0)
DECLARE @IsContentmentExists INT=ISNULL((SELECT COUNT(1) FROM contentment WHERE questionid = @questionid and employeeid= @employeeid and [date]=@date),0)
DECLARE @ErrorMessage VARCHAR(1000)=''
--If one of the validation not passed give error message
IF (@IsEmployeeExists=0 OR @IsQuestionExists=0 OR @IsContentmentExists=0)
BEGIN
IF @IsEmployeeExists=0
SET @ErrorMessage='-EmployeeId Not exists'
IF @IsQuestionExists=0
SET @ErrorMessage=@ErrorMessage+'-QuesitonId Not exists'
IF @IsContentmentExists=0
SET @ErrorMessage=@ErrorMessage+'-Contentment already exists'
RETURN
END
--If there is no problem insert it.
IF @IsEmployeeExists>0 and @IsQuestionExists>0 and @IsContentmentExists>0
BEGIN
INSERT INTO contentment (employeeid, questionid, date, score)
VALUES (@employeeid, @questionid, @date, null)
END
END
answered Nov 19 '18 at 18:15
Zeki GumusZeki Gumus
1,372212
1,372212
Why I need to provide date as well then?
– DutchFatBoys
Nov 19 '18 at 19:02
Because you want to validate date as well. You said you have three primary key QuestionId, EmployeeId and Date in contentment table. You need to provide Date to validate it.
– Zeki Gumus
Nov 19 '18 at 19:11
See my example, can I do it that way?
– DutchFatBoys
Nov 19 '18 at 19:20
You'd need to clarify under what circumstances you enter an actual date, because the code you show always uses the same date, and therefore will always cause an error the second time around. You can do the check after the insert, but then you need to rollback the transaction as well. Much better to test first if you can.
– Dale Burrell
Nov 19 '18 at 20:42
Some more questions: why do you do INT=ISNULL (Select Count(1) ...... )? And @ErrorMessage = @ErrorMessage+ ..... ? Thanks!
– DutchFatBoys
Nov 20 '18 at 8:27
add a comment |
Why I need to provide date as well then?
– DutchFatBoys
Nov 19 '18 at 19:02
Because you want to validate date as well. You said you have three primary key QuestionId, EmployeeId and Date in contentment table. You need to provide Date to validate it.
– Zeki Gumus
Nov 19 '18 at 19:11
See my example, can I do it that way?
– DutchFatBoys
Nov 19 '18 at 19:20
You'd need to clarify under what circumstances you enter an actual date, because the code you show always uses the same date, and therefore will always cause an error the second time around. You can do the check after the insert, but then you need to rollback the transaction as well. Much better to test first if you can.
– Dale Burrell
Nov 19 '18 at 20:42
Some more questions: why do you do INT=ISNULL (Select Count(1) ...... )? And @ErrorMessage = @ErrorMessage+ ..... ? Thanks!
– DutchFatBoys
Nov 20 '18 at 8:27
Why I need to provide date as well then?
– DutchFatBoys
Nov 19 '18 at 19:02
Why I need to provide date as well then?
– DutchFatBoys
Nov 19 '18 at 19:02
Because you want to validate date as well. You said you have three primary key QuestionId, EmployeeId and Date in contentment table. You need to provide Date to validate it.
– Zeki Gumus
Nov 19 '18 at 19:11
Because you want to validate date as well. You said you have three primary key QuestionId, EmployeeId and Date in contentment table. You need to provide Date to validate it.
– Zeki Gumus
Nov 19 '18 at 19:11
See my example, can I do it that way?
– DutchFatBoys
Nov 19 '18 at 19:20
See my example, can I do it that way?
– DutchFatBoys
Nov 19 '18 at 19:20
You'd need to clarify under what circumstances you enter an actual date, because the code you show always uses the same date, and therefore will always cause an error the second time around. You can do the check after the insert, but then you need to rollback the transaction as well. Much better to test first if you can.
– Dale Burrell
Nov 19 '18 at 20:42
You'd need to clarify under what circumstances you enter an actual date, because the code you show always uses the same date, and therefore will always cause an error the second time around. You can do the check after the insert, but then you need to rollback the transaction as well. Much better to test first if you can.
– Dale Burrell
Nov 19 '18 at 20:42
Some more questions: why do you do INT=ISNULL (Select Count(1) ...... )? And @ErrorMessage = @ErrorMessage+ ..... ? Thanks!
– DutchFatBoys
Nov 20 '18 at 8:27
Some more questions: why do you do INT=ISNULL (Select Count(1) ...... )? And @ErrorMessage = @ErrorMessage+ ..... ? Thanks!
– DutchFatBoys
Nov 20 '18 at 8:27
add a comment |
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1
Hi there, tag your database to get proper attention. Different RDBMs have different syntax and even commands
– Jorge Campos
Nov 19 '18 at 17:49
1
@JorgeCampos Sorry I forgot to mention, just did.
– DutchFatBoys
Nov 19 '18 at 17:53