Smallest set (typical set)
Given the following table of sequences, I'm trying to find the smallest set with probability $p = 0.9$.
The smallest set consists of some sequences from the table, which probability (column 3) should add up to $p$, while the length (found in the second column) is being minimized.
I'm struggling to find a good approach to find the smallest set, without just trying a lot of options and checking their length. Therefore I was wondering if there exists a fast approach to find the smallest set, given such a table.
information-theory
add a comment |
Given the following table of sequences, I'm trying to find the smallest set with probability $p = 0.9$.
The smallest set consists of some sequences from the table, which probability (column 3) should add up to $p$, while the length (found in the second column) is being minimized.
I'm struggling to find a good approach to find the smallest set, without just trying a lot of options and checking their length. Therefore I was wondering if there exists a fast approach to find the smallest set, given such a table.
information-theory
what you call length is unclear to me. do you mean hamming weight? And why would you minimize it?
– kodlu
Nov 24 '18 at 0:25
And what is the probability parameter in the binomial distribution? You use $p=0.9$ but this is not the $p$ in the equations generating column 3, that looks more like $papprox 15/25,$ judging by the peak in the binomial distribution.
– kodlu
Nov 24 '18 at 0:27
add a comment |
Given the following table of sequences, I'm trying to find the smallest set with probability $p = 0.9$.
The smallest set consists of some sequences from the table, which probability (column 3) should add up to $p$, while the length (found in the second column) is being minimized.
I'm struggling to find a good approach to find the smallest set, without just trying a lot of options and checking their length. Therefore I was wondering if there exists a fast approach to find the smallest set, given such a table.
information-theory
Given the following table of sequences, I'm trying to find the smallest set with probability $p = 0.9$.
The smallest set consists of some sequences from the table, which probability (column 3) should add up to $p$, while the length (found in the second column) is being minimized.
I'm struggling to find a good approach to find the smallest set, without just trying a lot of options and checking their length. Therefore I was wondering if there exists a fast approach to find the smallest set, given such a table.
information-theory
information-theory
asked Nov 22 '18 at 11:52
Steven Raaijmakers
1175
1175
what you call length is unclear to me. do you mean hamming weight? And why would you minimize it?
– kodlu
Nov 24 '18 at 0:25
And what is the probability parameter in the binomial distribution? You use $p=0.9$ but this is not the $p$ in the equations generating column 3, that looks more like $papprox 15/25,$ judging by the peak in the binomial distribution.
– kodlu
Nov 24 '18 at 0:27
add a comment |
what you call length is unclear to me. do you mean hamming weight? And why would you minimize it?
– kodlu
Nov 24 '18 at 0:25
And what is the probability parameter in the binomial distribution? You use $p=0.9$ but this is not the $p$ in the equations generating column 3, that looks more like $papprox 15/25,$ judging by the peak in the binomial distribution.
– kodlu
Nov 24 '18 at 0:27
what you call length is unclear to me. do you mean hamming weight? And why would you minimize it?
– kodlu
Nov 24 '18 at 0:25
what you call length is unclear to me. do you mean hamming weight? And why would you minimize it?
– kodlu
Nov 24 '18 at 0:25
And what is the probability parameter in the binomial distribution? You use $p=0.9$ but this is not the $p$ in the equations generating column 3, that looks more like $papprox 15/25,$ judging by the peak in the binomial distribution.
– kodlu
Nov 24 '18 at 0:27
And what is the probability parameter in the binomial distribution? You use $p=0.9$ but this is not the $p$ in the equations generating column 3, that looks more like $papprox 15/25,$ judging by the peak in the binomial distribution.
– kodlu
Nov 24 '18 at 0:27
add a comment |
1 Answer
1
active
oldest
votes
The smallest set should be (obviously?) formed by picking the most probable sequences.
For that, you should add to your sheet that column (probability of each sequence). In this case, because $p>0.5$, it should be clear that the most probable sequences are in the last rows (greater $k$, greater probability).
Hence you should acummulate the (total) probability of those sequences, until you get your total desired probability.
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3009042%2fsmallest-set-typical-set%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The smallest set should be (obviously?) formed by picking the most probable sequences.
For that, you should add to your sheet that column (probability of each sequence). In this case, because $p>0.5$, it should be clear that the most probable sequences are in the last rows (greater $k$, greater probability).
Hence you should acummulate the (total) probability of those sequences, until you get your total desired probability.
add a comment |
The smallest set should be (obviously?) formed by picking the most probable sequences.
For that, you should add to your sheet that column (probability of each sequence). In this case, because $p>0.5$, it should be clear that the most probable sequences are in the last rows (greater $k$, greater probability).
Hence you should acummulate the (total) probability of those sequences, until you get your total desired probability.
add a comment |
The smallest set should be (obviously?) formed by picking the most probable sequences.
For that, you should add to your sheet that column (probability of each sequence). In this case, because $p>0.5$, it should be clear that the most probable sequences are in the last rows (greater $k$, greater probability).
Hence you should acummulate the (total) probability of those sequences, until you get your total desired probability.
The smallest set should be (obviously?) formed by picking the most probable sequences.
For that, you should add to your sheet that column (probability of each sequence). In this case, because $p>0.5$, it should be clear that the most probable sequences are in the last rows (greater $k$, greater probability).
Hence you should acummulate the (total) probability of those sequences, until you get your total desired probability.
answered Nov 24 '18 at 1:22
leonbloy
40.4k645107
40.4k645107
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3009042%2fsmallest-set-typical-set%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
what you call length is unclear to me. do you mean hamming weight? And why would you minimize it?
– kodlu
Nov 24 '18 at 0:25
And what is the probability parameter in the binomial distribution? You use $p=0.9$ but this is not the $p$ in the equations generating column 3, that looks more like $papprox 15/25,$ judging by the peak in the binomial distribution.
– kodlu
Nov 24 '18 at 0:27