Matchstick puzzle with roman numerals
I got a puzzle from a book that asks to move one matchstick to get a valid equation. My "solutions"
feels like cheating... Does anyone have a good idea? The original equation, layed out with matches, is
VI = V + VII
matches
edited Dec 29 '18 at 21:52
Glorfindel
13.5k34983
asked Dec 29 '18 at 14:04
Marc
1434
add a comment |
I got a puzzle from a book that asks to move one matchstick to get a valid equation. My "solutions"
feels like cheating... Does anyone have a good idea? The original equation, layed out with matches, is
VI = V + VII
matches
edited Dec 29 '18 at 21:52
Glorfindel
13.5k34983
asked Dec 29 '18 at 14:04
Marc
1434
Is the I made of 1 or 3 sticks?
– Omega Krypton
Dec 29 '18 at 14:07
It is only 1 stick
– Marc
Dec 29 '18 at 14:09
2
Please add the source of the puzzle
– Dr Xorile
Dec 29 '18 at 14:32
I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
– Marc
Dec 29 '18 at 14:47
There appear to be further matches above/below the equation shown, but which don’t appear to relate to other equations... could they be relevant?
– eggyal
Dec 30 '18 at 2:08
add a comment |
I got a puzzle from a book that asks to move one matchstick to get a valid equation. My "solutions"
feels like cheating... Does anyone have a good idea? The original equation, layed out with matches, is
VI = V + VII
matches
edited Dec 29 '18 at 21:52
Glorfindel
13.5k34983
asked Dec 29 '18 at 14:04
Marc
1434
I got a puzzle from a book that asks to move one matchstick to get a valid equation. My "solutions"
feels like cheating... Does anyone have a good idea? The original equation, layed out with matches, is
VI = V + VII
matches
matches
edited Dec 29 '18 at 21:52
Glorfindel
13.5k34983
asked Dec 29 '18 at 14:04
Marc
1434
edited Dec 29 '18 at 21:52
Glorfindel
13.5k34983
asked Dec 29 '18 at 14:04
Marc
1434
edited Dec 29 '18 at 21:52
Glorfindel
13.5k34983
edited Dec 29 '18 at 21:52
Glorfindel
13.5k34983
edited Dec 29 '18 at 21:52
Glorfindel
13.5k34983
13.5k34983
asked Dec 29 '18 at 14:04
Marc
1434
asked Dec 29 '18 at 14:04
Marc
1434
asked Dec 29 '18 at 14:04
Marc
1434
1434
Is the I made of 1 or 3 sticks?
– Omega Krypton
Dec 29 '18 at 14:07
It is only 1 stick
– Marc
Dec 29 '18 at 14:09
2
Please add the source of the puzzle
– Dr Xorile
Dec 29 '18 at 14:32
I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
– Marc
Dec 29 '18 at 14:47
There appear to be further matches above/below the equation shown, but which don’t appear to relate to other equations... could they be relevant?
– eggyal
Dec 30 '18 at 2:08
add a comment |
Is the I made of 1 or 3 sticks?
– Omega Krypton
Dec 29 '18 at 14:07
It is only 1 stick
– Marc
Dec 29 '18 at 14:09
2
Please add the source of the puzzle
– Dr Xorile
Dec 29 '18 at 14:32
I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
– Marc
Dec 29 '18 at 14:47
There appear to be further matches above/below the equation shown, but which don’t appear to relate to other equations... could they be relevant?
– eggyal
Dec 30 '18 at 2:08
Is the I made of 1 or 3 sticks?
– Omega Krypton
Dec 29 '18 at 14:07
Is the I made of 1 or 3 sticks?
– Omega Krypton
Dec 29 '18 at 14:07
It is only 1 stick
– Marc
Dec 29 '18 at 14:09
It is only 1 stick
– Marc
Dec 29 '18 at 14:09
2
2
Please add the source of the puzzle
– Dr Xorile
Dec 29 '18 at 14:32
Please add the source of the puzzle
– Dr Xorile
Dec 29 '18 at 14:32
I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
– Marc
Dec 29 '18 at 14:47
I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
– Marc
Dec 29 '18 at 14:47
There appear to be further matches above/below the equation shown, but which don’t appear to relate to other equations... could they be relevant?
– eggyal
Dec 30 '18 at 2:08
There appear to be further matches above/below the equation shown, but which don’t appear to relate to other equations... could they be relevant?
– eggyal
Dec 30 '18 at 2:08
add a comment |
7 Answers
7
active
oldest
votes
Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$
answered Dec 29 '18 at 14:42
Dr Xorile
11.6k12466
That is a nifty idea.
– Marc
Dec 29 '18 at 14:53
Really nice one :)
– ABcDexter
11 hours ago
add a comment |
Something like this:
VII = V | VII (because 7=5|7, using bitwise |)
or:
VI ≠ V + VI
answered Dec 29 '18 at 14:47
chau giang
411
1
Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
– Dr Xorile
Dec 29 '18 at 14:50
add a comment |
According to Wikipedia (emphasis added):
Zero
The number zero does not have its own Roman numeral, but the word nulla (the Latin word meaning "none") was used by medieval scholars in lieu of 0. Dionysius Exiguus was known to use nulla alongside Roman numerals in 525.[32][33]About 725, Bede or one of his colleagues used the letter N, the initial of nulla or of nihil (the Latin word for "nothing"), in a table of epacts, all written in Roman numerals.[34]
Therefore:
Move the final
Ito the front of the secondVsuch that it forms an (italicised)Nand one gets:
VI = N + VI
Which, in Arabic numerals, Bede (at very least) would have considered to be:
6 = 0 + 6
answered Dec 30 '18 at 8:51
eggyal
1412
Awesome first answer.
– WAF
Dec 30 '18 at 9:20
Thanks @WAF—but actually I came up with another answer that I have a hunch is more likely to be that which the setter had in mind?
– eggyal
20 hours ago
add a comment |
How about this?
From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)
edited Dec 29 '18 at 14:44
Dr Xorile
11.6k12466
answered Dec 29 '18 at 14:31
ladynoirminou2546
192
These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
– Dr Xorile
Dec 29 '18 at 14:44
I also though about something like that. But then the 1 is not really a 1.
– Marc
Dec 29 '18 at 14:49
add a comment |
Take the matchstick that makes the final
I, snap it in two, and place each half beneath the initialVto create anX. You’d therefore have:
XI = V + VI
Which, in Arabic numerals, is of course the valid equation:
11 = 5 + 6
answered yesterday
eggyal
1412
New contributor
eggyal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
How about:
moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)
answered Dec 29 '18 at 14:53
Excited Raichu
6,09821065
3
Then you wouldn't have "a valid equation"!
– Dr Xorile
Dec 29 '18 at 15:07
add a comment |
Partial answer-ish
Looking at the first V, if you take the right match and cross it over the first match, you get
XI = V + VIIor11 = 5 + 7
answered Dec 29 '18 at 17:07
Chris Happy
33725
2
That equation isn't correct, though.
– Emmabee
Dec 29 '18 at 17:11
Yeah, still working on it...
– Chris Happy
Dec 29 '18 at 17:12
add a comment |
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7 Answers
7
active
oldest
votes
7 Answers
7
active
oldest
votes
active
oldest
votes
active
oldest
votes
Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$
answered Dec 29 '18 at 14:42
Dr Xorile
11.6k12466
That is a nifty idea.
– Marc
Dec 29 '18 at 14:53
Really nice one :)
– ABcDexter
11 hours ago
add a comment |
Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$
answered Dec 29 '18 at 14:42
Dr Xorile
11.6k12466
That is a nifty idea.
– Marc
Dec 29 '18 at 14:53
Really nice one :)
– ABcDexter
11 hours ago
add a comment |
Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$
answered Dec 29 '18 at 14:42
Dr Xorile
11.6k12466
Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$
answered Dec 29 '18 at 14:42
Dr Xorile
11.6k12466
answered Dec 29 '18 at 14:42
Dr Xorile
11.6k12466
answered Dec 29 '18 at 14:42
Dr Xorile
11.6k12466
answered Dec 29 '18 at 14:42
Dr Xorile
11.6k12466
11.6k12466
That is a nifty idea.
– Marc
Dec 29 '18 at 14:53
Really nice one :)
– ABcDexter
11 hours ago
add a comment |
That is a nifty idea.
– Marc
Dec 29 '18 at 14:53
Really nice one :)
– ABcDexter
11 hours ago
That is a nifty idea.
– Marc
Dec 29 '18 at 14:53
That is a nifty idea.
– Marc
Dec 29 '18 at 14:53
Really nice one :)
– ABcDexter
11 hours ago
Really nice one :)
– ABcDexter
11 hours ago
add a comment |
Something like this:
VII = V | VII (because 7=5|7, using bitwise |)
or:
VI ≠ V + VI
answered Dec 29 '18 at 14:47
chau giang
411
1
Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
– Dr Xorile
Dec 29 '18 at 14:50
add a comment |
Something like this:
VII = V | VII (because 7=5|7, using bitwise |)
or:
VI ≠ V + VI
answered Dec 29 '18 at 14:47
chau giang
411
1
Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
– Dr Xorile
Dec 29 '18 at 14:50
add a comment |
Something like this:
VII = V | VII (because 7=5|7, using bitwise |)
or:
VI ≠ V + VI
answered Dec 29 '18 at 14:47
chau giang
411
Something like this:
VII = V | VII (because 7=5|7, using bitwise |)
or:
VI ≠ V + VI
answered Dec 29 '18 at 14:47
chau giang
411
answered Dec 29 '18 at 14:47
chau giang
411
answered Dec 29 '18 at 14:47
chau giang
411
answered Dec 29 '18 at 14:47
chau giang
411
411
1
Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
– Dr Xorile
Dec 29 '18 at 14:50
add a comment |
1
Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
– Dr Xorile
Dec 29 '18 at 14:50
1
1
Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
– Dr Xorile
Dec 29 '18 at 14:50
Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
– Dr Xorile
Dec 29 '18 at 14:50
add a comment |
According to Wikipedia (emphasis added):
Zero
The number zero does not have its own Roman numeral, but the word nulla (the Latin word meaning "none") was used by medieval scholars in lieu of 0. Dionysius Exiguus was known to use nulla alongside Roman numerals in 525.[32][33]About 725, Bede or one of his colleagues used the letter N, the initial of nulla or of nihil (the Latin word for "nothing"), in a table of epacts, all written in Roman numerals.[34]
Therefore:
Move the final
Ito the front of the secondVsuch that it forms an (italicised)Nand one gets:
VI = N + VI
Which, in Arabic numerals, Bede (at very least) would have considered to be:
6 = 0 + 6
answered Dec 30 '18 at 8:51
eggyal
1412
Awesome first answer.
– WAF
Dec 30 '18 at 9:20
Thanks @WAF—but actually I came up with another answer that I have a hunch is more likely to be that which the setter had in mind?
– eggyal
20 hours ago
add a comment |
According to Wikipedia (emphasis added):
Zero
The number zero does not have its own Roman numeral, but the word nulla (the Latin word meaning "none") was used by medieval scholars in lieu of 0. Dionysius Exiguus was known to use nulla alongside Roman numerals in 525.[32][33]About 725, Bede or one of his colleagues used the letter N, the initial of nulla or of nihil (the Latin word for "nothing"), in a table of epacts, all written in Roman numerals.[34]
Therefore:
Move the final
Ito the front of the secondVsuch that it forms an (italicised)Nand one gets:
VI = N + VI
Which, in Arabic numerals, Bede (at very least) would have considered to be:
6 = 0 + 6
answered Dec 30 '18 at 8:51
eggyal
1412
Awesome first answer.
– WAF
Dec 30 '18 at 9:20
Thanks @WAF—but actually I came up with another answer that I have a hunch is more likely to be that which the setter had in mind?
– eggyal
20 hours ago
add a comment |
According to Wikipedia (emphasis added):
Zero
The number zero does not have its own Roman numeral, but the word nulla (the Latin word meaning "none") was used by medieval scholars in lieu of 0. Dionysius Exiguus was known to use nulla alongside Roman numerals in 525.[32][33]About 725, Bede or one of his colleagues used the letter N, the initial of nulla or of nihil (the Latin word for "nothing"), in a table of epacts, all written in Roman numerals.[34]
Therefore:
Move the final
Ito the front of the secondVsuch that it forms an (italicised)Nand one gets:
VI = N + VI
Which, in Arabic numerals, Bede (at very least) would have considered to be:
6 = 0 + 6
answered Dec 30 '18 at 8:51
eggyal
1412
According to Wikipedia (emphasis added):
Zero
The number zero does not have its own Roman numeral, but the word nulla (the Latin word meaning "none") was used by medieval scholars in lieu of 0. Dionysius Exiguus was known to use nulla alongside Roman numerals in 525.[32][33]About 725, Bede or one of his colleagues used the letter N, the initial of nulla or of nihil (the Latin word for "nothing"), in a table of epacts, all written in Roman numerals.[34]
Therefore:
Move the final
Ito the front of the secondVsuch that it forms an (italicised)Nand one gets:
VI = N + VI
Which, in Arabic numerals, Bede (at very least) would have considered to be:
6 = 0 + 6
answered Dec 30 '18 at 8:51
eggyal
1412
answered Dec 30 '18 at 8:51
eggyal
1412
answered Dec 30 '18 at 8:51
eggyal
1412
answered Dec 30 '18 at 8:51
eggyal
1412
1412
Awesome first answer.
– WAF
Dec 30 '18 at 9:20
Thanks @WAF—but actually I came up with another answer that I have a hunch is more likely to be that which the setter had in mind?
– eggyal
20 hours ago
add a comment |
Awesome first answer.
– WAF
Dec 30 '18 at 9:20
Thanks @WAF—but actually I came up with another answer that I have a hunch is more likely to be that which the setter had in mind?
– eggyal
20 hours ago
Awesome first answer.
– WAF
Dec 30 '18 at 9:20
Awesome first answer.
– WAF
Dec 30 '18 at 9:20
Thanks @WAF—but actually I came up with another answer that I have a hunch is more likely to be that which the setter had in mind?
– eggyal
20 hours ago
Thanks @WAF—but actually I came up with another answer that I have a hunch is more likely to be that which the setter had in mind?
– eggyal
20 hours ago
add a comment |
How about this?
From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)
edited Dec 29 '18 at 14:44
Dr Xorile
11.6k12466
answered Dec 29 '18 at 14:31
ladynoirminou2546
192
These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
– Dr Xorile
Dec 29 '18 at 14:44
I also though about something like that. But then the 1 is not really a 1.
– Marc
Dec 29 '18 at 14:49
add a comment |
How about this?
From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)
edited Dec 29 '18 at 14:44
Dr Xorile
11.6k12466
answered Dec 29 '18 at 14:31
ladynoirminou2546
192
These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
– Dr Xorile
Dec 29 '18 at 14:44
I also though about something like that. But then the 1 is not really a 1.
– Marc
Dec 29 '18 at 14:49
add a comment |
How about this?
From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)
edited Dec 29 '18 at 14:44
Dr Xorile
11.6k12466
answered Dec 29 '18 at 14:31
ladynoirminou2546
192
How about this?
From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)
edited Dec 29 '18 at 14:44
Dr Xorile
11.6k12466
answered Dec 29 '18 at 14:31
ladynoirminou2546
192
edited Dec 29 '18 at 14:44
Dr Xorile
11.6k12466
edited Dec 29 '18 at 14:44
Dr Xorile
11.6k12466
edited Dec 29 '18 at 14:44
Dr Xorile
11.6k12466
11.6k12466
answered Dec 29 '18 at 14:31
ladynoirminou2546
192
answered Dec 29 '18 at 14:31
ladynoirminou2546
192
answered Dec 29 '18 at 14:31
ladynoirminou2546
192
192
These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
– Dr Xorile
Dec 29 '18 at 14:44
I also though about something like that. But then the 1 is not really a 1.
– Marc
Dec 29 '18 at 14:49
add a comment |
These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
– Dr Xorile
Dec 29 '18 at 14:44
I also though about something like that. But then the 1 is not really a 1.
– Marc
Dec 29 '18 at 14:49
These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
– Dr Xorile
Dec 29 '18 at 14:44
These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
– Dr Xorile
Dec 29 '18 at 14:44
I also though about something like that. But then the 1 is not really a 1.
– Marc
Dec 29 '18 at 14:49
I also though about something like that. But then the 1 is not really a 1.
– Marc
Dec 29 '18 at 14:49
add a comment |
Take the matchstick that makes the final
I, snap it in two, and place each half beneath the initialVto create anX. You’d therefore have:
XI = V + VI
Which, in Arabic numerals, is of course the valid equation:
11 = 5 + 6
answered yesterday
eggyal
1412
New contributor
eggyal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Take the matchstick that makes the final
I, snap it in two, and place each half beneath the initialVto create anX. You’d therefore have:
XI = V + VI
Which, in Arabic numerals, is of course the valid equation:
11 = 5 + 6
answered yesterday
eggyal
1412
New contributor
eggyal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Take the matchstick that makes the final
I, snap it in two, and place each half beneath the initialVto create anX. You’d therefore have:
XI = V + VI
Which, in Arabic numerals, is of course the valid equation:
11 = 5 + 6
answered yesterday
eggyal
1412
New contributor
eggyal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Take the matchstick that makes the final
I, snap it in two, and place each half beneath the initialVto create anX. You’d therefore have:
XI = V + VI
Which, in Arabic numerals, is of course the valid equation:
11 = 5 + 6
answered yesterday
eggyal
1412
New contributor
eggyal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
eggyal
1412
New contributor
eggyal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
eggyal
1412
answered yesterday
eggyal
1412
1412
New contributor
eggyal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
eggyal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
eggyal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
How about:
moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)
answered Dec 29 '18 at 14:53
Excited Raichu
6,09821065
3
Then you wouldn't have "a valid equation"!
– Dr Xorile
Dec 29 '18 at 15:07
add a comment |
How about:
moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)
answered Dec 29 '18 at 14:53
Excited Raichu
6,09821065
3
Then you wouldn't have "a valid equation"!
– Dr Xorile
Dec 29 '18 at 15:07
add a comment |
How about:
moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)
answered Dec 29 '18 at 14:53
Excited Raichu
6,09821065
How about:
moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)
answered Dec 29 '18 at 14:53
Excited Raichu
6,09821065
answered Dec 29 '18 at 14:53
Excited Raichu
6,09821065
answered Dec 29 '18 at 14:53
Excited Raichu
6,09821065
answered Dec 29 '18 at 14:53
Excited Raichu
6,09821065
6,09821065
3
Then you wouldn't have "a valid equation"!
– Dr Xorile
Dec 29 '18 at 15:07
add a comment |
3
Then you wouldn't have "a valid equation"!
– Dr Xorile
Dec 29 '18 at 15:07
3
3
Then you wouldn't have "a valid equation"!
– Dr Xorile
Dec 29 '18 at 15:07
Then you wouldn't have "a valid equation"!
– Dr Xorile
Dec 29 '18 at 15:07
add a comment |
Partial answer-ish
Looking at the first V, if you take the right match and cross it over the first match, you get
XI = V + VIIor11 = 5 + 7
answered Dec 29 '18 at 17:07
Chris Happy
33725
2
That equation isn't correct, though.
– Emmabee
Dec 29 '18 at 17:11
Yeah, still working on it...
– Chris Happy
Dec 29 '18 at 17:12
add a comment |
Partial answer-ish
Looking at the first V, if you take the right match and cross it over the first match, you get
XI = V + VIIor11 = 5 + 7
answered Dec 29 '18 at 17:07
Chris Happy
33725
2
That equation isn't correct, though.
– Emmabee
Dec 29 '18 at 17:11
Yeah, still working on it...
– Chris Happy
Dec 29 '18 at 17:12
add a comment |
Partial answer-ish
Looking at the first V, if you take the right match and cross it over the first match, you get
XI = V + VIIor11 = 5 + 7
answered Dec 29 '18 at 17:07
Chris Happy
33725
Partial answer-ish
Looking at the first V, if you take the right match and cross it over the first match, you get
XI = V + VIIor11 = 5 + 7
answered Dec 29 '18 at 17:07
Chris Happy
33725
edited Dec 29 '18 at 17:12
answered Dec 29 '18 at 17:07
Chris Happy
33725
answered Dec 29 '18 at 17:07
Chris Happy
33725
answered Dec 29 '18 at 17:07
Chris Happy
33725
33725
2
That equation isn't correct, though.
– Emmabee
Dec 29 '18 at 17:11
Yeah, still working on it...
– Chris Happy
Dec 29 '18 at 17:12
add a comment |
2
That equation isn't correct, though.
– Emmabee
Dec 29 '18 at 17:11
Yeah, still working on it...
– Chris Happy
Dec 29 '18 at 17:12
2
2
That equation isn't correct, though.
– Emmabee
Dec 29 '18 at 17:11
That equation isn't correct, though.
– Emmabee
Dec 29 '18 at 17:11
Yeah, still working on it...
– Chris Happy
Dec 29 '18 at 17:12
Yeah, still working on it...
– Chris Happy
Dec 29 '18 at 17:12
add a comment |
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Is the I made of 1 or 3 sticks?
– Omega Krypton
Dec 29 '18 at 14:07
It is only 1 stick
– Marc
Dec 29 '18 at 14:09
2
Please add the source of the puzzle
– Dr Xorile
Dec 29 '18 at 14:32
I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
– Marc
Dec 29 '18 at 14:47
There appear to be further matches above/below the equation shown, but which don’t appear to relate to other equations... could they be relevant?
– eggyal
Dec 30 '18 at 2:08