Prove that in similar triangles ratio of correspondent medians is same as ratio of correspondent sides











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I had a math exam today about geometry and similar triangles.
One of our math puzzle wanted us to proves something. Now I’ll explain that for you and if you help me I won’t lose 2 points of my midterm exam! So imagine that I’m your student and you’ve asked this question and I’ve answered like that.



QUESTION: We have two similar triangles. Prove that ratio of correspondent medians is same as ratio of correspondent sides.



MY ANSWER: We suppose two similar triangles, $triangle ABC$ and $triangle A’B’C’$. and also I did not mention that sides are equal! I mean $AB neq A’B’$ , $AC neq A’C’$ , $BC neq B’C’$.
And then I draw diagram 2. You can take a look here.



MYdiagram



Actually I combined shapes in diagram 1, and I just draw diagram 2 in my exam paper. (I changed name of points in diagrams to explain what I answered better)



I wrote that we know:
$$triangle ABCthicksim triangle AMN$$
$$MN parallel BC$$
$$BH=HC$$
$$MO=ON$$
$AO space, AH$ are medians



So I continued based on thales theorem:
$$frac{AM}{MB}=frac{AO}{OH}$$
$$frac{AN}{NC}=frac{AO}{OH}$$
Thus $$frac{AM}{MB}=frac{AN}{NC}$$
On the other side :
$$frac{AM}{MB}=frac{AN}{NC}=frac{AO}{OH}$$
And finally he gave me a big beautiful zero! I don’t know why and I hadn’t a change to talk to him. What’s your Idea? Is my answer OK? If yes tell me why. Because I’m going to convince him.










share|cite|improve this question




























    up vote
    2
    down vote

    favorite












    I had a math exam today about geometry and similar triangles.
    One of our math puzzle wanted us to proves something. Now I’ll explain that for you and if you help me I won’t lose 2 points of my midterm exam! So imagine that I’m your student and you’ve asked this question and I’ve answered like that.



    QUESTION: We have two similar triangles. Prove that ratio of correspondent medians is same as ratio of correspondent sides.



    MY ANSWER: We suppose two similar triangles, $triangle ABC$ and $triangle A’B’C’$. and also I did not mention that sides are equal! I mean $AB neq A’B’$ , $AC neq A’C’$ , $BC neq B’C’$.
    And then I draw diagram 2. You can take a look here.



    MYdiagram



    Actually I combined shapes in diagram 1, and I just draw diagram 2 in my exam paper. (I changed name of points in diagrams to explain what I answered better)



    I wrote that we know:
    $$triangle ABCthicksim triangle AMN$$
    $$MN parallel BC$$
    $$BH=HC$$
    $$MO=ON$$
    $AO space, AH$ are medians



    So I continued based on thales theorem:
    $$frac{AM}{MB}=frac{AO}{OH}$$
    $$frac{AN}{NC}=frac{AO}{OH}$$
    Thus $$frac{AM}{MB}=frac{AN}{NC}$$
    On the other side :
    $$frac{AM}{MB}=frac{AN}{NC}=frac{AO}{OH}$$
    And finally he gave me a big beautiful zero! I don’t know why and I hadn’t a change to talk to him. What’s your Idea? Is my answer OK? If yes tell me why. Because I’m going to convince him.










    share|cite|improve this question


























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I had a math exam today about geometry and similar triangles.
      One of our math puzzle wanted us to proves something. Now I’ll explain that for you and if you help me I won’t lose 2 points of my midterm exam! So imagine that I’m your student and you’ve asked this question and I’ve answered like that.



      QUESTION: We have two similar triangles. Prove that ratio of correspondent medians is same as ratio of correspondent sides.



      MY ANSWER: We suppose two similar triangles, $triangle ABC$ and $triangle A’B’C’$. and also I did not mention that sides are equal! I mean $AB neq A’B’$ , $AC neq A’C’$ , $BC neq B’C’$.
      And then I draw diagram 2. You can take a look here.



      MYdiagram



      Actually I combined shapes in diagram 1, and I just draw diagram 2 in my exam paper. (I changed name of points in diagrams to explain what I answered better)



      I wrote that we know:
      $$triangle ABCthicksim triangle AMN$$
      $$MN parallel BC$$
      $$BH=HC$$
      $$MO=ON$$
      $AO space, AH$ are medians



      So I continued based on thales theorem:
      $$frac{AM}{MB}=frac{AO}{OH}$$
      $$frac{AN}{NC}=frac{AO}{OH}$$
      Thus $$frac{AM}{MB}=frac{AN}{NC}$$
      On the other side :
      $$frac{AM}{MB}=frac{AN}{NC}=frac{AO}{OH}$$
      And finally he gave me a big beautiful zero! I don’t know why and I hadn’t a change to talk to him. What’s your Idea? Is my answer OK? If yes tell me why. Because I’m going to convince him.










      share|cite|improve this question















      I had a math exam today about geometry and similar triangles.
      One of our math puzzle wanted us to proves something. Now I’ll explain that for you and if you help me I won’t lose 2 points of my midterm exam! So imagine that I’m your student and you’ve asked this question and I’ve answered like that.



      QUESTION: We have two similar triangles. Prove that ratio of correspondent medians is same as ratio of correspondent sides.



      MY ANSWER: We suppose two similar triangles, $triangle ABC$ and $triangle A’B’C’$. and also I did not mention that sides are equal! I mean $AB neq A’B’$ , $AC neq A’C’$ , $BC neq B’C’$.
      And then I draw diagram 2. You can take a look here.



      MYdiagram



      Actually I combined shapes in diagram 1, and I just draw diagram 2 in my exam paper. (I changed name of points in diagrams to explain what I answered better)



      I wrote that we know:
      $$triangle ABCthicksim triangle AMN$$
      $$MN parallel BC$$
      $$BH=HC$$
      $$MO=ON$$
      $AO space, AH$ are medians



      So I continued based on thales theorem:
      $$frac{AM}{MB}=frac{AO}{OH}$$
      $$frac{AN}{NC}=frac{AO}{OH}$$
      Thus $$frac{AM}{MB}=frac{AN}{NC}$$
      On the other side :
      $$frac{AM}{MB}=frac{AN}{NC}=frac{AO}{OH}$$
      And finally he gave me a big beautiful zero! I don’t know why and I hadn’t a change to talk to him. What’s your Idea? Is my answer OK? If yes tell me why. Because I’m going to convince him.







      geometry euclidean-geometry






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      edited Nov 19 at 16:48









      Micah

      29.5k1363104




      29.5k1363104










      asked Nov 19 at 16:33









      user602338

      1537




      1537






















          2 Answers
          2






          active

          oldest

          votes

















          up vote
          1
          down vote



          accepted










          Staying with diagram 1, by similarity$$frac{AB}{BC}=frac{A'B'}{B'C'}$$But since $M$ and $M'$ are midpoints we know$$frac{AB}{BM}=frac{A'B'}{B'M'}$$And we're given $$angle B=angle B'$$Therefore (Euclid, Elements VI, 4 & 6)$$triangle ABMsimtriangle A'B'M'$$from which it follows that$$frac{AB}{A'B'}=frac{AM}{A'M'}$$



          I'm not sure it helped to superimpose the triangles (diagram 2). Your concluding proportion has lines $MB$, $NC$, $OH$, which are differences of corresponding sides, but doesn't the question call for $AB$, $AC$, $AH$ instead? You're almost there, and the teacher's zero seems a bit harsh, but you may not win your case.






          share|cite|improve this answer





















          • Yep! I agree with you Mr.Porcella. I actually hadn't any Ideas about AB , AC , and AH and still no! Because our teacher didn't prove that and when i talked to one of my classmates his idea was that.
            – user602338
            Nov 22 at 7:10












          • Mr Porcella you are a teacher. Actually you are a retired one! So as a student who is going to study a lot in chemistry, physics, biology, literature , english, arabic, geography and so on for the entrance exam to medical college, is it reasonable that I spare my time with these math proofs that does'nt really help me!?
            – user602338
            Nov 22 at 7:14










          • Well you've got a lot to study, but mathematical proofs can help train you in ways that might not be obvious at first. Someone asked Abraham Lincoln once how he learned to think and write so clearly, and he said it was by studying the proofs in the first six books of Euclid's Elements. All the best to you.
            – Edward Porcella
            Nov 22 at 16:18










          • Yeah surely I agree with you there! Good night!
            – user602338
            Nov 22 at 18:07


















          up vote
          1
          down vote













          I think you have a reasonable idea here, but your proof is incomplete. In order to apply Thales' theorem in this way, you need to know that $A$, $O$, and $H$ are collinear, and you haven't given any reason why they should be.



          Notice that you haven't ever used the fact that $O$ and $H$ are midpoints. This is what you will need to prove collinearity.






          share|cite|improve this answer





















          • SO WOULD YOU TELL ME HOW CAN WE PROVE TGAT THEY ARE COLLINEAR?
            – user602338
            Nov 19 at 17:26










          • APPLY THALES' THEOREM AGAIN TO SHOW THAT THE INTERSECTION OF $overline{AH}$ WITH $overline{MN}$ IS THE MIDPOINT OF $overline{MN}$, AND THUS MUST COINCIDE WITH $O$. (also, stop shouting)
            – Micah
            Nov 19 at 17:29












          • Oh sorry i did't shout! My keyboard capslock was on! Also im not a native formal speaker bro hh! :D
            – user602338
            Nov 19 at 17:39











          Your Answer





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          2 Answers
          2






          active

          oldest

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          2 Answers
          2






          active

          oldest

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          active

          oldest

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          active

          oldest

          votes








          up vote
          1
          down vote



          accepted










          Staying with diagram 1, by similarity$$frac{AB}{BC}=frac{A'B'}{B'C'}$$But since $M$ and $M'$ are midpoints we know$$frac{AB}{BM}=frac{A'B'}{B'M'}$$And we're given $$angle B=angle B'$$Therefore (Euclid, Elements VI, 4 & 6)$$triangle ABMsimtriangle A'B'M'$$from which it follows that$$frac{AB}{A'B'}=frac{AM}{A'M'}$$



          I'm not sure it helped to superimpose the triangles (diagram 2). Your concluding proportion has lines $MB$, $NC$, $OH$, which are differences of corresponding sides, but doesn't the question call for $AB$, $AC$, $AH$ instead? You're almost there, and the teacher's zero seems a bit harsh, but you may not win your case.






          share|cite|improve this answer





















          • Yep! I agree with you Mr.Porcella. I actually hadn't any Ideas about AB , AC , and AH and still no! Because our teacher didn't prove that and when i talked to one of my classmates his idea was that.
            – user602338
            Nov 22 at 7:10












          • Mr Porcella you are a teacher. Actually you are a retired one! So as a student who is going to study a lot in chemistry, physics, biology, literature , english, arabic, geography and so on for the entrance exam to medical college, is it reasonable that I spare my time with these math proofs that does'nt really help me!?
            – user602338
            Nov 22 at 7:14










          • Well you've got a lot to study, but mathematical proofs can help train you in ways that might not be obvious at first. Someone asked Abraham Lincoln once how he learned to think and write so clearly, and he said it was by studying the proofs in the first six books of Euclid's Elements. All the best to you.
            – Edward Porcella
            Nov 22 at 16:18










          • Yeah surely I agree with you there! Good night!
            – user602338
            Nov 22 at 18:07















          up vote
          1
          down vote



          accepted










          Staying with diagram 1, by similarity$$frac{AB}{BC}=frac{A'B'}{B'C'}$$But since $M$ and $M'$ are midpoints we know$$frac{AB}{BM}=frac{A'B'}{B'M'}$$And we're given $$angle B=angle B'$$Therefore (Euclid, Elements VI, 4 & 6)$$triangle ABMsimtriangle A'B'M'$$from which it follows that$$frac{AB}{A'B'}=frac{AM}{A'M'}$$



          I'm not sure it helped to superimpose the triangles (diagram 2). Your concluding proportion has lines $MB$, $NC$, $OH$, which are differences of corresponding sides, but doesn't the question call for $AB$, $AC$, $AH$ instead? You're almost there, and the teacher's zero seems a bit harsh, but you may not win your case.






          share|cite|improve this answer





















          • Yep! I agree with you Mr.Porcella. I actually hadn't any Ideas about AB , AC , and AH and still no! Because our teacher didn't prove that and when i talked to one of my classmates his idea was that.
            – user602338
            Nov 22 at 7:10












          • Mr Porcella you are a teacher. Actually you are a retired one! So as a student who is going to study a lot in chemistry, physics, biology, literature , english, arabic, geography and so on for the entrance exam to medical college, is it reasonable that I spare my time with these math proofs that does'nt really help me!?
            – user602338
            Nov 22 at 7:14










          • Well you've got a lot to study, but mathematical proofs can help train you in ways that might not be obvious at first. Someone asked Abraham Lincoln once how he learned to think and write so clearly, and he said it was by studying the proofs in the first six books of Euclid's Elements. All the best to you.
            – Edward Porcella
            Nov 22 at 16:18










          • Yeah surely I agree with you there! Good night!
            – user602338
            Nov 22 at 18:07













          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          Staying with diagram 1, by similarity$$frac{AB}{BC}=frac{A'B'}{B'C'}$$But since $M$ and $M'$ are midpoints we know$$frac{AB}{BM}=frac{A'B'}{B'M'}$$And we're given $$angle B=angle B'$$Therefore (Euclid, Elements VI, 4 & 6)$$triangle ABMsimtriangle A'B'M'$$from which it follows that$$frac{AB}{A'B'}=frac{AM}{A'M'}$$



          I'm not sure it helped to superimpose the triangles (diagram 2). Your concluding proportion has lines $MB$, $NC$, $OH$, which are differences of corresponding sides, but doesn't the question call for $AB$, $AC$, $AH$ instead? You're almost there, and the teacher's zero seems a bit harsh, but you may not win your case.






          share|cite|improve this answer












          Staying with diagram 1, by similarity$$frac{AB}{BC}=frac{A'B'}{B'C'}$$But since $M$ and $M'$ are midpoints we know$$frac{AB}{BM}=frac{A'B'}{B'M'}$$And we're given $$angle B=angle B'$$Therefore (Euclid, Elements VI, 4 & 6)$$triangle ABMsimtriangle A'B'M'$$from which it follows that$$frac{AB}{A'B'}=frac{AM}{A'M'}$$



          I'm not sure it helped to superimpose the triangles (diagram 2). Your concluding proportion has lines $MB$, $NC$, $OH$, which are differences of corresponding sides, but doesn't the question call for $AB$, $AC$, $AH$ instead? You're almost there, and the teacher's zero seems a bit harsh, but you may not win your case.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 21 at 19:32









          Edward Porcella

          1,4111411




          1,4111411












          • Yep! I agree with you Mr.Porcella. I actually hadn't any Ideas about AB , AC , and AH and still no! Because our teacher didn't prove that and when i talked to one of my classmates his idea was that.
            – user602338
            Nov 22 at 7:10












          • Mr Porcella you are a teacher. Actually you are a retired one! So as a student who is going to study a lot in chemistry, physics, biology, literature , english, arabic, geography and so on for the entrance exam to medical college, is it reasonable that I spare my time with these math proofs that does'nt really help me!?
            – user602338
            Nov 22 at 7:14










          • Well you've got a lot to study, but mathematical proofs can help train you in ways that might not be obvious at first. Someone asked Abraham Lincoln once how he learned to think and write so clearly, and he said it was by studying the proofs in the first six books of Euclid's Elements. All the best to you.
            – Edward Porcella
            Nov 22 at 16:18










          • Yeah surely I agree with you there! Good night!
            – user602338
            Nov 22 at 18:07


















          • Yep! I agree with you Mr.Porcella. I actually hadn't any Ideas about AB , AC , and AH and still no! Because our teacher didn't prove that and when i talked to one of my classmates his idea was that.
            – user602338
            Nov 22 at 7:10












          • Mr Porcella you are a teacher. Actually you are a retired one! So as a student who is going to study a lot in chemistry, physics, biology, literature , english, arabic, geography and so on for the entrance exam to medical college, is it reasonable that I spare my time with these math proofs that does'nt really help me!?
            – user602338
            Nov 22 at 7:14










          • Well you've got a lot to study, but mathematical proofs can help train you in ways that might not be obvious at first. Someone asked Abraham Lincoln once how he learned to think and write so clearly, and he said it was by studying the proofs in the first six books of Euclid's Elements. All the best to you.
            – Edward Porcella
            Nov 22 at 16:18










          • Yeah surely I agree with you there! Good night!
            – user602338
            Nov 22 at 18:07
















          Yep! I agree with you Mr.Porcella. I actually hadn't any Ideas about AB , AC , and AH and still no! Because our teacher didn't prove that and when i talked to one of my classmates his idea was that.
          – user602338
          Nov 22 at 7:10






          Yep! I agree with you Mr.Porcella. I actually hadn't any Ideas about AB , AC , and AH and still no! Because our teacher didn't prove that and when i talked to one of my classmates his idea was that.
          – user602338
          Nov 22 at 7:10














          Mr Porcella you are a teacher. Actually you are a retired one! So as a student who is going to study a lot in chemistry, physics, biology, literature , english, arabic, geography and so on for the entrance exam to medical college, is it reasonable that I spare my time with these math proofs that does'nt really help me!?
          – user602338
          Nov 22 at 7:14




          Mr Porcella you are a teacher. Actually you are a retired one! So as a student who is going to study a lot in chemistry, physics, biology, literature , english, arabic, geography and so on for the entrance exam to medical college, is it reasonable that I spare my time with these math proofs that does'nt really help me!?
          – user602338
          Nov 22 at 7:14












          Well you've got a lot to study, but mathematical proofs can help train you in ways that might not be obvious at first. Someone asked Abraham Lincoln once how he learned to think and write so clearly, and he said it was by studying the proofs in the first six books of Euclid's Elements. All the best to you.
          – Edward Porcella
          Nov 22 at 16:18




          Well you've got a lot to study, but mathematical proofs can help train you in ways that might not be obvious at first. Someone asked Abraham Lincoln once how he learned to think and write so clearly, and he said it was by studying the proofs in the first six books of Euclid's Elements. All the best to you.
          – Edward Porcella
          Nov 22 at 16:18












          Yeah surely I agree with you there! Good night!
          – user602338
          Nov 22 at 18:07




          Yeah surely I agree with you there! Good night!
          – user602338
          Nov 22 at 18:07










          up vote
          1
          down vote













          I think you have a reasonable idea here, but your proof is incomplete. In order to apply Thales' theorem in this way, you need to know that $A$, $O$, and $H$ are collinear, and you haven't given any reason why they should be.



          Notice that you haven't ever used the fact that $O$ and $H$ are midpoints. This is what you will need to prove collinearity.






          share|cite|improve this answer





















          • SO WOULD YOU TELL ME HOW CAN WE PROVE TGAT THEY ARE COLLINEAR?
            – user602338
            Nov 19 at 17:26










          • APPLY THALES' THEOREM AGAIN TO SHOW THAT THE INTERSECTION OF $overline{AH}$ WITH $overline{MN}$ IS THE MIDPOINT OF $overline{MN}$, AND THUS MUST COINCIDE WITH $O$. (also, stop shouting)
            – Micah
            Nov 19 at 17:29












          • Oh sorry i did't shout! My keyboard capslock was on! Also im not a native formal speaker bro hh! :D
            – user602338
            Nov 19 at 17:39















          up vote
          1
          down vote













          I think you have a reasonable idea here, but your proof is incomplete. In order to apply Thales' theorem in this way, you need to know that $A$, $O$, and $H$ are collinear, and you haven't given any reason why they should be.



          Notice that you haven't ever used the fact that $O$ and $H$ are midpoints. This is what you will need to prove collinearity.






          share|cite|improve this answer





















          • SO WOULD YOU TELL ME HOW CAN WE PROVE TGAT THEY ARE COLLINEAR?
            – user602338
            Nov 19 at 17:26










          • APPLY THALES' THEOREM AGAIN TO SHOW THAT THE INTERSECTION OF $overline{AH}$ WITH $overline{MN}$ IS THE MIDPOINT OF $overline{MN}$, AND THUS MUST COINCIDE WITH $O$. (also, stop shouting)
            – Micah
            Nov 19 at 17:29












          • Oh sorry i did't shout! My keyboard capslock was on! Also im not a native formal speaker bro hh! :D
            – user602338
            Nov 19 at 17:39













          up vote
          1
          down vote










          up vote
          1
          down vote









          I think you have a reasonable idea here, but your proof is incomplete. In order to apply Thales' theorem in this way, you need to know that $A$, $O$, and $H$ are collinear, and you haven't given any reason why they should be.



          Notice that you haven't ever used the fact that $O$ and $H$ are midpoints. This is what you will need to prove collinearity.






          share|cite|improve this answer












          I think you have a reasonable idea here, but your proof is incomplete. In order to apply Thales' theorem in this way, you need to know that $A$, $O$, and $H$ are collinear, and you haven't given any reason why they should be.



          Notice that you haven't ever used the fact that $O$ and $H$ are midpoints. This is what you will need to prove collinearity.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 19 at 17:07









          Micah

          29.5k1363104




          29.5k1363104












          • SO WOULD YOU TELL ME HOW CAN WE PROVE TGAT THEY ARE COLLINEAR?
            – user602338
            Nov 19 at 17:26










          • APPLY THALES' THEOREM AGAIN TO SHOW THAT THE INTERSECTION OF $overline{AH}$ WITH $overline{MN}$ IS THE MIDPOINT OF $overline{MN}$, AND THUS MUST COINCIDE WITH $O$. (also, stop shouting)
            – Micah
            Nov 19 at 17:29












          • Oh sorry i did't shout! My keyboard capslock was on! Also im not a native formal speaker bro hh! :D
            – user602338
            Nov 19 at 17:39


















          • SO WOULD YOU TELL ME HOW CAN WE PROVE TGAT THEY ARE COLLINEAR?
            – user602338
            Nov 19 at 17:26










          • APPLY THALES' THEOREM AGAIN TO SHOW THAT THE INTERSECTION OF $overline{AH}$ WITH $overline{MN}$ IS THE MIDPOINT OF $overline{MN}$, AND THUS MUST COINCIDE WITH $O$. (also, stop shouting)
            – Micah
            Nov 19 at 17:29












          • Oh sorry i did't shout! My keyboard capslock was on! Also im not a native formal speaker bro hh! :D
            – user602338
            Nov 19 at 17:39
















          SO WOULD YOU TELL ME HOW CAN WE PROVE TGAT THEY ARE COLLINEAR?
          – user602338
          Nov 19 at 17:26




          SO WOULD YOU TELL ME HOW CAN WE PROVE TGAT THEY ARE COLLINEAR?
          – user602338
          Nov 19 at 17:26












          APPLY THALES' THEOREM AGAIN TO SHOW THAT THE INTERSECTION OF $overline{AH}$ WITH $overline{MN}$ IS THE MIDPOINT OF $overline{MN}$, AND THUS MUST COINCIDE WITH $O$. (also, stop shouting)
          – Micah
          Nov 19 at 17:29






          APPLY THALES' THEOREM AGAIN TO SHOW THAT THE INTERSECTION OF $overline{AH}$ WITH $overline{MN}$ IS THE MIDPOINT OF $overline{MN}$, AND THUS MUST COINCIDE WITH $O$. (also, stop shouting)
          – Micah
          Nov 19 at 17:29














          Oh sorry i did't shout! My keyboard capslock was on! Also im not a native formal speaker bro hh! :D
          – user602338
          Nov 19 at 17:39




          Oh sorry i did't shout! My keyboard capslock was on! Also im not a native formal speaker bro hh! :D
          – user602338
          Nov 19 at 17:39


















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