alignat: removing the gap between the aligned variable and its coefficient












0















For the second equation, how can I remove the space between the aligned dot{x}_1 and its coefficient without abusing extra ampersands?



documentclass[10pt,a4paper]{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{3}
dot{v}_1 &= -frac{k}{M_1} x_1 - frac{d_1+d_2}{M_1} &&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
%
dot{v}_2 &= frac{d_2}{M_2} &&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
end{alignat*}
end{document}


enter image description here










share|improve this question























  • By its coefficient do you mean frac{d_2}{M_2}?

    – Sigur
    Jan 16 at 20:36













  • @Sigur Yes.....

    – Diaa
    Jan 16 at 20:37
















0















For the second equation, how can I remove the space between the aligned dot{x}_1 and its coefficient without abusing extra ampersands?



documentclass[10pt,a4paper]{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{3}
dot{v}_1 &= -frac{k}{M_1} x_1 - frac{d_1+d_2}{M_1} &&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
%
dot{v}_2 &= frac{d_2}{M_2} &&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
end{alignat*}
end{document}


enter image description here










share|improve this question























  • By its coefficient do you mean frac{d_2}{M_2}?

    – Sigur
    Jan 16 at 20:36













  • @Sigur Yes.....

    – Diaa
    Jan 16 at 20:37














0












0








0








For the second equation, how can I remove the space between the aligned dot{x}_1 and its coefficient without abusing extra ampersands?



documentclass[10pt,a4paper]{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{3}
dot{v}_1 &= -frac{k}{M_1} x_1 - frac{d_1+d_2}{M_1} &&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
%
dot{v}_2 &= frac{d_2}{M_2} &&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
end{alignat*}
end{document}


enter image description here










share|improve this question














For the second equation, how can I remove the space between the aligned dot{x}_1 and its coefficient without abusing extra ampersands?



documentclass[10pt,a4paper]{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{3}
dot{v}_1 &= -frac{k}{M_1} x_1 - frac{d_1+d_2}{M_1} &&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
%
dot{v}_2 &= frac{d_2}{M_2} &&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
end{alignat*}
end{document}


enter image description here







align alignat






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share|improve this question










asked Jan 16 at 20:33









DiaaDiaa

2,69711750




2,69711750













  • By its coefficient do you mean frac{d_2}{M_2}?

    – Sigur
    Jan 16 at 20:36













  • @Sigur Yes.....

    – Diaa
    Jan 16 at 20:37



















  • By its coefficient do you mean frac{d_2}{M_2}?

    – Sigur
    Jan 16 at 20:36













  • @Sigur Yes.....

    – Diaa
    Jan 16 at 20:37

















By its coefficient do you mean frac{d_2}{M_2}?

– Sigur
Jan 16 at 20:36







By its coefficient do you mean frac{d_2}{M_2}?

– Sigur
Jan 16 at 20:36















@Sigur Yes.....

– Diaa
Jan 16 at 20:37





@Sigur Yes.....

– Diaa
Jan 16 at 20:37










2 Answers
2






active

oldest

votes


















2














enter image description here



documentclass[10pt,a4paper]{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{3}
dot{v}_1 &= -frac{k}{M_1} x_1 - &frac{d_1+d_2}{M_1} &dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
%
dot{v}_2 &= &frac{d_2}{M_2} &dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
end{alignat*}
end{document}





share|improve this answer
























  • I know it is a very basic question, but could you please tell me what is the difference between adding && and a single one &?

    – Diaa
    Jan 16 at 20:44






  • 1





    @Diaa the alignments are like tabular (it is the same tex halign command underneath) so it is a sequence of columns and x&& puts x in one column followed by a blank entry and &&x has a blank entry in one cell followed by x. the alignment is like begin{tabular}{rlrlrlrlrlrlrlrlrlr} so entries are left or right aligned depending which column they are in.

    – David Carlisle
    Jan 16 at 20:47













  • I highly appreciate your patience and consideration.

    – Diaa
    Jan 16 at 20:50













  • @DavidCarlisle, and what is the meaning of {3} ?

    – Sigur
    Jan 16 at 20:51






  • 1





    @Sigur it is the number of rl pairs in the alignment

    – David Carlisle
    Jan 16 at 20:57



















1














I propose one of these three variants – the last one with an extra pair of &:



documentclass[10pt,a4paper]{article}
usepackage{mathtools}

begin{document}

begin{alignat*}{3}
dot{v}_1 &= -frac{k}{M_1} x_1 &{} - frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
%
dot{v}_2 &= &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
end{alignat*}

begin{alignat*}{3}
dot{v}_1 &= -frac{k}{M_1} x_1 - {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
%
dot{v}_2 &=phantom{-} frac{f}{M_2} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
end{alignat*}

begin{alignat*}{4}
dot{v}_1 &= -frac{k}{M_1} x_1 & &{}- {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
%
dot{v}_2 &=phantom{-} frac{f}{M_2} & & {} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
end{alignat*}

end{document}


enter image description here






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    2 Answers
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    enter image description here



    documentclass[10pt,a4paper]{article}
    usepackage{mathtools}
    begin{document}
    begin{alignat*}{3}
    dot{v}_1 &= -frac{k}{M_1} x_1 - &frac{d_1+d_2}{M_1} &dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
    %
    dot{v}_2 &= &frac{d_2}{M_2} &dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
    end{alignat*}
    end{document}





    share|improve this answer
























    • I know it is a very basic question, but could you please tell me what is the difference between adding && and a single one &?

      – Diaa
      Jan 16 at 20:44






    • 1





      @Diaa the alignments are like tabular (it is the same tex halign command underneath) so it is a sequence of columns and x&& puts x in one column followed by a blank entry and &&x has a blank entry in one cell followed by x. the alignment is like begin{tabular}{rlrlrlrlrlrlrlrlrlr} so entries are left or right aligned depending which column they are in.

      – David Carlisle
      Jan 16 at 20:47













    • I highly appreciate your patience and consideration.

      – Diaa
      Jan 16 at 20:50













    • @DavidCarlisle, and what is the meaning of {3} ?

      – Sigur
      Jan 16 at 20:51






    • 1





      @Sigur it is the number of rl pairs in the alignment

      – David Carlisle
      Jan 16 at 20:57
















    2














    enter image description here



    documentclass[10pt,a4paper]{article}
    usepackage{mathtools}
    begin{document}
    begin{alignat*}{3}
    dot{v}_1 &= -frac{k}{M_1} x_1 - &frac{d_1+d_2}{M_1} &dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
    %
    dot{v}_2 &= &frac{d_2}{M_2} &dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
    end{alignat*}
    end{document}





    share|improve this answer
























    • I know it is a very basic question, but could you please tell me what is the difference between adding && and a single one &?

      – Diaa
      Jan 16 at 20:44






    • 1





      @Diaa the alignments are like tabular (it is the same tex halign command underneath) so it is a sequence of columns and x&& puts x in one column followed by a blank entry and &&x has a blank entry in one cell followed by x. the alignment is like begin{tabular}{rlrlrlrlrlrlrlrlrlr} so entries are left or right aligned depending which column they are in.

      – David Carlisle
      Jan 16 at 20:47













    • I highly appreciate your patience and consideration.

      – Diaa
      Jan 16 at 20:50













    • @DavidCarlisle, and what is the meaning of {3} ?

      – Sigur
      Jan 16 at 20:51






    • 1





      @Sigur it is the number of rl pairs in the alignment

      – David Carlisle
      Jan 16 at 20:57














    2












    2








    2







    enter image description here



    documentclass[10pt,a4paper]{article}
    usepackage{mathtools}
    begin{document}
    begin{alignat*}{3}
    dot{v}_1 &= -frac{k}{M_1} x_1 - &frac{d_1+d_2}{M_1} &dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
    %
    dot{v}_2 &= &frac{d_2}{M_2} &dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
    end{alignat*}
    end{document}





    share|improve this answer













    enter image description here



    documentclass[10pt,a4paper]{article}
    usepackage{mathtools}
    begin{document}
    begin{alignat*}{3}
    dot{v}_1 &= -frac{k}{M_1} x_1 - &frac{d_1+d_2}{M_1} &dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
    %
    dot{v}_2 &= &frac{d_2}{M_2} &dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
    end{alignat*}
    end{document}






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Jan 16 at 20:42









    David CarlisleDavid Carlisle

    487k4111231868




    487k4111231868













    • I know it is a very basic question, but could you please tell me what is the difference between adding && and a single one &?

      – Diaa
      Jan 16 at 20:44






    • 1





      @Diaa the alignments are like tabular (it is the same tex halign command underneath) so it is a sequence of columns and x&& puts x in one column followed by a blank entry and &&x has a blank entry in one cell followed by x. the alignment is like begin{tabular}{rlrlrlrlrlrlrlrlrlr} so entries are left or right aligned depending which column they are in.

      – David Carlisle
      Jan 16 at 20:47













    • I highly appreciate your patience and consideration.

      – Diaa
      Jan 16 at 20:50













    • @DavidCarlisle, and what is the meaning of {3} ?

      – Sigur
      Jan 16 at 20:51






    • 1





      @Sigur it is the number of rl pairs in the alignment

      – David Carlisle
      Jan 16 at 20:57



















    • I know it is a very basic question, but could you please tell me what is the difference between adding && and a single one &?

      – Diaa
      Jan 16 at 20:44






    • 1





      @Diaa the alignments are like tabular (it is the same tex halign command underneath) so it is a sequence of columns and x&& puts x in one column followed by a blank entry and &&x has a blank entry in one cell followed by x. the alignment is like begin{tabular}{rlrlrlrlrlrlrlrlrlr} so entries are left or right aligned depending which column they are in.

      – David Carlisle
      Jan 16 at 20:47













    • I highly appreciate your patience and consideration.

      – Diaa
      Jan 16 at 20:50













    • @DavidCarlisle, and what is the meaning of {3} ?

      – Sigur
      Jan 16 at 20:51






    • 1





      @Sigur it is the number of rl pairs in the alignment

      – David Carlisle
      Jan 16 at 20:57

















    I know it is a very basic question, but could you please tell me what is the difference between adding && and a single one &?

    – Diaa
    Jan 16 at 20:44





    I know it is a very basic question, but could you please tell me what is the difference between adding && and a single one &?

    – Diaa
    Jan 16 at 20:44




    1




    1





    @Diaa the alignments are like tabular (it is the same tex halign command underneath) so it is a sequence of columns and x&& puts x in one column followed by a blank entry and &&x has a blank entry in one cell followed by x. the alignment is like begin{tabular}{rlrlrlrlrlrlrlrlrlr} so entries are left or right aligned depending which column they are in.

    – David Carlisle
    Jan 16 at 20:47







    @Diaa the alignments are like tabular (it is the same tex halign command underneath) so it is a sequence of columns and x&& puts x in one column followed by a blank entry and &&x has a blank entry in one cell followed by x. the alignment is like begin{tabular}{rlrlrlrlrlrlrlrlrlr} so entries are left or right aligned depending which column they are in.

    – David Carlisle
    Jan 16 at 20:47















    I highly appreciate your patience and consideration.

    – Diaa
    Jan 16 at 20:50







    I highly appreciate your patience and consideration.

    – Diaa
    Jan 16 at 20:50















    @DavidCarlisle, and what is the meaning of {3} ?

    – Sigur
    Jan 16 at 20:51





    @DavidCarlisle, and what is the meaning of {3} ?

    – Sigur
    Jan 16 at 20:51




    1




    1





    @Sigur it is the number of rl pairs in the alignment

    – David Carlisle
    Jan 16 at 20:57





    @Sigur it is the number of rl pairs in the alignment

    – David Carlisle
    Jan 16 at 20:57











    1














    I propose one of these three variants – the last one with an extra pair of &:



    documentclass[10pt,a4paper]{article}
    usepackage{mathtools}

    begin{document}

    begin{alignat*}{3}
    dot{v}_1 &= -frac{k}{M_1} x_1 &{} - frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
    %
    dot{v}_2 &= &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
    end{alignat*}

    begin{alignat*}{3}
    dot{v}_1 &= -frac{k}{M_1} x_1 - {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
    %
    dot{v}_2 &=phantom{-} frac{f}{M_2} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
    end{alignat*}

    begin{alignat*}{4}
    dot{v}_1 &= -frac{k}{M_1} x_1 & &{}- {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
    %
    dot{v}_2 &=phantom{-} frac{f}{M_2} & & {} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
    end{alignat*}

    end{document}


    enter image description here






    share|improve this answer




























      1














      I propose one of these three variants – the last one with an extra pair of &:



      documentclass[10pt,a4paper]{article}
      usepackage{mathtools}

      begin{document}

      begin{alignat*}{3}
      dot{v}_1 &= -frac{k}{M_1} x_1 &{} - frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
      %
      dot{v}_2 &= &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
      end{alignat*}

      begin{alignat*}{3}
      dot{v}_1 &= -frac{k}{M_1} x_1 - {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
      %
      dot{v}_2 &=phantom{-} frac{f}{M_2} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
      end{alignat*}

      begin{alignat*}{4}
      dot{v}_1 &= -frac{k}{M_1} x_1 & &{}- {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
      %
      dot{v}_2 &=phantom{-} frac{f}{M_2} & & {} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
      end{alignat*}

      end{document}


      enter image description here






      share|improve this answer


























        1












        1








        1







        I propose one of these three variants – the last one with an extra pair of &:



        documentclass[10pt,a4paper]{article}
        usepackage{mathtools}

        begin{document}

        begin{alignat*}{3}
        dot{v}_1 &= -frac{k}{M_1} x_1 &{} - frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
        %
        dot{v}_2 &= &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
        end{alignat*}

        begin{alignat*}{3}
        dot{v}_1 &= -frac{k}{M_1} x_1 - {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
        %
        dot{v}_2 &=phantom{-} frac{f}{M_2} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
        end{alignat*}

        begin{alignat*}{4}
        dot{v}_1 &= -frac{k}{M_1} x_1 & &{}- {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
        %
        dot{v}_2 &=phantom{-} frac{f}{M_2} & & {} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
        end{alignat*}

        end{document}


        enter image description here






        share|improve this answer













        I propose one of these three variants – the last one with an extra pair of &:



        documentclass[10pt,a4paper]{article}
        usepackage{mathtools}

        begin{document}

        begin{alignat*}{3}
        dot{v}_1 &= -frac{k}{M_1} x_1 &{} - frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
        %
        dot{v}_2 &= &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2 + frac{f}{M_2}
        end{alignat*}

        begin{alignat*}{3}
        dot{v}_1 &= -frac{k}{M_1} x_1 - {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
        %
        dot{v}_2 &=phantom{-} frac{f}{M_2} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
        end{alignat*}

        begin{alignat*}{4}
        dot{v}_1 &= -frac{k}{M_1} x_1 & &{}- {}& frac{d_1+d_2}{M_1}&dot{x}_1 + frac{d_2}{M_1} &&dot{x}_2\
        %
        dot{v}_2 &=phantom{-} frac{f}{M_2} & & {} +{} &frac{d_2}{M_2}&dot{x}_1 - frac{d_2}{M_2} &&dot{x}_2
        end{alignat*}

        end{document}


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 16 at 20:52









        BernardBernard

        168k770195




        168k770195






























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