Spark Equivalent of IF Then ELSE











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I have seen this question earlier here and I have took lessons from that. However I am not sure why I am getting an error when I feel it should work.



I want to create a new column in existing Spark DataFrame by some rules. Here is what I wrote. iris_spark is the data frame with a categorical variable iris_spark with three distinct categories.



from pyspark.sql import functions as F

iris_spark_df = iris_spark.withColumn(
"Class",
F.when(iris_spark.iris_class == 'Iris-setosa', 0, F.when(iris_spark.iris_class == 'Iris-versicolor',1)).otherwise(2))


Throws the following error.



---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-157-21818c7dc060> in <module>()
----> 1 iris_spark_df=iris_spark.withColumn("Class",F.when(iris_spark.iris_class=='Iris-setosa',0,F.when(iris_spark.iris_class=='Iris-versicolor',1)))

TypeError: when() takes exactly 2 arguments (3 given)


---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-157-21818c7dc060> in <module>()
----> 1 iris_spark_df=iris_spark.withColumn("Class",F.when(iris_spark.iris_class=='Iris-setosa',0,F.when(iris_spark.iris_class=='Iris-versicolor',1)))

TypeError: when() takes exactly 2 arguments (3 given)


Any idea why?










share|improve this question




























    up vote
    9
    down vote

    favorite
    6












    I have seen this question earlier here and I have took lessons from that. However I am not sure why I am getting an error when I feel it should work.



    I want to create a new column in existing Spark DataFrame by some rules. Here is what I wrote. iris_spark is the data frame with a categorical variable iris_spark with three distinct categories.



    from pyspark.sql import functions as F

    iris_spark_df = iris_spark.withColumn(
    "Class",
    F.when(iris_spark.iris_class == 'Iris-setosa', 0, F.when(iris_spark.iris_class == 'Iris-versicolor',1)).otherwise(2))


    Throws the following error.



    ---------------------------------------------------------------------------
    TypeError Traceback (most recent call last)
    <ipython-input-157-21818c7dc060> in <module>()
    ----> 1 iris_spark_df=iris_spark.withColumn("Class",F.when(iris_spark.iris_class=='Iris-setosa',0,F.when(iris_spark.iris_class=='Iris-versicolor',1)))

    TypeError: when() takes exactly 2 arguments (3 given)


    ---------------------------------------------------------------------------
    TypeError Traceback (most recent call last)
    <ipython-input-157-21818c7dc060> in <module>()
    ----> 1 iris_spark_df=iris_spark.withColumn("Class",F.when(iris_spark.iris_class=='Iris-setosa',0,F.when(iris_spark.iris_class=='Iris-versicolor',1)))

    TypeError: when() takes exactly 2 arguments (3 given)


    Any idea why?










    share|improve this question


























      up vote
      9
      down vote

      favorite
      6









      up vote
      9
      down vote

      favorite
      6






      6





      I have seen this question earlier here and I have took lessons from that. However I am not sure why I am getting an error when I feel it should work.



      I want to create a new column in existing Spark DataFrame by some rules. Here is what I wrote. iris_spark is the data frame with a categorical variable iris_spark with three distinct categories.



      from pyspark.sql import functions as F

      iris_spark_df = iris_spark.withColumn(
      "Class",
      F.when(iris_spark.iris_class == 'Iris-setosa', 0, F.when(iris_spark.iris_class == 'Iris-versicolor',1)).otherwise(2))


      Throws the following error.



      ---------------------------------------------------------------------------
      TypeError Traceback (most recent call last)
      <ipython-input-157-21818c7dc060> in <module>()
      ----> 1 iris_spark_df=iris_spark.withColumn("Class",F.when(iris_spark.iris_class=='Iris-setosa',0,F.when(iris_spark.iris_class=='Iris-versicolor',1)))

      TypeError: when() takes exactly 2 arguments (3 given)


      ---------------------------------------------------------------------------
      TypeError Traceback (most recent call last)
      <ipython-input-157-21818c7dc060> in <module>()
      ----> 1 iris_spark_df=iris_spark.withColumn("Class",F.when(iris_spark.iris_class=='Iris-setosa',0,F.when(iris_spark.iris_class=='Iris-versicolor',1)))

      TypeError: when() takes exactly 2 arguments (3 given)


      Any idea why?










      share|improve this question















      I have seen this question earlier here and I have took lessons from that. However I am not sure why I am getting an error when I feel it should work.



      I want to create a new column in existing Spark DataFrame by some rules. Here is what I wrote. iris_spark is the data frame with a categorical variable iris_spark with three distinct categories.



      from pyspark.sql import functions as F

      iris_spark_df = iris_spark.withColumn(
      "Class",
      F.when(iris_spark.iris_class == 'Iris-setosa', 0, F.when(iris_spark.iris_class == 'Iris-versicolor',1)).otherwise(2))


      Throws the following error.



      ---------------------------------------------------------------------------
      TypeError Traceback (most recent call last)
      <ipython-input-157-21818c7dc060> in <module>()
      ----> 1 iris_spark_df=iris_spark.withColumn("Class",F.when(iris_spark.iris_class=='Iris-setosa',0,F.when(iris_spark.iris_class=='Iris-versicolor',1)))

      TypeError: when() takes exactly 2 arguments (3 given)


      ---------------------------------------------------------------------------
      TypeError Traceback (most recent call last)
      <ipython-input-157-21818c7dc060> in <module>()
      ----> 1 iris_spark_df=iris_spark.withColumn("Class",F.when(iris_spark.iris_class=='Iris-setosa',0,F.when(iris_spark.iris_class=='Iris-versicolor',1)))

      TypeError: when() takes exactly 2 arguments (3 given)


      Any idea why?







      python apache-spark pyspark apache-spark-sql






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      edited Dec 10 '17 at 1:43









      Community

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      asked Aug 19 '16 at 21:59









      Baktaawar

      1,62582957




      1,62582957
























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          Correct structure is either:



          (when(col("iris_class") == 'Iris-setosa', 0)
          .when(col("iris_class") == 'Iris-versicolor', 1)
          .otherwise(2))


          which is equivalent to



          CASE 
          WHEN (iris_class = 'Iris-setosa') THEN 0
          WHEN (iris_class = 'Iris-versicolor') THEN 1
          ELSE 2
          END


          or:



          (when(col("iris_class") == 'Iris-setosa', 0)
          .otherwise(when(col("iris_class") == 'Iris-versicolor', 1)
          .otherwise(2)))


          which is equivalent to:



          CASE WHEN (iris_class = 'Iris-setosa') THEN 0 
          ELSE CASE WHEN (iris_class = 'Iris-versicolor') THEN 1
          ELSE 2
          END
          END


          with general syntax:



          when(condition, value).when(...)


          or



          when(condition, value).otherwise(...)


          You probably mixed up things with Hive IF conditional:



          IF(condition, if-true, if-false)


          which can be used only in raw SQL with Hive support.






          share|improve this answer























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            1 Answer
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            up vote
            25
            down vote













            Correct structure is either:



            (when(col("iris_class") == 'Iris-setosa', 0)
            .when(col("iris_class") == 'Iris-versicolor', 1)
            .otherwise(2))


            which is equivalent to



            CASE 
            WHEN (iris_class = 'Iris-setosa') THEN 0
            WHEN (iris_class = 'Iris-versicolor') THEN 1
            ELSE 2
            END


            or:



            (when(col("iris_class") == 'Iris-setosa', 0)
            .otherwise(when(col("iris_class") == 'Iris-versicolor', 1)
            .otherwise(2)))


            which is equivalent to:



            CASE WHEN (iris_class = 'Iris-setosa') THEN 0 
            ELSE CASE WHEN (iris_class = 'Iris-versicolor') THEN 1
            ELSE 2
            END
            END


            with general syntax:



            when(condition, value).when(...)


            or



            when(condition, value).otherwise(...)


            You probably mixed up things with Hive IF conditional:



            IF(condition, if-true, if-false)


            which can be used only in raw SQL with Hive support.






            share|improve this answer



























              up vote
              25
              down vote













              Correct structure is either:



              (when(col("iris_class") == 'Iris-setosa', 0)
              .when(col("iris_class") == 'Iris-versicolor', 1)
              .otherwise(2))


              which is equivalent to



              CASE 
              WHEN (iris_class = 'Iris-setosa') THEN 0
              WHEN (iris_class = 'Iris-versicolor') THEN 1
              ELSE 2
              END


              or:



              (when(col("iris_class") == 'Iris-setosa', 0)
              .otherwise(when(col("iris_class") == 'Iris-versicolor', 1)
              .otherwise(2)))


              which is equivalent to:



              CASE WHEN (iris_class = 'Iris-setosa') THEN 0 
              ELSE CASE WHEN (iris_class = 'Iris-versicolor') THEN 1
              ELSE 2
              END
              END


              with general syntax:



              when(condition, value).when(...)


              or



              when(condition, value).otherwise(...)


              You probably mixed up things with Hive IF conditional:



              IF(condition, if-true, if-false)


              which can be used only in raw SQL with Hive support.






              share|improve this answer

























                up vote
                25
                down vote










                up vote
                25
                down vote









                Correct structure is either:



                (when(col("iris_class") == 'Iris-setosa', 0)
                .when(col("iris_class") == 'Iris-versicolor', 1)
                .otherwise(2))


                which is equivalent to



                CASE 
                WHEN (iris_class = 'Iris-setosa') THEN 0
                WHEN (iris_class = 'Iris-versicolor') THEN 1
                ELSE 2
                END


                or:



                (when(col("iris_class") == 'Iris-setosa', 0)
                .otherwise(when(col("iris_class") == 'Iris-versicolor', 1)
                .otherwise(2)))


                which is equivalent to:



                CASE WHEN (iris_class = 'Iris-setosa') THEN 0 
                ELSE CASE WHEN (iris_class = 'Iris-versicolor') THEN 1
                ELSE 2
                END
                END


                with general syntax:



                when(condition, value).when(...)


                or



                when(condition, value).otherwise(...)


                You probably mixed up things with Hive IF conditional:



                IF(condition, if-true, if-false)


                which can be used only in raw SQL with Hive support.






                share|improve this answer














                Correct structure is either:



                (when(col("iris_class") == 'Iris-setosa', 0)
                .when(col("iris_class") == 'Iris-versicolor', 1)
                .otherwise(2))


                which is equivalent to



                CASE 
                WHEN (iris_class = 'Iris-setosa') THEN 0
                WHEN (iris_class = 'Iris-versicolor') THEN 1
                ELSE 2
                END


                or:



                (when(col("iris_class") == 'Iris-setosa', 0)
                .otherwise(when(col("iris_class") == 'Iris-versicolor', 1)
                .otherwise(2)))


                which is equivalent to:



                CASE WHEN (iris_class = 'Iris-setosa') THEN 0 
                ELSE CASE WHEN (iris_class = 'Iris-versicolor') THEN 1
                ELSE 2
                END
                END


                with general syntax:



                when(condition, value).when(...)


                or



                when(condition, value).otherwise(...)


                You probably mixed up things with Hive IF conditional:



                IF(condition, if-true, if-false)


                which can be used only in raw SQL with Hive support.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Mar 1 '17 at 23:54

























                answered Aug 19 '16 at 22:26









                zero323

                161k39461562




                161k39461562






























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