Shall structured binding to a copy of a const c-array be const?












26














Consider this code (demo):



#include <tuple>
#include <type_traits>

struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];

const Ag ag {};
const T t {};
const Ar ar {};

void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}


A structured binding to a copy of a const c-array are declared const by Clang and non-const by GCC.



The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.



On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar is accordingly to [expr.type]/1 const int[2].



What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.










share|improve this question




















  • 1




    Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
    – Daniel Langr
    Dec 11 '18 at 14:44








  • 3




    gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
    – cpplearner
    Dec 11 '18 at 14:59
















26














Consider this code (demo):



#include <tuple>
#include <type_traits>

struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];

const Ag ag {};
const T t {};
const Ar ar {};

void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}


A structured binding to a copy of a const c-array are declared const by Clang and non-const by GCC.



The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.



On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar is accordingly to [expr.type]/1 const int[2].



What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.










share|improve this question




















  • 1




    Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
    – Daniel Langr
    Dec 11 '18 at 14:44








  • 3




    gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
    – cpplearner
    Dec 11 '18 at 14:59














26












26








26


4





Consider this code (demo):



#include <tuple>
#include <type_traits>

struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];

const Ag ag {};
const T t {};
const Ar ar {};

void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}


A structured binding to a copy of a const c-array are declared const by Clang and non-const by GCC.



The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.



On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar is accordingly to [expr.type]/1 const int[2].



What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.










share|improve this question















Consider this code (demo):



#include <tuple>
#include <type_traits>

struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];

const Ag ag {};
const T t {};
const Ar ar {};

void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}


A structured binding to a copy of a const c-array are declared const by Clang and non-const by GCC.



The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.



On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar is accordingly to [expr.type]/1 const int[2].



What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.







c++ language-lawyer c++17 structured-bindings






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 11 '18 at 14:27

























asked Dec 11 '18 at 14:21









Oliv

8,2601956




8,2601956








  • 1




    Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
    – Daniel Langr
    Dec 11 '18 at 14:44








  • 3




    gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
    – cpplearner
    Dec 11 '18 at 14:59














  • 1




    Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
    – Daniel Langr
    Dec 11 '18 at 14:44








  • 3




    gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
    – cpplearner
    Dec 11 '18 at 14:59








1




1




Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
Dec 11 '18 at 14:44






Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
Dec 11 '18 at 14:44






3




3




gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
Dec 11 '18 at 14:59




gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
Dec 11 '18 at 14:59












1 Answer
1






active

oldest

votes


















19














The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.






share|improve this answer





















  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:21








  • 5




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    Dec 11 '18 at 16:25










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:56











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19














The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.






share|improve this answer





















  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:21








  • 5




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    Dec 11 '18 at 16:25










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:56
















19














The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.






share|improve this answer





















  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:21








  • 5




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    Dec 11 '18 at 16:25










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:56














19












19








19






The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.






share|improve this answer












The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.







share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 11 '18 at 15:32









Barry

177k18304558




177k18304558












  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:21








  • 5




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    Dec 11 '18 at 16:25










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:56


















  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:21








  • 5




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    Dec 11 '18 at 16:25










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    Dec 11 '18 at 16:56
















The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
– Lightness Races in Orbit
Dec 11 '18 at 16:21






The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
– Lightness Races in Orbit
Dec 11 '18 at 16:21






5




5




@LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
– Barry
Dec 11 '18 at 16:25




@LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
– Barry
Dec 11 '18 at 16:25












Mm, I could be persuaded by that.
– Lightness Races in Orbit
Dec 11 '18 at 16:56




Mm, I could be persuaded by that.
– Lightness Races in Orbit
Dec 11 '18 at 16:56


















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