Hypegeometric differential equation
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I was wondering if someone, a smart person, can tell me how to transform the following equations (see below) into the well-known Hypergeometric equations. I know that this can be done provided The Mathematica does it, but I need to know the specific rules of transformation: Case 1:
(x^2)*(x+b)f,xx -bxf,x = (a+dx)f
case 2 (x^2)*(x+b)f,xx +(x^2)f,x = (a+dx)f
where b can be positive or negative while a and d are positive.
Thank you for any help that you can provide to this fellow in need. G.W
hypergeometric-function
asked Jan 2 at 2:54
user630770user630770
1
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add a comment |
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0
I was wondering if someone, a smart person, can tell me how to transform the following equations (see below) into the well-known Hypergeometric equations. I know that this can be done provided The Mathematica does it, but I need to know the specific rules of transformation: Case 1:
(x^2)*(x+b)f,xx -bxf,x = (a+dx)f
case 2 (x^2)*(x+b)f,xx +(x^2)f,x = (a+dx)f
where b can be positive or negative while a and d are positive.
Thank you for any help that you can provide to this fellow in need. G.W
hypergeometric-function
asked Jan 2 at 2:54
user630770user630770
1
$endgroup$
2
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This is hard to read. Please see math.meta.stackexchange.com/questions/5020
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– Lord Shark the Unknown
Jan 2 at 3:30
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Change of function $f(x)=x^py(x)$ and determines $p$ to get the hypergeometric ODE with unknown function $y(x)$.
$endgroup$
– JJacquelin
Jan 2 at 5:06
add a comment |
$begingroup$
0
I was wondering if someone, a smart person, can tell me how to transform the following equations (see below) into the well-known Hypergeometric equations. I know that this can be done provided The Mathematica does it, but I need to know the specific rules of transformation: Case 1:
(x^2)*(x+b)f,xx -bxf,x = (a+dx)f
case 2 (x^2)*(x+b)f,xx +(x^2)f,x = (a+dx)f
where b can be positive or negative while a and d are positive.
Thank you for any help that you can provide to this fellow in need. G.W
hypergeometric-function
asked Jan 2 at 2:54
user630770user630770
1
$endgroup$
0
I was wondering if someone, a smart person, can tell me how to transform the following equations (see below) into the well-known Hypergeometric equations. I know that this can be done provided The Mathematica does it, but I need to know the specific rules of transformation: Case 1:
(x^2)*(x+b)f,xx -bxf,x = (a+dx)f
case 2 (x^2)*(x+b)f,xx +(x^2)f,x = (a+dx)f
where b can be positive or negative while a and d are positive.
Thank you for any help that you can provide to this fellow in need. G.W
hypergeometric-function
hypergeometric-function
asked Jan 2 at 2:54
user630770user630770
1
asked Jan 2 at 2:54
user630770user630770
1
asked Jan 2 at 2:54
user630770user630770
1
asked Jan 2 at 2:54
user630770user630770
1
asked Jan 2 at 2:54
user630770user630770
1
1
2
$begingroup$
This is hard to read. Please see math.meta.stackexchange.com/questions/5020
$endgroup$
– Lord Shark the Unknown
Jan 2 at 3:30
$begingroup$
Change of function $f(x)=x^py(x)$ and determines $p$ to get the hypergeometric ODE with unknown function $y(x)$.
$endgroup$
– JJacquelin
Jan 2 at 5:06
add a comment |
2
$begingroup$
This is hard to read. Please see math.meta.stackexchange.com/questions/5020
$endgroup$
– Lord Shark the Unknown
Jan 2 at 3:30
$begingroup$
Change of function $f(x)=x^py(x)$ and determines $p$ to get the hypergeometric ODE with unknown function $y(x)$.
$endgroup$
– JJacquelin
Jan 2 at 5:06
2
2
$begingroup$
This is hard to read. Please see math.meta.stackexchange.com/questions/5020
$endgroup$
– Lord Shark the Unknown
Jan 2 at 3:30
$begingroup$
This is hard to read. Please see math.meta.stackexchange.com/questions/5020
$endgroup$
– Lord Shark the Unknown
Jan 2 at 3:30
$begingroup$
Change of function $f(x)=x^py(x)$ and determines $p$ to get the hypergeometric ODE with unknown function $y(x)$.
$endgroup$
– JJacquelin
Jan 2 at 5:06
$begingroup$
Change of function $f(x)=x^py(x)$ and determines $p$ to get the hypergeometric ODE with unknown function $y(x)$.
$endgroup$
– JJacquelin
Jan 2 at 5:06
add a comment |
0
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This is hard to read. Please see math.meta.stackexchange.com/questions/5020
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– Lord Shark the Unknown
Jan 2 at 3:30
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Change of function $f(x)=x^py(x)$ and determines $p$ to get the hypergeometric ODE with unknown function $y(x)$.
$endgroup$
– JJacquelin
Jan 2 at 5:06