Scala: given multiple strings, use an if statement to find if given string is in set 1,2,or none

Given Strings: "A", "BDS", "DE", "BO", "IID"
Here is what I have:

def givenStrings(code: List[String]) = {

   //val code = List("A", "BDS", "DE", "BO", "IID")

      if (code.contains("A", "BDS"))

         "It is in the first set";

      else if(security_code.contains("DE", "BO", "IID"))

         "It is in the second set";

      else 

         "Not given";

}



givenStrings(List("A")) -> Should result in "It is in the first set"

givenStrings(List("DE")) -> Should result in "It is in the second set"

givenStrings(List("OOOOOO")) -> Should result in "Not given"

The error I get is
type mismatch; found :String("A") required: List[String]

edited Nov 21 '18 at 19:40

SCouto

4,00731428

asked Nov 21 '18 at 19:21

YouSun

133

Hi @YouSun, the error is clear you're passing an String to your function, but it requires a List[String], because that is how you declared it here: def givenStrings(code: List[String]).

– Luis Miguel Mejía Suárez
Nov 21 '18 at 19:27

also code and securitycode are misleading

– stack0114106
Nov 21 '18 at 19:27

add a comment |

Given Strings: "A", "BDS", "DE", "BO", "IID"
Here is what I have:

def givenStrings(code: List[String]) = {

   //val code = List("A", "BDS", "DE", "BO", "IID")

      if (code.contains("A", "BDS"))

         "It is in the first set";

      else if(security_code.contains("DE", "BO", "IID"))

         "It is in the second set";

      else 

         "Not given";

}



givenStrings(List("A")) -> Should result in "It is in the first set"

givenStrings(List("DE")) -> Should result in "It is in the second set"

givenStrings(List("OOOOOO")) -> Should result in "Not given"

The error I get is
type mismatch; found :String("A") required: List[String]

edited Nov 21 '18 at 19:40

SCouto

4,00731428

asked Nov 21 '18 at 19:21

YouSun

133

Hi @YouSun, the error is clear you're passing an String to your function, but it requires a List[String], because that is how you declared it here: def givenStrings(code: List[String]).

– Luis Miguel Mejía Suárez
Nov 21 '18 at 19:27

also code and securitycode are misleading

– stack0114106
Nov 21 '18 at 19:27

add a comment |

Given Strings: "A", "BDS", "DE", "BO", "IID"
Here is what I have:

def givenStrings(code: List[String]) = {

   //val code = List("A", "BDS", "DE", "BO", "IID")

      if (code.contains("A", "BDS"))

         "It is in the first set";

      else if(security_code.contains("DE", "BO", "IID"))

         "It is in the second set";

      else 

         "Not given";

}



givenStrings(List("A")) -> Should result in "It is in the first set"

givenStrings(List("DE")) -> Should result in "It is in the second set"

givenStrings(List("OOOOOO")) -> Should result in "Not given"

The error I get is
type mismatch; found :String("A") required: List[String]

edited Nov 21 '18 at 19:40

SCouto

4,00731428

asked Nov 21 '18 at 19:21

YouSun

133

Given Strings: "A", "BDS", "DE", "BO", "IID"
Here is what I have:

def givenStrings(code: List[String]) = {

   //val code = List("A", "BDS", "DE", "BO", "IID")

      if (code.contains("A", "BDS"))

         "It is in the first set";

      else if(security_code.contains("DE", "BO", "IID"))

         "It is in the second set";

      else 

         "Not given";

}



givenStrings(List("A")) -> Should result in "It is in the first set"

givenStrings(List("DE")) -> Should result in "It is in the second set"

givenStrings(List("OOOOOO")) -> Should result in "Not given"

The error I get is
type mismatch; found :String("A") required: List[String]

scala

edited Nov 21 '18 at 19:40

SCouto

4,00731428

asked Nov 21 '18 at 19:21

YouSun

133

edited Nov 21 '18 at 19:40

SCouto

4,00731428

asked Nov 21 '18 at 19:21

YouSun

133

edited Nov 21 '18 at 19:40

SCouto

4,00731428

edited Nov 21 '18 at 19:40

SCouto

4,00731428

edited Nov 21 '18 at 19:40

SCouto

4,00731428

asked Nov 21 '18 at 19:21

YouSun

133

asked Nov 21 '18 at 19:21

YouSun

133

asked Nov 21 '18 at 19:21

YouSun

133

Hi @YouSun, the error is clear you're passing an String to your function, but it requires a List[String], because that is how you declared it here: def givenStrings(code: List[String]).

– Luis Miguel Mejía Suárez
Nov 21 '18 at 19:27

also code and securitycode are misleading

– stack0114106
Nov 21 '18 at 19:27

add a comment |

Hi @YouSun, the error is clear you're passing an String to your function, but it requires a List[String], because that is how you declared it here: def givenStrings(code: List[String]).

– Luis Miguel Mejía Suárez
Nov 21 '18 at 19:27

also code and securitycode are misleading

– stack0114106
Nov 21 '18 at 19:27

Hi @YouSun, the error is clear you're passing an String to your function, but it requires a List[String], because that is how you declared it here: def givenStrings(code: List[String]).

– Luis Miguel Mejía Suárez
Nov 21 '18 at 19:27

also code and securitycode are misleading

– stack0114106
Nov 21 '18 at 19:27

add a comment |

2 Answers
2

active

oldest

votes

The problem is that you're checking if your string contains the list, while what you want is the opposite.

I believe this is more close to what you need.

object Codes {

  private val codes: Set[String] = Set("A", "BDS")

  private val securityCodes: Set[String] = Set("DE", "BO", "IID")

  def givenString(code: String): Unit = {

    if (codes.contains(code)) {

      println("It is in the first set")

    } else if (securityCodes.contains(code)) {

      println("It is in the second set")

    } else {

      println("Not given")

    }

  }

}

edited Nov 21 '18 at 20:12

answered Nov 21 '18 at 19:47

Luis Miguel Mejía Suárez

2,7712923

Thanks, however the keyword contain is not a member of Set[String]

– YouSun
Nov 21 '18 at 20:02

@YouSun my bad, it is contains, I edited the answer - my apologies for the confusion. PS: in this case contains is not a keyword, just a method name.

– Luis Miguel Mejía Suárez
Nov 21 '18 at 20:13

add a comment |

The method you wrote is expecting a list, but you are passing in a string. So change your method signature to:

def givenStrings(code: String) = {

and now you'll have a method that expects a string, and won't complain to you when you give it one.

Now, you also don't want to over-write the value of code that is passed in to your function. You should remove that line.

Finally, you can't just start calling the variable security_code. So change that back to simply code.

answered Nov 21 '18 at 19:26

Metropolis

1,240927

Thanks, I have changed it to def givenStrings(code: String) = { if (code.contains("A", "BDS")) "It is in the first set"; else if(code.contains("DE", "BO", "IID")) "It is in the second set"; else "Not given"; } givenStrings("A") however I get "Not given" when it should be "It is in the first set"

– YouSun
Nov 21 '18 at 19:36

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53419178%2fscala-given-multiple-strings-use-an-if-statement-to-find-if-given-string-is-in%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

The problem is that you're checking if your string contains the list, while what you want is the opposite.

I believe this is more close to what you need.

object Codes {

  private val codes: Set[String] = Set("A", "BDS")

  private val securityCodes: Set[String] = Set("DE", "BO", "IID")

  def givenString(code: String): Unit = {

    if (codes.contains(code)) {

      println("It is in the first set")

    } else if (securityCodes.contains(code)) {

      println("It is in the second set")

    } else {

      println("Not given")

    }

  }

}

edited Nov 21 '18 at 20:12

answered Nov 21 '18 at 19:47

Luis Miguel Mejía Suárez

2,7712923

Thanks, however the keyword contain is not a member of Set[String]

– YouSun
Nov 21 '18 at 20:02

@YouSun my bad, it is contains, I edited the answer - my apologies for the confusion. PS: in this case contains is not a keyword, just a method name.

– Luis Miguel Mejía Suárez
Nov 21 '18 at 20:13

add a comment |

The problem is that you're checking if your string contains the list, while what you want is the opposite.

I believe this is more close to what you need.

object Codes {

  private val codes: Set[String] = Set("A", "BDS")

  private val securityCodes: Set[String] = Set("DE", "BO", "IID")

  def givenString(code: String): Unit = {

    if (codes.contains(code)) {

      println("It is in the first set")

    } else if (securityCodes.contains(code)) {

      println("It is in the second set")

    } else {

      println("Not given")

    }

  }

}

edited Nov 21 '18 at 20:12

answered Nov 21 '18 at 19:47

Luis Miguel Mejía Suárez

2,7712923

Thanks, however the keyword contain is not a member of Set[String]

– YouSun
Nov 21 '18 at 20:02

@YouSun my bad, it is contains, I edited the answer - my apologies for the confusion. PS: in this case contains is not a keyword, just a method name.

– Luis Miguel Mejía Suárez
Nov 21 '18 at 20:13

add a comment |

The problem is that you're checking if your string contains the list, while what you want is the opposite.

I believe this is more close to what you need.

object Codes {

  private val codes: Set[String] = Set("A", "BDS")

  private val securityCodes: Set[String] = Set("DE", "BO", "IID")

  def givenString(code: String): Unit = {

    if (codes.contains(code)) {

      println("It is in the first set")

    } else if (securityCodes.contains(code)) {

      println("It is in the second set")

    } else {

      println("Not given")

    }

  }

}

edited Nov 21 '18 at 20:12

answered Nov 21 '18 at 19:47

Luis Miguel Mejía Suárez

2,7712923

The problem is that you're checking if your string contains the list, while what you want is the opposite.

I believe this is more close to what you need.

object Codes {

  private val codes: Set[String] = Set("A", "BDS")

  private val securityCodes: Set[String] = Set("DE", "BO", "IID")

  def givenString(code: String): Unit = {

    if (codes.contains(code)) {

      println("It is in the first set")

    } else if (securityCodes.contains(code)) {

      println("It is in the second set")

    } else {

      println("Not given")

    }

  }

}

edited Nov 21 '18 at 20:12

answered Nov 21 '18 at 19:47

Luis Miguel Mejía Suárez

2,7712923

edited Nov 21 '18 at 20:12

answered Nov 21 '18 at 19:47

Luis Miguel Mejía Suárez

2,7712923

answered Nov 21 '18 at 19:47

Luis Miguel Mejía Suárez

2,7712923

answered Nov 21 '18 at 19:47

Luis Miguel Mejía Suárez

2,7712923

Thanks, however the keyword contain is not a member of Set[String]

– YouSun
Nov 21 '18 at 20:02

@YouSun my bad, it is contains, I edited the answer - my apologies for the confusion. PS: in this case contains is not a keyword, just a method name.

– Luis Miguel Mejía Suárez
Nov 21 '18 at 20:13

add a comment |

Thanks, however the keyword contain is not a member of Set[String]

– YouSun
Nov 21 '18 at 20:02

@YouSun my bad, it is contains, I edited the answer - my apologies for the confusion. PS: in this case contains is not a keyword, just a method name.

– Luis Miguel Mejía Suárez
Nov 21 '18 at 20:13

Thanks, however the keyword contain is not a member of Set[String]

– YouSun
Nov 21 '18 at 20:02

@YouSun my bad, it is contains, I edited the answer - my apologies for the confusion. PS: in this case contains is not a keyword, just a method name.

– Luis Miguel Mejía Suárez
Nov 21 '18 at 20:13

add a comment |

The method you wrote is expecting a list, but you are passing in a string. So change your method signature to:

def givenStrings(code: String) = {

and now you'll have a method that expects a string, and won't complain to you when you give it one.

Now, you also don't want to over-write the value of code that is passed in to your function. You should remove that line.

Finally, you can't just start calling the variable security_code. So change that back to simply code.

answered Nov 21 '18 at 19:26

Metropolis

1,240927

Thanks, I have changed it to def givenStrings(code: String) = { if (code.contains("A", "BDS")) "It is in the first set"; else if(code.contains("DE", "BO", "IID")) "It is in the second set"; else "Not given"; } givenStrings("A") however I get "Not given" when it should be "It is in the first set"

– YouSun
Nov 21 '18 at 19:36

add a comment |

The method you wrote is expecting a list, but you are passing in a string. So change your method signature to:

def givenStrings(code: String) = {

and now you'll have a method that expects a string, and won't complain to you when you give it one.

Now, you also don't want to over-write the value of code that is passed in to your function. You should remove that line.

Finally, you can't just start calling the variable security_code. So change that back to simply code.

answered Nov 21 '18 at 19:26

Metropolis

1,240927

Thanks, I have changed it to def givenStrings(code: String) = { if (code.contains("A", "BDS")) "It is in the first set"; else if(code.contains("DE", "BO", "IID")) "It is in the second set"; else "Not given"; } givenStrings("A") however I get "Not given" when it should be "It is in the first set"

– YouSun
Nov 21 '18 at 19:36

add a comment |

The method you wrote is expecting a list, but you are passing in a string. So change your method signature to:

def givenStrings(code: String) = {

and now you'll have a method that expects a string, and won't complain to you when you give it one.

Now, you also don't want to over-write the value of code that is passed in to your function. You should remove that line.

Finally, you can't just start calling the variable security_code. So change that back to simply code.

answered Nov 21 '18 at 19:26

Metropolis

1,240927

The method you wrote is expecting a list, but you are passing in a string. So change your method signature to:

def givenStrings(code: String) = {

and now you'll have a method that expects a string, and won't complain to you when you give it one.

Now, you also don't want to over-write the value of code that is passed in to your function. You should remove that line.

Finally, you can't just start calling the variable security_code. So change that back to simply code.

answered Nov 21 '18 at 19:26

Metropolis

1,240927

answered Nov 21 '18 at 19:26

Metropolis

1,240927

answered Nov 21 '18 at 19:26

Metropolis

1,240927

answered Nov 21 '18 at 19:26

Metropolis

1,240927

Thanks, I have changed it to def givenStrings(code: String) = { if (code.contains("A", "BDS")) "It is in the first set"; else if(code.contains("DE", "BO", "IID")) "It is in the second set"; else "Not given"; } givenStrings("A") however I get "Not given" when it should be "It is in the first set"

– YouSun
Nov 21 '18 at 19:36

add a comment |

Thanks, I have changed it to def givenStrings(code: String) = { if (code.contains("A", "BDS")) "It is in the first set"; else if(code.contains("DE", "BO", "IID")) "It is in the second set"; else "Not given"; } givenStrings("A") however I get "Not given" when it should be "It is in the first set"

– YouSun
Nov 21 '18 at 19:36

Thanks, I have changed it to def givenStrings(code: String) = { if (code.contains("A", "BDS")) "It is in the first set"; else if(code.contains("DE", "BO", "IID")) "It is in the second set"; else "Not given"; } givenStrings("A") however I get "Not given" when it should be "It is in the first set"

– YouSun
Nov 21 '18 at 19:36

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Cfrgtkky