Ruby:— Accept array as input and put it into hash












-3















User must enter the array as input. Hash has to accept the input array elements as values.



Create a Ruby program for this by using loops. If array completed print this statement “All array elements are assigned to keys in the hash”



A = [1, 6, 4, 5]

H = {“k1” => 1

“k2” => 6

“k3” => 4

“k4” => 5}





ruby-on-rails ruby







share|improve this question























  • 1):-User must enter the array as input.

    – Sagar
    Nov 21 '18 at 12:36
















-3















User must enter the array as input. Hash has to accept the input array elements as values.



Create a Ruby program for this by using loops. If array completed print this statement “All array elements are assigned to keys in the hash”



A = [1, 6, 4, 5]

H = {“k1” => 1

“k2” => 6

“k3” => 4

“k4” => 5}





ruby-on-rails ruby







share|improve this question























  • 1):-User must enter the array as input.

    – Sagar
    Nov 21 '18 at 12:36














-3












-3








-3








User must enter the array as input. Hash has to accept the input array elements as values.



Create a Ruby program for this by using loops. If array completed print this statement “All array elements are assigned to keys in the hash”



A = [1, 6, 4, 5]

H = {“k1” => 1

“k2” => 6

“k3” => 4

“k4” => 5}





ruby-on-rails ruby







share|improve this question














User must enter the array as input. Hash has to accept the input array elements as values.



Create a Ruby program for this by using loops. If array completed print this statement “All array elements are assigned to keys in the hash”



A = [1, 6, 4, 5]

H = {“k1” => 1

“k2” => 6

“k3” => 4

“k4” => 5}





ruby-on-rails ruby




ruby-on-rails ruby






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 21 '18 at 10:37









SagarSagar

4




4













  • 1):-User must enter the array as input.

    – Sagar
    Nov 21 '18 at 12:36



















  • 1):-User must enter the array as input.

    – Sagar
    Nov 21 '18 at 12:36

















1):-User must enter the array as input.

– Sagar
Nov 21 '18 at 12:36





1):-User must enter the array as input.

– Sagar
Nov 21 '18 at 12:36












2 Answers
2






active

oldest

votes


















1














Another solution can be,



a.each_with_index.inject({}) { |m,(a,i)| m["k#{i+1}"] = a; m }


Update: answering to your question



puts 'Enter number of hash elements'

n = gets.to_i

n.times |i|

    hash["k#{i+1}"] = gets.to_i

end

puts 'All array elements are assigned to keys in the hash'





share|improve this answer





















  • 1





    You can use each_with_object and get rid of returning m a.each_with_object({}).with_index { |(a,m), i| m["k#{i+1}"] = a }.

    – Sebastian Palma
    Nov 21 '18 at 11:09











  • @SebastianPalma Yeah, it is better than I gave, thanks :)

    – ray
    Nov 21 '18 at 11:15











  • case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values.

    – Sagar
    Nov 21 '18 at 12:06











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:08











  • @Sagar check update

    – ray
    Nov 21 '18 at 12:28



















0














A = [1, 6, 4, 5]

Hash[[*'k1'.."k#{A.length}"].zip(A)]





share|improve this answer
























  • Case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values

    – Sagar
    Nov 21 '18 at 12:07











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:07











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Another solution can be,



a.each_with_index.inject({}) { |m,(a,i)| m["k#{i+1}"] = a; m }


Update: answering to your question



puts 'Enter number of hash elements'

n = gets.to_i

n.times |i|

    hash["k#{i+1}"] = gets.to_i

end

puts 'All array elements are assigned to keys in the hash'





share|improve this answer





















  • 1





    You can use each_with_object and get rid of returning m a.each_with_object({}).with_index { |(a,m), i| m["k#{i+1}"] = a }.

    – Sebastian Palma
    Nov 21 '18 at 11:09











  • @SebastianPalma Yeah, it is better than I gave, thanks :)

    – ray
    Nov 21 '18 at 11:15











  • case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values.

    – Sagar
    Nov 21 '18 at 12:06











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:08











  • @Sagar check update

    – ray
    Nov 21 '18 at 12:28
















1














Another solution can be,



a.each_with_index.inject({}) { |m,(a,i)| m["k#{i+1}"] = a; m }


Update: answering to your question



puts 'Enter number of hash elements'

n = gets.to_i

n.times |i|

    hash["k#{i+1}"] = gets.to_i

end

puts 'All array elements are assigned to keys in the hash'





share|improve this answer





















  • 1





    You can use each_with_object and get rid of returning m a.each_with_object({}).with_index { |(a,m), i| m["k#{i+1}"] = a }.

    – Sebastian Palma
    Nov 21 '18 at 11:09











  • @SebastianPalma Yeah, it is better than I gave, thanks :)

    – ray
    Nov 21 '18 at 11:15











  • case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values.

    – Sagar
    Nov 21 '18 at 12:06











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:08











  • @Sagar check update

    – ray
    Nov 21 '18 at 12:28














1












1








1







Another solution can be,



a.each_with_index.inject({}) { |m,(a,i)| m["k#{i+1}"] = a; m }


Update: answering to your question



puts 'Enter number of hash elements'

n = gets.to_i

n.times |i|

    hash["k#{i+1}"] = gets.to_i

end

puts 'All array elements are assigned to keys in the hash'





share|improve this answer















Another solution can be,



a.each_with_index.inject({}) { |m,(a,i)| m["k#{i+1}"] = a; m }


Update: answering to your question



puts 'Enter number of hash elements'

n = gets.to_i

n.times |i|

    hash["k#{i+1}"] = gets.to_i

end

puts 'All array elements are assigned to keys in the hash'






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 21 '18 at 12:28

























answered Nov 21 '18 at 10:59









rayray

3,3481729




3,3481729








  • 1





    You can use each_with_object and get rid of returning m a.each_with_object({}).with_index { |(a,m), i| m["k#{i+1}"] = a }.

    – Sebastian Palma
    Nov 21 '18 at 11:09











  • @SebastianPalma Yeah, it is better than I gave, thanks :)

    – ray
    Nov 21 '18 at 11:15











  • case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values.

    – Sagar
    Nov 21 '18 at 12:06











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:08











  • @Sagar check update

    – ray
    Nov 21 '18 at 12:28














  • 1





    You can use each_with_object and get rid of returning m a.each_with_object({}).with_index { |(a,m), i| m["k#{i+1}"] = a }.

    – Sebastian Palma
    Nov 21 '18 at 11:09











  • @SebastianPalma Yeah, it is better than I gave, thanks :)

    – ray
    Nov 21 '18 at 11:15











  • case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values.

    – Sagar
    Nov 21 '18 at 12:06











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:08











  • @Sagar check update

    – ray
    Nov 21 '18 at 12:28








1




1





You can use each_with_object and get rid of returning m a.each_with_object({}).with_index { |(a,m), i| m["k#{i+1}"] = a }.

– Sebastian Palma
Nov 21 '18 at 11:09





You can use each_with_object and get rid of returning m a.each_with_object({}).with_index { |(a,m), i| m["k#{i+1}"] = a }.

– Sebastian Palma
Nov 21 '18 at 11:09













@SebastianPalma Yeah, it is better than I gave, thanks :)

– ray
Nov 21 '18 at 11:15





@SebastianPalma Yeah, it is better than I gave, thanks :)

– ray
Nov 21 '18 at 11:15













case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values.

– Sagar
Nov 21 '18 at 12:06





case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values.

– Sagar
Nov 21 '18 at 12:06













Using for loop only

– Sagar
Nov 21 '18 at 12:08





Using for loop only

– Sagar
Nov 21 '18 at 12:08













@Sagar check update

– ray
Nov 21 '18 at 12:28





@Sagar check update

– ray
Nov 21 '18 at 12:28













0














A = [1, 6, 4, 5]

Hash[[*'k1'.."k#{A.length}"].zip(A)]





share|improve this answer
























  • Case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values

    – Sagar
    Nov 21 '18 at 12:07











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:07
















0














A = [1, 6, 4, 5]

Hash[[*'k1'.."k#{A.length}"].zip(A)]





share|improve this answer
























  • Case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values

    – Sagar
    Nov 21 '18 at 12:07











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:07














0












0








0







A = [1, 6, 4, 5]

Hash[[*'k1'.."k#{A.length}"].zip(A)]





share|improve this answer













A = [1, 6, 4, 5]

Hash[[*'k1'.."k#{A.length}"].zip(A)]






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 21 '18 at 10:51









Dyaniyal NadarDyaniyal Nadar

38529




38529













  • Case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values

    – Sagar
    Nov 21 '18 at 12:07











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:07



















  • Case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values

    – Sagar
    Nov 21 '18 at 12:07











  • Using for loop only

    – Sagar
    Nov 21 '18 at 12:07

















Case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values

– Sagar
Nov 21 '18 at 12:07





Case is i am getting array from user input, Then, create an empty hash = H=Hash.new{}. After that i need to iterate through that array(user input) and put values into hash values

– Sagar
Nov 21 '18 at 12:07













Using for loop only

– Sagar
Nov 21 '18 at 12:07





Using for loop only

– Sagar
Nov 21 '18 at 12:07


















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