Cfrgtkky

documentclass{article}

usepackage{amsthm,amsmath}

begin{document}

    begin{proof}

        begin{align*}

            F(x) & = P(Xle x)\

                 & = P(g^{-1}(X)le g^{-1}(x))

        end{align*}

    end{proof}



    begin{proof}

        I want the formular to show on the same line with textit{proof.}

        begin{align*}

        F(x) & = P(Xle x)\

             & = P(g^{-1}(X)le g^{-1}(x))

        end{align*}

    end{proof}

end{document}

documentclass{article}

usepackage{amsthm,amsmath}

begin{document}

    begin{proof}

        begin{align*}

            F(x) & = P(Xle x)\

                 & = P(g^{-1}(X)le g^{-1}(x))

        end{align*}

    end{proof}



    begin{proof}

        I want the formular to show on the same line with textit{proof.}

        begin{align*}

        F(x) & = P(Xle x)\

             & = P(g^{-1}(X)le g^{-1}(x))

        end{align*}

    end{proof}

end{document}

documentclass{article}

usepackage{amsthm,amsmath}

begin{document}

    begin{proof}

        begin{align*}

            F(x) & = P(Xle x)\

                 & = P(g^{-1}(X)le g^{-1}(x))

        end{align*}

    end{proof}



    begin{proof}

        I want the formular to show on the same line with textit{proof.}

        begin{align*}

        F(x) & = P(Xle x)\

             & = P(g^{-1}(X)le g^{-1}(x))

        end{align*}

    end{proof}

end{document}

documentclass{article}

usepackage{amsthm,amsmath}

begin{document}

    begin{proof}

        begin{align*}

            F(x) & = P(Xle x)\

                 & = P(g^{-1}(X)le g^{-1}(x))

        end{align*}

    end{proof}



    begin{proof}

        I want the formular to show on the same line with textit{proof.}

        begin{align*}

        F(x) & = P(Xle x)\

             & = P(g^{-1}(X)le g^{-1}(x))

        end{align*}

    end{proof}

end{document}

add a comment | 

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documentclass{article}

usepackage{amsthm,amsmath}

begin{document}

    begin{proof}hfil   $begin{aligned}[t]

            F(x) & = P(Xle x)\

                 & = P(g^{-1}(X)le g^{-1}(x))

                         end{aligned}$



    vskip-baselineskip   % needed to align `qed` to bottom equation

    end{proof}

end{document}

documentclass{article}

usepackage{amsthm,amsmath}

begin{document}

    begin{proof}hfil   $begin{aligned}[t]

            F(x) & = P(Xle x)\

                 & = P(g^{-1}(X)le g^{-1}(x))

                         end{aligned}$



    vskip-baselineskip   % needed to align `qed` to bottom equation

    end{proof}

end{document}

documentclass{article}

usepackage{amsthm,amsmath}

begin{document}

    begin{proof}hfil   $begin{aligned}[t]

            F(x) & = P(Xle x)\

                 & = P(g^{-1}(X)le g^{-1}(x))

                         end{aligned}$



    vskip-baselineskip   % needed to align `qed` to bottom equation

    end{proof}

end{document}

documentclass{article}

usepackage{amsthm,amsmath}

begin{document}

    begin{proof}hfil   $begin{aligned}[t]

            F(x) & = P(Xle x)\

                 & = P(g^{-1}(X)le g^{-1}(x))

                         end{aligned}$



    vskip-baselineskip   % needed to align `qed` to bottom equation

    end{proof}

end{document}

add a comment | 

documentclass{article}

usepackage{amsmath,amssymb}

usepackage[amsmath,thmmarks]{ntheorem}



begingroup

  theoremstyle{nonumberplain}

  theoremheaderfont{itshape}

  theorembodyfont{normalfont}

  theoremsymbol{mbox{$Box$}}

  newtheorem{proof}{Proof}

endgroup



begin{document}



begin{proof}

The proof of this theorem is very simple:

begin{align*}

   1 +  1 & =  2 \

  10 + 10 & = 20

end{align*}

end{proof}



end{document}

documentclass{article}

usepackage{amsmath,amssymb}

usepackage[amsmath,thmmarks]{ntheorem}



begingroup

  theoremstyle{nonumberplain}

  theoremheaderfont{itshape}

  theorembodyfont{normalfont}

  theoremsymbol{mbox{$Box$}}

  newtheorem{proof}{Proof}

endgroup



begin{document}



begin{proof}

The proof of this theorem is very simple:

begin{align*}

   1 +  1 & =  2 \

  10 + 10 & = 20

end{align*}

end{proof}



end{document}

documentclass{article}

usepackage{amsmath,amssymb}

usepackage[amsmath,thmmarks]{ntheorem}



begingroup

  theoremstyle{nonumberplain}

  theoremheaderfont{itshape}

  theorembodyfont{normalfont}

  theoremsymbol{mbox{$Box$}}

  newtheorem{proof}{Proof}

endgroup



begin{document}



begin{proof}

The proof of this theorem is very simple:

begin{align*}

   1 +  1 & =  2 \

  10 + 10 & = 20

end{align*}

end{proof}



end{document}

documentclass{article}

usepackage{amsmath,amssymb}

usepackage[amsmath,thmmarks]{ntheorem}



begingroup

  theoremstyle{nonumberplain}

  theoremheaderfont{itshape}

  theorembodyfont{normalfont}

  theoremsymbol{mbox{$Box$}}

  newtheorem{proof}{Proof}

endgroup



begin{document}



begin{proof}

The proof of this theorem is very simple:

begin{align*}

   1 +  1 & =  2 \

  10 + 10 & = 20

end{align*}

end{proof}



end{document}

add a comment |