How do I draw a little red square to label my right triangle?












14















The sample code:



documentclass{minimal}
usepackage{tikz}
begin{document}
begin{tikzpicture}
draw ( 0 , 0 ) coordinate (A)
-- ( 4 , 0 ) coordinate (C)
-- ( 0 , 3 ) coordinate (B)
-- (0, 0);
end{tikzpicture}
end{document}


The figure:



Right Triangle



I would like to use a box in the lower left angle of the triangle to indicate a right angle.










share|improve this question




















  • 1





    Hi Stuart, welcome to the site! There's been a similar question before: Insertion of perpendicular symbol at intersection of two perpendicular lines

    – Jake
    Jan 16 '14 at 8:57











  • Excellent, very helpful link. Exactly what I was looking for.

    – StuartRCarter
    Jan 16 '14 at 9:16
















14















The sample code:



documentclass{minimal}
usepackage{tikz}
begin{document}
begin{tikzpicture}
draw ( 0 , 0 ) coordinate (A)
-- ( 4 , 0 ) coordinate (C)
-- ( 0 , 3 ) coordinate (B)
-- (0, 0);
end{tikzpicture}
end{document}


The figure:



Right Triangle



I would like to use a box in the lower left angle of the triangle to indicate a right angle.










share|improve this question




















  • 1





    Hi Stuart, welcome to the site! There's been a similar question before: Insertion of perpendicular symbol at intersection of two perpendicular lines

    – Jake
    Jan 16 '14 at 8:57











  • Excellent, very helpful link. Exactly what I was looking for.

    – StuartRCarter
    Jan 16 '14 at 9:16














14












14








14


5






The sample code:



documentclass{minimal}
usepackage{tikz}
begin{document}
begin{tikzpicture}
draw ( 0 , 0 ) coordinate (A)
-- ( 4 , 0 ) coordinate (C)
-- ( 0 , 3 ) coordinate (B)
-- (0, 0);
end{tikzpicture}
end{document}


The figure:



Right Triangle



I would like to use a box in the lower left angle of the triangle to indicate a right angle.










share|improve this question
















The sample code:



documentclass{minimal}
usepackage{tikz}
begin{document}
begin{tikzpicture}
draw ( 0 , 0 ) coordinate (A)
-- ( 4 , 0 ) coordinate (C)
-- ( 0 , 3 ) coordinate (B)
-- (0, 0);
end{tikzpicture}
end{document}


The figure:



Right Triangle



I would like to use a box in the lower left angle of the triangle to indicate a right angle.







tikz-pgf labels






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 16 '14 at 8:50









Claudio Fiandrino

52.3k11152307




52.3k11152307










asked Jan 16 '14 at 8:48









StuartRCarterStuartRCarter

713




713








  • 1





    Hi Stuart, welcome to the site! There's been a similar question before: Insertion of perpendicular symbol at intersection of two perpendicular lines

    – Jake
    Jan 16 '14 at 8:57











  • Excellent, very helpful link. Exactly what I was looking for.

    – StuartRCarter
    Jan 16 '14 at 9:16














  • 1





    Hi Stuart, welcome to the site! There's been a similar question before: Insertion of perpendicular symbol at intersection of two perpendicular lines

    – Jake
    Jan 16 '14 at 8:57











  • Excellent, very helpful link. Exactly what I was looking for.

    – StuartRCarter
    Jan 16 '14 at 9:16








1




1





Hi Stuart, welcome to the site! There's been a similar question before: Insertion of perpendicular symbol at intersection of two perpendicular lines

– Jake
Jan 16 '14 at 8:57





Hi Stuart, welcome to the site! There's been a similar question before: Insertion of perpendicular symbol at intersection of two perpendicular lines

– Jake
Jan 16 '14 at 8:57













Excellent, very helpful link. Exactly what I was looking for.

– StuartRCarter
Jan 16 '14 at 9:16





Excellent, very helpful link. Exactly what I was looking for.

– StuartRCarter
Jan 16 '14 at 9:16










6 Answers
6






active

oldest

votes


















13














With the help of the new library angles of TikZ 3.0.0 and a small patch, it is possible to get:



enter image description here



thanks to:



begin{tikzpicture}
draw ( 0 , 0 ) coordinate (A)
-- ( 4 , 0 ) coordinate (C)
-- ( 0 , 3 ) coordinate (B)
-- ( 0 , 0 )
pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
;
end{tikzpicture}


The complete code:



documentclass[tikz,border=10pt]{standalone}
usepackage{tikz}
usetikzlibrary{angles}

makeatletter
tikzset{
pics/squared angle/.style = {
setup code = tikz@lib@angle@parse#1pgf@stop,
background code = tikz@lib@angle@background#1pgf@stop,
foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
},
pics/squared angle/.default=A--B--C,
angle eccentricity/.initial=.6,
angle radius/.initial=5mm
}

deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
path [name prefix ..] [pic actions]
([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
|-
([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
ifxtikzpictextrelaxelse%
defpgf@temp{node()[name prefix
..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
fi
}
makeatother

begin{document}
begin{tikzpicture}
draw ( 0 , 0 ) coordinate (A)
-- ( 4 , 0 ) coordinate (C)
-- ( 0 , 3 ) coordinate (B)
-- ( 0 , 0 )
pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
;
end{tikzpicture}
end{document}


The desired output seems to have the box filled in red as well as a label, hence let's use the quotes library:



documentclass[tikz,border=10pt]{standalone}
usepackage{tikz}
usetikzlibrary{angles,quotes}

makeatletter
tikzset{
pics/squared angle/.style = {
setup code = tikz@lib@angle@parse#1pgf@stop,
background code = tikz@lib@angle@background#1pgf@stop,
foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
},
pics/squared angle/.default=A--B--C,
angle eccentricity/.initial=.6,
angle radius/.initial=5mm
}

deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
path [name prefix ..] [pic actions]
([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
|-
([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
ifxtikzpictextrelaxelse%
defpgf@temp{node()[name prefix
..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
fi
}
makeatother

begin{document}
begin{tikzpicture}
draw ( 0 , 0 ) coordinate (A)
-- ( 4 , 0 ) coordinate (C)
-- ( 0 , 3 ) coordinate (B)
-- ( 0 , 0 )
pic [draw,fill=red,angle radius=0.5cm,angle eccentricity=2,
"$90^circ$" {black,font=footnotesize}] {squared angle = C--A--B}
;
end{tikzpicture}
end{document}


The result:



enter image description here






share|improve this answer





















  • 4





    "Small patch" is the understatement of the day.

    – Thorsten Donig
    Jan 16 '14 at 9:32






  • 1





    @ThorstenDonig: a suggestion: make a diff of the original library; the change concerns only two lines of code.

    – Claudio Fiandrino
    Jan 16 '14 at 9:35











  • Can this be made to work when the sides are not axis-aligned?

    – Neil G
    Feb 10 '14 at 4:45






  • 1





    @NeilG: of course it should be possible, but very complex. Basically, you have to change the |- in ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center) |- so that the first part of the path would be orthogonal to the base line of the triangle.

    – Claudio Fiandrino
    Feb 10 '14 at 7:34













  • Have you considered to submit your code to be included in angles library?

    – Ignasi
    May 6 '14 at 7:00



















10














For this simple case, you can just draw a square at (A):



documentclass[tikz,border=10pt]{standalone}
begin{document}
begin{tikzpicture}
draw ( 0 , 0 ) coordinate (A)
-- ( 4 , 0 ) coordinate (C)
-- ( 0 , 3 ) coordinate (B)
-- (0, 0);
draw [fill=red](A) rectangle ++(0.5,0.5) node[above right]{$90^circ$};
end{tikzpicture}
end{document}


enter image description here






share|improve this answer





















  • 2





    To make it a little more general you could use relative coordinates, i.e. draw [fill=red](A) rectangle ++(0.5,0.5).

    – Torbjørn T.
    Jan 16 '14 at 12:59











  • @TorbjørnT. Good point, Thanks and edited. :)

    – user11232
    Jan 16 '14 at 13:03



















7














This is an approach simplified by »tkz-euclide«, which is mentioned indirectly in the comment to your question. Wherever the points are located that define the triangle, the right angle will be marked automatically.



documentclass[11pt]{article}
usepackage[T1]{fontenc}
usepackage{tkz-euclide}
usetkzobj{all}

begin{document}
begin{tikzpicture}
tkzDefPoint(0,0){A}
tkzDefPoint(0,3){B}
tkzDefPoint(4,0){C}
tkzMarkRightAngle[draw=red,fill=red](B,A,C)
tkzDrawPolygon(A,B,C)
end{tikzpicture}
end{document}


For details please refer to the package manual, which is unfortunately only available in French.





enter image description here






share|improve this answer































    6














    This is how. Take the (A) as your reference point. Then (1) yshift to move the starting point up a little; (2) xshift to determine the end point; (3) connect these two points using -| (going horizontally and then vertically to the end point.)
    enter image description here



    documentclass{minimal}
    usepackage{tikz}
    begin{document}
    begin{tikzpicture}
    draw ( 0 , 0 ) coordinate (A)
    -- ( 4 , 0 ) coordinate (C)
    -- ( 0 , 3 ) coordinate (B)
    -- (0, 0);
    %draw [red]([yshift=0.5cm]A) -| node[above right]{$90^circ$}; % generates red line
    draw [fill=red]([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A)
    -- (A) -- cycle ; % if path is used, the square becomes invisible.
    end{tikzpicture}
    end{document}





    share|improve this answer


























    • How could one label the vertices, please? (Say by a letter X)

      – Abhimanyu Arora
      Jan 16 '14 at 9:03













    • Is there a way to use a simple command, rather than drawing it? In my more complicated figures the triangles are rotated and drawing is a hassle, especially if I want to go back and change anything.

      – StuartRCarter
      Jan 16 '14 at 9:03








    • 1





      @AbhimanyuArora -- Use node technique as shown heredraw ([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A){}; Same idea applies to the triangle tips.

      – Jesse
      Jan 16 '14 at 9:07











    • @StuartRCarter -- Please refer to Jake's comment and take a look, to see if his 3-point command is what you need.

      – Jesse
      Jan 16 '14 at 9:16



















    4














    With PSTricks.



    documentclass[pstricks,border=12pt,12pt]{standalone}
    usepackage{pst-eucl}
    begin{document}
    begin{pspicture}(6,6)
    pstGeonode[CurveType=polygon,PosAngle={-90,0,90}](1,1){A}(5,1){B}(1,5){C}
    pstRightAngle[fillstyle=solid,fillcolor=red]{B}{A}{C}
    end{pspicture}
    end{document}


    enter image description here






    share|improve this answer































      3















      Note : Since version 3.1 of TikZ right angle is part of the standard angles library. It works in the same way as angle pic.




      This answer is very close to the answer of @ClaudioFiandrino, which is a slight modification of the standard angles library.



      documentclass[tikz,border=7pt]{standalone}
      usetikzlibrary{angles, quotes}

      makeatletter
      tikzset{
      pics/right angle/.style = {
      setup code = tikz@lib@angle@parse#1pgf@stop,
      background code = tikz@lib@rightangle@background#1pgf@stop,
      foreground code = tikz@lib@rightangle@foreground#1pgf@stop,
      },
      pics/right angle/.default=A--B--C,
      angle eccentricity/.initial=.6,
      angle radius/.initial=5mm
      }

      deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions, draw=none] (#2.center)
      -- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
      -- cycle;
      }

      deftikz@lib@rightangle@foreground#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions, fill=none, shade=none]
      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt);
      ifxtikzpictextrelaxelse%
      defpgf@temp{node()[name prefix
      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
      eccentricity}*sqrt(1/2)*tikz@lib@angle@rad pt)}]#2.center)}]}
      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
      fi
      }
      makeatother

      begin{document}
      begin{tikzpicture}
      draw (4,1) coordinate (C)
      -- (0,0) coordinate (A)
      -- ([turn] 0,3) coordinate (B)
      -- cycle
      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
      pic [draw,blue,thick] {right angle = A--C--B}
      pic [fill=green,draw] {right angle = C--B--A};
      ;
      end{tikzpicture}
      end{document}


      enter image description here



      Note : I have created a rightangles library, available at GitHub that can be used in place of this hack like this



      documentclass[tikz,border=7pt]{standalone}
      usetikzlibrary{rightangles, quotes}

      begin{document}
      begin{tikzpicture}
      draw (4,1) coordinate (C)
      -- (0,0) coordinate (A)
      -- ([turn] 0,3) coordinate (B)
      -- cycle
      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
      pic [draw,blue,thick] {right angle = A--C--B}
      pic [fill=green,draw] {right angle = C--B--A};
      ;
      end{tikzpicture}
      end{document}





      share|improve this answer


























      • Best answer! The main one does not work for rotated angles! ;)

        – GiuTeX
        Jun 16 '18 at 22:07











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      6 Answers
      6






      active

      oldest

      votes








      6 Answers
      6






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      13














      With the help of the new library angles of TikZ 3.0.0 and a small patch, it is possible to get:



      enter image description here



      thanks to:



      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
      pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
      pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
      ;
      end{tikzpicture}


      The complete code:



      documentclass[tikz,border=10pt]{standalone}
      usepackage{tikz}
      usetikzlibrary{angles}

      makeatletter
      tikzset{
      pics/squared angle/.style = {
      setup code = tikz@lib@angle@parse#1pgf@stop,
      background code = tikz@lib@angle@background#1pgf@stop,
      foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
      },
      pics/squared angle/.default=A--B--C,
      angle eccentricity/.initial=.6,
      angle radius/.initial=5mm
      }

      deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions]
      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
      |-
      ([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
      ifxtikzpictextrelaxelse%
      defpgf@temp{node()[name prefix
      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
      eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
      fi
      }
      makeatother

      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
      pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
      pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
      ;
      end{tikzpicture}
      end{document}


      The desired output seems to have the box filled in red as well as a label, hence let's use the quotes library:



      documentclass[tikz,border=10pt]{standalone}
      usepackage{tikz}
      usetikzlibrary{angles,quotes}

      makeatletter
      tikzset{
      pics/squared angle/.style = {
      setup code = tikz@lib@angle@parse#1pgf@stop,
      background code = tikz@lib@angle@background#1pgf@stop,
      foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
      },
      pics/squared angle/.default=A--B--C,
      angle eccentricity/.initial=.6,
      angle radius/.initial=5mm
      }

      deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions]
      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
      |-
      ([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
      ifxtikzpictextrelaxelse%
      defpgf@temp{node()[name prefix
      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
      eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
      fi
      }
      makeatother

      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,fill=red,angle radius=0.5cm,angle eccentricity=2,
      "$90^circ$" {black,font=footnotesize}] {squared angle = C--A--B}
      ;
      end{tikzpicture}
      end{document}


      The result:



      enter image description here






      share|improve this answer





















      • 4





        "Small patch" is the understatement of the day.

        – Thorsten Donig
        Jan 16 '14 at 9:32






      • 1





        @ThorstenDonig: a suggestion: make a diff of the original library; the change concerns only two lines of code.

        – Claudio Fiandrino
        Jan 16 '14 at 9:35











      • Can this be made to work when the sides are not axis-aligned?

        – Neil G
        Feb 10 '14 at 4:45






      • 1





        @NeilG: of course it should be possible, but very complex. Basically, you have to change the |- in ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center) |- so that the first part of the path would be orthogonal to the base line of the triangle.

        – Claudio Fiandrino
        Feb 10 '14 at 7:34













      • Have you considered to submit your code to be included in angles library?

        – Ignasi
        May 6 '14 at 7:00
















      13














      With the help of the new library angles of TikZ 3.0.0 and a small patch, it is possible to get:



      enter image description here



      thanks to:



      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
      pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
      pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
      ;
      end{tikzpicture}


      The complete code:



      documentclass[tikz,border=10pt]{standalone}
      usepackage{tikz}
      usetikzlibrary{angles}

      makeatletter
      tikzset{
      pics/squared angle/.style = {
      setup code = tikz@lib@angle@parse#1pgf@stop,
      background code = tikz@lib@angle@background#1pgf@stop,
      foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
      },
      pics/squared angle/.default=A--B--C,
      angle eccentricity/.initial=.6,
      angle radius/.initial=5mm
      }

      deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions]
      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
      |-
      ([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
      ifxtikzpictextrelaxelse%
      defpgf@temp{node()[name prefix
      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
      eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
      fi
      }
      makeatother

      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
      pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
      pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
      ;
      end{tikzpicture}
      end{document}


      The desired output seems to have the box filled in red as well as a label, hence let's use the quotes library:



      documentclass[tikz,border=10pt]{standalone}
      usepackage{tikz}
      usetikzlibrary{angles,quotes}

      makeatletter
      tikzset{
      pics/squared angle/.style = {
      setup code = tikz@lib@angle@parse#1pgf@stop,
      background code = tikz@lib@angle@background#1pgf@stop,
      foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
      },
      pics/squared angle/.default=A--B--C,
      angle eccentricity/.initial=.6,
      angle radius/.initial=5mm
      }

      deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions]
      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
      |-
      ([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
      ifxtikzpictextrelaxelse%
      defpgf@temp{node()[name prefix
      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
      eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
      fi
      }
      makeatother

      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,fill=red,angle radius=0.5cm,angle eccentricity=2,
      "$90^circ$" {black,font=footnotesize}] {squared angle = C--A--B}
      ;
      end{tikzpicture}
      end{document}


      The result:



      enter image description here






      share|improve this answer





















      • 4





        "Small patch" is the understatement of the day.

        – Thorsten Donig
        Jan 16 '14 at 9:32






      • 1





        @ThorstenDonig: a suggestion: make a diff of the original library; the change concerns only two lines of code.

        – Claudio Fiandrino
        Jan 16 '14 at 9:35











      • Can this be made to work when the sides are not axis-aligned?

        – Neil G
        Feb 10 '14 at 4:45






      • 1





        @NeilG: of course it should be possible, but very complex. Basically, you have to change the |- in ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center) |- so that the first part of the path would be orthogonal to the base line of the triangle.

        – Claudio Fiandrino
        Feb 10 '14 at 7:34













      • Have you considered to submit your code to be included in angles library?

        – Ignasi
        May 6 '14 at 7:00














      13












      13








      13







      With the help of the new library angles of TikZ 3.0.0 and a small patch, it is possible to get:



      enter image description here



      thanks to:



      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
      pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
      pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
      ;
      end{tikzpicture}


      The complete code:



      documentclass[tikz,border=10pt]{standalone}
      usepackage{tikz}
      usetikzlibrary{angles}

      makeatletter
      tikzset{
      pics/squared angle/.style = {
      setup code = tikz@lib@angle@parse#1pgf@stop,
      background code = tikz@lib@angle@background#1pgf@stop,
      foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
      },
      pics/squared angle/.default=A--B--C,
      angle eccentricity/.initial=.6,
      angle radius/.initial=5mm
      }

      deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions]
      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
      |-
      ([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
      ifxtikzpictextrelaxelse%
      defpgf@temp{node()[name prefix
      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
      eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
      fi
      }
      makeatother

      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
      pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
      pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
      ;
      end{tikzpicture}
      end{document}


      The desired output seems to have the box filled in red as well as a label, hence let's use the quotes library:



      documentclass[tikz,border=10pt]{standalone}
      usepackage{tikz}
      usetikzlibrary{angles,quotes}

      makeatletter
      tikzset{
      pics/squared angle/.style = {
      setup code = tikz@lib@angle@parse#1pgf@stop,
      background code = tikz@lib@angle@background#1pgf@stop,
      foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
      },
      pics/squared angle/.default=A--B--C,
      angle eccentricity/.initial=.6,
      angle radius/.initial=5mm
      }

      deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions]
      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
      |-
      ([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
      ifxtikzpictextrelaxelse%
      defpgf@temp{node()[name prefix
      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
      eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
      fi
      }
      makeatother

      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,fill=red,angle radius=0.5cm,angle eccentricity=2,
      "$90^circ$" {black,font=footnotesize}] {squared angle = C--A--B}
      ;
      end{tikzpicture}
      end{document}


      The result:



      enter image description here






      share|improve this answer















      With the help of the new library angles of TikZ 3.0.0 and a small patch, it is possible to get:



      enter image description here



      thanks to:



      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
      pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
      pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
      ;
      end{tikzpicture}


      The complete code:



      documentclass[tikz,border=10pt]{standalone}
      usepackage{tikz}
      usetikzlibrary{angles}

      makeatletter
      tikzset{
      pics/squared angle/.style = {
      setup code = tikz@lib@angle@parse#1pgf@stop,
      background code = tikz@lib@angle@background#1pgf@stop,
      foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
      },
      pics/squared angle/.default=A--B--C,
      angle eccentricity/.initial=.6,
      angle radius/.initial=5mm
      }

      deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions]
      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
      |-
      ([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
      ifxtikzpictextrelaxelse%
      defpgf@temp{node()[name prefix
      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
      eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
      fi
      }
      makeatother

      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,blue,thick,angle radius=0.5cm] {squared angle = A--C--B}
      pic [draw,red,thick,angle radius=0.5cm] {squared angle = C--A--B}
      pic [draw,green,thick,angle radius=0.5cm] {squared angle = C--B--A};
      ;
      end{tikzpicture}
      end{document}


      The desired output seems to have the box filled in red as well as a label, hence let's use the quotes library:



      documentclass[tikz,border=10pt]{standalone}
      usepackage{tikz}
      usetikzlibrary{angles,quotes}

      makeatletter
      tikzset{
      pics/squared angle/.style = {
      setup code = tikz@lib@angle@parse#1pgf@stop,
      background code = tikz@lib@angle@background#1pgf@stop,
      foreground code = tikz@lib@squaredangle@foreground#1pgf@stop,
      },
      pics/squared angle/.default=A--B--C,
      angle eccentricity/.initial=.6,
      angle radius/.initial=5mm
      }

      deftikz@lib@squaredangle@foreground#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions]
      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
      |-
      ([shift={(tikz@end@angle@temp:tikz@lib@angle@rad pt)}]#2.center);
      ifxtikzpictextrelaxelse%
      defpgf@temp{node()[name prefix
      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
      eccentricity}*tikz@lib@angle@rad pt)}]#2.center)}]}
      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
      fi
      }
      makeatother

      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- ( 0 , 0 )
      pic [draw,fill=red,angle radius=0.5cm,angle eccentricity=2,
      "$90^circ$" {black,font=footnotesize}] {squared angle = C--A--B}
      ;
      end{tikzpicture}
      end{document}


      The result:



      enter image description here







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Feb 10 '14 at 1:30









      Neil G

      7,636135292




      7,636135292










      answered Jan 16 '14 at 9:26









      Claudio FiandrinoClaudio Fiandrino

      52.3k11152307




      52.3k11152307








      • 4





        "Small patch" is the understatement of the day.

        – Thorsten Donig
        Jan 16 '14 at 9:32






      • 1





        @ThorstenDonig: a suggestion: make a diff of the original library; the change concerns only two lines of code.

        – Claudio Fiandrino
        Jan 16 '14 at 9:35











      • Can this be made to work when the sides are not axis-aligned?

        – Neil G
        Feb 10 '14 at 4:45






      • 1





        @NeilG: of course it should be possible, but very complex. Basically, you have to change the |- in ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center) |- so that the first part of the path would be orthogonal to the base line of the triangle.

        – Claudio Fiandrino
        Feb 10 '14 at 7:34













      • Have you considered to submit your code to be included in angles library?

        – Ignasi
        May 6 '14 at 7:00














      • 4





        "Small patch" is the understatement of the day.

        – Thorsten Donig
        Jan 16 '14 at 9:32






      • 1





        @ThorstenDonig: a suggestion: make a diff of the original library; the change concerns only two lines of code.

        – Claudio Fiandrino
        Jan 16 '14 at 9:35











      • Can this be made to work when the sides are not axis-aligned?

        – Neil G
        Feb 10 '14 at 4:45






      • 1





        @NeilG: of course it should be possible, but very complex. Basically, you have to change the |- in ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center) |- so that the first part of the path would be orthogonal to the base line of the triangle.

        – Claudio Fiandrino
        Feb 10 '14 at 7:34













      • Have you considered to submit your code to be included in angles library?

        – Ignasi
        May 6 '14 at 7:00








      4




      4





      "Small patch" is the understatement of the day.

      – Thorsten Donig
      Jan 16 '14 at 9:32





      "Small patch" is the understatement of the day.

      – Thorsten Donig
      Jan 16 '14 at 9:32




      1




      1





      @ThorstenDonig: a suggestion: make a diff of the original library; the change concerns only two lines of code.

      – Claudio Fiandrino
      Jan 16 '14 at 9:35





      @ThorstenDonig: a suggestion: make a diff of the original library; the change concerns only two lines of code.

      – Claudio Fiandrino
      Jan 16 '14 at 9:35













      Can this be made to work when the sides are not axis-aligned?

      – Neil G
      Feb 10 '14 at 4:45





      Can this be made to work when the sides are not axis-aligned?

      – Neil G
      Feb 10 '14 at 4:45




      1




      1





      @NeilG: of course it should be possible, but very complex. Basically, you have to change the |- in ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center) |- so that the first part of the path would be orthogonal to the base line of the triangle.

      – Claudio Fiandrino
      Feb 10 '14 at 7:34







      @NeilG: of course it should be possible, but very complex. Basically, you have to change the |- in ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center) |- so that the first part of the path would be orthogonal to the base line of the triangle.

      – Claudio Fiandrino
      Feb 10 '14 at 7:34















      Have you considered to submit your code to be included in angles library?

      – Ignasi
      May 6 '14 at 7:00





      Have you considered to submit your code to be included in angles library?

      – Ignasi
      May 6 '14 at 7:00











      10














      For this simple case, you can just draw a square at (A):



      documentclass[tikz,border=10pt]{standalone}
      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- (0, 0);
      draw [fill=red](A) rectangle ++(0.5,0.5) node[above right]{$90^circ$};
      end{tikzpicture}
      end{document}


      enter image description here






      share|improve this answer





















      • 2





        To make it a little more general you could use relative coordinates, i.e. draw [fill=red](A) rectangle ++(0.5,0.5).

        – Torbjørn T.
        Jan 16 '14 at 12:59











      • @TorbjørnT. Good point, Thanks and edited. :)

        – user11232
        Jan 16 '14 at 13:03
















      10














      For this simple case, you can just draw a square at (A):



      documentclass[tikz,border=10pt]{standalone}
      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- (0, 0);
      draw [fill=red](A) rectangle ++(0.5,0.5) node[above right]{$90^circ$};
      end{tikzpicture}
      end{document}


      enter image description here






      share|improve this answer





















      • 2





        To make it a little more general you could use relative coordinates, i.e. draw [fill=red](A) rectangle ++(0.5,0.5).

        – Torbjørn T.
        Jan 16 '14 at 12:59











      • @TorbjørnT. Good point, Thanks and edited. :)

        – user11232
        Jan 16 '14 at 13:03














      10












      10








      10







      For this simple case, you can just draw a square at (A):



      documentclass[tikz,border=10pt]{standalone}
      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- (0, 0);
      draw [fill=red](A) rectangle ++(0.5,0.5) node[above right]{$90^circ$};
      end{tikzpicture}
      end{document}


      enter image description here






      share|improve this answer















      For this simple case, you can just draw a square at (A):



      documentclass[tikz,border=10pt]{standalone}
      begin{document}
      begin{tikzpicture}
      draw ( 0 , 0 ) coordinate (A)
      -- ( 4 , 0 ) coordinate (C)
      -- ( 0 , 3 ) coordinate (B)
      -- (0, 0);
      draw [fill=red](A) rectangle ++(0.5,0.5) node[above right]{$90^circ$};
      end{tikzpicture}
      end{document}


      enter image description here







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Jan 16 '14 at 13:03

























      answered Jan 16 '14 at 12:45







      user11232















      • 2





        To make it a little more general you could use relative coordinates, i.e. draw [fill=red](A) rectangle ++(0.5,0.5).

        – Torbjørn T.
        Jan 16 '14 at 12:59











      • @TorbjørnT. Good point, Thanks and edited. :)

        – user11232
        Jan 16 '14 at 13:03














      • 2





        To make it a little more general you could use relative coordinates, i.e. draw [fill=red](A) rectangle ++(0.5,0.5).

        – Torbjørn T.
        Jan 16 '14 at 12:59











      • @TorbjørnT. Good point, Thanks and edited. :)

        – user11232
        Jan 16 '14 at 13:03








      2




      2





      To make it a little more general you could use relative coordinates, i.e. draw [fill=red](A) rectangle ++(0.5,0.5).

      – Torbjørn T.
      Jan 16 '14 at 12:59





      To make it a little more general you could use relative coordinates, i.e. draw [fill=red](A) rectangle ++(0.5,0.5).

      – Torbjørn T.
      Jan 16 '14 at 12:59













      @TorbjørnT. Good point, Thanks and edited. :)

      – user11232
      Jan 16 '14 at 13:03





      @TorbjørnT. Good point, Thanks and edited. :)

      – user11232
      Jan 16 '14 at 13:03











      7














      This is an approach simplified by »tkz-euclide«, which is mentioned indirectly in the comment to your question. Wherever the points are located that define the triangle, the right angle will be marked automatically.



      documentclass[11pt]{article}
      usepackage[T1]{fontenc}
      usepackage{tkz-euclide}
      usetkzobj{all}

      begin{document}
      begin{tikzpicture}
      tkzDefPoint(0,0){A}
      tkzDefPoint(0,3){B}
      tkzDefPoint(4,0){C}
      tkzMarkRightAngle[draw=red,fill=red](B,A,C)
      tkzDrawPolygon(A,B,C)
      end{tikzpicture}
      end{document}


      For details please refer to the package manual, which is unfortunately only available in French.





      enter image description here






      share|improve this answer




























        7














        This is an approach simplified by »tkz-euclide«, which is mentioned indirectly in the comment to your question. Wherever the points are located that define the triangle, the right angle will be marked automatically.



        documentclass[11pt]{article}
        usepackage[T1]{fontenc}
        usepackage{tkz-euclide}
        usetkzobj{all}

        begin{document}
        begin{tikzpicture}
        tkzDefPoint(0,0){A}
        tkzDefPoint(0,3){B}
        tkzDefPoint(4,0){C}
        tkzMarkRightAngle[draw=red,fill=red](B,A,C)
        tkzDrawPolygon(A,B,C)
        end{tikzpicture}
        end{document}


        For details please refer to the package manual, which is unfortunately only available in French.





        enter image description here






        share|improve this answer


























          7












          7








          7







          This is an approach simplified by »tkz-euclide«, which is mentioned indirectly in the comment to your question. Wherever the points are located that define the triangle, the right angle will be marked automatically.



          documentclass[11pt]{article}
          usepackage[T1]{fontenc}
          usepackage{tkz-euclide}
          usetkzobj{all}

          begin{document}
          begin{tikzpicture}
          tkzDefPoint(0,0){A}
          tkzDefPoint(0,3){B}
          tkzDefPoint(4,0){C}
          tkzMarkRightAngle[draw=red,fill=red](B,A,C)
          tkzDrawPolygon(A,B,C)
          end{tikzpicture}
          end{document}


          For details please refer to the package manual, which is unfortunately only available in French.





          enter image description here






          share|improve this answer













          This is an approach simplified by »tkz-euclide«, which is mentioned indirectly in the comment to your question. Wherever the points are located that define the triangle, the right angle will be marked automatically.



          documentclass[11pt]{article}
          usepackage[T1]{fontenc}
          usepackage{tkz-euclide}
          usetkzobj{all}

          begin{document}
          begin{tikzpicture}
          tkzDefPoint(0,0){A}
          tkzDefPoint(0,3){B}
          tkzDefPoint(4,0){C}
          tkzMarkRightAngle[draw=red,fill=red](B,A,C)
          tkzDrawPolygon(A,B,C)
          end{tikzpicture}
          end{document}


          For details please refer to the package manual, which is unfortunately only available in French.





          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jan 16 '14 at 9:15









          Thorsten DonigThorsten Donig

          36.5k590119




          36.5k590119























              6














              This is how. Take the (A) as your reference point. Then (1) yshift to move the starting point up a little; (2) xshift to determine the end point; (3) connect these two points using -| (going horizontally and then vertically to the end point.)
              enter image description here



              documentclass{minimal}
              usepackage{tikz}
              begin{document}
              begin{tikzpicture}
              draw ( 0 , 0 ) coordinate (A)
              -- ( 4 , 0 ) coordinate (C)
              -- ( 0 , 3 ) coordinate (B)
              -- (0, 0);
              %draw [red]([yshift=0.5cm]A) -| node[above right]{$90^circ$}; % generates red line
              draw [fill=red]([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A)
              -- (A) -- cycle ; % if path is used, the square becomes invisible.
              end{tikzpicture}
              end{document}





              share|improve this answer


























              • How could one label the vertices, please? (Say by a letter X)

                – Abhimanyu Arora
                Jan 16 '14 at 9:03













              • Is there a way to use a simple command, rather than drawing it? In my more complicated figures the triangles are rotated and drawing is a hassle, especially if I want to go back and change anything.

                – StuartRCarter
                Jan 16 '14 at 9:03








              • 1





                @AbhimanyuArora -- Use node technique as shown heredraw ([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A){}; Same idea applies to the triangle tips.

                – Jesse
                Jan 16 '14 at 9:07











              • @StuartRCarter -- Please refer to Jake's comment and take a look, to see if his 3-point command is what you need.

                – Jesse
                Jan 16 '14 at 9:16
















              6














              This is how. Take the (A) as your reference point. Then (1) yshift to move the starting point up a little; (2) xshift to determine the end point; (3) connect these two points using -| (going horizontally and then vertically to the end point.)
              enter image description here



              documentclass{minimal}
              usepackage{tikz}
              begin{document}
              begin{tikzpicture}
              draw ( 0 , 0 ) coordinate (A)
              -- ( 4 , 0 ) coordinate (C)
              -- ( 0 , 3 ) coordinate (B)
              -- (0, 0);
              %draw [red]([yshift=0.5cm]A) -| node[above right]{$90^circ$}; % generates red line
              draw [fill=red]([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A)
              -- (A) -- cycle ; % if path is used, the square becomes invisible.
              end{tikzpicture}
              end{document}





              share|improve this answer


























              • How could one label the vertices, please? (Say by a letter X)

                – Abhimanyu Arora
                Jan 16 '14 at 9:03













              • Is there a way to use a simple command, rather than drawing it? In my more complicated figures the triangles are rotated and drawing is a hassle, especially if I want to go back and change anything.

                – StuartRCarter
                Jan 16 '14 at 9:03








              • 1





                @AbhimanyuArora -- Use node technique as shown heredraw ([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A){}; Same idea applies to the triangle tips.

                – Jesse
                Jan 16 '14 at 9:07











              • @StuartRCarter -- Please refer to Jake's comment and take a look, to see if his 3-point command is what you need.

                – Jesse
                Jan 16 '14 at 9:16














              6












              6








              6







              This is how. Take the (A) as your reference point. Then (1) yshift to move the starting point up a little; (2) xshift to determine the end point; (3) connect these two points using -| (going horizontally and then vertically to the end point.)
              enter image description here



              documentclass{minimal}
              usepackage{tikz}
              begin{document}
              begin{tikzpicture}
              draw ( 0 , 0 ) coordinate (A)
              -- ( 4 , 0 ) coordinate (C)
              -- ( 0 , 3 ) coordinate (B)
              -- (0, 0);
              %draw [red]([yshift=0.5cm]A) -| node[above right]{$90^circ$}; % generates red line
              draw [fill=red]([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A)
              -- (A) -- cycle ; % if path is used, the square becomes invisible.
              end{tikzpicture}
              end{document}





              share|improve this answer















              This is how. Take the (A) as your reference point. Then (1) yshift to move the starting point up a little; (2) xshift to determine the end point; (3) connect these two points using -| (going horizontally and then vertically to the end point.)
              enter image description here



              documentclass{minimal}
              usepackage{tikz}
              begin{document}
              begin{tikzpicture}
              draw ( 0 , 0 ) coordinate (A)
              -- ( 4 , 0 ) coordinate (C)
              -- ( 0 , 3 ) coordinate (B)
              -- (0, 0);
              %draw [red]([yshift=0.5cm]A) -| node[above right]{$90^circ$}; % generates red line
              draw [fill=red]([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A)
              -- (A) -- cycle ; % if path is used, the square becomes invisible.
              end{tikzpicture}
              end{document}






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Jan 16 '14 at 9:27

























              answered Jan 16 '14 at 8:55









              JesseJesse

              26.3k72577




              26.3k72577













              • How could one label the vertices, please? (Say by a letter X)

                – Abhimanyu Arora
                Jan 16 '14 at 9:03













              • Is there a way to use a simple command, rather than drawing it? In my more complicated figures the triangles are rotated and drawing is a hassle, especially if I want to go back and change anything.

                – StuartRCarter
                Jan 16 '14 at 9:03








              • 1





                @AbhimanyuArora -- Use node technique as shown heredraw ([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A){}; Same idea applies to the triangle tips.

                – Jesse
                Jan 16 '14 at 9:07











              • @StuartRCarter -- Please refer to Jake's comment and take a look, to see if his 3-point command is what you need.

                – Jesse
                Jan 16 '14 at 9:16



















              • How could one label the vertices, please? (Say by a letter X)

                – Abhimanyu Arora
                Jan 16 '14 at 9:03













              • Is there a way to use a simple command, rather than drawing it? In my more complicated figures the triangles are rotated and drawing is a hassle, especially if I want to go back and change anything.

                – StuartRCarter
                Jan 16 '14 at 9:03








              • 1





                @AbhimanyuArora -- Use node technique as shown heredraw ([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A){}; Same idea applies to the triangle tips.

                – Jesse
                Jan 16 '14 at 9:07











              • @StuartRCarter -- Please refer to Jake's comment and take a look, to see if his 3-point command is what you need.

                – Jesse
                Jan 16 '14 at 9:16

















              How could one label the vertices, please? (Say by a letter X)

              – Abhimanyu Arora
              Jan 16 '14 at 9:03







              How could one label the vertices, please? (Say by a letter X)

              – Abhimanyu Arora
              Jan 16 '14 at 9:03















              Is there a way to use a simple command, rather than drawing it? In my more complicated figures the triangles are rotated and drawing is a hassle, especially if I want to go back and change anything.

              – StuartRCarter
              Jan 16 '14 at 9:03







              Is there a way to use a simple command, rather than drawing it? In my more complicated figures the triangles are rotated and drawing is a hassle, especially if I want to go back and change anything.

              – StuartRCarter
              Jan 16 '14 at 9:03






              1




              1





              @AbhimanyuArora -- Use node technique as shown heredraw ([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A){}; Same idea applies to the triangle tips.

              – Jesse
              Jan 16 '14 at 9:07





              @AbhimanyuArora -- Use node technique as shown heredraw ([yshift=0.5cm]A) -| node[above right]{$90^circ$} ([xshift=0.5cm]A){}; Same idea applies to the triangle tips.

              – Jesse
              Jan 16 '14 at 9:07













              @StuartRCarter -- Please refer to Jake's comment and take a look, to see if his 3-point command is what you need.

              – Jesse
              Jan 16 '14 at 9:16





              @StuartRCarter -- Please refer to Jake's comment and take a look, to see if his 3-point command is what you need.

              – Jesse
              Jan 16 '14 at 9:16











              4














              With PSTricks.



              documentclass[pstricks,border=12pt,12pt]{standalone}
              usepackage{pst-eucl}
              begin{document}
              begin{pspicture}(6,6)
              pstGeonode[CurveType=polygon,PosAngle={-90,0,90}](1,1){A}(5,1){B}(1,5){C}
              pstRightAngle[fillstyle=solid,fillcolor=red]{B}{A}{C}
              end{pspicture}
              end{document}


              enter image description here






              share|improve this answer




























                4














                With PSTricks.



                documentclass[pstricks,border=12pt,12pt]{standalone}
                usepackage{pst-eucl}
                begin{document}
                begin{pspicture}(6,6)
                pstGeonode[CurveType=polygon,PosAngle={-90,0,90}](1,1){A}(5,1){B}(1,5){C}
                pstRightAngle[fillstyle=solid,fillcolor=red]{B}{A}{C}
                end{pspicture}
                end{document}


                enter image description here






                share|improve this answer


























                  4












                  4








                  4







                  With PSTricks.



                  documentclass[pstricks,border=12pt,12pt]{standalone}
                  usepackage{pst-eucl}
                  begin{document}
                  begin{pspicture}(6,6)
                  pstGeonode[CurveType=polygon,PosAngle={-90,0,90}](1,1){A}(5,1){B}(1,5){C}
                  pstRightAngle[fillstyle=solid,fillcolor=red]{B}{A}{C}
                  end{pspicture}
                  end{document}


                  enter image description here






                  share|improve this answer













                  With PSTricks.



                  documentclass[pstricks,border=12pt,12pt]{standalone}
                  usepackage{pst-eucl}
                  begin{document}
                  begin{pspicture}(6,6)
                  pstGeonode[CurveType=polygon,PosAngle={-90,0,90}](1,1){A}(5,1){B}(1,5){C}
                  pstRightAngle[fillstyle=solid,fillcolor=red]{B}{A}{C}
                  end{pspicture}
                  end{document}


                  enter image description here







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Jan 16 '14 at 12:45









                  kiss my armpitkiss my armpit

                  12.7k20170404




                  12.7k20170404























                      3















                      Note : Since version 3.1 of TikZ right angle is part of the standard angles library. It works in the same way as angle pic.




                      This answer is very close to the answer of @ClaudioFiandrino, which is a slight modification of the standard angles library.



                      documentclass[tikz,border=7pt]{standalone}
                      usetikzlibrary{angles, quotes}

                      makeatletter
                      tikzset{
                      pics/right angle/.style = {
                      setup code = tikz@lib@angle@parse#1pgf@stop,
                      background code = tikz@lib@rightangle@background#1pgf@stop,
                      foreground code = tikz@lib@rightangle@foreground#1pgf@stop,
                      },
                      pics/right angle/.default=A--B--C,
                      angle eccentricity/.initial=.6,
                      angle radius/.initial=5mm
                      }

                      deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
                      path [name prefix ..] [pic actions, draw=none] (#2.center)
                      -- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
                      -- cycle;
                      }

                      deftikz@lib@rightangle@foreground#1--#2--#3pgf@stop{%
                      path [name prefix ..] [pic actions, fill=none, shade=none]
                      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
                      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt);
                      ifxtikzpictextrelaxelse%
                      defpgf@temp{node()[name prefix
                      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
                      eccentricity}*sqrt(1/2)*tikz@lib@angle@rad pt)}]#2.center)}]}
                      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
                      fi
                      }
                      makeatother

                      begin{document}
                      begin{tikzpicture}
                      draw (4,1) coordinate (C)
                      -- (0,0) coordinate (A)
                      -- ([turn] 0,3) coordinate (B)
                      -- cycle
                      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
                      pic [draw,blue,thick] {right angle = A--C--B}
                      pic [fill=green,draw] {right angle = C--B--A};
                      ;
                      end{tikzpicture}
                      end{document}


                      enter image description here



                      Note : I have created a rightangles library, available at GitHub that can be used in place of this hack like this



                      documentclass[tikz,border=7pt]{standalone}
                      usetikzlibrary{rightangles, quotes}

                      begin{document}
                      begin{tikzpicture}
                      draw (4,1) coordinate (C)
                      -- (0,0) coordinate (A)
                      -- ([turn] 0,3) coordinate (B)
                      -- cycle
                      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
                      pic [draw,blue,thick] {right angle = A--C--B}
                      pic [fill=green,draw] {right angle = C--B--A};
                      ;
                      end{tikzpicture}
                      end{document}





                      share|improve this answer


























                      • Best answer! The main one does not work for rotated angles! ;)

                        – GiuTeX
                        Jun 16 '18 at 22:07
















                      3















                      Note : Since version 3.1 of TikZ right angle is part of the standard angles library. It works in the same way as angle pic.




                      This answer is very close to the answer of @ClaudioFiandrino, which is a slight modification of the standard angles library.



                      documentclass[tikz,border=7pt]{standalone}
                      usetikzlibrary{angles, quotes}

                      makeatletter
                      tikzset{
                      pics/right angle/.style = {
                      setup code = tikz@lib@angle@parse#1pgf@stop,
                      background code = tikz@lib@rightangle@background#1pgf@stop,
                      foreground code = tikz@lib@rightangle@foreground#1pgf@stop,
                      },
                      pics/right angle/.default=A--B--C,
                      angle eccentricity/.initial=.6,
                      angle radius/.initial=5mm
                      }

                      deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
                      path [name prefix ..] [pic actions, draw=none] (#2.center)
                      -- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
                      -- cycle;
                      }

                      deftikz@lib@rightangle@foreground#1--#2--#3pgf@stop{%
                      path [name prefix ..] [pic actions, fill=none, shade=none]
                      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
                      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt);
                      ifxtikzpictextrelaxelse%
                      defpgf@temp{node()[name prefix
                      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
                      eccentricity}*sqrt(1/2)*tikz@lib@angle@rad pt)}]#2.center)}]}
                      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
                      fi
                      }
                      makeatother

                      begin{document}
                      begin{tikzpicture}
                      draw (4,1) coordinate (C)
                      -- (0,0) coordinate (A)
                      -- ([turn] 0,3) coordinate (B)
                      -- cycle
                      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
                      pic [draw,blue,thick] {right angle = A--C--B}
                      pic [fill=green,draw] {right angle = C--B--A};
                      ;
                      end{tikzpicture}
                      end{document}


                      enter image description here



                      Note : I have created a rightangles library, available at GitHub that can be used in place of this hack like this



                      documentclass[tikz,border=7pt]{standalone}
                      usetikzlibrary{rightangles, quotes}

                      begin{document}
                      begin{tikzpicture}
                      draw (4,1) coordinate (C)
                      -- (0,0) coordinate (A)
                      -- ([turn] 0,3) coordinate (B)
                      -- cycle
                      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
                      pic [draw,blue,thick] {right angle = A--C--B}
                      pic [fill=green,draw] {right angle = C--B--A};
                      ;
                      end{tikzpicture}
                      end{document}





                      share|improve this answer


























                      • Best answer! The main one does not work for rotated angles! ;)

                        – GiuTeX
                        Jun 16 '18 at 22:07














                      3












                      3








                      3








                      Note : Since version 3.1 of TikZ right angle is part of the standard angles library. It works in the same way as angle pic.




                      This answer is very close to the answer of @ClaudioFiandrino, which is a slight modification of the standard angles library.



                      documentclass[tikz,border=7pt]{standalone}
                      usetikzlibrary{angles, quotes}

                      makeatletter
                      tikzset{
                      pics/right angle/.style = {
                      setup code = tikz@lib@angle@parse#1pgf@stop,
                      background code = tikz@lib@rightangle@background#1pgf@stop,
                      foreground code = tikz@lib@rightangle@foreground#1pgf@stop,
                      },
                      pics/right angle/.default=A--B--C,
                      angle eccentricity/.initial=.6,
                      angle radius/.initial=5mm
                      }

                      deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
                      path [name prefix ..] [pic actions, draw=none] (#2.center)
                      -- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
                      -- cycle;
                      }

                      deftikz@lib@rightangle@foreground#1--#2--#3pgf@stop{%
                      path [name prefix ..] [pic actions, fill=none, shade=none]
                      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
                      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt);
                      ifxtikzpictextrelaxelse%
                      defpgf@temp{node()[name prefix
                      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
                      eccentricity}*sqrt(1/2)*tikz@lib@angle@rad pt)}]#2.center)}]}
                      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
                      fi
                      }
                      makeatother

                      begin{document}
                      begin{tikzpicture}
                      draw (4,1) coordinate (C)
                      -- (0,0) coordinate (A)
                      -- ([turn] 0,3) coordinate (B)
                      -- cycle
                      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
                      pic [draw,blue,thick] {right angle = A--C--B}
                      pic [fill=green,draw] {right angle = C--B--A};
                      ;
                      end{tikzpicture}
                      end{document}


                      enter image description here



                      Note : I have created a rightangles library, available at GitHub that can be used in place of this hack like this



                      documentclass[tikz,border=7pt]{standalone}
                      usetikzlibrary{rightangles, quotes}

                      begin{document}
                      begin{tikzpicture}
                      draw (4,1) coordinate (C)
                      -- (0,0) coordinate (A)
                      -- ([turn] 0,3) coordinate (B)
                      -- cycle
                      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
                      pic [draw,blue,thick] {right angle = A--C--B}
                      pic [fill=green,draw] {right angle = C--B--A};
                      ;
                      end{tikzpicture}
                      end{document}





                      share|improve this answer
















                      Note : Since version 3.1 of TikZ right angle is part of the standard angles library. It works in the same way as angle pic.




                      This answer is very close to the answer of @ClaudioFiandrino, which is a slight modification of the standard angles library.



                      documentclass[tikz,border=7pt]{standalone}
                      usetikzlibrary{angles, quotes}

                      makeatletter
                      tikzset{
                      pics/right angle/.style = {
                      setup code = tikz@lib@angle@parse#1pgf@stop,
                      background code = tikz@lib@rightangle@background#1pgf@stop,
                      foreground code = tikz@lib@rightangle@foreground#1pgf@stop,
                      },
                      pics/right angle/.default=A--B--C,
                      angle eccentricity/.initial=.6,
                      angle radius/.initial=5mm
                      }

                      deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
                      path [name prefix ..] [pic actions, draw=none] (#2.center)
                      -- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
                      -- cycle;
                      }

                      deftikz@lib@rightangle@foreground#1--#2--#3pgf@stop{%
                      path [name prefix ..] [pic actions, fill=none, shade=none]
                      ([shift={(tikz@start@angle@temp:tikz@lib@angle@rad pt)}]#2.center)
                      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
                      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt);
                      ifxtikzpictextrelaxelse%
                      defpgf@temp{node()[name prefix
                      ..,at={([shift={({.5*tikz@start@angle@temp+.5*tikz@end@angle@temp}:pgfkeysvalueof{/tikz/angle
                      eccentricity}*sqrt(1/2)*tikz@lib@angle@rad pt)}]#2.center)}]}
                      expandafterpgf@tempexpandafter[tikzpictextoptions]{tikzpictext};%
                      fi
                      }
                      makeatother

                      begin{document}
                      begin{tikzpicture}
                      draw (4,1) coordinate (C)
                      -- (0,0) coordinate (A)
                      -- ([turn] 0,3) coordinate (B)
                      -- cycle
                      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
                      pic [draw,blue,thick] {right angle = A--C--B}
                      pic [fill=green,draw] {right angle = C--B--A};
                      ;
                      end{tikzpicture}
                      end{document}


                      enter image description here



                      Note : I have created a rightangles library, available at GitHub that can be used in place of this hack like this



                      documentclass[tikz,border=7pt]{standalone}
                      usetikzlibrary{rightangles, quotes}

                      begin{document}
                      begin{tikzpicture}
                      draw (4,1) coordinate (C)
                      -- (0,0) coordinate (A)
                      -- ([turn] 0,3) coordinate (B)
                      -- cycle
                      pic [draw,red,"$cdot$",angle eccentricity=.5] {right angle = B--A--C}
                      pic [draw,blue,thick] {right angle = A--C--B}
                      pic [fill=green,draw] {right angle = C--B--A};
                      ;
                      end{tikzpicture}
                      end{document}






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Jan 12 at 8:00

























                      answered Jan 9 '18 at 18:18









                      KpymKpym

                      16k23986




                      16k23986













                      • Best answer! The main one does not work for rotated angles! ;)

                        – GiuTeX
                        Jun 16 '18 at 22:07



















                      • Best answer! The main one does not work for rotated angles! ;)

                        – GiuTeX
                        Jun 16 '18 at 22:07

















                      Best answer! The main one does not work for rotated angles! ;)

                      – GiuTeX
                      Jun 16 '18 at 22:07





                      Best answer! The main one does not work for rotated angles! ;)

                      – GiuTeX
                      Jun 16 '18 at 22:07


















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