filter queryset based on url arguments
0
how to get parameters in a url in view and filter the query based on that?
i also want to have multiple arguments in urls and all of them are optional?
to deliver the requiremnt clearly here is a look on the urls in urls.py:
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<slug>D+)/(?P<illness>D+)$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>D+)/$',new_search,name='new_search'),
how to filter a queryset based on those urls in views.py ???
python django
edited Nov 19 '18 at 14:36
Daniel Roseman
447k41578635
asked Nov 19 '18 at 14:36
user9292558user9292558
1
add a comment |
0
how to get parameters in a url in view and filter the query based on that?
i also want to have multiple arguments in urls and all of them are optional?
to deliver the requiremnt clearly here is a look on the urls in urls.py:
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<slug>D+)/(?P<illness>D+)$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>D+)/$',new_search,name='new_search'),
how to filter a queryset based on those urls in views.py ???
python django
edited Nov 19 '18 at 14:36
Daniel Roseman
447k41578635
asked Nov 19 '18 at 14:36
user9292558user9292558
1
5
Really, don't do this. Define a single URL with just^search/$and use querystring parameters to do the query.
– Daniel Roseman
Nov 19 '18 at 14:37
add a comment |
0
0
0
how to get parameters in a url in view and filter the query based on that?
i also want to have multiple arguments in urls and all of them are optional?
to deliver the requiremnt clearly here is a look on the urls in urls.py:
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<slug>D+)/(?P<illness>D+)$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>D+)/$',new_search,name='new_search'),
how to filter a queryset based on those urls in views.py ???
python django
edited Nov 19 '18 at 14:36
Daniel Roseman
447k41578635
asked Nov 19 '18 at 14:36
user9292558user9292558
1
how to get parameters in a url in view and filter the query based on that?
i also want to have multiple arguments in urls and all of them are optional?
to deliver the requiremnt clearly here is a look on the urls in urls.py:
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<slug>D+)/(?P<illness>D+)$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<slug>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>D+)/(?P<illness>D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>D+)/$',new_search,name='new_search'),
how to filter a queryset based on those urls in views.py ???
python django
python django
edited Nov 19 '18 at 14:36
Daniel Roseman
447k41578635
asked Nov 19 '18 at 14:36
user9292558user9292558
1
edited Nov 19 '18 at 14:36
Daniel Roseman
447k41578635
asked Nov 19 '18 at 14:36
user9292558user9292558
1
edited Nov 19 '18 at 14:36
Daniel Roseman
447k41578635
edited Nov 19 '18 at 14:36
Daniel Roseman
447k41578635
edited Nov 19 '18 at 14:36
Daniel Roseman
447k41578635
447k41578635
asked Nov 19 '18 at 14:36
user9292558user9292558
1
asked Nov 19 '18 at 14:36
user9292558user9292558
1
asked Nov 19 '18 at 14:36
user9292558user9292558
1
1
5
Really, don't do this. Define a single URL with just^search/$and use querystring parameters to do the query.
– Daniel Roseman
Nov 19 '18 at 14:37
add a comment |
5
Really, don't do this. Define a single URL with just^search/$and use querystring parameters to do the query.
– Daniel Roseman
Nov 19 '18 at 14:37
5
5
Really, don't do this. Define a single URL with just
^search/$ and use querystring parameters to do the query.– Daniel Roseman
Nov 19 '18 at 14:37
Really, don't do this. Define a single URL with just
^search/$ and use querystring parameters to do the query.– Daniel Roseman
Nov 19 '18 at 14:37
add a comment |
0
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5
Really, don't do this. Define a single URL with just
^search/$and use querystring parameters to do the query.– Daniel Roseman
Nov 19 '18 at 14:37