Using SQL Alchemy in python to obtain x most recent items











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I am trying to make a nested list RECENT_STORES of the x most recently ordered from stores that has their name from the table store and time_ordered from the table shipment. They are connected via shipment.store_id and store.id



How do I write a sqlalchemy query (db.session.query...) so that I do the following in order (in psuedocode):




  1. get most recent shipment by time_ordered

  2. if shipment.store_id not in RECENT_STORES:

  3. append store.name and shipment.time_ordered to RECENT_STORES at index x where shipment.store_id == store.id

  4. else: get next most recent shipment by time_ordered and repeat the same checks






python python-2.7 sqlalchemy







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    up vote
    -2
    down vote

    favorite












    I am trying to make a nested list RECENT_STORES of the x most recently ordered from stores that has their name from the table store and time_ordered from the table shipment. They are connected via shipment.store_id and store.id



    How do I write a sqlalchemy query (db.session.query...) so that I do the following in order (in psuedocode):




    1. get most recent shipment by time_ordered

    2. if shipment.store_id not in RECENT_STORES:

    3. append store.name and shipment.time_ordered to RECENT_STORES at index x where shipment.store_id == store.id

    4. else: get next most recent shipment by time_ordered and repeat the same checks






    python python-2.7 sqlalchemy







    share|improve this question
























      up vote
      -2
      down vote

      favorite









      up vote
      -2
      down vote

      favorite











      I am trying to make a nested list RECENT_STORES of the x most recently ordered from stores that has their name from the table store and time_ordered from the table shipment. They are connected via shipment.store_id and store.id



      How do I write a sqlalchemy query (db.session.query...) so that I do the following in order (in psuedocode):




      1. get most recent shipment by time_ordered

      2. if shipment.store_id not in RECENT_STORES:

      3. append store.name and shipment.time_ordered to RECENT_STORES at index x where shipment.store_id == store.id

      4. else: get next most recent shipment by time_ordered and repeat the same checks






      python python-2.7 sqlalchemy







      share|improve this question













      I am trying to make a nested list RECENT_STORES of the x most recently ordered from stores that has their name from the table store and time_ordered from the table shipment. They are connected via shipment.store_id and store.id



      How do I write a sqlalchemy query (db.session.query...) so that I do the following in order (in psuedocode):




      1. get most recent shipment by time_ordered

      2. if shipment.store_id not in RECENT_STORES:

      3. append store.name and shipment.time_ordered to RECENT_STORES at index x where shipment.store_id == store.id

      4. else: get next most recent shipment by time_ordered and repeat the same checks






      python python-2.7 sqlalchemy




      python python-2.7 sqlalchemy






      share|improve this question













      share|improve this question











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      share|improve this question










      asked Nov 15 at 1:55









      Keyadun

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