Using SQL Alchemy in python to obtain x most recent items
up vote
-2
down vote
favorite
I am trying to make a nested list RECENT_STORES
of the x
most recently ordered from stores that has their name
from the table store
and time_ordered
from the table shipment
. They are connected via shipment.store_id
and store.id
How do I write a sqlalchemy query (db.session.query...) so that I do the following in order (in psuedocode):
- get most recent
shipment
bytime_ordered
- if
shipment.store_id
not inRECENT_STORES
: - append
store.name
andshipment.time_ordered
toRECENT_STORES
at indexx
whereshipment.store_id == store.id
- else: get next most recent
shipment
bytime_ordered
and repeat the same checks
python python-2.7 sqlalchemy
add a comment |
up vote
-2
down vote
favorite
I am trying to make a nested list RECENT_STORES
of the x
most recently ordered from stores that has their name
from the table store
and time_ordered
from the table shipment
. They are connected via shipment.store_id
and store.id
How do I write a sqlalchemy query (db.session.query...) so that I do the following in order (in psuedocode):
- get most recent
shipment
bytime_ordered
- if
shipment.store_id
not inRECENT_STORES
: - append
store.name
andshipment.time_ordered
toRECENT_STORES
at indexx
whereshipment.store_id == store.id
- else: get next most recent
shipment
bytime_ordered
and repeat the same checks
python python-2.7 sqlalchemy
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
I am trying to make a nested list RECENT_STORES
of the x
most recently ordered from stores that has their name
from the table store
and time_ordered
from the table shipment
. They are connected via shipment.store_id
and store.id
How do I write a sqlalchemy query (db.session.query...) so that I do the following in order (in psuedocode):
- get most recent
shipment
bytime_ordered
- if
shipment.store_id
not inRECENT_STORES
: - append
store.name
andshipment.time_ordered
toRECENT_STORES
at indexx
whereshipment.store_id == store.id
- else: get next most recent
shipment
bytime_ordered
and repeat the same checks
python python-2.7 sqlalchemy
I am trying to make a nested list RECENT_STORES
of the x
most recently ordered from stores that has their name
from the table store
and time_ordered
from the table shipment
. They are connected via shipment.store_id
and store.id
How do I write a sqlalchemy query (db.session.query...) so that I do the following in order (in psuedocode):
- get most recent
shipment
bytime_ordered
- if
shipment.store_id
not inRECENT_STORES
: - append
store.name
andshipment.time_ordered
toRECENT_STORES
at indexx
whereshipment.store_id == store.id
- else: get next most recent
shipment
bytime_ordered
and repeat the same checks
python python-2.7 sqlalchemy
python python-2.7 sqlalchemy
asked Nov 15 at 1:55
Keyadun
318
318
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