How to get date&time using curl command?











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In my PC, RTC is not working, So I want Date&Time from server using curl command or is there any possibilities to get date and time without RTC in PC. Required format for date&time is DDMMYYYYHHMMSS.










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  • I'm curious, why you need to do this using curl?
    – Vlad Tarniceru
    Mar 2 '16 at 17:49










  • In my PC RTC Not working. But, i want time Stamp in my code. So i use Curl to do that.
    – manikanta
    Mar 5 '16 at 7:29















up vote
-1
down vote

favorite












In my PC, RTC is not working, So I want Date&Time from server using curl command or is there any possibilities to get date and time without RTC in PC. Required format for date&time is DDMMYYYYHHMMSS.










share|improve this question
























  • I'm curious, why you need to do this using curl?
    – Vlad Tarniceru
    Mar 2 '16 at 17:49










  • In my PC RTC Not working. But, i want time Stamp in my code. So i use Curl to do that.
    – manikanta
    Mar 5 '16 at 7:29













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











In my PC, RTC is not working, So I want Date&Time from server using curl command or is there any possibilities to get date and time without RTC in PC. Required format for date&time is DDMMYYYYHHMMSS.










share|improve this question















In my PC, RTC is not working, So I want Date&Time from server using curl command or is there any possibilities to get date and time without RTC in PC. Required format for date&time is DDMMYYYYHHMMSS.







command-line curl






share|improve this question















share|improve this question













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share|improve this question








edited Jul 13 '17 at 12:50









αғsнιη

24.1k2294155




24.1k2294155










asked Mar 2 '16 at 17:38









manikanta

872213




872213












  • I'm curious, why you need to do this using curl?
    – Vlad Tarniceru
    Mar 2 '16 at 17:49










  • In my PC RTC Not working. But, i want time Stamp in my code. So i use Curl to do that.
    – manikanta
    Mar 5 '16 at 7:29


















  • I'm curious, why you need to do this using curl?
    – Vlad Tarniceru
    Mar 2 '16 at 17:49










  • In my PC RTC Not working. But, i want time Stamp in my code. So i use Curl to do that.
    – manikanta
    Mar 5 '16 at 7:29
















I'm curious, why you need to do this using curl?
– Vlad Tarniceru
Mar 2 '16 at 17:49




I'm curious, why you need to do this using curl?
– Vlad Tarniceru
Mar 2 '16 at 17:49












In my PC RTC Not working. But, i want time Stamp in my code. So i use Curl to do that.
– manikanta
Mar 5 '16 at 7:29




In my PC RTC Not working. But, i want time Stamp in my code. So i use Curl to do that.
– manikanta
Mar 5 '16 at 7:29










3 Answers
3






active

oldest

votes

















up vote
3
down vote



accepted










First, curl makes http(s) requests. Assuming that you have a webserver listening on the machine, so you have 2 options:




  1. Create a script (php/asp/node) that gives you the date and time as response to the request.



  2. Get the time from server response headers.



    curl -v https://google.com/


    this will give you among other things, a line like this



    ...
    < Date: Wed, 02 Mar 2016 18:39:13 GMT
    ...


    With that result, you can parse and transform to the format that you want.



    dateFromServer=$(curl -v --silent https://google.com/ 2>&1 
    | grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"


    You must note the difference of GMT vs. local time, and adapt it to your needs.




Update 2018-11-26:

As @SopalajodeArrierez noted, it's not possible to run this when the Certificates are not updated or the time is way off the correct value, so the --insecure options is needed on curl command.



    dateFromServer=$(curl -v --insecure --silent https://google.com/ 2>&1 
| grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"





share|improve this answer























  • getting like this not working...root@sai:~# curl -v https://google.cl * Rebuilt URL to: https://google.cl/ * Hostname was NOT found in DNS cache * Could not resolve host: google.cl * Closing connection 0 curl: (6) Could not resolve host: google.cl
    – manikanta
    Feb 10 '17 at 11:36












  • what about using https://google.com/
    – bistoco
    Feb 10 '17 at 19:12






  • 1




    Not possible to run this curl command from some wrong date's computer (i.e: date at 2006 year): there will be a SSL certificate problem: certificate is not yet valid. In this case, I have managed to solve it with the -k (--insecure) option.
    – Sopalajo de Arrierez
    Nov 26 at 4:39


















up vote
1
down vote













If you must get the time from a remote server, use an NTP server.



For example:



$ ntpq -c 'rv 0 clock' localhost
clock=da8b6fe7.ae195287 Thu, Mar 10 2016 9:30:39.680


The clock value is the an NTP timestamp in hex (the epoch being 01/01/1900). You can process it a bit to get an Unix timestamp which you can then use with date:



$ ntpq -c raw -c 'rv 0 clock' localhost
Output set to raw
clock=0xda8b775d.ee94c630
$ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[ =.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}'
@1457497973.4177870717
$ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[=.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}' | xargs date +'%d%m%Y%H%M%S' -d
09032016100323


In my case, I have an NTP daemon running locally, which I could query, hence the usage of localhost. You could use, instead, one of the many public NTP servers, such as ntp.ubuntu.com.



The awk command reads the line, splits it on = and ., so that the three fields are clock, the integer part of the timestamp and the fractional part. Then, it subtracts 2209075200 (the difference in seconds between the Unix and NTP epochs, as obtained from this SO post) from the integer part and prints both the parts in decimal.






share|improve this answer






























    up vote
    0
    down vote













    Get the date from a HTTP response header. Remove clutter. Set the date.



    $ date -s `curl -I 'https://google.com/' 2>/dev/null | grep -i '^date:' | sed 's/^[Dd]ate: //g'`


    Hope it helps.






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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      3
      down vote



      accepted










      First, curl makes http(s) requests. Assuming that you have a webserver listening on the machine, so you have 2 options:




      1. Create a script (php/asp/node) that gives you the date and time as response to the request.



      2. Get the time from server response headers.



        curl -v https://google.com/


        this will give you among other things, a line like this



        ...
        < Date: Wed, 02 Mar 2016 18:39:13 GMT
        ...


        With that result, you can parse and transform to the format that you want.



        dateFromServer=$(curl -v --silent https://google.com/ 2>&1 
        | grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"


        You must note the difference of GMT vs. local time, and adapt it to your needs.




      Update 2018-11-26:

      As @SopalajodeArrierez noted, it's not possible to run this when the Certificates are not updated or the time is way off the correct value, so the --insecure options is needed on curl command.



          dateFromServer=$(curl -v --insecure --silent https://google.com/ 2>&1 
      | grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"





      share|improve this answer























      • getting like this not working...root@sai:~# curl -v https://google.cl * Rebuilt URL to: https://google.cl/ * Hostname was NOT found in DNS cache * Could not resolve host: google.cl * Closing connection 0 curl: (6) Could not resolve host: google.cl
        – manikanta
        Feb 10 '17 at 11:36












      • what about using https://google.com/
        – bistoco
        Feb 10 '17 at 19:12






      • 1




        Not possible to run this curl command from some wrong date's computer (i.e: date at 2006 year): there will be a SSL certificate problem: certificate is not yet valid. In this case, I have managed to solve it with the -k (--insecure) option.
        – Sopalajo de Arrierez
        Nov 26 at 4:39















      up vote
      3
      down vote



      accepted










      First, curl makes http(s) requests. Assuming that you have a webserver listening on the machine, so you have 2 options:




      1. Create a script (php/asp/node) that gives you the date and time as response to the request.



      2. Get the time from server response headers.



        curl -v https://google.com/


        this will give you among other things, a line like this



        ...
        < Date: Wed, 02 Mar 2016 18:39:13 GMT
        ...


        With that result, you can parse and transform to the format that you want.



        dateFromServer=$(curl -v --silent https://google.com/ 2>&1 
        | grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"


        You must note the difference of GMT vs. local time, and adapt it to your needs.




      Update 2018-11-26:

      As @SopalajodeArrierez noted, it's not possible to run this when the Certificates are not updated or the time is way off the correct value, so the --insecure options is needed on curl command.



          dateFromServer=$(curl -v --insecure --silent https://google.com/ 2>&1 
      | grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"





      share|improve this answer























      • getting like this not working...root@sai:~# curl -v https://google.cl * Rebuilt URL to: https://google.cl/ * Hostname was NOT found in DNS cache * Could not resolve host: google.cl * Closing connection 0 curl: (6) Could not resolve host: google.cl
        – manikanta
        Feb 10 '17 at 11:36












      • what about using https://google.com/
        – bistoco
        Feb 10 '17 at 19:12






      • 1




        Not possible to run this curl command from some wrong date's computer (i.e: date at 2006 year): there will be a SSL certificate problem: certificate is not yet valid. In this case, I have managed to solve it with the -k (--insecure) option.
        – Sopalajo de Arrierez
        Nov 26 at 4:39













      up vote
      3
      down vote



      accepted







      up vote
      3
      down vote



      accepted






      First, curl makes http(s) requests. Assuming that you have a webserver listening on the machine, so you have 2 options:




      1. Create a script (php/asp/node) that gives you the date and time as response to the request.



      2. Get the time from server response headers.



        curl -v https://google.com/


        this will give you among other things, a line like this



        ...
        < Date: Wed, 02 Mar 2016 18:39:13 GMT
        ...


        With that result, you can parse and transform to the format that you want.



        dateFromServer=$(curl -v --silent https://google.com/ 2>&1 
        | grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"


        You must note the difference of GMT vs. local time, and adapt it to your needs.




      Update 2018-11-26:

      As @SopalajodeArrierez noted, it's not possible to run this when the Certificates are not updated or the time is way off the correct value, so the --insecure options is needed on curl command.



          dateFromServer=$(curl -v --insecure --silent https://google.com/ 2>&1 
      | grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"





      share|improve this answer














      First, curl makes http(s) requests. Assuming that you have a webserver listening on the machine, so you have 2 options:




      1. Create a script (php/asp/node) that gives you the date and time as response to the request.



      2. Get the time from server response headers.



        curl -v https://google.com/


        this will give you among other things, a line like this



        ...
        < Date: Wed, 02 Mar 2016 18:39:13 GMT
        ...


        With that result, you can parse and transform to the format that you want.



        dateFromServer=$(curl -v --silent https://google.com/ 2>&1 
        | grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"


        You must note the difference of GMT vs. local time, and adapt it to your needs.




      Update 2018-11-26:

      As @SopalajodeArrierez noted, it's not possible to run this when the Certificates are not updated or the time is way off the correct value, so the --insecure options is needed on curl command.



          dateFromServer=$(curl -v --insecure --silent https://google.com/ 2>&1 
      | grep Date | sed -e 's/< Date: //'); date +"%d%m%Y%H%M%S" -d "$dateFromServer"






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 26 at 18:02

























      answered Mar 2 '16 at 18:45









      bistoco

      1,014717




      1,014717












      • getting like this not working...root@sai:~# curl -v https://google.cl * Rebuilt URL to: https://google.cl/ * Hostname was NOT found in DNS cache * Could not resolve host: google.cl * Closing connection 0 curl: (6) Could not resolve host: google.cl
        – manikanta
        Feb 10 '17 at 11:36












      • what about using https://google.com/
        – bistoco
        Feb 10 '17 at 19:12






      • 1




        Not possible to run this curl command from some wrong date's computer (i.e: date at 2006 year): there will be a SSL certificate problem: certificate is not yet valid. In this case, I have managed to solve it with the -k (--insecure) option.
        – Sopalajo de Arrierez
        Nov 26 at 4:39


















      • getting like this not working...root@sai:~# curl -v https://google.cl * Rebuilt URL to: https://google.cl/ * Hostname was NOT found in DNS cache * Could not resolve host: google.cl * Closing connection 0 curl: (6) Could not resolve host: google.cl
        – manikanta
        Feb 10 '17 at 11:36












      • what about using https://google.com/
        – bistoco
        Feb 10 '17 at 19:12






      • 1




        Not possible to run this curl command from some wrong date's computer (i.e: date at 2006 year): there will be a SSL certificate problem: certificate is not yet valid. In this case, I have managed to solve it with the -k (--insecure) option.
        – Sopalajo de Arrierez
        Nov 26 at 4:39
















      getting like this not working...root@sai:~# curl -v https://google.cl * Rebuilt URL to: https://google.cl/ * Hostname was NOT found in DNS cache * Could not resolve host: google.cl * Closing connection 0 curl: (6) Could not resolve host: google.cl
      – manikanta
      Feb 10 '17 at 11:36






      getting like this not working...root@sai:~# curl -v https://google.cl * Rebuilt URL to: https://google.cl/ * Hostname was NOT found in DNS cache * Could not resolve host: google.cl * Closing connection 0 curl: (6) Could not resolve host: google.cl
      – manikanta
      Feb 10 '17 at 11:36














      what about using https://google.com/
      – bistoco
      Feb 10 '17 at 19:12




      what about using https://google.com/
      – bistoco
      Feb 10 '17 at 19:12




      1




      1




      Not possible to run this curl command from some wrong date's computer (i.e: date at 2006 year): there will be a SSL certificate problem: certificate is not yet valid. In this case, I have managed to solve it with the -k (--insecure) option.
      – Sopalajo de Arrierez
      Nov 26 at 4:39




      Not possible to run this curl command from some wrong date's computer (i.e: date at 2006 year): there will be a SSL certificate problem: certificate is not yet valid. In this case, I have managed to solve it with the -k (--insecure) option.
      – Sopalajo de Arrierez
      Nov 26 at 4:39












      up vote
      1
      down vote













      If you must get the time from a remote server, use an NTP server.



      For example:



      $ ntpq -c 'rv 0 clock' localhost
      clock=da8b6fe7.ae195287 Thu, Mar 10 2016 9:30:39.680


      The clock value is the an NTP timestamp in hex (the epoch being 01/01/1900). You can process it a bit to get an Unix timestamp which you can then use with date:



      $ ntpq -c raw -c 'rv 0 clock' localhost
      Output set to raw
      clock=0xda8b775d.ee94c630
      $ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[ =.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}'
      @1457497973.4177870717
      $ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[=.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}' | xargs date +'%d%m%Y%H%M%S' -d
      09032016100323


      In my case, I have an NTP daemon running locally, which I could query, hence the usage of localhost. You could use, instead, one of the many public NTP servers, such as ntp.ubuntu.com.



      The awk command reads the line, splits it on = and ., so that the three fields are clock, the integer part of the timestamp and the fractional part. Then, it subtracts 2209075200 (the difference in seconds between the Unix and NTP epochs, as obtained from this SO post) from the integer part and prints both the parts in decimal.






      share|improve this answer



























        up vote
        1
        down vote













        If you must get the time from a remote server, use an NTP server.



        For example:



        $ ntpq -c 'rv 0 clock' localhost
        clock=da8b6fe7.ae195287 Thu, Mar 10 2016 9:30:39.680


        The clock value is the an NTP timestamp in hex (the epoch being 01/01/1900). You can process it a bit to get an Unix timestamp which you can then use with date:



        $ ntpq -c raw -c 'rv 0 clock' localhost
        Output set to raw
        clock=0xda8b775d.ee94c630
        $ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[ =.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}'
        @1457497973.4177870717
        $ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[=.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}' | xargs date +'%d%m%Y%H%M%S' -d
        09032016100323


        In my case, I have an NTP daemon running locally, which I could query, hence the usage of localhost. You could use, instead, one of the many public NTP servers, such as ntp.ubuntu.com.



        The awk command reads the line, splits it on = and ., so that the three fields are clock, the integer part of the timestamp and the fractional part. Then, it subtracts 2209075200 (the difference in seconds between the Unix and NTP epochs, as obtained from this SO post) from the integer part and prints both the parts in decimal.






        share|improve this answer

























          up vote
          1
          down vote










          up vote
          1
          down vote









          If you must get the time from a remote server, use an NTP server.



          For example:



          $ ntpq -c 'rv 0 clock' localhost
          clock=da8b6fe7.ae195287 Thu, Mar 10 2016 9:30:39.680


          The clock value is the an NTP timestamp in hex (the epoch being 01/01/1900). You can process it a bit to get an Unix timestamp which you can then use with date:



          $ ntpq -c raw -c 'rv 0 clock' localhost
          Output set to raw
          clock=0xda8b775d.ee94c630
          $ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[ =.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}'
          @1457497973.4177870717
          $ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[=.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}' | xargs date +'%d%m%Y%H%M%S' -d
          09032016100323


          In my case, I have an NTP daemon running locally, which I could query, hence the usage of localhost. You could use, instead, one of the many public NTP servers, such as ntp.ubuntu.com.



          The awk command reads the line, splits it on = and ., so that the three fields are clock, the integer part of the timestamp and the fractional part. Then, it subtracts 2209075200 (the difference in seconds between the Unix and NTP epochs, as obtained from this SO post) from the integer part and prints both the parts in decimal.






          share|improve this answer














          If you must get the time from a remote server, use an NTP server.



          For example:



          $ ntpq -c 'rv 0 clock' localhost
          clock=da8b6fe7.ae195287 Thu, Mar 10 2016 9:30:39.680


          The clock value is the an NTP timestamp in hex (the epoch being 01/01/1900). You can process it a bit to get an Unix timestamp which you can then use with date:



          $ ntpq -c raw -c 'rv 0 clock' localhost
          Output set to raw
          clock=0xda8b775d.ee94c630
          $ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[ =.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}'
          @1457497973.4177870717
          $ ntpq -c raw -c 'rv 0 clock' localhost | gawk -F '[=.]' --non-decimal-data 'NR==2{printf "@%d.%dn", $2 - 2209075200, "0x"$3}' | xargs date +'%d%m%Y%H%M%S' -d
          09032016100323


          In my case, I have an NTP daemon running locally, which I could query, hence the usage of localhost. You could use, instead, one of the many public NTP servers, such as ntp.ubuntu.com.



          The awk command reads the line, splits it on = and ., so that the three fields are clock, the integer part of the timestamp and the fractional part. Then, it subtracts 2209075200 (the difference in seconds between the Unix and NTP epochs, as obtained from this SO post) from the integer part and prints both the parts in decimal.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited May 23 '17 at 12:39









          Community

          1




          1










          answered Mar 10 '16 at 4:37









          muru

          135k19288488




          135k19288488






















              up vote
              0
              down vote













              Get the date from a HTTP response header. Remove clutter. Set the date.



              $ date -s `curl -I 'https://google.com/' 2>/dev/null | grep -i '^date:' | sed 's/^[Dd]ate: //g'`


              Hope it helps.






              share|improve this answer

























                up vote
                0
                down vote













                Get the date from a HTTP response header. Remove clutter. Set the date.



                $ date -s `curl -I 'https://google.com/' 2>/dev/null | grep -i '^date:' | sed 's/^[Dd]ate: //g'`


                Hope it helps.






                share|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  Get the date from a HTTP response header. Remove clutter. Set the date.



                  $ date -s `curl -I 'https://google.com/' 2>/dev/null | grep -i '^date:' | sed 's/^[Dd]ate: //g'`


                  Hope it helps.






                  share|improve this answer












                  Get the date from a HTTP response header. Remove clutter. Set the date.



                  $ date -s `curl -I 'https://google.com/' 2>/dev/null | grep -i '^date:' | sed 's/^[Dd]ate: //g'`


                  Hope it helps.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Jul 13 '17 at 11:38









                  Koutheir Attouchi

                  1092




                  1092






























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