How to calculate a 1D convolution summation?
I hope I said that right. I'm trying to follow along with a convolution example but maybe I am in over my head. I don't understand how in this example they get the values on the right. For example, I would think when n=0 the result would be 0*0 not 1*2.
convolution
asked Oct 10 '13 at 18:26
user1873073
1113
add a comment |
I hope I said that right. I'm trying to follow along with a convolution example but maybe I am in over my head. I don't understand how in this example they get the values on the right. For example, I would think when n=0 the result would be 0*0 not 1*2.
convolution
asked Oct 10 '13 at 18:26
user1873073
1113
add a comment |
I hope I said that right. I'm trying to follow along with a convolution example but maybe I am in over my head. I don't understand how in this example they get the values on the right. For example, I would think when n=0 the result would be 0*0 not 1*2.
convolution
asked Oct 10 '13 at 18:26
user1873073
1113
I hope I said that right. I'm trying to follow along with a convolution example but maybe I am in over my head. I don't understand how in this example they get the values on the right. For example, I would think when n=0 the result would be 0*0 not 1*2.
convolution
convolution
asked Oct 10 '13 at 18:26
user1873073
1113
asked Oct 10 '13 at 18:26
user1873073
1113
asked Oct 10 '13 at 18:26
user1873073
1113
asked Oct 10 '13 at 18:26
user1873073
1113
asked Oct 10 '13 at 18:26
user1873073
1113
1113
add a comment |
add a comment |
2 Answers
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Something you might want to watch if you are having trouble with the convolution of two signals is the animation at 34:00 or so from this lecture from MIT Open Courseware: here. The lecturer is Oppenheim, who co-wrote a classic book on discrete-time signal processing.
answered May 28 '14 at 13:54
RNG
10310
Wow that was cool thanks.
– hellyale
Nov 9 '15 at 6:21
add a comment |
I got it.
the 1 is x[0] and the 2 is h[0] which if you look at the impulse response h[0] is 2.
the 3 is x[1] and the 2 is h[0]
etc.
answered Oct 11 '13 at 17:13
user1873073
1113
add a comment |
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2 Answers
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active
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votes
2 Answers
2
active
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votes
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Something you might want to watch if you are having trouble with the convolution of two signals is the animation at 34:00 or so from this lecture from MIT Open Courseware: here. The lecturer is Oppenheim, who co-wrote a classic book on discrete-time signal processing.
answered May 28 '14 at 13:54
RNG
10310
Wow that was cool thanks.
– hellyale
Nov 9 '15 at 6:21
add a comment |
Something you might want to watch if you are having trouble with the convolution of two signals is the animation at 34:00 or so from this lecture from MIT Open Courseware: here. The lecturer is Oppenheim, who co-wrote a classic book on discrete-time signal processing.
answered May 28 '14 at 13:54
RNG
10310
Wow that was cool thanks.
– hellyale
Nov 9 '15 at 6:21
add a comment |
Something you might want to watch if you are having trouble with the convolution of two signals is the animation at 34:00 or so from this lecture from MIT Open Courseware: here. The lecturer is Oppenheim, who co-wrote a classic book on discrete-time signal processing.
answered May 28 '14 at 13:54
RNG
10310
Something you might want to watch if you are having trouble with the convolution of two signals is the animation at 34:00 or so from this lecture from MIT Open Courseware: here. The lecturer is Oppenheim, who co-wrote a classic book on discrete-time signal processing.
answered May 28 '14 at 13:54
RNG
10310
answered May 28 '14 at 13:54
RNG
10310
answered May 28 '14 at 13:54
RNG
10310
answered May 28 '14 at 13:54
RNG
10310
10310
Wow that was cool thanks.
– hellyale
Nov 9 '15 at 6:21
add a comment |
Wow that was cool thanks.
– hellyale
Nov 9 '15 at 6:21
Wow that was cool thanks.
– hellyale
Nov 9 '15 at 6:21
Wow that was cool thanks.
– hellyale
Nov 9 '15 at 6:21
add a comment |
I got it.
the 1 is x[0] and the 2 is h[0] which if you look at the impulse response h[0] is 2.
the 3 is x[1] and the 2 is h[0]
etc.
answered Oct 11 '13 at 17:13
user1873073
1113
add a comment |
I got it.
the 1 is x[0] and the 2 is h[0] which if you look at the impulse response h[0] is 2.
the 3 is x[1] and the 2 is h[0]
etc.
answered Oct 11 '13 at 17:13
user1873073
1113
add a comment |
I got it.
the 1 is x[0] and the 2 is h[0] which if you look at the impulse response h[0] is 2.
the 3 is x[1] and the 2 is h[0]
etc.
answered Oct 11 '13 at 17:13
user1873073
1113
I got it.
the 1 is x[0] and the 2 is h[0] which if you look at the impulse response h[0] is 2.
the 3 is x[1] and the 2 is h[0]
etc.
answered Oct 11 '13 at 17:13
user1873073
1113
answered Oct 11 '13 at 17:13
user1873073
1113
answered Oct 11 '13 at 17:13
user1873073
1113
answered Oct 11 '13 at 17:13
user1873073
1113
1113
add a comment |
add a comment |
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