10 names in a hat — odds that no one picks themself?
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I have an annual tradition where 10 names are placed in a hat, and those same 10 members randomly select one at a time. If anyone selects their own name, the entire process restarts.
What are the odds that all 10 people select a name that is NOT themself?
probability conditional-probability
asked Nov 18 at 18:49
CDutton
1
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I have an annual tradition where 10 names are placed in a hat, and those same 10 members randomly select one at a time. If anyone selects their own name, the entire process restarts.
What are the odds that all 10 people select a name that is NOT themself?
probability conditional-probability
asked Nov 18 at 18:49
CDutton
1
google.com/url?sa=t&source=web&rct=j&url=http://….
– Oscar Lanzi
Nov 18 at 18:51
This is a derangement problem. Did you mean probability rather than odds?
– N. F. Taussig
Nov 18 at 19:20
Yes, I suppose probability would be the correct term here. Given the conditions described above, how would that be calculated?
– CDutton
Nov 19 at 19:13
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have an annual tradition where 10 names are placed in a hat, and those same 10 members randomly select one at a time. If anyone selects their own name, the entire process restarts.
What are the odds that all 10 people select a name that is NOT themself?
probability conditional-probability
asked Nov 18 at 18:49
CDutton
1
I have an annual tradition where 10 names are placed in a hat, and those same 10 members randomly select one at a time. If anyone selects their own name, the entire process restarts.
What are the odds that all 10 people select a name that is NOT themself?
probability conditional-probability
probability conditional-probability
asked Nov 18 at 18:49
CDutton
1
asked Nov 18 at 18:49
CDutton
1
asked Nov 18 at 18:49
CDutton
1
asked Nov 18 at 18:49
CDutton
1
asked Nov 18 at 18:49
CDutton
1
1
google.com/url?sa=t&source=web&rct=j&url=http://….
– Oscar Lanzi
Nov 18 at 18:51
This is a derangement problem. Did you mean probability rather than odds?
– N. F. Taussig
Nov 18 at 19:20
Yes, I suppose probability would be the correct term here. Given the conditions described above, how would that be calculated?
– CDutton
Nov 19 at 19:13
add a comment |
google.com/url?sa=t&source=web&rct=j&url=http://….
– Oscar Lanzi
Nov 18 at 18:51
This is a derangement problem. Did you mean probability rather than odds?
– N. F. Taussig
Nov 18 at 19:20
Yes, I suppose probability would be the correct term here. Given the conditions described above, how would that be calculated?
– CDutton
Nov 19 at 19:13
google.com/url?sa=t&source=web&rct=j&url=http://….
– Oscar Lanzi
Nov 18 at 18:51
google.com/url?sa=t&source=web&rct=j&url=http://….
– Oscar Lanzi
Nov 18 at 18:51
This is a derangement problem. Did you mean probability rather than odds?
– N. F. Taussig
Nov 18 at 19:20
This is a derangement problem. Did you mean probability rather than odds?
– N. F. Taussig
Nov 18 at 19:20
Yes, I suppose probability would be the correct term here. Given the conditions described above, how would that be calculated?
– CDutton
Nov 19 at 19:13
Yes, I suppose probability would be the correct term here. Given the conditions described above, how would that be calculated?
– CDutton
Nov 19 at 19:13
add a comment |
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google.com/url?sa=t&source=web&rct=j&url=http://….
– Oscar Lanzi
Nov 18 at 18:51
This is a derangement problem. Did you mean probability rather than odds?
– N. F. Taussig
Nov 18 at 19:20
Yes, I suppose probability would be the correct term here. Given the conditions described above, how would that be calculated?
– CDutton
Nov 19 at 19:13