Rename multiple files sequentially and starting by the same prefix
I have a folder containing like 1500 files, I want to rename them automatically via the terminal or a shell script as follows: "prefix_number.extension".
Example: cin_1.jpg, cin_2.png ...
command-line scripts rename batch-rename
asked Jan 8 at 22:32
singriumsingrium
1,211424
add a comment |
I have a folder containing like 1500 files, I want to rename them automatically via the terminal or a shell script as follows: "prefix_number.extension".
Example: cin_1.jpg, cin_2.png ...
command-line scripts rename batch-rename
asked Jan 8 at 22:32
singriumsingrium
1,211424
Likely related: Sequential renaming of files
– steeldriver
Jan 8 at 22:42
add a comment |
I have a folder containing like 1500 files, I want to rename them automatically via the terminal or a shell script as follows: "prefix_number.extension".
Example: cin_1.jpg, cin_2.png ...
command-line scripts rename batch-rename
asked Jan 8 at 22:32
singriumsingrium
1,211424
I have a folder containing like 1500 files, I want to rename them automatically via the terminal or a shell script as follows: "prefix_number.extension".
Example: cin_1.jpg, cin_2.png ...
command-line scripts rename batch-rename
command-line scripts rename batch-rename
asked Jan 8 at 22:32
singriumsingrium
1,211424
asked Jan 8 at 22:32
singriumsingrium
1,211424
edited Jan 9 at 15:14
singrium
asked Jan 8 at 22:32
singriumsingrium
1,211424
asked Jan 8 at 22:32
singriumsingrium
1,211424
asked Jan 8 at 22:32
singriumsingrium
1,211424
1,211424
Likely related: Sequential renaming of files
– steeldriver
Jan 8 at 22:42
add a comment |
Likely related: Sequential renaming of files
– steeldriver
Jan 8 at 22:42
Likely related: Sequential renaming of files
– steeldriver
Jan 8 at 22:42
Likely related: Sequential renaming of files
– steeldriver
Jan 8 at 22:42
add a comment |
2 Answers
2
active
oldest
votes
Try:
count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
Or, if you prefer your commands spread over multiple lines:
count=0
for f in *
do
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
done
How it works
count=0
This initializes the variable
countto zero.
for f in *; do
This starts a loop over all files in the current directory.
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
[ -f "$f" ]tests to see if the file$fis a regular file (not a directory).
If
$fis a regular file, then the move (mv) command is run.-itellsmvnot to overwrite any existing files without asking."cin_$((++count)).${f##*.}"is the name of the new file.cin_is the prefix.$((++count))returns the value ofcountafter it has been incremented.${f##*.}is the extension of file$f.
done
This marks the end of the loop.
Example
Consider a directory with these three files:
$ ls
alpha.jpg beta.png gamma.txt
Let's run our command:
$ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
After running our command, the files in the directory now are:
$ ls
cin_1.jpg cin_2.png cin_3.txt
edited Jan 8 at 22:53
dessert
23.3k565103
answered Jan 8 at 22:45
John1024John1024
9,9692434
1
That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!
– singrium
Jan 8 at 22:50
add a comment |
A rename oneliner:
rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.
Example run
$ ls
a.jpg b.jpg d.png e.png
$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
rename(a.jpg, cin_1.jpg)
rename(b.jpg, cin_2.jpg)
rename(d.png, cin_3.png)
rename(e.png, cin_4.png)
$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
$ ls
cin_1.jpg cin_2.jpg cin_3.png cin_4.png
Source: How to rename multiple files sequentially from command line?
answered Jan 8 at 22:52
dessertdessert
23.3k565103
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try:
count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
Or, if you prefer your commands spread over multiple lines:
count=0
for f in *
do
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
done
How it works
count=0
This initializes the variable
countto zero.
for f in *; do
This starts a loop over all files in the current directory.
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
[ -f "$f" ]tests to see if the file$fis a regular file (not a directory).
If
$fis a regular file, then the move (mv) command is run.-itellsmvnot to overwrite any existing files without asking."cin_$((++count)).${f##*.}"is the name of the new file.cin_is the prefix.$((++count))returns the value ofcountafter it has been incremented.${f##*.}is the extension of file$f.
done
This marks the end of the loop.
Example
Consider a directory with these three files:
$ ls
alpha.jpg beta.png gamma.txt
Let's run our command:
$ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
After running our command, the files in the directory now are:
$ ls
cin_1.jpg cin_2.png cin_3.txt
edited Jan 8 at 22:53
dessert
23.3k565103
answered Jan 8 at 22:45
John1024John1024
9,9692434
1
That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!
– singrium
Jan 8 at 22:50
add a comment |
Try:
count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
Or, if you prefer your commands spread over multiple lines:
count=0
for f in *
do
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
done
How it works
count=0
This initializes the variable
countto zero.
for f in *; do
This starts a loop over all files in the current directory.
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
[ -f "$f" ]tests to see if the file$fis a regular file (not a directory).
If
$fis a regular file, then the move (mv) command is run.-itellsmvnot to overwrite any existing files without asking."cin_$((++count)).${f##*.}"is the name of the new file.cin_is the prefix.$((++count))returns the value ofcountafter it has been incremented.${f##*.}is the extension of file$f.
done
This marks the end of the loop.
Example
Consider a directory with these three files:
$ ls
alpha.jpg beta.png gamma.txt
Let's run our command:
$ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
After running our command, the files in the directory now are:
$ ls
cin_1.jpg cin_2.png cin_3.txt
edited Jan 8 at 22:53
dessert
23.3k565103
answered Jan 8 at 22:45
John1024John1024
9,9692434
1
That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!
– singrium
Jan 8 at 22:50
add a comment |
Try:
count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
Or, if you prefer your commands spread over multiple lines:
count=0
for f in *
do
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
done
How it works
count=0
This initializes the variable
countto zero.
for f in *; do
This starts a loop over all files in the current directory.
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
[ -f "$f" ]tests to see if the file$fis a regular file (not a directory).
If
$fis a regular file, then the move (mv) command is run.-itellsmvnot to overwrite any existing files without asking."cin_$((++count)).${f##*.}"is the name of the new file.cin_is the prefix.$((++count))returns the value ofcountafter it has been incremented.${f##*.}is the extension of file$f.
done
This marks the end of the loop.
Example
Consider a directory with these three files:
$ ls
alpha.jpg beta.png gamma.txt
Let's run our command:
$ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
After running our command, the files in the directory now are:
$ ls
cin_1.jpg cin_2.png cin_3.txt
edited Jan 8 at 22:53
dessert
23.3k565103
answered Jan 8 at 22:45
John1024John1024
9,9692434
Try:
count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
Or, if you prefer your commands spread over multiple lines:
count=0
for f in *
do
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
done
How it works
count=0
This initializes the variable
countto zero.
for f in *; do
This starts a loop over all files in the current directory.
[ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
[ -f "$f" ]tests to see if the file$fis a regular file (not a directory).
If
$fis a regular file, then the move (mv) command is run.-itellsmvnot to overwrite any existing files without asking."cin_$((++count)).${f##*.}"is the name of the new file.cin_is the prefix.$((++count))returns the value ofcountafter it has been incremented.${f##*.}is the extension of file$f.
done
This marks the end of the loop.
Example
Consider a directory with these three files:
$ ls
alpha.jpg beta.png gamma.txt
Let's run our command:
$ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done
After running our command, the files in the directory now are:
$ ls
cin_1.jpg cin_2.png cin_3.txt
edited Jan 8 at 22:53
dessert
23.3k565103
answered Jan 8 at 22:45
John1024John1024
9,9692434
edited Jan 8 at 22:53
dessert
23.3k565103
edited Jan 8 at 22:53
dessert
23.3k565103
edited Jan 8 at 22:53
dessert
23.3k565103
23.3k565103
answered Jan 8 at 22:45
John1024John1024
9,9692434
answered Jan 8 at 22:45
John1024John1024
9,9692434
answered Jan 8 at 22:45
John1024John1024
9,9692434
9,9692434
1
That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!
– singrium
Jan 8 at 22:50
add a comment |
1
That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!
– singrium
Jan 8 at 22:50
1
1
That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!
– singrium
Jan 8 at 22:50
That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!
– singrium
Jan 8 at 22:50
add a comment |
A rename oneliner:
rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.
Example run
$ ls
a.jpg b.jpg d.png e.png
$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
rename(a.jpg, cin_1.jpg)
rename(b.jpg, cin_2.jpg)
rename(d.png, cin_3.png)
rename(e.png, cin_4.png)
$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
$ ls
cin_1.jpg cin_2.jpg cin_3.png cin_4.png
Source: How to rename multiple files sequentially from command line?
answered Jan 8 at 22:52
dessertdessert
23.3k565103
add a comment |
A rename oneliner:
rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.
Example run
$ ls
a.jpg b.jpg d.png e.png
$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
rename(a.jpg, cin_1.jpg)
rename(b.jpg, cin_2.jpg)
rename(d.png, cin_3.png)
rename(e.png, cin_4.png)
$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
$ ls
cin_1.jpg cin_2.jpg cin_3.png cin_4.png
Source: How to rename multiple files sequentially from command line?
answered Jan 8 at 22:52
dessertdessert
23.3k565103
add a comment |
A rename oneliner:
rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.
Example run
$ ls
a.jpg b.jpg d.png e.png
$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
rename(a.jpg, cin_1.jpg)
rename(b.jpg, cin_2.jpg)
rename(d.png, cin_3.png)
rename(e.png, cin_4.png)
$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
$ ls
cin_1.jpg cin_2.jpg cin_3.png cin_4.png
Source: How to rename multiple files sequentially from command line?
answered Jan 8 at 22:52
dessertdessert
23.3k565103
A rename oneliner:
rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.
Example run
$ ls
a.jpg b.jpg d.png e.png
$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
rename(a.jpg, cin_1.jpg)
rename(b.jpg, cin_2.jpg)
rename(d.png, cin_3.png)
rename(e.png, cin_4.png)
$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
$ ls
cin_1.jpg cin_2.jpg cin_3.png cin_4.png
Source: How to rename multiple files sequentially from command line?
answered Jan 8 at 22:52
dessertdessert
23.3k565103
answered Jan 8 at 22:52
dessertdessert
23.3k565103
answered Jan 8 at 22:52
dessertdessert
23.3k565103
answered Jan 8 at 22:52
dessertdessert
23.3k565103
23.3k565103
add a comment |
add a comment |
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Likely related: Sequential renaming of files
– steeldriver
Jan 8 at 22:42