Rename multiple files sequentially and starting by the same prefix












1















I have a folder containing like 1500 files, I want to rename them automatically via the terminal or a shell script as follows: "prefix_number.extension".
Example: cin_1.jpg, cin_2.png ...






command-line scripts rename batch-rename







share|improve this question

























  • Likely related: Sequential renaming of files

    – steeldriver
    Jan 8 at 22:42
















1















I have a folder containing like 1500 files, I want to rename them automatically via the terminal or a shell script as follows: "prefix_number.extension".
Example: cin_1.jpg, cin_2.png ...






command-line scripts rename batch-rename







share|improve this question

























  • Likely related: Sequential renaming of files

    – steeldriver
    Jan 8 at 22:42














1












1








1








I have a folder containing like 1500 files, I want to rename them automatically via the terminal or a shell script as follows: "prefix_number.extension".
Example: cin_1.jpg, cin_2.png ...






command-line scripts rename batch-rename







share|improve this question
















I have a folder containing like 1500 files, I want to rename them automatically via the terminal or a shell script as follows: "prefix_number.extension".
Example: cin_1.jpg, cin_2.png ...






command-line scripts rename batch-rename




command-line scripts rename batch-rename






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 9 at 15:14







singrium

















asked Jan 8 at 22:32









singriumsingrium

1,211424




1,211424













  • Likely related: Sequential renaming of files

    – steeldriver
    Jan 8 at 22:42



















  • Likely related: Sequential renaming of files

    – steeldriver
    Jan 8 at 22:42

















Likely related: Sequential renaming of files

– steeldriver
Jan 8 at 22:42





Likely related: Sequential renaming of files

– steeldriver
Jan 8 at 22:42










2 Answers
2






active

oldest

votes


















1














Try:





count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


Or, if you prefer your commands spread over multiple lines:



count=0

for f in *

do

    [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"

done


How it works





  • count=0



    This initializes the variable count to zero.




  • for f in *; do



    This starts a loop over all files in the current directory.




  • [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"



    [ -f "$f" ] tests to see if the file $f is a regular file (not a directory).



    If $f is a regular file, then the move (mv) command is run. -i tells mv not to overwrite any existing files without asking. "cin_$((++count)).${f##*.}" is the name of the new file. cin_ is the prefix. $((++count)) returns the value of count after it has been incremented. ${f##*.} is the extension of file $f.




  • done



    This marks the end of the loop.




Example



Consider a directory with these three files:



$ ls

alpha.jpg  beta.png  gamma.txt


Let's run our command:



$ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


After running our command, the files in the directory now are:



$ ls

cin_1.jpg  cin_2.png  cin_3.txt





share|improve this answer





















  • 1





    That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!

    – singrium
    Jan 8 at 22:50



















1














A rename oneliner:



rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *


This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.



Example run



$ ls

a.jpg  b.jpg  d.png  e.png

$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *

rename(a.jpg, cin_1.jpg)

rename(b.jpg, cin_2.jpg)

rename(d.png, cin_3.png)

rename(e.png, cin_4.png)

$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *

$ ls

cin_1.jpg  cin_2.jpg  cin_3.png  cin_4.png


Source: How to rename multiple files sequentially from command line?






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    2 Answers
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    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Try:





    count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


    Or, if you prefer your commands spread over multiple lines:



    count=0
    
for f in *
    
do
    
    [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
    
done


    How it works





    • count=0



      This initializes the variable count to zero.




    • for f in *; do



      This starts a loop over all files in the current directory.




    • [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"



      [ -f "$f" ] tests to see if the file $f is a regular file (not a directory).



      If $f is a regular file, then the move (mv) command is run. -i tells mv not to overwrite any existing files without asking. "cin_$((++count)).${f##*.}" is the name of the new file. cin_ is the prefix. $((++count)) returns the value of count after it has been incremented. ${f##*.} is the extension of file $f.




    • done



      This marks the end of the loop.




    Example



    Consider a directory with these three files:



    $ ls
    
alpha.jpg  beta.png  gamma.txt


    Let's run our command:



    $ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


    After running our command, the files in the directory now are:



    $ ls
    
cin_1.jpg  cin_2.png  cin_3.txt





    share|improve this answer





















    • 1





      That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!

      – singrium
      Jan 8 at 22:50
















    1














    Try:





    count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


    Or, if you prefer your commands spread over multiple lines:



    count=0
    
for f in *
    
do
    
    [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
    
done


    How it works





    • count=0



      This initializes the variable count to zero.




    • for f in *; do



      This starts a loop over all files in the current directory.




    • [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"



      [ -f "$f" ] tests to see if the file $f is a regular file (not a directory).



      If $f is a regular file, then the move (mv) command is run. -i tells mv not to overwrite any existing files without asking. "cin_$((++count)).${f##*.}" is the name of the new file. cin_ is the prefix. $((++count)) returns the value of count after it has been incremented. ${f##*.} is the extension of file $f.




    • done



      This marks the end of the loop.




    Example



    Consider a directory with these three files:



    $ ls
    
alpha.jpg  beta.png  gamma.txt


    Let's run our command:



    $ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


    After running our command, the files in the directory now are:



    $ ls
    
cin_1.jpg  cin_2.png  cin_3.txt





    share|improve this answer





















    • 1





      That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!

      – singrium
      Jan 8 at 22:50














    1












    1








    1







    Try:





    count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


    Or, if you prefer your commands spread over multiple lines:



    count=0
    
for f in *
    
do
    
    [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
    
done


    How it works





    • count=0



      This initializes the variable count to zero.




    • for f in *; do



      This starts a loop over all files in the current directory.




    • [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"



      [ -f "$f" ] tests to see if the file $f is a regular file (not a directory).



      If $f is a regular file, then the move (mv) command is run. -i tells mv not to overwrite any existing files without asking. "cin_$((++count)).${f##*.}" is the name of the new file. cin_ is the prefix. $((++count)) returns the value of count after it has been incremented. ${f##*.} is the extension of file $f.




    • done



      This marks the end of the loop.




    Example



    Consider a directory with these three files:



    $ ls
    
alpha.jpg  beta.png  gamma.txt


    Let's run our command:



    $ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


    After running our command, the files in the directory now are:



    $ ls
    
cin_1.jpg  cin_2.png  cin_3.txt





    share|improve this answer















    Try:





    count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


    Or, if you prefer your commands spread over multiple lines:



    count=0
    
for f in *
    
do
    
    [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"
    
done


    How it works





    • count=0



      This initializes the variable count to zero.




    • for f in *; do



      This starts a loop over all files in the current directory.




    • [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"



      [ -f "$f" ] tests to see if the file $f is a regular file (not a directory).



      If $f is a regular file, then the move (mv) command is run. -i tells mv not to overwrite any existing files without asking. "cin_$((++count)).${f##*.}" is the name of the new file. cin_ is the prefix. $((++count)) returns the value of count after it has been incremented. ${f##*.} is the extension of file $f.




    • done



      This marks the end of the loop.




    Example



    Consider a directory with these three files:



    $ ls
    
alpha.jpg  beta.png  gamma.txt


    Let's run our command:



    $ count=0; for f in *; do [ -f "$f" ] && mv -i "$f" "cin_$((++count)).${f##*.}"; done


    After running our command, the files in the directory now are:



    $ ls
    
cin_1.jpg  cin_2.png  cin_3.txt






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 8 at 22:53









    dessert

    23.3k565103




    23.3k565103










    answered Jan 8 at 22:45









    John1024John1024

    9,9692434




    9,9692434








    • 1





      That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!

      – singrium
      Jan 8 at 22:50














    • 1





      That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!

      – singrium
      Jan 8 at 22:50








    1




    1





    That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!

    – singrium
    Jan 8 at 22:50





    That did exactly what I wanted, and it is super fast (faster than with Python). Thank you!

    – singrium
    Jan 8 at 22:50













    1














    A rename oneliner:



    rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *


    This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.



    Example run



    $ ls
    
a.jpg  b.jpg  d.png  e.png
    
$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
    
rename(a.jpg, cin_1.jpg)
    
rename(b.jpg, cin_2.jpg)
    
rename(d.png, cin_3.png)
    
rename(e.png, cin_4.png)
    
$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
    
$ ls
    
cin_1.jpg  cin_2.jpg  cin_3.png  cin_4.png


    Source: How to rename multiple files sequentially from command line?






    share|improve this answer




























      1














      A rename oneliner:



      rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *


      This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.



      Example run



      $ ls
      
a.jpg  b.jpg  d.png  e.png
      
$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
      
rename(a.jpg, cin_1.jpg)
      
rename(b.jpg, cin_2.jpg)
      
rename(d.png, cin_3.png)
      
rename(e.png, cin_4.png)
      
$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
      
$ ls
      
cin_1.jpg  cin_2.jpg  cin_3.png  cin_4.png


      Source: How to rename multiple files sequentially from command line?






      share|improve this answer


























        1












        1








        1







        A rename oneliner:



        rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *


        This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.



        Example run



        $ ls
        
a.jpg  b.jpg  d.png  e.png
        
$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
        
rename(a.jpg, cin_1.jpg)
        
rename(b.jpg, cin_2.jpg)
        
rename(d.png, cin_3.png)
        
rename(e.png, cin_4.png)
        
$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
        
$ ls
        
cin_1.jpg  cin_2.jpg  cin_3.png  cin_4.png


        Source: How to rename multiple files sequentially from command line?






        share|improve this answer













        A rename oneliner:



        rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *


        This matches every file with a dot in its name (the last one, if multiple) and renames the part until the dot with cin_ followed by an incrementing number and a dot. With the -n flag it just prints what it would do, remove it to perform the renaming.



        Example run



        $ ls
        
a.jpg  b.jpg  d.png  e.png
        
$ rename -n 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
        
rename(a.jpg, cin_1.jpg)
        
rename(b.jpg, cin_2.jpg)
        
rename(d.png, cin_3.png)
        
rename(e.png, cin_4.png)
        
$ rename 's/.+./our $i; sprintf("cin_%d.", 1+$i++)/e' *
        
$ ls
        
cin_1.jpg  cin_2.jpg  cin_3.png  cin_4.png


        Source: How to rename multiple files sequentially from command line?







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 8 at 22:52









        dessertdessert

        23.3k565103




        23.3k565103






























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