Calculate the sum of an array
-1
I have created an array using the following JavaScript:
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease)
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
console.log("annualCostA= " + annualCostA);
}
For context:
var numOfPeriodsCost = 10;
var annualElecIncrease = 0.1;
var consumptionA = 520;
The console logs the following for annualCostA:
How would I take this one step further and calculate the sum of the array?
Thanks
javascript arrays sum
edited Nov 20 '18 at 10:12
Eugene Mihaylin
9681424
asked Nov 20 '18 at 9:47
JohnGISJohnGIS
828
add a comment |
-1
I have created an array using the following JavaScript:
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease)
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
console.log("annualCostA= " + annualCostA);
}
For context:
var numOfPeriodsCost = 10;
var annualElecIncrease = 0.1;
var consumptionA = 520;
The console logs the following for annualCostA:
How would I take this one step further and calculate the sum of the array?
Thanks
javascript arrays sum
edited Nov 20 '18 at 10:12
Eugene Mihaylin
9681424
asked Nov 20 '18 at 9:47
JohnGISJohnGIS
828
What is the initial value ofesclatedPrice?
– Gary Thomas
Nov 20 '18 at 9:51
add a comment |
-1
-1
-1
1
I have created an array using the following JavaScript:
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease)
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
console.log("annualCostA= " + annualCostA);
}
For context:
var numOfPeriodsCost = 10;
var annualElecIncrease = 0.1;
var consumptionA = 520;
The console logs the following for annualCostA:
How would I take this one step further and calculate the sum of the array?
Thanks
javascript arrays sum
edited Nov 20 '18 at 10:12
Eugene Mihaylin
9681424
asked Nov 20 '18 at 9:47
JohnGISJohnGIS
828
I have created an array using the following JavaScript:
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease)
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
console.log("annualCostA= " + annualCostA);
}
For context:
var numOfPeriodsCost = 10;
var annualElecIncrease = 0.1;
var consumptionA = 520;
The console logs the following for annualCostA:
How would I take this one step further and calculate the sum of the array?
Thanks
javascript arrays sum
javascript arrays sum
edited Nov 20 '18 at 10:12
Eugene Mihaylin
9681424
asked Nov 20 '18 at 9:47
JohnGISJohnGIS
828
edited Nov 20 '18 at 10:12
Eugene Mihaylin
9681424
asked Nov 20 '18 at 9:47
JohnGISJohnGIS
828
edited Nov 20 '18 at 10:12
Eugene Mihaylin
9681424
edited Nov 20 '18 at 10:12
Eugene Mihaylin
9681424
edited Nov 20 '18 at 10:12
Eugene Mihaylin
9681424
9681424
asked Nov 20 '18 at 9:47
JohnGISJohnGIS
828
asked Nov 20 '18 at 9:47
JohnGISJohnGIS
828
asked Nov 20 '18 at 9:47
JohnGISJohnGIS
828
828
What is the initial value ofesclatedPrice?
– Gary Thomas
Nov 20 '18 at 9:51
add a comment |
What is the initial value ofesclatedPrice?
– Gary Thomas
Nov 20 '18 at 9:51
What is the initial value of
esclatedPrice?– Gary Thomas
Nov 20 '18 at 9:51
What is the initial value of
esclatedPrice?– Gary Thomas
Nov 20 '18 at 9:51
add a comment |
7 Answers
7
active
oldest
votes
1
In your loop, you just need to add a variable sum that will add the value of annualCostA in each iteration like so:
var sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease)
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
sum += annualCostA // add the annualCostA value in each iteration
console.log("annualCostA= " + annualCostA);
}
console.log(sum); //total sum
answered Nov 20 '18 at 9:55
Ahsan AliAhsan Ali
2,435821
Your solution worked perfectly for my situation. Thanks so much, it was awesome to learn about this :)
– JohnGIS
Nov 20 '18 at 14:07
add a comment |
1
You can use Array.prototype.reduce():
var sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
Code:
const rateArray = [12.100000000000001,13.310000000000002,14.641000000000004,16.105100000000004,17.715610000000005,19.487171000000007,21.43588810000001,23.579476910000015,25.937424601000018];
const sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
console.log(sumOfRateArray);answered Nov 20 '18 at 9:56
Yosvel QuinteroYosvel Quintero
11.2k42430
add a comment |
0
Add a sum variable before the loop let sum=0;
Add the element you want to sum inside the loop sum+= your_element;
Print the result console.log("Sum= "+sum);
answered Nov 20 '18 at 9:51
Kristjan KicaKristjan Kica
2,1971926
add a comment |
0
Using Array.prototype.reduce() on your rateArray variable after the loop:
var rateArray = [
936,
1029.6,
1132.56
];
var arraySum = rateArray.reduce((total, e) => total + e);
console.log(arraySum)answered Nov 20 '18 at 9:56
Gary ThomasGary Thomas
1,1351412
add a comment |
0
var numOfPeriodsCost = 10;
var annualElecIncrease = 0.1;
var consumptionA = 520;
let sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease);
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
console.log("annualCostA= " + annualCostA);
sum += annualCostA;
}
console.log('sum', sum);
answered Nov 20 '18 at 9:56
Eugene MihaylinEugene Mihaylin
9681424
add a comment |
0
The following is the forEach approach:
let numbers = [1, 2, 3, 4];
let sum = 0;
numbers.forEach((item, index)=>{sum= sum + item;});
document.write("Sum: " + sum);
Test: link
Doc: link
answered Nov 20 '18 at 9:59
Tu.maTu.ma
807219
add a comment |
0
I think there is something wrong with your yearly calculation, should it be consumption + (years*increase*consumption)?
You can map an array of 0-numOfPeriodsCost to yearly costs and reduce that to an array containing costs for that year and total until that year. Then map those values into objects containing total and year:
const numOfPeriodsCost = 10;
const annualElecIncrease = 0.1;
const consumptionA = 520;
console.log(
[...new Array(numOfPeriodsCost)]
.map(
(_, period) =>
consumptionA +
period * annualElecIncrease * consumptionA,
)
.reduce(
([sum, result], item) => [
sum + item,
result.concat([[sum + item, item]]),
],
[0, ],
)[1]
.map(([total, year]) => ({ total, year })),
);answered Nov 20 '18 at 10:26
HMRHMR
13.8k113898
add a comment |
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7 Answers
7
active
oldest
votes
7 Answers
7
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
In your loop, you just need to add a variable sum that will add the value of annualCostA in each iteration like so:
var sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease)
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
sum += annualCostA // add the annualCostA value in each iteration
console.log("annualCostA= " + annualCostA);
}
console.log(sum); //total sum
answered Nov 20 '18 at 9:55
Ahsan AliAhsan Ali
2,435821
Your solution worked perfectly for my situation. Thanks so much, it was awesome to learn about this :)
– JohnGIS
Nov 20 '18 at 14:07
add a comment |
1
In your loop, you just need to add a variable sum that will add the value of annualCostA in each iteration like so:
var sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease)
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
sum += annualCostA // add the annualCostA value in each iteration
console.log("annualCostA= " + annualCostA);
}
console.log(sum); //total sum
answered Nov 20 '18 at 9:55
Ahsan AliAhsan Ali
2,435821
Your solution worked perfectly for my situation. Thanks so much, it was awesome to learn about this :)
– JohnGIS
Nov 20 '18 at 14:07
add a comment |
1
1
1
In your loop, you just need to add a variable sum that will add the value of annualCostA in each iteration like so:
var sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease)
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
sum += annualCostA // add the annualCostA value in each iteration
console.log("annualCostA= " + annualCostA);
}
console.log(sum); //total sum
answered Nov 20 '18 at 9:55
Ahsan AliAhsan Ali
2,435821
In your loop, you just need to add a variable sum that will add the value of annualCostA in each iteration like so:
var sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease)
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
sum += annualCostA // add the annualCostA value in each iteration
console.log("annualCostA= " + annualCostA);
}
console.log(sum); //total sum
answered Nov 20 '18 at 9:55
Ahsan AliAhsan Ali
2,435821
answered Nov 20 '18 at 9:55
Ahsan AliAhsan Ali
2,435821
answered Nov 20 '18 at 9:55
Ahsan AliAhsan Ali
2,435821
answered Nov 20 '18 at 9:55
Ahsan AliAhsan Ali
2,435821
2,435821
Your solution worked perfectly for my situation. Thanks so much, it was awesome to learn about this :)
– JohnGIS
Nov 20 '18 at 14:07
add a comment |
Your solution worked perfectly for my situation. Thanks so much, it was awesome to learn about this :)
– JohnGIS
Nov 20 '18 at 14:07
Your solution worked perfectly for my situation. Thanks so much, it was awesome to learn about this :)
– JohnGIS
Nov 20 '18 at 14:07
Your solution worked perfectly for my situation. Thanks so much, it was awesome to learn about this :)
– JohnGIS
Nov 20 '18 at 14:07
add a comment |
1
You can use Array.prototype.reduce():
var sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
Code:
const rateArray = [12.100000000000001,13.310000000000002,14.641000000000004,16.105100000000004,17.715610000000005,19.487171000000007,21.43588810000001,23.579476910000015,25.937424601000018];
const sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
console.log(sumOfRateArray);answered Nov 20 '18 at 9:56
Yosvel QuinteroYosvel Quintero
11.2k42430
add a comment |
1
You can use Array.prototype.reduce():
var sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
Code:
const rateArray = [12.100000000000001,13.310000000000002,14.641000000000004,16.105100000000004,17.715610000000005,19.487171000000007,21.43588810000001,23.579476910000015,25.937424601000018];
const sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
console.log(sumOfRateArray);answered Nov 20 '18 at 9:56
Yosvel QuinteroYosvel Quintero
11.2k42430
add a comment |
1
1
1
You can use Array.prototype.reduce():
var sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
Code:
const rateArray = [12.100000000000001,13.310000000000002,14.641000000000004,16.105100000000004,17.715610000000005,19.487171000000007,21.43588810000001,23.579476910000015,25.937424601000018];
const sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
console.log(sumOfRateArray);answered Nov 20 '18 at 9:56
Yosvel QuinteroYosvel Quintero
11.2k42430
You can use Array.prototype.reduce():
var sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
Code:
const rateArray = [12.100000000000001,13.310000000000002,14.641000000000004,16.105100000000004,17.715610000000005,19.487171000000007,21.43588810000001,23.579476910000015,25.937424601000018];
const sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
console.log(sumOfRateArray);const rateArray = [12.100000000000001,13.310000000000002,14.641000000000004,16.105100000000004,17.715610000000005,19.487171000000007,21.43588810000001,23.579476910000015,25.937424601000018];
const sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
console.log(sumOfRateArray);const rateArray = [12.100000000000001,13.310000000000002,14.641000000000004,16.105100000000004,17.715610000000005,19.487171000000007,21.43588810000001,23.579476910000015,25.937424601000018];
const sumOfRateArray = rateArray.reduce((a, c) => a + c, 0);
console.log(sumOfRateArray);answered Nov 20 '18 at 9:56
Yosvel QuinteroYosvel Quintero
11.2k42430
edited Nov 24 '18 at 2:42
answered Nov 20 '18 at 9:56
Yosvel QuinteroYosvel Quintero
11.2k42430
answered Nov 20 '18 at 9:56
Yosvel QuinteroYosvel Quintero
11.2k42430
answered Nov 20 '18 at 9:56
Yosvel QuinteroYosvel Quintero
11.2k42430
11.2k42430
add a comment |
add a comment |
0
Add a sum variable before the loop let sum=0;
Add the element you want to sum inside the loop sum+= your_element;
Print the result console.log("Sum= "+sum);
answered Nov 20 '18 at 9:51
Kristjan KicaKristjan Kica
2,1971926
add a comment |
0
Add a sum variable before the loop let sum=0;
Add the element you want to sum inside the loop sum+= your_element;
Print the result console.log("Sum= "+sum);
answered Nov 20 '18 at 9:51
Kristjan KicaKristjan Kica
2,1971926
add a comment |
0
0
0
Add a sum variable before the loop let sum=0;
Add the element you want to sum inside the loop sum+= your_element;
Print the result console.log("Sum= "+sum);
answered Nov 20 '18 at 9:51
Kristjan KicaKristjan Kica
2,1971926
Add a sum variable before the loop let sum=0;
Add the element you want to sum inside the loop sum+= your_element;
Print the result console.log("Sum= "+sum);
answered Nov 20 '18 at 9:51
Kristjan KicaKristjan Kica
2,1971926
answered Nov 20 '18 at 9:51
Kristjan KicaKristjan Kica
2,1971926
answered Nov 20 '18 at 9:51
Kristjan KicaKristjan Kica
2,1971926
answered Nov 20 '18 at 9:51
Kristjan KicaKristjan Kica
2,1971926
2,1971926
add a comment |
add a comment |
0
Using Array.prototype.reduce() on your rateArray variable after the loop:
var rateArray = [
936,
1029.6,
1132.56
];
var arraySum = rateArray.reduce((total, e) => total + e);
console.log(arraySum)answered Nov 20 '18 at 9:56
Gary ThomasGary Thomas
1,1351412
add a comment |
0
Using Array.prototype.reduce() on your rateArray variable after the loop:
var rateArray = [
936,
1029.6,
1132.56
];
var arraySum = rateArray.reduce((total, e) => total + e);
console.log(arraySum)answered Nov 20 '18 at 9:56
Gary ThomasGary Thomas
1,1351412
add a comment |
0
0
0
Using Array.prototype.reduce() on your rateArray variable after the loop:
var rateArray = [
936,
1029.6,
1132.56
];
var arraySum = rateArray.reduce((total, e) => total + e);
console.log(arraySum)answered Nov 20 '18 at 9:56
Gary ThomasGary Thomas
1,1351412
Using Array.prototype.reduce() on your rateArray variable after the loop:
var rateArray = [
936,
1029.6,
1132.56
];
var arraySum = rateArray.reduce((total, e) => total + e);
console.log(arraySum)var rateArray = [
936,
1029.6,
1132.56
];
var arraySum = rateArray.reduce((total, e) => total + e);
console.log(arraySum)var rateArray = [
936,
1029.6,
1132.56
];
var arraySum = rateArray.reduce((total, e) => total + e);
console.log(arraySum)answered Nov 20 '18 at 9:56
Gary ThomasGary Thomas
1,1351412
answered Nov 20 '18 at 9:56
Gary ThomasGary Thomas
1,1351412
answered Nov 20 '18 at 9:56
Gary ThomasGary Thomas
1,1351412
answered Nov 20 '18 at 9:56
Gary ThomasGary Thomas
1,1351412
1,1351412
add a comment |
add a comment |
0
var numOfPeriodsCost = 10;
var annualElecIncrease = 0.1;
var consumptionA = 520;
let sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease);
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
console.log("annualCostA= " + annualCostA);
sum += annualCostA;
}
console.log('sum', sum);
answered Nov 20 '18 at 9:56
Eugene MihaylinEugene Mihaylin
9681424
add a comment |
0
var numOfPeriodsCost = 10;
var annualElecIncrease = 0.1;
var consumptionA = 520;
let sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease);
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
console.log("annualCostA= " + annualCostA);
sum += annualCostA;
}
console.log('sum', sum);
answered Nov 20 '18 at 9:56
Eugene MihaylinEugene Mihaylin
9681424
add a comment |
0
0
0
var numOfPeriodsCost = 10;
var annualElecIncrease = 0.1;
var consumptionA = 520;
let sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease);
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
console.log("annualCostA= " + annualCostA);
sum += annualCostA;
}
console.log('sum', sum);
answered Nov 20 '18 at 9:56
Eugene MihaylinEugene Mihaylin
9681424
var numOfPeriodsCost = 10;
var annualElecIncrease = 0.1;
var consumptionA = 520;
let sum = 0;
for (i = 0; i < numOfPeriodsCost; i++) {
esclatedPrice *= (1 + annualElecIncrease);
rateArray.push(esclatedPrice);
annualCostA = consumptionA * rateArray[i]
console.log("annualCostA= " + annualCostA);
sum += annualCostA;
}
console.log('sum', sum);
answered Nov 20 '18 at 9:56
Eugene MihaylinEugene Mihaylin
9681424
answered Nov 20 '18 at 9:56
Eugene MihaylinEugene Mihaylin
9681424
answered Nov 20 '18 at 9:56
Eugene MihaylinEugene Mihaylin
9681424
answered Nov 20 '18 at 9:56
Eugene MihaylinEugene Mihaylin
9681424
9681424
add a comment |
add a comment |
0
The following is the forEach approach:
let numbers = [1, 2, 3, 4];
let sum = 0;
numbers.forEach((item, index)=>{sum= sum + item;});
document.write("Sum: " + sum);
Test: link
Doc: link
answered Nov 20 '18 at 9:59
Tu.maTu.ma
807219
add a comment |
0
The following is the forEach approach:
let numbers = [1, 2, 3, 4];
let sum = 0;
numbers.forEach((item, index)=>{sum= sum + item;});
document.write("Sum: " + sum);
Test: link
Doc: link
answered Nov 20 '18 at 9:59
Tu.maTu.ma
807219
add a comment |
0
0
0
The following is the forEach approach:
let numbers = [1, 2, 3, 4];
let sum = 0;
numbers.forEach((item, index)=>{sum= sum + item;});
document.write("Sum: " + sum);
Test: link
Doc: link
answered Nov 20 '18 at 9:59
Tu.maTu.ma
807219
The following is the forEach approach:
let numbers = [1, 2, 3, 4];
let sum = 0;
numbers.forEach((item, index)=>{sum= sum + item;});
document.write("Sum: " + sum);
Test: link
Doc: link
answered Nov 20 '18 at 9:59
Tu.maTu.ma
807219
answered Nov 20 '18 at 9:59
Tu.maTu.ma
807219
answered Nov 20 '18 at 9:59
Tu.maTu.ma
807219
answered Nov 20 '18 at 9:59
Tu.maTu.ma
807219
807219
add a comment |
add a comment |
0
I think there is something wrong with your yearly calculation, should it be consumption + (years*increase*consumption)?
You can map an array of 0-numOfPeriodsCost to yearly costs and reduce that to an array containing costs for that year and total until that year. Then map those values into objects containing total and year:
const numOfPeriodsCost = 10;
const annualElecIncrease = 0.1;
const consumptionA = 520;
console.log(
[...new Array(numOfPeriodsCost)]
.map(
(_, period) =>
consumptionA +
period * annualElecIncrease * consumptionA,
)
.reduce(
([sum, result], item) => [
sum + item,
result.concat([[sum + item, item]]),
],
[0, ],
)[1]
.map(([total, year]) => ({ total, year })),
);answered Nov 20 '18 at 10:26
HMRHMR
13.8k113898
add a comment |
0
I think there is something wrong with your yearly calculation, should it be consumption + (years*increase*consumption)?
You can map an array of 0-numOfPeriodsCost to yearly costs and reduce that to an array containing costs for that year and total until that year. Then map those values into objects containing total and year:
const numOfPeriodsCost = 10;
const annualElecIncrease = 0.1;
const consumptionA = 520;
console.log(
[...new Array(numOfPeriodsCost)]
.map(
(_, period) =>
consumptionA +
period * annualElecIncrease * consumptionA,
)
.reduce(
([sum, result], item) => [
sum + item,
result.concat([[sum + item, item]]),
],
[0, ],
)[1]
.map(([total, year]) => ({ total, year })),
);answered Nov 20 '18 at 10:26
HMRHMR
13.8k113898
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0
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I think there is something wrong with your yearly calculation, should it be consumption + (years*increase*consumption)?
You can map an array of 0-numOfPeriodsCost to yearly costs and reduce that to an array containing costs for that year and total until that year. Then map those values into objects containing total and year:
const numOfPeriodsCost = 10;
const annualElecIncrease = 0.1;
const consumptionA = 520;
console.log(
[...new Array(numOfPeriodsCost)]
.map(
(_, period) =>
consumptionA +
period * annualElecIncrease * consumptionA,
)
.reduce(
([sum, result], item) => [
sum + item,
result.concat([[sum + item, item]]),
],
[0, ],
)[1]
.map(([total, year]) => ({ total, year })),
);answered Nov 20 '18 at 10:26
HMRHMR
13.8k113898
I think there is something wrong with your yearly calculation, should it be consumption + (years*increase*consumption)?
You can map an array of 0-numOfPeriodsCost to yearly costs and reduce that to an array containing costs for that year and total until that year. Then map those values into objects containing total and year:
const numOfPeriodsCost = 10;
const annualElecIncrease = 0.1;
const consumptionA = 520;
console.log(
[...new Array(numOfPeriodsCost)]
.map(
(_, period) =>
consumptionA +
period * annualElecIncrease * consumptionA,
)
.reduce(
([sum, result], item) => [
sum + item,
result.concat([[sum + item, item]]),
],
[0, ],
)[1]
.map(([total, year]) => ({ total, year })),
);const numOfPeriodsCost = 10;
const annualElecIncrease = 0.1;
const consumptionA = 520;
console.log(
[...new Array(numOfPeriodsCost)]
.map(
(_, period) =>
consumptionA +
period * annualElecIncrease * consumptionA,
)
.reduce(
([sum, result], item) => [
sum + item,
result.concat([[sum + item, item]]),
],
[0, ],
)[1]
.map(([total, year]) => ({ total, year })),
);const numOfPeriodsCost = 10;
const annualElecIncrease = 0.1;
const consumptionA = 520;
console.log(
[...new Array(numOfPeriodsCost)]
.map(
(_, period) =>
consumptionA +
period * annualElecIncrease * consumptionA,
)
.reduce(
([sum, result], item) => [
sum + item,
result.concat([[sum + item, item]]),
],
[0, ],
)[1]
.map(([total, year]) => ({ total, year })),
);answered Nov 20 '18 at 10:26
HMRHMR
13.8k113898
answered Nov 20 '18 at 10:26
HMRHMR
13.8k113898
answered Nov 20 '18 at 10:26
HMRHMR
13.8k113898
answered Nov 20 '18 at 10:26
HMRHMR
13.8k113898
13.8k113898
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What is the initial value of
esclatedPrice?– Gary Thomas
Nov 20 '18 at 9:51