If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
up vote
-3
down vote
favorite
If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
$v$ and $w$ are vectors, they aren't given. I have no idea how to do this and apparently it's asked on a quiz as a "surprise" question.
multivariable-calculus vectors 3d
edited Nov 19 at 5:10
Brahadeesh
5,97842159
asked Nov 19 at 3:31
ufotink
43
add a comment |
up vote
-3
down vote
favorite
If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
$v$ and $w$ are vectors, they aren't given. I have no idea how to do this and apparently it's asked on a quiz as a "surprise" question.
multivariable-calculus vectors 3d
edited Nov 19 at 5:10
Brahadeesh
5,97842159
asked Nov 19 at 3:31
ufotink
43
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
Nov 19 at 3:46
add a comment |
up vote
-3
down vote
favorite
up vote
-3
down vote
favorite
If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
$v$ and $w$ are vectors, they aren't given. I have no idea how to do this and apparently it's asked on a quiz as a "surprise" question.
multivariable-calculus vectors 3d
edited Nov 19 at 5:10
Brahadeesh
5,97842159
asked Nov 19 at 3:31
ufotink
43
If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
$v$ and $w$ are vectors, they aren't given. I have no idea how to do this and apparently it's asked on a quiz as a "surprise" question.
multivariable-calculus vectors 3d
multivariable-calculus vectors 3d
edited Nov 19 at 5:10
Brahadeesh
5,97842159
asked Nov 19 at 3:31
ufotink
43
edited Nov 19 at 5:10
Brahadeesh
5,97842159
asked Nov 19 at 3:31
ufotink
43
edited Nov 19 at 5:10
Brahadeesh
5,97842159
edited Nov 19 at 5:10
Brahadeesh
5,97842159
edited Nov 19 at 5:10
Brahadeesh
5,97842159
5,97842159
asked Nov 19 at 3:31
ufotink
43
asked Nov 19 at 3:31
ufotink
43
asked Nov 19 at 3:31
ufotink
43
43
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
Nov 19 at 3:46
add a comment |
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
Nov 19 at 3:46
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
Nov 19 at 3:46
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
Nov 19 at 3:46
add a comment |
1 Answer
1
active
oldest
votes
up vote
2
down vote
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
answered Nov 19 at 3:36
Eevee Trainer
2,179220
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
Nov 19 at 3:37
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
Nov 19 at 3:38
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
answered Nov 19 at 3:36
Eevee Trainer
2,179220
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
Nov 19 at 3:37
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
Nov 19 at 3:38
add a comment |
up vote
2
down vote
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
answered Nov 19 at 3:36
Eevee Trainer
2,179220
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
Nov 19 at 3:37
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
Nov 19 at 3:38
add a comment |
up vote
2
down vote
up vote
2
down vote
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
answered Nov 19 at 3:36
Eevee Trainer
2,179220
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
answered Nov 19 at 3:36
Eevee Trainer
2,179220
answered Nov 19 at 3:36
Eevee Trainer
2,179220
answered Nov 19 at 3:36
Eevee Trainer
2,179220
answered Nov 19 at 3:36
Eevee Trainer
2,179220
2,179220
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
Nov 19 at 3:37
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
Nov 19 at 3:38
add a comment |
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
Nov 19 at 3:37
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
Nov 19 at 3:38
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
Nov 19 at 3:37
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
Nov 19 at 3:37
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
Nov 19 at 3:38
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
Nov 19 at 3:38
add a comment |
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The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
Nov 19 at 3:46