With server.py running:

from flask import Flask, request, Response, json



app = Flask(__name__)



@app.route('/test', methods=['GET','POST'])

def route():  

    open_read =  open(r'C:log.log').read()

    dict_data = {'str': str(), 'list': list(), 'dict': dict()}

    return Response(json.dumps(dict_data), mimetype='text/plain')



if __name__ == '__main__':

    app.run('0.0.0.0', 5000)

I would like to send a client request and receive back the open_read and dict_data variables data.

Is there a way to return both variables to the client using flask.Response object?

client:

import json, requests  

response = requests.post('http://127.0.0.1:5000/test')

print '...response: %s' % response.json(), type(response.json())

FULLY WORKING SOLUTION IS POSTED BELOW:

Server:

from flask import Flask, request, Response, json

import base64



app = Flask(__name__)



@app.route('/test', methods=['GET','POST'])

def route():  

    open_read =  open('my_file.zip').read()

    encoded = base64.b64encode(open_read)

    dict_data = {'str': str(), 'list': list(), 'dict': dict(), 'encoded': encoded}

    return Response(json.dumps(dict_data), mimetype='text/plain')



if __name__ == '__main__':

    app.run('0.0.0.0', 5000)

Client:

response = requests.post('http://127.0.0.1:5000/test')

response_json = response.json()

encoded = response_json['encoded']



decoded = base64.b64decode(encoded)



dst_filepath = "my_zip.zip"

with open(dst_filepath, 'w') as _file:

    _file.write(decoded)