Expected value when involving intangible factors











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Rebecca and James play the following game. James pays her 1.50 for her to roll two dice. If the sum of these two dice is exactly 6, then she will pay him of 10.50 and return him the cost of 1.50 he paid her to roll the dice. Otherwise, Rebecca will keep the 1.50. At this point the expected value is easy: One just take $$frac{31}{35} times (-1.5)+frac{5}{36}times 10.5=frac{1}{6}$$



However the question now ask, if intangible factors are included in "expectation", and say that : Before betting James only has 1.50, which he needs to take a train home. If he has to walk home, the unhappiness is equivalent to losing 15 cents.



Now I am a bit confused with this addition. Should I just naively use $frac{1}{6} - 0.15$ or do I need to consider his loss as $-1.5-0.15 = -1.65$?










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  • The second one, since he only is unhappy if he looses his dollar-fifty. By the way it would be easier to understand your work if you stated what you were taking the expectation of. For example it would help to define $X$ as the earnings of James (not the earnings of Rebecca), and then you are computing $E[X]$. So then $X = -1.5-.15$ if James looses, and $X=10.5$ if he wins.
    – Michael
    Nov 16 at 17:43

















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0
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Rebecca and James play the following game. James pays her 1.50 for her to roll two dice. If the sum of these two dice is exactly 6, then she will pay him of 10.50 and return him the cost of 1.50 he paid her to roll the dice. Otherwise, Rebecca will keep the 1.50. At this point the expected value is easy: One just take $$frac{31}{35} times (-1.5)+frac{5}{36}times 10.5=frac{1}{6}$$



However the question now ask, if intangible factors are included in "expectation", and say that : Before betting James only has 1.50, which he needs to take a train home. If he has to walk home, the unhappiness is equivalent to losing 15 cents.



Now I am a bit confused with this addition. Should I just naively use $frac{1}{6} - 0.15$ or do I need to consider his loss as $-1.5-0.15 = -1.65$?










share|cite|improve this question






















  • The second one, since he only is unhappy if he looses his dollar-fifty. By the way it would be easier to understand your work if you stated what you were taking the expectation of. For example it would help to define $X$ as the earnings of James (not the earnings of Rebecca), and then you are computing $E[X]$. So then $X = -1.5-.15$ if James looses, and $X=10.5$ if he wins.
    – Michael
    Nov 16 at 17:43















up vote
0
down vote

favorite









up vote
0
down vote

favorite











Rebecca and James play the following game. James pays her 1.50 for her to roll two dice. If the sum of these two dice is exactly 6, then she will pay him of 10.50 and return him the cost of 1.50 he paid her to roll the dice. Otherwise, Rebecca will keep the 1.50. At this point the expected value is easy: One just take $$frac{31}{35} times (-1.5)+frac{5}{36}times 10.5=frac{1}{6}$$



However the question now ask, if intangible factors are included in "expectation", and say that : Before betting James only has 1.50, which he needs to take a train home. If he has to walk home, the unhappiness is equivalent to losing 15 cents.



Now I am a bit confused with this addition. Should I just naively use $frac{1}{6} - 0.15$ or do I need to consider his loss as $-1.5-0.15 = -1.65$?










share|cite|improve this question













Rebecca and James play the following game. James pays her 1.50 for her to roll two dice. If the sum of these two dice is exactly 6, then she will pay him of 10.50 and return him the cost of 1.50 he paid her to roll the dice. Otherwise, Rebecca will keep the 1.50. At this point the expected value is easy: One just take $$frac{31}{35} times (-1.5)+frac{5}{36}times 10.5=frac{1}{6}$$



However the question now ask, if intangible factors are included in "expectation", and say that : Before betting James only has 1.50, which he needs to take a train home. If he has to walk home, the unhappiness is equivalent to losing 15 cents.



Now I am a bit confused with this addition. Should I just naively use $frac{1}{6} - 0.15$ or do I need to consider his loss as $-1.5-0.15 = -1.65$?







probability expected-value






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asked Nov 16 at 17:12









ilovewt

932517




932517












  • The second one, since he only is unhappy if he looses his dollar-fifty. By the way it would be easier to understand your work if you stated what you were taking the expectation of. For example it would help to define $X$ as the earnings of James (not the earnings of Rebecca), and then you are computing $E[X]$. So then $X = -1.5-.15$ if James looses, and $X=10.5$ if he wins.
    – Michael
    Nov 16 at 17:43




















  • The second one, since he only is unhappy if he looses his dollar-fifty. By the way it would be easier to understand your work if you stated what you were taking the expectation of. For example it would help to define $X$ as the earnings of James (not the earnings of Rebecca), and then you are computing $E[X]$. So then $X = -1.5-.15$ if James looses, and $X=10.5$ if he wins.
    – Michael
    Nov 16 at 17:43


















The second one, since he only is unhappy if he looses his dollar-fifty. By the way it would be easier to understand your work if you stated what you were taking the expectation of. For example it would help to define $X$ as the earnings of James (not the earnings of Rebecca), and then you are computing $E[X]$. So then $X = -1.5-.15$ if James looses, and $X=10.5$ if he wins.
– Michael
Nov 16 at 17:43






The second one, since he only is unhappy if he looses his dollar-fifty. By the way it would be easier to understand your work if you stated what you were taking the expectation of. For example it would help to define $X$ as the earnings of James (not the earnings of Rebecca), and then you are computing $E[X]$. So then $X = -1.5-.15$ if James looses, and $X=10.5$ if he wins.
– Michael
Nov 16 at 17:43

















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