How to insert a big brace, arrows crossing etc
As english is not my primary language, I don't know how describe my problem the right way. But I have a picture of what I want to type.
This is how far I have made it:
documentclass[a4paper]{article}
usepackage{tikz-cd}
begin{document}
begin{tikzcd}
Cr & 3downarrow arrow[rd] & 2Cr: & 6downarrow \
C & 2uparrow arrow[ru]& 3C: & 6uparrow
end{tikzcd}
end{document}
Background: At my school we use this to show how to align(?) a redox-reaction.
tikz-cd
add a comment |
As english is not my primary language, I don't know how describe my problem the right way. But I have a picture of what I want to type.
This is how far I have made it:
documentclass[a4paper]{article}
usepackage{tikz-cd}
begin{document}
begin{tikzcd}
Cr & 3downarrow arrow[rd] & 2Cr: & 6downarrow \
C & 2uparrow arrow[ru]& 3C: & 6uparrow
end{tikzcd}
end{document}
Background: At my school we use this to show how to align(?) a redox-reaction.
tikz-cd
1
This won't help your problem, but it's usually best if you include everything we need to copy and paste to get a working example. In this case, I think that would mean just adding a handful of lines:documentclass{article}
/usepackage{tikz}
/tikzlibrary{tikzcd}
/begin{document}
, and thenend{article}
.
– Teepeemm
Oct 28 '16 at 11:53
add a comment |
As english is not my primary language, I don't know how describe my problem the right way. But I have a picture of what I want to type.
This is how far I have made it:
documentclass[a4paper]{article}
usepackage{tikz-cd}
begin{document}
begin{tikzcd}
Cr & 3downarrow arrow[rd] & 2Cr: & 6downarrow \
C & 2uparrow arrow[ru]& 3C: & 6uparrow
end{tikzcd}
end{document}
Background: At my school we use this to show how to align(?) a redox-reaction.
tikz-cd
As english is not my primary language, I don't know how describe my problem the right way. But I have a picture of what I want to type.
This is how far I have made it:
documentclass[a4paper]{article}
usepackage{tikz-cd}
begin{document}
begin{tikzcd}
Cr & 3downarrow arrow[rd] & 2Cr: & 6downarrow \
C & 2uparrow arrow[ru]& 3C: & 6uparrow
end{tikzcd}
end{document}
Background: At my school we use this to show how to align(?) a redox-reaction.
tikz-cd
tikz-cd
edited Feb 26 at 10:19
Hotschke
2,22321841
2,22321841
asked Oct 28 '16 at 11:40
Jens ClausenJens Clausen
233
233
1
This won't help your problem, but it's usually best if you include everything we need to copy and paste to get a working example. In this case, I think that would mean just adding a handful of lines:documentclass{article}
/usepackage{tikz}
/tikzlibrary{tikzcd}
/begin{document}
, and thenend{article}
.
– Teepeemm
Oct 28 '16 at 11:53
add a comment |
1
This won't help your problem, but it's usually best if you include everything we need to copy and paste to get a working example. In this case, I think that would mean just adding a handful of lines:documentclass{article}
/usepackage{tikz}
/tikzlibrary{tikzcd}
/begin{document}
, and thenend{article}
.
– Teepeemm
Oct 28 '16 at 11:53
1
1
This won't help your problem, but it's usually best if you include everything we need to copy and paste to get a working example. In this case, I think that would mean just adding a handful of lines:
documentclass{article}
/ usepackage{tikz}
/ tikzlibrary{tikzcd}
/ begin{document}
, and then end{article}
.– Teepeemm
Oct 28 '16 at 11:53
This won't help your problem, but it's usually best if you include everything we need to copy and paste to get a working example. In this case, I think that would mean just adding a handful of lines:
documentclass{article}
/ usepackage{tikz}
/ tikzlibrary{tikzcd}
/ begin{document}
, and then end{article}
.– Teepeemm
Oct 28 '16 at 11:53
add a comment |
3 Answers
3
active
oldest
votes
If you would like to think of the reaction as an equation rather than a diagram, you can also use tikz marks to do that:
documentclass{article}
usepackage{amsmath, tikz}
usetikzlibrary{decorations.pathreplacing, calc}
newcommand{tikzmathnode}[2]{tikz[remember picture, baseline]{node[inner sep=1pt, outer sep=0pt, anchor=base, minimum height=1em] (#1) {$displaystyle #2$};}}
newcommand{redoxdraw}{
begin{tikzpicture}[overlay, remember picture]
draw[decoration = {brace, amplitude=.3em, raise=.1em}, decorate] (redox1.north east) -- (redox2.south east);
draw[-to, out=0, in=180] ([xshift=.8em] redox1.east) to ([xshift=2.5em] redox2.east);
draw[-to, out=0, in=180] ([xshift=.8em] redox2.east) to ([xshift=2.5em] redox1.east);
end{tikzpicture}
}
newcommand{redoxfirst}[1]{tikzmathnode{redox1}{#1}qquad}
newcommand{redoxsecond}[1]{tikzmathnode{redox2}{#1}qquadredoxdraw}
begin{document}
begin{equation*}
begin{array}{rrrr}
Cr: & redoxfirst{3downarrow} & 2Cr: & 6downarrow\[.3em]
C: & redoxsecond{2uparrow} & 3C: & 6uparrow
end{array}
end{equation*}
end{document}
You can of course play around with the spacing or hard-code less of the format. You could also make redoxfirst
and redoxsecond
take an optional argument to name the reaction, so as to allow multiple reactions in the same line.
add a comment |
Try with tikzmark
:
documentclass[a4paper]{article}
usepackage{tikz}
usepackage{tikz-cd}
usetikzlibrary{decorations.pathreplacing}
usetikzlibrary{calc,tikzmark}
begin{document}
begin{tikzcd}
Cr: & 3downarrow tikzmark{bracebegin} hspace{4pt} arrow[rd] & hspace{4pt} 2Cr: & 6downarrow \
C: & 2uparrow tikzmark{braceend} hspace{4pt} arrow[ru] & hspace{4pt} 3C: & 6uparrow
end{tikzcd}
begin{tikzpicture}[overlay,remember picture]
draw[decorate,decoration={brace}] ( $ (pic cs:bracebegin) +(0, 9pt) $ ) -- ( $ (pic cs:braceend) -(0, 4pt) $ );
end{tikzpicture}%
end{document}
add a comment |
documentclass[a4paper]{article}
usepackage{tikz}
usetikzlibrary{decorations.pathreplacing}
begin{document}
begin{tikzpicture}[node distance = 3cm]
node at (-1,1){Cr: 3};
draw[->](-0.5,1.1)--(-0.5,0.8);
node at (-1,-1){C: 2};
draw[->](-0.5,-1.1)--(-0.5,-0.8);
draw [->] (0,1) --(1,-1);
draw [->] (0,-1) -- (1,1);
draw[decorate,decoration={brace}] (-0.3,1.2) -- (-0.3,-1.2);
node at (1.7, 1.0){2 Cr: 6};
node at (1.7, -1.0){3Cr: 6};
draw[->](2.4,-1.1)--(2.4,-0.9);
draw[->](2.4,1.1)--(2.4,0.9);
end{tikzpicture}
end{document}
I have edited your minimal working example to make it compilable and I've used yourdraw[decorate,decoration={brace}]
in my answer :)
– CarLaTeX
Oct 30 '16 at 7:02
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you would like to think of the reaction as an equation rather than a diagram, you can also use tikz marks to do that:
documentclass{article}
usepackage{amsmath, tikz}
usetikzlibrary{decorations.pathreplacing, calc}
newcommand{tikzmathnode}[2]{tikz[remember picture, baseline]{node[inner sep=1pt, outer sep=0pt, anchor=base, minimum height=1em] (#1) {$displaystyle #2$};}}
newcommand{redoxdraw}{
begin{tikzpicture}[overlay, remember picture]
draw[decoration = {brace, amplitude=.3em, raise=.1em}, decorate] (redox1.north east) -- (redox2.south east);
draw[-to, out=0, in=180] ([xshift=.8em] redox1.east) to ([xshift=2.5em] redox2.east);
draw[-to, out=0, in=180] ([xshift=.8em] redox2.east) to ([xshift=2.5em] redox1.east);
end{tikzpicture}
}
newcommand{redoxfirst}[1]{tikzmathnode{redox1}{#1}qquad}
newcommand{redoxsecond}[1]{tikzmathnode{redox2}{#1}qquadredoxdraw}
begin{document}
begin{equation*}
begin{array}{rrrr}
Cr: & redoxfirst{3downarrow} & 2Cr: & 6downarrow\[.3em]
C: & redoxsecond{2uparrow} & 3C: & 6uparrow
end{array}
end{equation*}
end{document}
You can of course play around with the spacing or hard-code less of the format. You could also make redoxfirst
and redoxsecond
take an optional argument to name the reaction, so as to allow multiple reactions in the same line.
add a comment |
If you would like to think of the reaction as an equation rather than a diagram, you can also use tikz marks to do that:
documentclass{article}
usepackage{amsmath, tikz}
usetikzlibrary{decorations.pathreplacing, calc}
newcommand{tikzmathnode}[2]{tikz[remember picture, baseline]{node[inner sep=1pt, outer sep=0pt, anchor=base, minimum height=1em] (#1) {$displaystyle #2$};}}
newcommand{redoxdraw}{
begin{tikzpicture}[overlay, remember picture]
draw[decoration = {brace, amplitude=.3em, raise=.1em}, decorate] (redox1.north east) -- (redox2.south east);
draw[-to, out=0, in=180] ([xshift=.8em] redox1.east) to ([xshift=2.5em] redox2.east);
draw[-to, out=0, in=180] ([xshift=.8em] redox2.east) to ([xshift=2.5em] redox1.east);
end{tikzpicture}
}
newcommand{redoxfirst}[1]{tikzmathnode{redox1}{#1}qquad}
newcommand{redoxsecond}[1]{tikzmathnode{redox2}{#1}qquadredoxdraw}
begin{document}
begin{equation*}
begin{array}{rrrr}
Cr: & redoxfirst{3downarrow} & 2Cr: & 6downarrow\[.3em]
C: & redoxsecond{2uparrow} & 3C: & 6uparrow
end{array}
end{equation*}
end{document}
You can of course play around with the spacing or hard-code less of the format. You could also make redoxfirst
and redoxsecond
take an optional argument to name the reaction, so as to allow multiple reactions in the same line.
add a comment |
If you would like to think of the reaction as an equation rather than a diagram, you can also use tikz marks to do that:
documentclass{article}
usepackage{amsmath, tikz}
usetikzlibrary{decorations.pathreplacing, calc}
newcommand{tikzmathnode}[2]{tikz[remember picture, baseline]{node[inner sep=1pt, outer sep=0pt, anchor=base, minimum height=1em] (#1) {$displaystyle #2$};}}
newcommand{redoxdraw}{
begin{tikzpicture}[overlay, remember picture]
draw[decoration = {brace, amplitude=.3em, raise=.1em}, decorate] (redox1.north east) -- (redox2.south east);
draw[-to, out=0, in=180] ([xshift=.8em] redox1.east) to ([xshift=2.5em] redox2.east);
draw[-to, out=0, in=180] ([xshift=.8em] redox2.east) to ([xshift=2.5em] redox1.east);
end{tikzpicture}
}
newcommand{redoxfirst}[1]{tikzmathnode{redox1}{#1}qquad}
newcommand{redoxsecond}[1]{tikzmathnode{redox2}{#1}qquadredoxdraw}
begin{document}
begin{equation*}
begin{array}{rrrr}
Cr: & redoxfirst{3downarrow} & 2Cr: & 6downarrow\[.3em]
C: & redoxsecond{2uparrow} & 3C: & 6uparrow
end{array}
end{equation*}
end{document}
You can of course play around with the spacing or hard-code less of the format. You could also make redoxfirst
and redoxsecond
take an optional argument to name the reaction, so as to allow multiple reactions in the same line.
If you would like to think of the reaction as an equation rather than a diagram, you can also use tikz marks to do that:
documentclass{article}
usepackage{amsmath, tikz}
usetikzlibrary{decorations.pathreplacing, calc}
newcommand{tikzmathnode}[2]{tikz[remember picture, baseline]{node[inner sep=1pt, outer sep=0pt, anchor=base, minimum height=1em] (#1) {$displaystyle #2$};}}
newcommand{redoxdraw}{
begin{tikzpicture}[overlay, remember picture]
draw[decoration = {brace, amplitude=.3em, raise=.1em}, decorate] (redox1.north east) -- (redox2.south east);
draw[-to, out=0, in=180] ([xshift=.8em] redox1.east) to ([xshift=2.5em] redox2.east);
draw[-to, out=0, in=180] ([xshift=.8em] redox2.east) to ([xshift=2.5em] redox1.east);
end{tikzpicture}
}
newcommand{redoxfirst}[1]{tikzmathnode{redox1}{#1}qquad}
newcommand{redoxsecond}[1]{tikzmathnode{redox2}{#1}qquadredoxdraw}
begin{document}
begin{equation*}
begin{array}{rrrr}
Cr: & redoxfirst{3downarrow} & 2Cr: & 6downarrow\[.3em]
C: & redoxsecond{2uparrow} & 3C: & 6uparrow
end{array}
end{equation*}
end{document}
You can of course play around with the spacing or hard-code less of the format. You could also make redoxfirst
and redoxsecond
take an optional argument to name the reaction, so as to allow multiple reactions in the same line.
edited Oct 30 '16 at 13:24
answered Oct 29 '16 at 15:33
EmmaEmma
2,923717
2,923717
add a comment |
add a comment |
Try with tikzmark
:
documentclass[a4paper]{article}
usepackage{tikz}
usepackage{tikz-cd}
usetikzlibrary{decorations.pathreplacing}
usetikzlibrary{calc,tikzmark}
begin{document}
begin{tikzcd}
Cr: & 3downarrow tikzmark{bracebegin} hspace{4pt} arrow[rd] & hspace{4pt} 2Cr: & 6downarrow \
C: & 2uparrow tikzmark{braceend} hspace{4pt} arrow[ru] & hspace{4pt} 3C: & 6uparrow
end{tikzcd}
begin{tikzpicture}[overlay,remember picture]
draw[decorate,decoration={brace}] ( $ (pic cs:bracebegin) +(0, 9pt) $ ) -- ( $ (pic cs:braceend) -(0, 4pt) $ );
end{tikzpicture}%
end{document}
add a comment |
Try with tikzmark
:
documentclass[a4paper]{article}
usepackage{tikz}
usepackage{tikz-cd}
usetikzlibrary{decorations.pathreplacing}
usetikzlibrary{calc,tikzmark}
begin{document}
begin{tikzcd}
Cr: & 3downarrow tikzmark{bracebegin} hspace{4pt} arrow[rd] & hspace{4pt} 2Cr: & 6downarrow \
C: & 2uparrow tikzmark{braceend} hspace{4pt} arrow[ru] & hspace{4pt} 3C: & 6uparrow
end{tikzcd}
begin{tikzpicture}[overlay,remember picture]
draw[decorate,decoration={brace}] ( $ (pic cs:bracebegin) +(0, 9pt) $ ) -- ( $ (pic cs:braceend) -(0, 4pt) $ );
end{tikzpicture}%
end{document}
add a comment |
Try with tikzmark
:
documentclass[a4paper]{article}
usepackage{tikz}
usepackage{tikz-cd}
usetikzlibrary{decorations.pathreplacing}
usetikzlibrary{calc,tikzmark}
begin{document}
begin{tikzcd}
Cr: & 3downarrow tikzmark{bracebegin} hspace{4pt} arrow[rd] & hspace{4pt} 2Cr: & 6downarrow \
C: & 2uparrow tikzmark{braceend} hspace{4pt} arrow[ru] & hspace{4pt} 3C: & 6uparrow
end{tikzcd}
begin{tikzpicture}[overlay,remember picture]
draw[decorate,decoration={brace}] ( $ (pic cs:bracebegin) +(0, 9pt) $ ) -- ( $ (pic cs:braceend) -(0, 4pt) $ );
end{tikzpicture}%
end{document}
Try with tikzmark
:
documentclass[a4paper]{article}
usepackage{tikz}
usepackage{tikz-cd}
usetikzlibrary{decorations.pathreplacing}
usetikzlibrary{calc,tikzmark}
begin{document}
begin{tikzcd}
Cr: & 3downarrow tikzmark{bracebegin} hspace{4pt} arrow[rd] & hspace{4pt} 2Cr: & 6downarrow \
C: & 2uparrow tikzmark{braceend} hspace{4pt} arrow[ru] & hspace{4pt} 3C: & 6uparrow
end{tikzcd}
begin{tikzpicture}[overlay,remember picture]
draw[decorate,decoration={brace}] ( $ (pic cs:bracebegin) +(0, 9pt) $ ) -- ( $ (pic cs:braceend) -(0, 4pt) $ );
end{tikzpicture}%
end{document}
answered Oct 29 '16 at 15:13
CarLaTeXCarLaTeX
32.7k551135
32.7k551135
add a comment |
add a comment |
documentclass[a4paper]{article}
usepackage{tikz}
usetikzlibrary{decorations.pathreplacing}
begin{document}
begin{tikzpicture}[node distance = 3cm]
node at (-1,1){Cr: 3};
draw[->](-0.5,1.1)--(-0.5,0.8);
node at (-1,-1){C: 2};
draw[->](-0.5,-1.1)--(-0.5,-0.8);
draw [->] (0,1) --(1,-1);
draw [->] (0,-1) -- (1,1);
draw[decorate,decoration={brace}] (-0.3,1.2) -- (-0.3,-1.2);
node at (1.7, 1.0){2 Cr: 6};
node at (1.7, -1.0){3Cr: 6};
draw[->](2.4,-1.1)--(2.4,-0.9);
draw[->](2.4,1.1)--(2.4,0.9);
end{tikzpicture}
end{document}
I have edited your minimal working example to make it compilable and I've used yourdraw[decorate,decoration={brace}]
in my answer :)
– CarLaTeX
Oct 30 '16 at 7:02
add a comment |
documentclass[a4paper]{article}
usepackage{tikz}
usetikzlibrary{decorations.pathreplacing}
begin{document}
begin{tikzpicture}[node distance = 3cm]
node at (-1,1){Cr: 3};
draw[->](-0.5,1.1)--(-0.5,0.8);
node at (-1,-1){C: 2};
draw[->](-0.5,-1.1)--(-0.5,-0.8);
draw [->] (0,1) --(1,-1);
draw [->] (0,-1) -- (1,1);
draw[decorate,decoration={brace}] (-0.3,1.2) -- (-0.3,-1.2);
node at (1.7, 1.0){2 Cr: 6};
node at (1.7, -1.0){3Cr: 6};
draw[->](2.4,-1.1)--(2.4,-0.9);
draw[->](2.4,1.1)--(2.4,0.9);
end{tikzpicture}
end{document}
I have edited your minimal working example to make it compilable and I've used yourdraw[decorate,decoration={brace}]
in my answer :)
– CarLaTeX
Oct 30 '16 at 7:02
add a comment |
documentclass[a4paper]{article}
usepackage{tikz}
usetikzlibrary{decorations.pathreplacing}
begin{document}
begin{tikzpicture}[node distance = 3cm]
node at (-1,1){Cr: 3};
draw[->](-0.5,1.1)--(-0.5,0.8);
node at (-1,-1){C: 2};
draw[->](-0.5,-1.1)--(-0.5,-0.8);
draw [->] (0,1) --(1,-1);
draw [->] (0,-1) -- (1,1);
draw[decorate,decoration={brace}] (-0.3,1.2) -- (-0.3,-1.2);
node at (1.7, 1.0){2 Cr: 6};
node at (1.7, -1.0){3Cr: 6};
draw[->](2.4,-1.1)--(2.4,-0.9);
draw[->](2.4,1.1)--(2.4,0.9);
end{tikzpicture}
end{document}
documentclass[a4paper]{article}
usepackage{tikz}
usetikzlibrary{decorations.pathreplacing}
begin{document}
begin{tikzpicture}[node distance = 3cm]
node at (-1,1){Cr: 3};
draw[->](-0.5,1.1)--(-0.5,0.8);
node at (-1,-1){C: 2};
draw[->](-0.5,-1.1)--(-0.5,-0.8);
draw [->] (0,1) --(1,-1);
draw [->] (0,-1) -- (1,1);
draw[decorate,decoration={brace}] (-0.3,1.2) -- (-0.3,-1.2);
node at (1.7, 1.0){2 Cr: 6};
node at (1.7, -1.0){3Cr: 6};
draw[->](2.4,-1.1)--(2.4,-0.9);
draw[->](2.4,1.1)--(2.4,0.9);
end{tikzpicture}
end{document}
edited Oct 30 '16 at 6:58
Stefan Pinnow
20.1k83276
20.1k83276
answered Oct 29 '16 at 10:16
vamanvaman
452
452
I have edited your minimal working example to make it compilable and I've used yourdraw[decorate,decoration={brace}]
in my answer :)
– CarLaTeX
Oct 30 '16 at 7:02
add a comment |
I have edited your minimal working example to make it compilable and I've used yourdraw[decorate,decoration={brace}]
in my answer :)
– CarLaTeX
Oct 30 '16 at 7:02
I have edited your minimal working example to make it compilable and I've used your
draw[decorate,decoration={brace}]
in my answer :)– CarLaTeX
Oct 30 '16 at 7:02
I have edited your minimal working example to make it compilable and I've used your
draw[decorate,decoration={brace}]
in my answer :)– CarLaTeX
Oct 30 '16 at 7:02
add a comment |
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1
This won't help your problem, but it's usually best if you include everything we need to copy and paste to get a working example. In this case, I think that would mean just adding a handful of lines:
documentclass{article}
/usepackage{tikz}
/tikzlibrary{tikzcd}
/begin{document}
, and thenend{article}
.– Teepeemm
Oct 28 '16 at 11:53