Length of secant line in respect to circumference
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![circle with secant line]https://images.google.com/imgres?imgurl=http%3A%2F%2Fimage.mathcaptain.com%2Fcms%2Fimages%2F113%2Fsecant.png&imgrefurl=http%3A%2F%2Fwww.mathcaptain.com%2Fgeometry%2Fsecant.html&tbnid=mvxOwDyPBQ3svM&vet=1&docid=YUhMzW49fXk_wM&w=238&h=208 If you have a circle and you know the circumference is 30, the length of arc AB is 7, how would you find the length of the decant line AB?
secant
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Iyla Baker
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![circle with secant line]https://images.google.com/imgres?imgurl=http%3A%2F%2Fimage.mathcaptain.com%2Fcms%2Fimages%2F113%2Fsecant.png&imgrefurl=http%3A%2F%2Fwww.mathcaptain.com%2Fgeometry%2Fsecant.html&tbnid=mvxOwDyPBQ3svM&vet=1&docid=YUhMzW49fXk_wM&w=238&h=208 If you have a circle and you know the circumference is 30, the length of arc AB is 7, how would you find the length of the decant line AB?
secant
asked 10 hours ago
Iyla Baker
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Iyla Baker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
up vote
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up vote
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down vote
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![circle with secant line]https://images.google.com/imgres?imgurl=http%3A%2F%2Fimage.mathcaptain.com%2Fcms%2Fimages%2F113%2Fsecant.png&imgrefurl=http%3A%2F%2Fwww.mathcaptain.com%2Fgeometry%2Fsecant.html&tbnid=mvxOwDyPBQ3svM&vet=1&docid=YUhMzW49fXk_wM&w=238&h=208 If you have a circle and you know the circumference is 30, the length of arc AB is 7, how would you find the length of the decant line AB?
secant
asked 10 hours ago
Iyla Baker
61
New contributor
Iyla Baker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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![circle with secant line]https://images.google.com/imgres?imgurl=http%3A%2F%2Fimage.mathcaptain.com%2Fcms%2Fimages%2F113%2Fsecant.png&imgrefurl=http%3A%2F%2Fwww.mathcaptain.com%2Fgeometry%2Fsecant.html&tbnid=mvxOwDyPBQ3svM&vet=1&docid=YUhMzW49fXk_wM&w=238&h=208 If you have a circle and you know the circumference is 30, the length of arc AB is 7, how would you find the length of the decant line AB?
secant
secant
asked 10 hours ago
Iyla Baker
61
New contributor
Iyla Baker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 10 hours ago
Iyla Baker
61
New contributor
Iyla Baker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 hours ago
Iyla Baker
61
New contributor
Iyla Baker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 hours ago
Iyla Baker
61
asked 10 hours ago
Iyla Baker
61
61
New contributor
Iyla Baker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Iyla Baker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Iyla Baker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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1 Answer
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First, find the radius of the circle: $2pi R=30$, $R=frac{15}{pi}$. Let $O$ be the center of the circle. Then $mangle{AOB}=frac{7}{R}=frac{7pi}{15}$. Observe that $triangle{AOB}$ is isosceles with $AO=OB=R$. Then $AB=2Rsin frac{7pi}{30}=frac{30}{pi}sin frac{7pi}{30}approx 6.4$
answered 9 hours ago
Vasya
3,1441515
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
First, find the radius of the circle: $2pi R=30$, $R=frac{15}{pi}$. Let $O$ be the center of the circle. Then $mangle{AOB}=frac{7}{R}=frac{7pi}{15}$. Observe that $triangle{AOB}$ is isosceles with $AO=OB=R$. Then $AB=2Rsin frac{7pi}{30}=frac{30}{pi}sin frac{7pi}{30}approx 6.4$
answered 9 hours ago
Vasya
3,1441515
add a comment |
up vote
0
down vote
First, find the radius of the circle: $2pi R=30$, $R=frac{15}{pi}$. Let $O$ be the center of the circle. Then $mangle{AOB}=frac{7}{R}=frac{7pi}{15}$. Observe that $triangle{AOB}$ is isosceles with $AO=OB=R$. Then $AB=2Rsin frac{7pi}{30}=frac{30}{pi}sin frac{7pi}{30}approx 6.4$
answered 9 hours ago
Vasya
3,1441515
add a comment |
up vote
0
down vote
up vote
0
down vote
First, find the radius of the circle: $2pi R=30$, $R=frac{15}{pi}$. Let $O$ be the center of the circle. Then $mangle{AOB}=frac{7}{R}=frac{7pi}{15}$. Observe that $triangle{AOB}$ is isosceles with $AO=OB=R$. Then $AB=2Rsin frac{7pi}{30}=frac{30}{pi}sin frac{7pi}{30}approx 6.4$
answered 9 hours ago
Vasya
3,1441515
First, find the radius of the circle: $2pi R=30$, $R=frac{15}{pi}$. Let $O$ be the center of the circle. Then $mangle{AOB}=frac{7}{R}=frac{7pi}{15}$. Observe that $triangle{AOB}$ is isosceles with $AO=OB=R$. Then $AB=2Rsin frac{7pi}{30}=frac{30}{pi}sin frac{7pi}{30}approx 6.4$
answered 9 hours ago
Vasya
3,1441515
answered 9 hours ago
Vasya
3,1441515
answered 9 hours ago
Vasya
3,1441515
answered 9 hours ago
Vasya
3,1441515
3,1441515
add a comment |
add a comment |
Iyla Baker is a new contributor. Be nice, and check out our Code of Conduct.
Iyla Baker is a new contributor. Be nice, and check out our Code of Conduct.
Iyla Baker is a new contributor. Be nice, and check out our Code of Conduct.
Iyla Baker is a new contributor. Be nice, and check out our Code of Conduct.
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