Merge two dataframes on string column - compound string column





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I am trying to merge two huge dataframes (4+ millions each) that have the following structure:



Dataframe A:



     date    Fruit        a    b    c    d
01 "apple" 0 3 5 1
03 "apple" 8 2 7 2
02 "banana" 1 4 3 5
04 "banana" 3 5 2 6
03 "pineapple" 2 6 4 6
05 "pineapple" 3 5 7 9


Dataframe B:



     date   Fruits                         x    y    z 
01 "apple, pear, strawberry" a n q
02 "banana, apple, coconut" b m p
03 "pineapple, pear, banana" c s o
04 "banana, apple, coconut" d f v
05 "pineapple, pear, banana" r ñ t


What I am trying to achieve is a third dataframe with the following structure:



Dataframe C:



     date   Fruit        a    b    c    d    x    y    z
01 "apple" 0 3 5 1 a n q
03 "apple" 0 3 5 1 0 0 0
02 "banana" 1 4 3 5 b m p
04 "banana" 1 4 3 5 d f v
03 "pineapple" 2 6 4 6 c s o
05 "pineapple" 2 6 4 6 r ñ t
...


I had already tried something like:



test = market_test.assetCode.apply(lambda x : news_test.assetCodes.str.find(x)>=0)


But my kernel breaks, I also had tried using a for cycle to expand the fruit column of B dataframe into a 'fruit-b' column, keeping the data from the other B columns and then merging between the date column and the 'fruit-B' columns, but the time of execution is too high.



Is there a way of obtaining dataframe C using dataframe A and B that does not consume a lot of time and memory?



Fruit and Fruits columns type is string.










share|improve this question

























  • What is the total number of unique fruits occurring across df_A and df_B? You could convert them to one-hot or Categorical, instead of storing as string.

    – smci
    Nov 23 '18 at 1:03






  • 1





    df_B.Fruits is a compound column. I would retitle this "Merge two dataframes on string column/ compound string column"

    – smci
    Nov 23 '18 at 1:13













  • @smci, thanks for your response, the unique fruits number should be around 5000, i'll rename the question as you suggested too.

    – Santiago Hernàndez
    Nov 23 '18 at 14:11


















3















I am trying to merge two huge dataframes (4+ millions each) that have the following structure:



Dataframe A:



     date    Fruit        a    b    c    d
01 "apple" 0 3 5 1
03 "apple" 8 2 7 2
02 "banana" 1 4 3 5
04 "banana" 3 5 2 6
03 "pineapple" 2 6 4 6
05 "pineapple" 3 5 7 9


Dataframe B:



     date   Fruits                         x    y    z 
01 "apple, pear, strawberry" a n q
02 "banana, apple, coconut" b m p
03 "pineapple, pear, banana" c s o
04 "banana, apple, coconut" d f v
05 "pineapple, pear, banana" r ñ t


What I am trying to achieve is a third dataframe with the following structure:



Dataframe C:



     date   Fruit        a    b    c    d    x    y    z
01 "apple" 0 3 5 1 a n q
03 "apple" 0 3 5 1 0 0 0
02 "banana" 1 4 3 5 b m p
04 "banana" 1 4 3 5 d f v
03 "pineapple" 2 6 4 6 c s o
05 "pineapple" 2 6 4 6 r ñ t
...


I had already tried something like:



test = market_test.assetCode.apply(lambda x : news_test.assetCodes.str.find(x)>=0)


But my kernel breaks, I also had tried using a for cycle to expand the fruit column of B dataframe into a 'fruit-b' column, keeping the data from the other B columns and then merging between the date column and the 'fruit-B' columns, but the time of execution is too high.



Is there a way of obtaining dataframe C using dataframe A and B that does not consume a lot of time and memory?



Fruit and Fruits columns type is string.










share|improve this question

























  • What is the total number of unique fruits occurring across df_A and df_B? You could convert them to one-hot or Categorical, instead of storing as string.

    – smci
    Nov 23 '18 at 1:03






  • 1





    df_B.Fruits is a compound column. I would retitle this "Merge two dataframes on string column/ compound string column"

    – smci
    Nov 23 '18 at 1:13













  • @smci, thanks for your response, the unique fruits number should be around 5000, i'll rename the question as you suggested too.

    – Santiago Hernàndez
    Nov 23 '18 at 14:11














3












3








3


0






I am trying to merge two huge dataframes (4+ millions each) that have the following structure:



Dataframe A:



     date    Fruit        a    b    c    d
01 "apple" 0 3 5 1
03 "apple" 8 2 7 2
02 "banana" 1 4 3 5
04 "banana" 3 5 2 6
03 "pineapple" 2 6 4 6
05 "pineapple" 3 5 7 9


Dataframe B:



     date   Fruits                         x    y    z 
01 "apple, pear, strawberry" a n q
02 "banana, apple, coconut" b m p
03 "pineapple, pear, banana" c s o
04 "banana, apple, coconut" d f v
05 "pineapple, pear, banana" r ñ t


What I am trying to achieve is a third dataframe with the following structure:



Dataframe C:



     date   Fruit        a    b    c    d    x    y    z
01 "apple" 0 3 5 1 a n q
03 "apple" 0 3 5 1 0 0 0
02 "banana" 1 4 3 5 b m p
04 "banana" 1 4 3 5 d f v
03 "pineapple" 2 6 4 6 c s o
05 "pineapple" 2 6 4 6 r ñ t
...


I had already tried something like:



test = market_test.assetCode.apply(lambda x : news_test.assetCodes.str.find(x)>=0)


But my kernel breaks, I also had tried using a for cycle to expand the fruit column of B dataframe into a 'fruit-b' column, keeping the data from the other B columns and then merging between the date column and the 'fruit-B' columns, but the time of execution is too high.



Is there a way of obtaining dataframe C using dataframe A and B that does not consume a lot of time and memory?



Fruit and Fruits columns type is string.










share|improve this question
















I am trying to merge two huge dataframes (4+ millions each) that have the following structure:



Dataframe A:



     date    Fruit        a    b    c    d
01 "apple" 0 3 5 1
03 "apple" 8 2 7 2
02 "banana" 1 4 3 5
04 "banana" 3 5 2 6
03 "pineapple" 2 6 4 6
05 "pineapple" 3 5 7 9


Dataframe B:



     date   Fruits                         x    y    z 
01 "apple, pear, strawberry" a n q
02 "banana, apple, coconut" b m p
03 "pineapple, pear, banana" c s o
04 "banana, apple, coconut" d f v
05 "pineapple, pear, banana" r ñ t


What I am trying to achieve is a third dataframe with the following structure:



Dataframe C:



     date   Fruit        a    b    c    d    x    y    z
01 "apple" 0 3 5 1 a n q
03 "apple" 0 3 5 1 0 0 0
02 "banana" 1 4 3 5 b m p
04 "banana" 1 4 3 5 d f v
03 "pineapple" 2 6 4 6 c s o
05 "pineapple" 2 6 4 6 r ñ t
...


I had already tried something like:



test = market_test.assetCode.apply(lambda x : news_test.assetCodes.str.find(x)>=0)


But my kernel breaks, I also had tried using a for cycle to expand the fruit column of B dataframe into a 'fruit-b' column, keeping the data from the other B columns and then merging between the date column and the 'fruit-B' columns, but the time of execution is too high.



Is there a way of obtaining dataframe C using dataframe A and B that does not consume a lot of time and memory?



Fruit and Fruits columns type is string.







python pandas dataframe merge






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 14:11







Santiago Hernàndez

















asked Nov 22 '18 at 23:13









Santiago HernàndezSantiago Hernàndez

185




185













  • What is the total number of unique fruits occurring across df_A and df_B? You could convert them to one-hot or Categorical, instead of storing as string.

    – smci
    Nov 23 '18 at 1:03






  • 1





    df_B.Fruits is a compound column. I would retitle this "Merge two dataframes on string column/ compound string column"

    – smci
    Nov 23 '18 at 1:13













  • @smci, thanks for your response, the unique fruits number should be around 5000, i'll rename the question as you suggested too.

    – Santiago Hernàndez
    Nov 23 '18 at 14:11



















  • What is the total number of unique fruits occurring across df_A and df_B? You could convert them to one-hot or Categorical, instead of storing as string.

    – smci
    Nov 23 '18 at 1:03






  • 1





    df_B.Fruits is a compound column. I would retitle this "Merge two dataframes on string column/ compound string column"

    – smci
    Nov 23 '18 at 1:13













  • @smci, thanks for your response, the unique fruits number should be around 5000, i'll rename the question as you suggested too.

    – Santiago Hernàndez
    Nov 23 '18 at 14:11

















What is the total number of unique fruits occurring across df_A and df_B? You could convert them to one-hot or Categorical, instead of storing as string.

– smci
Nov 23 '18 at 1:03





What is the total number of unique fruits occurring across df_A and df_B? You could convert them to one-hot or Categorical, instead of storing as string.

– smci
Nov 23 '18 at 1:03




1




1





df_B.Fruits is a compound column. I would retitle this "Merge two dataframes on string column/ compound string column"

– smci
Nov 23 '18 at 1:13







df_B.Fruits is a compound column. I would retitle this "Merge two dataframes on string column/ compound string column"

– smci
Nov 23 '18 at 1:13















@smci, thanks for your response, the unique fruits number should be around 5000, i'll rename the question as you suggested too.

– Santiago Hernàndez
Nov 23 '18 at 14:11





@smci, thanks for your response, the unique fruits number should be around 5000, i'll rename the question as you suggested too.

– Santiago Hernàndez
Nov 23 '18 at 14:11












1 Answer
1






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oldest

votes


















0














Use:



print (df_A)

date Fruit a b c d
0 1 apple 0 3 5 1
1 3 apple 8 2 7 2
2 2 banana 1 4 3 5
3 4 banana 3 5 2 6
4 3 pineapple 2 6 4 6
5 5 pineapple 3 5 7 9

print (df_B)

date Fruits x y z
0 1 apple, pear, strawberry a n q
1 2 banana, apple, coconut b m p
2 3 pineapple, pear, banana c s o
3 4 banana, apple, coconut d f v
4 5 pineapple, pear, banana r ñ t




import pandas as pd
import numpy as np

# Split the strings into list.
df_B.Fruits = df_B.Fruits.str.split(', ')

# reindex and repeat on length of list
temp = df_B.reindex(df_B.index.repeat(df_B.Fruits.str.len())).drop('Fruits',1)

temp['Fruit'] = np.concatenate(df_B.Fruits.values)

df_C = df_A.merge(temp, on=['date','Fruit'], how='left').fillna(0)

print (df_C)

date Fruit a b c d x y z
0 1 apple 0 3 5 1 a n q
1 3 apple 8 2 7 2 0 0 0
2 2 banana 1 4 3 5 b m p
3 4 banana 3 5 2 6 d f v
4 3 pineapple 2 6 4 6 c s o
5 5 pineapple 3 5 7 9 r ñ t





share|improve this answer





















  • 1





    Thanks it's working!

    – Santiago Hernàndez
    Nov 23 '18 at 20:15












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1 Answer
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1 Answer
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active

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Use:



print (df_A)

date Fruit a b c d
0 1 apple 0 3 5 1
1 3 apple 8 2 7 2
2 2 banana 1 4 3 5
3 4 banana 3 5 2 6
4 3 pineapple 2 6 4 6
5 5 pineapple 3 5 7 9

print (df_B)

date Fruits x y z
0 1 apple, pear, strawberry a n q
1 2 banana, apple, coconut b m p
2 3 pineapple, pear, banana c s o
3 4 banana, apple, coconut d f v
4 5 pineapple, pear, banana r ñ t




import pandas as pd
import numpy as np

# Split the strings into list.
df_B.Fruits = df_B.Fruits.str.split(', ')

# reindex and repeat on length of list
temp = df_B.reindex(df_B.index.repeat(df_B.Fruits.str.len())).drop('Fruits',1)

temp['Fruit'] = np.concatenate(df_B.Fruits.values)

df_C = df_A.merge(temp, on=['date','Fruit'], how='left').fillna(0)

print (df_C)

date Fruit a b c d x y z
0 1 apple 0 3 5 1 a n q
1 3 apple 8 2 7 2 0 0 0
2 2 banana 1 4 3 5 b m p
3 4 banana 3 5 2 6 d f v
4 3 pineapple 2 6 4 6 c s o
5 5 pineapple 3 5 7 9 r ñ t





share|improve this answer





















  • 1





    Thanks it's working!

    – Santiago Hernàndez
    Nov 23 '18 at 20:15
















0














Use:



print (df_A)

date Fruit a b c d
0 1 apple 0 3 5 1
1 3 apple 8 2 7 2
2 2 banana 1 4 3 5
3 4 banana 3 5 2 6
4 3 pineapple 2 6 4 6
5 5 pineapple 3 5 7 9

print (df_B)

date Fruits x y z
0 1 apple, pear, strawberry a n q
1 2 banana, apple, coconut b m p
2 3 pineapple, pear, banana c s o
3 4 banana, apple, coconut d f v
4 5 pineapple, pear, banana r ñ t




import pandas as pd
import numpy as np

# Split the strings into list.
df_B.Fruits = df_B.Fruits.str.split(', ')

# reindex and repeat on length of list
temp = df_B.reindex(df_B.index.repeat(df_B.Fruits.str.len())).drop('Fruits',1)

temp['Fruit'] = np.concatenate(df_B.Fruits.values)

df_C = df_A.merge(temp, on=['date','Fruit'], how='left').fillna(0)

print (df_C)

date Fruit a b c d x y z
0 1 apple 0 3 5 1 a n q
1 3 apple 8 2 7 2 0 0 0
2 2 banana 1 4 3 5 b m p
3 4 banana 3 5 2 6 d f v
4 3 pineapple 2 6 4 6 c s o
5 5 pineapple 3 5 7 9 r ñ t





share|improve this answer





















  • 1





    Thanks it's working!

    – Santiago Hernàndez
    Nov 23 '18 at 20:15














0












0








0







Use:



print (df_A)

date Fruit a b c d
0 1 apple 0 3 5 1
1 3 apple 8 2 7 2
2 2 banana 1 4 3 5
3 4 banana 3 5 2 6
4 3 pineapple 2 6 4 6
5 5 pineapple 3 5 7 9

print (df_B)

date Fruits x y z
0 1 apple, pear, strawberry a n q
1 2 banana, apple, coconut b m p
2 3 pineapple, pear, banana c s o
3 4 banana, apple, coconut d f v
4 5 pineapple, pear, banana r ñ t




import pandas as pd
import numpy as np

# Split the strings into list.
df_B.Fruits = df_B.Fruits.str.split(', ')

# reindex and repeat on length of list
temp = df_B.reindex(df_B.index.repeat(df_B.Fruits.str.len())).drop('Fruits',1)

temp['Fruit'] = np.concatenate(df_B.Fruits.values)

df_C = df_A.merge(temp, on=['date','Fruit'], how='left').fillna(0)

print (df_C)

date Fruit a b c d x y z
0 1 apple 0 3 5 1 a n q
1 3 apple 8 2 7 2 0 0 0
2 2 banana 1 4 3 5 b m p
3 4 banana 3 5 2 6 d f v
4 3 pineapple 2 6 4 6 c s o
5 5 pineapple 3 5 7 9 r ñ t





share|improve this answer















Use:



print (df_A)

date Fruit a b c d
0 1 apple 0 3 5 1
1 3 apple 8 2 7 2
2 2 banana 1 4 3 5
3 4 banana 3 5 2 6
4 3 pineapple 2 6 4 6
5 5 pineapple 3 5 7 9

print (df_B)

date Fruits x y z
0 1 apple, pear, strawberry a n q
1 2 banana, apple, coconut b m p
2 3 pineapple, pear, banana c s o
3 4 banana, apple, coconut d f v
4 5 pineapple, pear, banana r ñ t




import pandas as pd
import numpy as np

# Split the strings into list.
df_B.Fruits = df_B.Fruits.str.split(', ')

# reindex and repeat on length of list
temp = df_B.reindex(df_B.index.repeat(df_B.Fruits.str.len())).drop('Fruits',1)

temp['Fruit'] = np.concatenate(df_B.Fruits.values)

df_C = df_A.merge(temp, on=['date','Fruit'], how='left').fillna(0)

print (df_C)

date Fruit a b c d x y z
0 1 apple 0 3 5 1 a n q
1 3 apple 8 2 7 2 0 0 0
2 2 banana 1 4 3 5 b m p
3 4 banana 3 5 2 6 d f v
4 3 pineapple 2 6 4 6 c s o
5 5 pineapple 3 5 7 9 r ñ t






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 23 '18 at 0:55

























answered Nov 23 '18 at 0:33









AbhiAbhi

2,539422




2,539422








  • 1





    Thanks it's working!

    – Santiago Hernàndez
    Nov 23 '18 at 20:15














  • 1





    Thanks it's working!

    – Santiago Hernàndez
    Nov 23 '18 at 20:15








1




1





Thanks it's working!

– Santiago Hernàndez
Nov 23 '18 at 20:15





Thanks it's working!

– Santiago Hernàndez
Nov 23 '18 at 20:15




















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