get data from async function
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i'm trying to do a little website like sickgearr for my seedbox :
i want a search form which will send a search query to my torrent providers using this api : https://github.com/JimmyLaurent/torrent-search-api
i managed getting text from the form, making the api calls and get results printed in the console.
but when i try to pass them to the soon to-become result page, i'm only passing promises and i don't quite understand the principle of promises.
If someone could help me resolve my issues i'd be really really gratefull or atleast give me some hints !
Here is my code made up from several ejs, nodejs begginers tutorials :
const express = require('express');
const bodyParser = require('body-parser');
const app = express()
const TorrentSearchApi = require('torrent-search-api');
const tableify = require('tableify');
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password');
app.use(express.static('public'));
app.use(bodyParser.urlencoded({ extended: true }));
app.set('view engine', 'ejs')
async function search(query){ // Search for torrents using the api
var string = query.toLowerCase();
//console.log(string);
const torrents = await TorrentSearchApi.search(string,'All',20); // Search for legal linux distros
return(JSON.stringify(torrents));
}
app.get('/', function (req, res) {
res.render('index');
})
app.post('/', function (req, res) {
var rawTorrent = search(req.body.torrent);
var page = tableify(rawTorrent); //printing rawtorrent will only give me "promise"
res.render('results',page);
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
javascript node.js api web
add a comment |
i'm trying to do a little website like sickgearr for my seedbox :
i want a search form which will send a search query to my torrent providers using this api : https://github.com/JimmyLaurent/torrent-search-api
i managed getting text from the form, making the api calls and get results printed in the console.
but when i try to pass them to the soon to-become result page, i'm only passing promises and i don't quite understand the principle of promises.
If someone could help me resolve my issues i'd be really really gratefull or atleast give me some hints !
Here is my code made up from several ejs, nodejs begginers tutorials :
const express = require('express');
const bodyParser = require('body-parser');
const app = express()
const TorrentSearchApi = require('torrent-search-api');
const tableify = require('tableify');
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password');
app.use(express.static('public'));
app.use(bodyParser.urlencoded({ extended: true }));
app.set('view engine', 'ejs')
async function search(query){ // Search for torrents using the api
var string = query.toLowerCase();
//console.log(string);
const torrents = await TorrentSearchApi.search(string,'All',20); // Search for legal linux distros
return(JSON.stringify(torrents));
}
app.get('/', function (req, res) {
res.render('index');
})
app.post('/', function (req, res) {
var rawTorrent = search(req.body.torrent);
var page = tableify(rawTorrent); //printing rawtorrent will only give me "promise"
res.render('results',page);
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
javascript node.js api web
Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?
– shmit
Nov 22 '18 at 23:19
add a comment |
i'm trying to do a little website like sickgearr for my seedbox :
i want a search form which will send a search query to my torrent providers using this api : https://github.com/JimmyLaurent/torrent-search-api
i managed getting text from the form, making the api calls and get results printed in the console.
but when i try to pass them to the soon to-become result page, i'm only passing promises and i don't quite understand the principle of promises.
If someone could help me resolve my issues i'd be really really gratefull or atleast give me some hints !
Here is my code made up from several ejs, nodejs begginers tutorials :
const express = require('express');
const bodyParser = require('body-parser');
const app = express()
const TorrentSearchApi = require('torrent-search-api');
const tableify = require('tableify');
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password');
app.use(express.static('public'));
app.use(bodyParser.urlencoded({ extended: true }));
app.set('view engine', 'ejs')
async function search(query){ // Search for torrents using the api
var string = query.toLowerCase();
//console.log(string);
const torrents = await TorrentSearchApi.search(string,'All',20); // Search for legal linux distros
return(JSON.stringify(torrents));
}
app.get('/', function (req, res) {
res.render('index');
})
app.post('/', function (req, res) {
var rawTorrent = search(req.body.torrent);
var page = tableify(rawTorrent); //printing rawtorrent will only give me "promise"
res.render('results',page);
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
javascript node.js api web
i'm trying to do a little website like sickgearr for my seedbox :
i want a search form which will send a search query to my torrent providers using this api : https://github.com/JimmyLaurent/torrent-search-api
i managed getting text from the form, making the api calls and get results printed in the console.
but when i try to pass them to the soon to-become result page, i'm only passing promises and i don't quite understand the principle of promises.
If someone could help me resolve my issues i'd be really really gratefull or atleast give me some hints !
Here is my code made up from several ejs, nodejs begginers tutorials :
const express = require('express');
const bodyParser = require('body-parser');
const app = express()
const TorrentSearchApi = require('torrent-search-api');
const tableify = require('tableify');
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password');
app.use(express.static('public'));
app.use(bodyParser.urlencoded({ extended: true }));
app.set('view engine', 'ejs')
async function search(query){ // Search for torrents using the api
var string = query.toLowerCase();
//console.log(string);
const torrents = await TorrentSearchApi.search(string,'All',20); // Search for legal linux distros
return(JSON.stringify(torrents));
}
app.get('/', function (req, res) {
res.render('index');
})
app.post('/', function (req, res) {
var rawTorrent = search(req.body.torrent);
var page = tableify(rawTorrent); //printing rawtorrent will only give me "promise"
res.render('results',page);
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
javascript node.js api web
javascript node.js api web
asked Nov 22 '18 at 23:04
SliteSlite
2918
2918
Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?
– shmit
Nov 22 '18 at 23:19
add a comment |
Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?
– shmit
Nov 22 '18 at 23:19
Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?
– shmit
Nov 22 '18 at 23:19
Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?
– shmit
Nov 22 '18 at 23:19
add a comment |
1 Answer
1
active
oldest
votes
Your search function is using async
/await
.
It means the search function is asynchrone and returns a Promise
.
You should await its result (line 23).
https://javascript.info/async-await
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function
const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')
app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')
const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}
app.get('/', (_, res) => res.render('index'))
app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?
– Slite
Nov 23 '18 at 9:01
1
The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved
– Patrick Hund
Nov 23 '18 at 9:19
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your search function is using async
/await
.
It means the search function is asynchrone and returns a Promise
.
You should await its result (line 23).
https://javascript.info/async-await
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function
const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')
app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')
const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}
app.get('/', (_, res) => res.render('index'))
app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?
– Slite
Nov 23 '18 at 9:01
1
The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved
– Patrick Hund
Nov 23 '18 at 9:19
add a comment |
Your search function is using async
/await
.
It means the search function is asynchrone and returns a Promise
.
You should await its result (line 23).
https://javascript.info/async-await
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function
const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')
app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')
const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}
app.get('/', (_, res) => res.render('index'))
app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?
– Slite
Nov 23 '18 at 9:01
1
The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved
– Patrick Hund
Nov 23 '18 at 9:19
add a comment |
Your search function is using async
/await
.
It means the search function is asynchrone and returns a Promise
.
You should await its result (line 23).
https://javascript.info/async-await
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function
const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')
app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')
const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}
app.get('/', (_, res) => res.render('index'))
app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
Your search function is using async
/await
.
It means the search function is asynchrone and returns a Promise
.
You should await its result (line 23).
https://javascript.info/async-await
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function
const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')
app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')
const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}
app.get('/', (_, res) => res.render('index'))
app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})
answered Nov 22 '18 at 23:30
BlitzBlitz
11115
11115
Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?
– Slite
Nov 23 '18 at 9:01
1
The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved
– Patrick Hund
Nov 23 '18 at 9:19
add a comment |
Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?
– Slite
Nov 23 '18 at 9:01
1
The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved
– Patrick Hund
Nov 23 '18 at 9:19
Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?
– Slite
Nov 23 '18 at 9:01
Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?
– Slite
Nov 23 '18 at 9:01
1
1
The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved
– Patrick Hund
Nov 23 '18 at 9:19
The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved
– Patrick Hund
Nov 23 '18 at 9:19
add a comment |
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Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?
– shmit
Nov 22 '18 at 23:19