get data from async function





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i'm trying to do a little website like sickgearr for my seedbox :
i want a search form which will send a search query to my torrent providers using this api : https://github.com/JimmyLaurent/torrent-search-api



i managed getting text from the form, making the api calls and get results printed in the console.



but when i try to pass them to the soon to-become result page, i'm only passing promises and i don't quite understand the principle of promises.



If someone could help me resolve my issues i'd be really really gratefull or atleast give me some hints !



Here is my code made up from several ejs, nodejs begginers tutorials :



const express = require('express');
const bodyParser = require('body-parser');
const app = express()
const TorrentSearchApi = require('torrent-search-api');
const tableify = require('tableify');
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password');

app.use(express.static('public'));
app.use(bodyParser.urlencoded({ extended: true }));
app.set('view engine', 'ejs')

async function search(query){ // Search for torrents using the api

var string = query.toLowerCase();
//console.log(string);
const torrents = await TorrentSearchApi.search(string,'All',20); // Search for legal linux distros
return(JSON.stringify(torrents));
}

app.get('/', function (req, res) {
res.render('index');
})

app.post('/', function (req, res) {
var rawTorrent = search(req.body.torrent);
var page = tableify(rawTorrent); //printing rawtorrent will only give me "promise"
res.render('results',page);
})


app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})









share|improve this question























  • Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?

    – shmit
    Nov 22 '18 at 23:19


















0















i'm trying to do a little website like sickgearr for my seedbox :
i want a search form which will send a search query to my torrent providers using this api : https://github.com/JimmyLaurent/torrent-search-api



i managed getting text from the form, making the api calls and get results printed in the console.



but when i try to pass them to the soon to-become result page, i'm only passing promises and i don't quite understand the principle of promises.



If someone could help me resolve my issues i'd be really really gratefull or atleast give me some hints !



Here is my code made up from several ejs, nodejs begginers tutorials :



const express = require('express');
const bodyParser = require('body-parser');
const app = express()
const TorrentSearchApi = require('torrent-search-api');
const tableify = require('tableify');
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password');

app.use(express.static('public'));
app.use(bodyParser.urlencoded({ extended: true }));
app.set('view engine', 'ejs')

async function search(query){ // Search for torrents using the api

var string = query.toLowerCase();
//console.log(string);
const torrents = await TorrentSearchApi.search(string,'All',20); // Search for legal linux distros
return(JSON.stringify(torrents));
}

app.get('/', function (req, res) {
res.render('index');
})

app.post('/', function (req, res) {
var rawTorrent = search(req.body.torrent);
var page = tableify(rawTorrent); //printing rawtorrent will only give me "promise"
res.render('results',page);
})


app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})









share|improve this question























  • Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?

    – shmit
    Nov 22 '18 at 23:19














0












0








0








i'm trying to do a little website like sickgearr for my seedbox :
i want a search form which will send a search query to my torrent providers using this api : https://github.com/JimmyLaurent/torrent-search-api



i managed getting text from the form, making the api calls and get results printed in the console.



but when i try to pass them to the soon to-become result page, i'm only passing promises and i don't quite understand the principle of promises.



If someone could help me resolve my issues i'd be really really gratefull or atleast give me some hints !



Here is my code made up from several ejs, nodejs begginers tutorials :



const express = require('express');
const bodyParser = require('body-parser');
const app = express()
const TorrentSearchApi = require('torrent-search-api');
const tableify = require('tableify');
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password');

app.use(express.static('public'));
app.use(bodyParser.urlencoded({ extended: true }));
app.set('view engine', 'ejs')

async function search(query){ // Search for torrents using the api

var string = query.toLowerCase();
//console.log(string);
const torrents = await TorrentSearchApi.search(string,'All',20); // Search for legal linux distros
return(JSON.stringify(torrents));
}

app.get('/', function (req, res) {
res.render('index');
})

app.post('/', function (req, res) {
var rawTorrent = search(req.body.torrent);
var page = tableify(rawTorrent); //printing rawtorrent will only give me "promise"
res.render('results',page);
})


app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})









share|improve this question














i'm trying to do a little website like sickgearr for my seedbox :
i want a search form which will send a search query to my torrent providers using this api : https://github.com/JimmyLaurent/torrent-search-api



i managed getting text from the form, making the api calls and get results printed in the console.



but when i try to pass them to the soon to-become result page, i'm only passing promises and i don't quite understand the principle of promises.



If someone could help me resolve my issues i'd be really really gratefull or atleast give me some hints !



Here is my code made up from several ejs, nodejs begginers tutorials :



const express = require('express');
const bodyParser = require('body-parser');
const app = express()
const TorrentSearchApi = require('torrent-search-api');
const tableify = require('tableify');
TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password');

app.use(express.static('public'));
app.use(bodyParser.urlencoded({ extended: true }));
app.set('view engine', 'ejs')

async function search(query){ // Search for torrents using the api

var string = query.toLowerCase();
//console.log(string);
const torrents = await TorrentSearchApi.search(string,'All',20); // Search for legal linux distros
return(JSON.stringify(torrents));
}

app.get('/', function (req, res) {
res.render('index');
})

app.post('/', function (req, res) {
var rawTorrent = search(req.body.torrent);
var page = tableify(rawTorrent); //printing rawtorrent will only give me "promise"
res.render('results',page);
})


app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})






javascript node.js api web






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asked Nov 22 '18 at 23:04









SliteSlite

2918




2918













  • Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?

    – shmit
    Nov 22 '18 at 23:19



















  • Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?

    – shmit
    Nov 22 '18 at 23:19

















Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?

– shmit
Nov 22 '18 at 23:19





Have you tried to enable a provider? torrentSearchApi.enableProvider('Torrent9'); or specific provider?

– shmit
Nov 22 '18 at 23:19












1 Answer
1






active

oldest

votes


















1














Your search function is using async/await.
It means the search function is asynchrone and returns a Promise.
You should await its result (line 23).



https://javascript.info/async-await



https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function



const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')

TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')

app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')


const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}

app.get('/', (_, res) => res.render('index'))

app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})

app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})





share|improve this answer
























  • Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?

    – Slite
    Nov 23 '18 at 9:01








  • 1





    The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved

    – Patrick Hund
    Nov 23 '18 at 9:19












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1 Answer
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oldest

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1 Answer
1






active

oldest

votes









active

oldest

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active

oldest

votes









1














Your search function is using async/await.
It means the search function is asynchrone and returns a Promise.
You should await its result (line 23).



https://javascript.info/async-await



https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function



const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')

TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')

app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')


const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}

app.get('/', (_, res) => res.render('index'))

app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})

app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})





share|improve this answer
























  • Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?

    – Slite
    Nov 23 '18 at 9:01








  • 1





    The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved

    – Patrick Hund
    Nov 23 '18 at 9:19
















1














Your search function is using async/await.
It means the search function is asynchrone and returns a Promise.
You should await its result (line 23).



https://javascript.info/async-await



https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function



const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')

TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')

app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')


const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}

app.get('/', (_, res) => res.render('index'))

app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})

app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})





share|improve this answer
























  • Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?

    – Slite
    Nov 23 '18 at 9:01








  • 1





    The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved

    – Patrick Hund
    Nov 23 '18 at 9:19














1












1








1







Your search function is using async/await.
It means the search function is asynchrone and returns a Promise.
You should await its result (line 23).



https://javascript.info/async-await



https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function



const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')

TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')

app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')


const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}

app.get('/', (_, res) => res.render('index'))

app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})

app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})





share|improve this answer













Your search function is using async/await.
It means the search function is asynchrone and returns a Promise.
You should await its result (line 23).



https://javascript.info/async-await



https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function



const express = require('express')
const bodyParser = require('body-parser')
const app = express()
const TorrentSearchApi = require('torrent-search-api')
const tableify = require('tableify')

TorrentSearchApi.enableProvider('Yggtorrent','Login', 'Password')

app.use(express.static('public'))
app.use(bodyParser.urlencoded({ extended: true }))
app.set('view engine', 'ejs')


const search = async query => {
const loweredQuery = query.toLowerCase()
const torrents = await TorrentSearchApi.search(loweredQuery, 'All', 20)
return JSON.stringify(torrents)
}

app.get('/', (_, res) => res.render('index'))

app.post('/', async (req, res) => {
const torrents = await search(req.body.torrent) // Right here
const htmlTable = tableify(torrents)
res.render('results', htmlTable)
})

app.listen(3000, function () {
console.log('Example app listening on port 3000!')
})






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 22 '18 at 23:30









BlitzBlitz

11115




11115













  • Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?

    – Slite
    Nov 23 '18 at 9:01








  • 1





    The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved

    – Patrick Hund
    Nov 23 '18 at 9:19



















  • Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?

    – Slite
    Nov 23 '18 at 9:01








  • 1





    The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved

    – Patrick Hund
    Nov 23 '18 at 9:19

















Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?

– Slite
Nov 23 '18 at 9:01







Thank you very much, will try this when i get home and i'll keep you posted if i understand right i must call an async function with await otherwise the promise wont be resolved ?

– Slite
Nov 23 '18 at 9:01






1




1





The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved

– Patrick Hund
Nov 23 '18 at 9:19





The promise will be resolved either way, but without „await“ the execution of the program resumes before it is resolved

– Patrick Hund
Nov 23 '18 at 9:19




















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