Is there a way to make the text smaller inside a default font setting?
so I've written one document using the default margin settings and another using different margin settings(much wider). I needed to compile both documents so there's an obvious issue now. Let me show you what I mean:
documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
usepackage{floatrow}
begin{document}
Computation of the Inverse Fourier transform from definition 3.1.3:
[
f_{(0,0,0)} = frac{1}{8}[f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}] = f_{(0,0,0)}
]
[
f_{(0,0,1)} = frac{1}{8}[f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}] = f_{(0,0,1)}
]
[
f_{(0,1,0)} = frac{1}{8}[f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}+f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}] = f_{(0,1,0)}
]
[
f_{(0,1,1)} = frac{1}{8}[f_{(0,1,1)}+f_{(0,1,1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}+f_{(0,1,1)}+f_{(0,1,1)}] = f_{(0,1,1)}
]
[
f_{(1,0,0)} = frac{1}{8}[f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}] = f_{(1,0,0)}
]
[
f_{(1,0,1)} = frac{1}{8}[f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}] = f_{(1,0,1)}
]
[
f_{(1,1,0)} = frac{1}{8}[f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}+f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}] = f_{(1,1,0)}
]
[
f_{(1,1,1)} = frac{1}{8}[f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}] = f_{(1,1,1)}
]
end{document}
I want to use the default margins which means making the code above font smaller or are there better solutions?
Thank you.
EDIT: I have rechecked the output and making the font smaller wont be useful. I think I should break the line using align but I don't know how to use it properly.
begin{align*}
setlengthextrarowheight{3pt}
noindentbegin{tabular}{c | c c c c c c c c }
+ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
cline{1-9}
$(0,0,0)$ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
$(0,0,1)$ & $(0,0,1)$ & $(0,0,0)$ & $(0,1,1)$ & $(0,1,0)$ & $(1,0,1)$ & $(1,0,0)$ & $(1,1,1)$ & $(1,1,0)$\
$(0,1,0)$ & $(0,1,0)$ & $(0,1,1)$ & $(0,0,0)$ & $(0,0,1)$ & $(1,1,0)$ & $(1,1,1)$ & $(1,0,0)$ & $(1,0,1)$\
$(0,1,1)$ & $(0,1,1)$ & $(0,1,0)$ & $(0,0,1)$ & $(0,0,0)$ & $(1,1,1)$ & $(1,1,0)$ & $(1,0,1)$ & $(1,0,0)$\
$(1,0,0)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$\
$(1,0,1)$ & $(1,0,1)$ & $(1,0,0)$ & $(1,1,1)$ & $(1,1,0)$ & $(0,0,1)$ & $(0,0,0)$ & $(0,1,1)$ & $(0,1,0)$\
$(1,1,0)$ & $(1,1,0)$ & $(1,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(0,0,0)$ & $(0,0,1)$\
$(1,1,1)$ & $(1,1,1)$ & $(1,1,0)$ & $(1,0,1)$ & $(1,0,0)$ & $(0,1,1)$ & $(0,1,0)$ & $(0,0,1)$ & $(0,0,0)$\
end{tabular}
end{align*}
The character table:
begin{align*}
setlengthextrarowheight{3pt}
noindentbegin{tabular}{c | c c c c c c c c }
+ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
cline{1-9}
$chi_{(0,0,0)}$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$\
$chi_{(0,0,1)}$ & $1$ & $1$ & $1$ & $1$ & $-1$ & $-1$ & $-1$ & $-1$\
$chi_{(0,1,0)}$ & $1$ & $1$ & $-1$ & $-1$ & $1$ & $1$ & $-1$ & $-1$\
$chi_{(0,1,1)}$ & $1$ & $1$ & $-1$ & $-1$ & $-1$ & $-1$ & $1$ & $1$\
$chi_{(1,0,0)}$ & $1$ & $-1$ & $1$ & $-1$ & $1$ & $-1$ & $1$ & $-1$\
$chi_{(1,0,1)}$ & $1$ & $-1$ & $1$ & $-1$ & $-1$ & $1$ & $-1$ & $1$\
$chi_{(1,1,0)}$ & $1$ & $-1$ & $-1$ & $1$ & $1$ & $-1$ & $-1$ & $1$\
$chi_{(1,1,1)}$ & $1$ & $-1$ & $-1$ & $1$ & $-1$ & $1$ & $1$ & $-1$\
end{tabular}
end{align*}
spacing width
|
show 3 more comments
so I've written one document using the default margin settings and another using different margin settings(much wider). I needed to compile both documents so there's an obvious issue now. Let me show you what I mean:
documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
usepackage{floatrow}
begin{document}
Computation of the Inverse Fourier transform from definition 3.1.3:
[
f_{(0,0,0)} = frac{1}{8}[f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}] = f_{(0,0,0)}
]
[
f_{(0,0,1)} = frac{1}{8}[f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}] = f_{(0,0,1)}
]
[
f_{(0,1,0)} = frac{1}{8}[f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}+f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}] = f_{(0,1,0)}
]
[
f_{(0,1,1)} = frac{1}{8}[f_{(0,1,1)}+f_{(0,1,1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}+f_{(0,1,1)}+f_{(0,1,1)}] = f_{(0,1,1)}
]
[
f_{(1,0,0)} = frac{1}{8}[f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}] = f_{(1,0,0)}
]
[
f_{(1,0,1)} = frac{1}{8}[f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}] = f_{(1,0,1)}
]
[
f_{(1,1,0)} = frac{1}{8}[f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}+f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}] = f_{(1,1,0)}
]
[
f_{(1,1,1)} = frac{1}{8}[f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}] = f_{(1,1,1)}
]
end{document}
I want to use the default margins which means making the code above font smaller or are there better solutions?
Thank you.
EDIT: I have rechecked the output and making the font smaller wont be useful. I think I should break the line using align but I don't know how to use it properly.
begin{align*}
setlengthextrarowheight{3pt}
noindentbegin{tabular}{c | c c c c c c c c }
+ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
cline{1-9}
$(0,0,0)$ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
$(0,0,1)$ & $(0,0,1)$ & $(0,0,0)$ & $(0,1,1)$ & $(0,1,0)$ & $(1,0,1)$ & $(1,0,0)$ & $(1,1,1)$ & $(1,1,0)$\
$(0,1,0)$ & $(0,1,0)$ & $(0,1,1)$ & $(0,0,0)$ & $(0,0,1)$ & $(1,1,0)$ & $(1,1,1)$ & $(1,0,0)$ & $(1,0,1)$\
$(0,1,1)$ & $(0,1,1)$ & $(0,1,0)$ & $(0,0,1)$ & $(0,0,0)$ & $(1,1,1)$ & $(1,1,0)$ & $(1,0,1)$ & $(1,0,0)$\
$(1,0,0)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$\
$(1,0,1)$ & $(1,0,1)$ & $(1,0,0)$ & $(1,1,1)$ & $(1,1,0)$ & $(0,0,1)$ & $(0,0,0)$ & $(0,1,1)$ & $(0,1,0)$\
$(1,1,0)$ & $(1,1,0)$ & $(1,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(0,0,0)$ & $(0,0,1)$\
$(1,1,1)$ & $(1,1,1)$ & $(1,1,0)$ & $(1,0,1)$ & $(1,0,0)$ & $(0,1,1)$ & $(0,1,0)$ & $(0,0,1)$ & $(0,0,0)$\
end{tabular}
end{align*}
The character table:
begin{align*}
setlengthextrarowheight{3pt}
noindentbegin{tabular}{c | c c c c c c c c }
+ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
cline{1-9}
$chi_{(0,0,0)}$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$\
$chi_{(0,0,1)}$ & $1$ & $1$ & $1$ & $1$ & $-1$ & $-1$ & $-1$ & $-1$\
$chi_{(0,1,0)}$ & $1$ & $1$ & $-1$ & $-1$ & $1$ & $1$ & $-1$ & $-1$\
$chi_{(0,1,1)}$ & $1$ & $1$ & $-1$ & $-1$ & $-1$ & $-1$ & $1$ & $1$\
$chi_{(1,0,0)}$ & $1$ & $-1$ & $1$ & $-1$ & $1$ & $-1$ & $1$ & $-1$\
$chi_{(1,0,1)}$ & $1$ & $-1$ & $1$ & $-1$ & $-1$ & $1$ & $-1$ & $1$\
$chi_{(1,1,0)}$ & $1$ & $-1$ & $-1$ & $1$ & $1$ & $-1$ & $-1$ & $1$\
$chi_{(1,1,1)}$ & $1$ & $-1$ & $-1$ & $1$ & $-1$ & $1$ & $1$ & $-1$\
end{tabular}
end{align*}
spacing width
I am not sure I understand. What's it with the two documents you wrote? I only see one. You can change the fontsize e.g. withfootnotesize
, but that's probably not what you're asking, is it?
– sheß
Apr 1 at 11:04
You should not change the font sizes, you are already usingamsmath
, so why aren't you using the environments from it? I'd usealign*
and introduce line breaks on each of the original lines
– daleif
Apr 1 at 11:04
@daleif so it almost fits the default margins but it is off by a word or two so I don't want to break the line as it wouldn't look as neat. Ok I rechecked, its off by quite a lot, not what I aforementioned.
– Maths
Apr 1 at 11:08
For me those lines as off my up to 150pt. Remember, this is not about what is neat, it is about readability, consistency and good design. Changing the font size because something does not fit, or does not look neat, is not a good design.
– daleif
Apr 1 at 11:25
1
Regarding tables, quoting Robert Bringhurst (author of the Elements of Typographic style): "Tables are notoriously time-consuming to typeset, but the problems posed are often editorial as much as typographic. If the table is not planned in a readable form to begin with, the typographer can render it readable only by rewriting or redesigning it from scratch."
– daleif
Apr 1 at 11:38
|
show 3 more comments
so I've written one document using the default margin settings and another using different margin settings(much wider). I needed to compile both documents so there's an obvious issue now. Let me show you what I mean:
documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
usepackage{floatrow}
begin{document}
Computation of the Inverse Fourier transform from definition 3.1.3:
[
f_{(0,0,0)} = frac{1}{8}[f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}] = f_{(0,0,0)}
]
[
f_{(0,0,1)} = frac{1}{8}[f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}] = f_{(0,0,1)}
]
[
f_{(0,1,0)} = frac{1}{8}[f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}+f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}] = f_{(0,1,0)}
]
[
f_{(0,1,1)} = frac{1}{8}[f_{(0,1,1)}+f_{(0,1,1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}+f_{(0,1,1)}+f_{(0,1,1)}] = f_{(0,1,1)}
]
[
f_{(1,0,0)} = frac{1}{8}[f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}] = f_{(1,0,0)}
]
[
f_{(1,0,1)} = frac{1}{8}[f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}] = f_{(1,0,1)}
]
[
f_{(1,1,0)} = frac{1}{8}[f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}+f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}] = f_{(1,1,0)}
]
[
f_{(1,1,1)} = frac{1}{8}[f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}] = f_{(1,1,1)}
]
end{document}
I want to use the default margins which means making the code above font smaller or are there better solutions?
Thank you.
EDIT: I have rechecked the output and making the font smaller wont be useful. I think I should break the line using align but I don't know how to use it properly.
begin{align*}
setlengthextrarowheight{3pt}
noindentbegin{tabular}{c | c c c c c c c c }
+ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
cline{1-9}
$(0,0,0)$ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
$(0,0,1)$ & $(0,0,1)$ & $(0,0,0)$ & $(0,1,1)$ & $(0,1,0)$ & $(1,0,1)$ & $(1,0,0)$ & $(1,1,1)$ & $(1,1,0)$\
$(0,1,0)$ & $(0,1,0)$ & $(0,1,1)$ & $(0,0,0)$ & $(0,0,1)$ & $(1,1,0)$ & $(1,1,1)$ & $(1,0,0)$ & $(1,0,1)$\
$(0,1,1)$ & $(0,1,1)$ & $(0,1,0)$ & $(0,0,1)$ & $(0,0,0)$ & $(1,1,1)$ & $(1,1,0)$ & $(1,0,1)$ & $(1,0,0)$\
$(1,0,0)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$\
$(1,0,1)$ & $(1,0,1)$ & $(1,0,0)$ & $(1,1,1)$ & $(1,1,0)$ & $(0,0,1)$ & $(0,0,0)$ & $(0,1,1)$ & $(0,1,0)$\
$(1,1,0)$ & $(1,1,0)$ & $(1,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(0,0,0)$ & $(0,0,1)$\
$(1,1,1)$ & $(1,1,1)$ & $(1,1,0)$ & $(1,0,1)$ & $(1,0,0)$ & $(0,1,1)$ & $(0,1,0)$ & $(0,0,1)$ & $(0,0,0)$\
end{tabular}
end{align*}
The character table:
begin{align*}
setlengthextrarowheight{3pt}
noindentbegin{tabular}{c | c c c c c c c c }
+ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
cline{1-9}
$chi_{(0,0,0)}$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$\
$chi_{(0,0,1)}$ & $1$ & $1$ & $1$ & $1$ & $-1$ & $-1$ & $-1$ & $-1$\
$chi_{(0,1,0)}$ & $1$ & $1$ & $-1$ & $-1$ & $1$ & $1$ & $-1$ & $-1$\
$chi_{(0,1,1)}$ & $1$ & $1$ & $-1$ & $-1$ & $-1$ & $-1$ & $1$ & $1$\
$chi_{(1,0,0)}$ & $1$ & $-1$ & $1$ & $-1$ & $1$ & $-1$ & $1$ & $-1$\
$chi_{(1,0,1)}$ & $1$ & $-1$ & $1$ & $-1$ & $-1$ & $1$ & $-1$ & $1$\
$chi_{(1,1,0)}$ & $1$ & $-1$ & $-1$ & $1$ & $1$ & $-1$ & $-1$ & $1$\
$chi_{(1,1,1)}$ & $1$ & $-1$ & $-1$ & $1$ & $-1$ & $1$ & $1$ & $-1$\
end{tabular}
end{align*}
spacing width
so I've written one document using the default margin settings and another using different margin settings(much wider). I needed to compile both documents so there's an obvious issue now. Let me show you what I mean:
documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
usepackage{floatrow}
begin{document}
Computation of the Inverse Fourier transform from definition 3.1.3:
[
f_{(0,0,0)} = frac{1}{8}[f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}] = f_{(0,0,0)}
]
[
f_{(0,0,1)} = frac{1}{8}[f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot {(-1)}] = f_{(0,0,1)}
]
[
f_{(0,1,0)} = frac{1}{8}[f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}+f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}] = f_{(0,1,0)}
]
[
f_{(0,1,1)} = frac{1}{8}[f_{(0,1,1)}+f_{(0,1,1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}+f_{(0,1,1)}+f_{(0,1,1)}] = f_{(0,1,1)}
]
[
f_{(1,0,0)} = frac{1}{8}[f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}] = f_{(1,0,0)}
]
[
f_{(1,0,1)} = frac{1}{8}[f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}] = f_{(1,0,1)}
]
[
f_{(1,1,0)} = frac{1}{8}[f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}+f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}] = f_{(1,1,0)}
]
[
f_{(1,1,1)} = frac{1}{8}[f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}] = f_{(1,1,1)}
]
end{document}
I want to use the default margins which means making the code above font smaller or are there better solutions?
Thank you.
EDIT: I have rechecked the output and making the font smaller wont be useful. I think I should break the line using align but I don't know how to use it properly.
begin{align*}
setlengthextrarowheight{3pt}
noindentbegin{tabular}{c | c c c c c c c c }
+ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
cline{1-9}
$(0,0,0)$ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
$(0,0,1)$ & $(0,0,1)$ & $(0,0,0)$ & $(0,1,1)$ & $(0,1,0)$ & $(1,0,1)$ & $(1,0,0)$ & $(1,1,1)$ & $(1,1,0)$\
$(0,1,0)$ & $(0,1,0)$ & $(0,1,1)$ & $(0,0,0)$ & $(0,0,1)$ & $(1,1,0)$ & $(1,1,1)$ & $(1,0,0)$ & $(1,0,1)$\
$(0,1,1)$ & $(0,1,1)$ & $(0,1,0)$ & $(0,0,1)$ & $(0,0,0)$ & $(1,1,1)$ & $(1,1,0)$ & $(1,0,1)$ & $(1,0,0)$\
$(1,0,0)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$\
$(1,0,1)$ & $(1,0,1)$ & $(1,0,0)$ & $(1,1,1)$ & $(1,1,0)$ & $(0,0,1)$ & $(0,0,0)$ & $(0,1,1)$ & $(0,1,0)$\
$(1,1,0)$ & $(1,1,0)$ & $(1,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(0,0,0)$ & $(0,0,1)$\
$(1,1,1)$ & $(1,1,1)$ & $(1,1,0)$ & $(1,0,1)$ & $(1,0,0)$ & $(0,1,1)$ & $(0,1,0)$ & $(0,0,1)$ & $(0,0,0)$\
end{tabular}
end{align*}
The character table:
begin{align*}
setlengthextrarowheight{3pt}
noindentbegin{tabular}{c | c c c c c c c c }
+ & $(0,0,0)$ & $(0,0,1)$ & $(0,1,0)$ & $(0,1,1)$ & $(1,0,0)$ & $(1,0,1)$ & $(1,1,0)$ & $(1,1,1)$\
cline{1-9}
$chi_{(0,0,0)}$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$ & $1$\
$chi_{(0,0,1)}$ & $1$ & $1$ & $1$ & $1$ & $-1$ & $-1$ & $-1$ & $-1$\
$chi_{(0,1,0)}$ & $1$ & $1$ & $-1$ & $-1$ & $1$ & $1$ & $-1$ & $-1$\
$chi_{(0,1,1)}$ & $1$ & $1$ & $-1$ & $-1$ & $-1$ & $-1$ & $1$ & $1$\
$chi_{(1,0,0)}$ & $1$ & $-1$ & $1$ & $-1$ & $1$ & $-1$ & $1$ & $-1$\
$chi_{(1,0,1)}$ & $1$ & $-1$ & $1$ & $-1$ & $-1$ & $1$ & $-1$ & $1$\
$chi_{(1,1,0)}$ & $1$ & $-1$ & $-1$ & $1$ & $1$ & $-1$ & $-1$ & $1$\
$chi_{(1,1,1)}$ & $1$ & $-1$ & $-1$ & $1$ & $-1$ & $1$ & $1$ & $-1$\
end{tabular}
end{align*}
spacing width
spacing width
edited Apr 1 at 11:36
Maths
asked Apr 1 at 10:59
MathsMaths
44311
44311
I am not sure I understand. What's it with the two documents you wrote? I only see one. You can change the fontsize e.g. withfootnotesize
, but that's probably not what you're asking, is it?
– sheß
Apr 1 at 11:04
You should not change the font sizes, you are already usingamsmath
, so why aren't you using the environments from it? I'd usealign*
and introduce line breaks on each of the original lines
– daleif
Apr 1 at 11:04
@daleif so it almost fits the default margins but it is off by a word or two so I don't want to break the line as it wouldn't look as neat. Ok I rechecked, its off by quite a lot, not what I aforementioned.
– Maths
Apr 1 at 11:08
For me those lines as off my up to 150pt. Remember, this is not about what is neat, it is about readability, consistency and good design. Changing the font size because something does not fit, or does not look neat, is not a good design.
– daleif
Apr 1 at 11:25
1
Regarding tables, quoting Robert Bringhurst (author of the Elements of Typographic style): "Tables are notoriously time-consuming to typeset, but the problems posed are often editorial as much as typographic. If the table is not planned in a readable form to begin with, the typographer can render it readable only by rewriting or redesigning it from scratch."
– daleif
Apr 1 at 11:38
|
show 3 more comments
I am not sure I understand. What's it with the two documents you wrote? I only see one. You can change the fontsize e.g. withfootnotesize
, but that's probably not what you're asking, is it?
– sheß
Apr 1 at 11:04
You should not change the font sizes, you are already usingamsmath
, so why aren't you using the environments from it? I'd usealign*
and introduce line breaks on each of the original lines
– daleif
Apr 1 at 11:04
@daleif so it almost fits the default margins but it is off by a word or two so I don't want to break the line as it wouldn't look as neat. Ok I rechecked, its off by quite a lot, not what I aforementioned.
– Maths
Apr 1 at 11:08
For me those lines as off my up to 150pt. Remember, this is not about what is neat, it is about readability, consistency and good design. Changing the font size because something does not fit, or does not look neat, is not a good design.
– daleif
Apr 1 at 11:25
1
Regarding tables, quoting Robert Bringhurst (author of the Elements of Typographic style): "Tables are notoriously time-consuming to typeset, but the problems posed are often editorial as much as typographic. If the table is not planned in a readable form to begin with, the typographer can render it readable only by rewriting or redesigning it from scratch."
– daleif
Apr 1 at 11:38
I am not sure I understand. What's it with the two documents you wrote? I only see one. You can change the fontsize e.g. with
footnotesize
, but that's probably not what you're asking, is it?– sheß
Apr 1 at 11:04
I am not sure I understand. What's it with the two documents you wrote? I only see one. You can change the fontsize e.g. with
footnotesize
, but that's probably not what you're asking, is it?– sheß
Apr 1 at 11:04
You should not change the font sizes, you are already using
amsmath
, so why aren't you using the environments from it? I'd use align*
and introduce line breaks on each of the original lines– daleif
Apr 1 at 11:04
You should not change the font sizes, you are already using
amsmath
, so why aren't you using the environments from it? I'd use align*
and introduce line breaks on each of the original lines– daleif
Apr 1 at 11:04
@daleif so it almost fits the default margins but it is off by a word or two so I don't want to break the line as it wouldn't look as neat. Ok I rechecked, its off by quite a lot, not what I aforementioned.
– Maths
Apr 1 at 11:08
@daleif so it almost fits the default margins but it is off by a word or two so I don't want to break the line as it wouldn't look as neat. Ok I rechecked, its off by quite a lot, not what I aforementioned.
– Maths
Apr 1 at 11:08
For me those lines as off my up to 150pt. Remember, this is not about what is neat, it is about readability, consistency and good design. Changing the font size because something does not fit, or does not look neat, is not a good design.
– daleif
Apr 1 at 11:25
For me those lines as off my up to 150pt. Remember, this is not about what is neat, it is about readability, consistency and good design. Changing the font size because something does not fit, or does not look neat, is not a good design.
– daleif
Apr 1 at 11:25
1
1
Regarding tables, quoting Robert Bringhurst (author of the Elements of Typographic style): "Tables are notoriously time-consuming to typeset, but the problems posed are often editorial as much as typographic. If the table is not planned in a readable form to begin with, the typographer can render it readable only by rewriting or redesigning it from scratch."
– daleif
Apr 1 at 11:38
Regarding tables, quoting Robert Bringhurst (author of the Elements of Typographic style): "Tables are notoriously time-consuming to typeset, but the problems posed are often editorial as much as typographic. If the table is not planned in a readable form to begin with, the typographer can render it readable only by rewriting or redesigning it from scratch."
– daleif
Apr 1 at 11:38
|
show 3 more comments
1 Answer
1
active
oldest
votes
Here is probably how I'd typeset it. Note, there is a thought behind where each line is broken, highlighting the ending =f...
documentclass[11pt, a4paper]{report}
usepackage{amsmath}
begin{document}
Computation of the Inverse Fourier transform from definition 3.1.3:
begin{align*}
f_{(0,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}
\
&+f_{(0,0,0)}
+f_{(0,0,0)}
+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}bigr]
= f_{(0,0,0)}
end{aligned}
\
f_{(0,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}-f_{(0,0,1)}cdot
{(-1)}\
&-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot
{(-1)}-f_{(0,0,1)}cdot {(-1)}bigr] = f_{(0,0,1)}
end{aligned}
\
f_{(0,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}
\
&+f_{(0,1,0)}
+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}bigr] =
f_{(0,1,0)}
end{aligned}
\
f_{(0,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,1)}+f_{(0,1,1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}
\
&-f_{(0,1,1)}cdot{(-1)}
-f_{(0,1,1)}cdot{(-1)}+f_{(0,1,1)}+f_{(0,1,1)}bigr]
= f_{(0,1,1)}
end{aligned}
\
f_{(1,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}
\
&+f_{(1,0,0)}
-f_{(1,0,0)}cdot{(-1)}
+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}bigr]
= f_{(1,0,0)}
end{aligned}
\
f_{(1,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}
\
&-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}bigr]
= f_{(1,0,1)}
end{aligned}
\
f_{(1,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}
\
&+f_{(1,1,0)}
-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}bigr]
= f_{(1,1,0)}
end{aligned}
\
f_{(1,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}
\
&
-f_{(1,1,1)}cdot{(-1)}
+f_{(1,1,1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}bigr]
= f_{(1,1,1)}
end{aligned}
end{align*}
end{document}
I cannot thank you enough for the solution provided. +1
– Maths
Apr 1 at 11:45
Now If I may ask, how can I apply a similar trick to the tables in the question?
– Maths
Apr 1 at 11:47
1
Please post another question instead of highjacking, and note that tabulars does not belong in math mode, use array instead.
– daleif
Apr 1 at 11:56
add a comment |
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1 Answer
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Here is probably how I'd typeset it. Note, there is a thought behind where each line is broken, highlighting the ending =f...
documentclass[11pt, a4paper]{report}
usepackage{amsmath}
begin{document}
Computation of the Inverse Fourier transform from definition 3.1.3:
begin{align*}
f_{(0,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}
\
&+f_{(0,0,0)}
+f_{(0,0,0)}
+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}bigr]
= f_{(0,0,0)}
end{aligned}
\
f_{(0,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}-f_{(0,0,1)}cdot
{(-1)}\
&-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot
{(-1)}-f_{(0,0,1)}cdot {(-1)}bigr] = f_{(0,0,1)}
end{aligned}
\
f_{(0,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}
\
&+f_{(0,1,0)}
+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}bigr] =
f_{(0,1,0)}
end{aligned}
\
f_{(0,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,1)}+f_{(0,1,1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}
\
&-f_{(0,1,1)}cdot{(-1)}
-f_{(0,1,1)}cdot{(-1)}+f_{(0,1,1)}+f_{(0,1,1)}bigr]
= f_{(0,1,1)}
end{aligned}
\
f_{(1,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}
\
&+f_{(1,0,0)}
-f_{(1,0,0)}cdot{(-1)}
+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}bigr]
= f_{(1,0,0)}
end{aligned}
\
f_{(1,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}
\
&-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}bigr]
= f_{(1,0,1)}
end{aligned}
\
f_{(1,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}
\
&+f_{(1,1,0)}
-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}bigr]
= f_{(1,1,0)}
end{aligned}
\
f_{(1,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}
\
&
-f_{(1,1,1)}cdot{(-1)}
+f_{(1,1,1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}bigr]
= f_{(1,1,1)}
end{aligned}
end{align*}
end{document}
I cannot thank you enough for the solution provided. +1
– Maths
Apr 1 at 11:45
Now If I may ask, how can I apply a similar trick to the tables in the question?
– Maths
Apr 1 at 11:47
1
Please post another question instead of highjacking, and note that tabulars does not belong in math mode, use array instead.
– daleif
Apr 1 at 11:56
add a comment |
Here is probably how I'd typeset it. Note, there is a thought behind where each line is broken, highlighting the ending =f...
documentclass[11pt, a4paper]{report}
usepackage{amsmath}
begin{document}
Computation of the Inverse Fourier transform from definition 3.1.3:
begin{align*}
f_{(0,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}
\
&+f_{(0,0,0)}
+f_{(0,0,0)}
+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}bigr]
= f_{(0,0,0)}
end{aligned}
\
f_{(0,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}-f_{(0,0,1)}cdot
{(-1)}\
&-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot
{(-1)}-f_{(0,0,1)}cdot {(-1)}bigr] = f_{(0,0,1)}
end{aligned}
\
f_{(0,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}
\
&+f_{(0,1,0)}
+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}bigr] =
f_{(0,1,0)}
end{aligned}
\
f_{(0,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,1)}+f_{(0,1,1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}
\
&-f_{(0,1,1)}cdot{(-1)}
-f_{(0,1,1)}cdot{(-1)}+f_{(0,1,1)}+f_{(0,1,1)}bigr]
= f_{(0,1,1)}
end{aligned}
\
f_{(1,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}
\
&+f_{(1,0,0)}
-f_{(1,0,0)}cdot{(-1)}
+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}bigr]
= f_{(1,0,0)}
end{aligned}
\
f_{(1,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}
\
&-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}bigr]
= f_{(1,0,1)}
end{aligned}
\
f_{(1,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}
\
&+f_{(1,1,0)}
-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}bigr]
= f_{(1,1,0)}
end{aligned}
\
f_{(1,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}
\
&
-f_{(1,1,1)}cdot{(-1)}
+f_{(1,1,1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}bigr]
= f_{(1,1,1)}
end{aligned}
end{align*}
end{document}
I cannot thank you enough for the solution provided. +1
– Maths
Apr 1 at 11:45
Now If I may ask, how can I apply a similar trick to the tables in the question?
– Maths
Apr 1 at 11:47
1
Please post another question instead of highjacking, and note that tabulars does not belong in math mode, use array instead.
– daleif
Apr 1 at 11:56
add a comment |
Here is probably how I'd typeset it. Note, there is a thought behind where each line is broken, highlighting the ending =f...
documentclass[11pt, a4paper]{report}
usepackage{amsmath}
begin{document}
Computation of the Inverse Fourier transform from definition 3.1.3:
begin{align*}
f_{(0,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}
\
&+f_{(0,0,0)}
+f_{(0,0,0)}
+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}bigr]
= f_{(0,0,0)}
end{aligned}
\
f_{(0,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}-f_{(0,0,1)}cdot
{(-1)}\
&-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot
{(-1)}-f_{(0,0,1)}cdot {(-1)}bigr] = f_{(0,0,1)}
end{aligned}
\
f_{(0,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}
\
&+f_{(0,1,0)}
+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}bigr] =
f_{(0,1,0)}
end{aligned}
\
f_{(0,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,1)}+f_{(0,1,1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}
\
&-f_{(0,1,1)}cdot{(-1)}
-f_{(0,1,1)}cdot{(-1)}+f_{(0,1,1)}+f_{(0,1,1)}bigr]
= f_{(0,1,1)}
end{aligned}
\
f_{(1,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}
\
&+f_{(1,0,0)}
-f_{(1,0,0)}cdot{(-1)}
+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}bigr]
= f_{(1,0,0)}
end{aligned}
\
f_{(1,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}
\
&-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}bigr]
= f_{(1,0,1)}
end{aligned}
\
f_{(1,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}
\
&+f_{(1,1,0)}
-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}bigr]
= f_{(1,1,0)}
end{aligned}
\
f_{(1,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}
\
&
-f_{(1,1,1)}cdot{(-1)}
+f_{(1,1,1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}bigr]
= f_{(1,1,1)}
end{aligned}
end{align*}
end{document}
Here is probably how I'd typeset it. Note, there is a thought behind where each line is broken, highlighting the ending =f...
documentclass[11pt, a4paper]{report}
usepackage{amsmath}
begin{document}
Computation of the Inverse Fourier transform from definition 3.1.3:
begin{align*}
f_{(0,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}
\
&+f_{(0,0,0)}
+f_{(0,0,0)}
+f_{(0,0,0)}+f_{(0,0,0)}+f_{(0,0,0)}bigr]
= f_{(0,0,0)}
end{aligned}
\
f_{(0,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}+f_{(0,0,1)}-f_{(0,0,1)}cdot
{(-1)}\
&-f_{(0,0,1)}cdot {(-1)}-f_{(0,0,1)}cdot
{(-1)}-f_{(0,0,1)}cdot {(-1)}bigr] = f_{(0,0,1)}
end{aligned}
\
f_{(0,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,0)}+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}
\
&+f_{(0,1,0)}
+f_{(0,1,0)}-f_{(0,1,0)}cdot{(-1)}-f_{(0,1,0)}cdot{(-1)}bigr] =
f_{(0,1,0)}
end{aligned}
\
f_{(0,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(0,1,1)}+f_{(0,1,1)}-f_{(0,1,1)}cdot{(-1)}-f_{(0,1,1)}cdot{(-1)}
\
&-f_{(0,1,1)}cdot{(-1)}
-f_{(0,1,1)}cdot{(-1)}+f_{(0,1,1)}+f_{(0,1,1)}bigr]
= f_{(0,1,1)}
end{aligned}
\
f_{(1,0,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}
\
&+f_{(1,0,0)}
-f_{(1,0,0)}cdot{(-1)}
+f_{(1,0,0)}-f_{(1,0,0)}cdot{(-1)}bigr]
= f_{(1,0,0)}
end{aligned}
\
f_{(1,0,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}
\
&-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}-f_{(1,0,1)}cdot{(-1)}+f_{(1,0,1)}bigr]
= f_{(1,0,1)}
end{aligned}
\
f_{(1,1,0)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,0)}-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}
\
&+f_{(1,1,0)}
-f_{(1,1,0)}cdot{(-1)}-f_{(1,1,0)}cdot{(-1)}+f_{(1,1,0)}bigr]
= f_{(1,1,0)}
end{aligned}
\
f_{(1,1,1)} &= frac{1}{8}
begin{aligned}[t]
bigl[&f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}-f_{(1,1,1)}cdot{(-1)}+f_{(1,1,1)}
\
&
-f_{(1,1,1)}cdot{(-1)}
+f_{(1,1,1)}+f_{(1,1,1)}-f_{(1,1,1)}cdot{(-1)}bigr]
= f_{(1,1,1)}
end{aligned}
end{align*}
end{document}
answered Apr 1 at 11:42
daleifdaleif
33.8k255118
33.8k255118
I cannot thank you enough for the solution provided. +1
– Maths
Apr 1 at 11:45
Now If I may ask, how can I apply a similar trick to the tables in the question?
– Maths
Apr 1 at 11:47
1
Please post another question instead of highjacking, and note that tabulars does not belong in math mode, use array instead.
– daleif
Apr 1 at 11:56
add a comment |
I cannot thank you enough for the solution provided. +1
– Maths
Apr 1 at 11:45
Now If I may ask, how can I apply a similar trick to the tables in the question?
– Maths
Apr 1 at 11:47
1
Please post another question instead of highjacking, and note that tabulars does not belong in math mode, use array instead.
– daleif
Apr 1 at 11:56
I cannot thank you enough for the solution provided. +1
– Maths
Apr 1 at 11:45
I cannot thank you enough for the solution provided. +1
– Maths
Apr 1 at 11:45
Now If I may ask, how can I apply a similar trick to the tables in the question?
– Maths
Apr 1 at 11:47
Now If I may ask, how can I apply a similar trick to the tables in the question?
– Maths
Apr 1 at 11:47
1
1
Please post another question instead of highjacking, and note that tabulars does not belong in math mode, use array instead.
– daleif
Apr 1 at 11:56
Please post another question instead of highjacking, and note that tabulars does not belong in math mode, use array instead.
– daleif
Apr 1 at 11:56
add a comment |
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I am not sure I understand. What's it with the two documents you wrote? I only see one. You can change the fontsize e.g. with
footnotesize
, but that's probably not what you're asking, is it?– sheß
Apr 1 at 11:04
You should not change the font sizes, you are already using
amsmath
, so why aren't you using the environments from it? I'd usealign*
and introduce line breaks on each of the original lines– daleif
Apr 1 at 11:04
@daleif so it almost fits the default margins but it is off by a word or two so I don't want to break the line as it wouldn't look as neat. Ok I rechecked, its off by quite a lot, not what I aforementioned.
– Maths
Apr 1 at 11:08
For me those lines as off my up to 150pt. Remember, this is not about what is neat, it is about readability, consistency and good design. Changing the font size because something does not fit, or does not look neat, is not a good design.
– daleif
Apr 1 at 11:25
1
Regarding tables, quoting Robert Bringhurst (author of the Elements of Typographic style): "Tables are notoriously time-consuming to typeset, but the problems posed are often editorial as much as typographic. If the table is not planned in a readable form to begin with, the typographer can render it readable only by rewriting or redesigning it from scratch."
– daleif
Apr 1 at 11:38