Contour integral over a non-rectifiable contour












1












$begingroup$


In chapter 16 of Mathematical Analysis Apostol defines contour integrals in terms of Riemann-Stieltjes integrals, specifically:



$$int_gamma f = int_a^b f[gamma(t)],dgamma(t)$$
whenever the Riemann-Stieltjes integral on the right exists. My question would be "Find necessary and sufficient conditions on a contour $gamma$ to ensure that the Riemann-Stieltjes integral defined above (and thus the contour integral) exists for all continuous complex functions $f$."



It is well-known that requiring $gamma$ to be rectifiable is a sufficient condition for the contour integral to exist. But is it necessary? Is it the case that for every non-rectifiable curve $gamma$ we can find a continuous function $f$ for which $int_gamma f$ (as defined above) does not exist? If it is not a necessary condition, what is?










share|cite|improve this question









$endgroup$












  • $begingroup$
    If $f(x) = 1$ then for every tagged partition of the interval [a,b] the finite Riemann sum has the form $sum_{i=1}^n(gamma(x_i) - gamma(x_{i-1}))$ which is a telescoping sum that collapses to $gamma(x_n) - gamma(x_0) = gamma(b) - gamma(a)$. Non-rectifiability only means that partitions can be found that make $sum_{i=1}^n|gamma(x_i) - gamma(x_{i-1})|$ arbitrarily high.
    $endgroup$
    – A.C.
    Dec 14 '18 at 21:05
















1












$begingroup$


In chapter 16 of Mathematical Analysis Apostol defines contour integrals in terms of Riemann-Stieltjes integrals, specifically:



$$int_gamma f = int_a^b f[gamma(t)],dgamma(t)$$
whenever the Riemann-Stieltjes integral on the right exists. My question would be "Find necessary and sufficient conditions on a contour $gamma$ to ensure that the Riemann-Stieltjes integral defined above (and thus the contour integral) exists for all continuous complex functions $f$."



It is well-known that requiring $gamma$ to be rectifiable is a sufficient condition for the contour integral to exist. But is it necessary? Is it the case that for every non-rectifiable curve $gamma$ we can find a continuous function $f$ for which $int_gamma f$ (as defined above) does not exist? If it is not a necessary condition, what is?










share|cite|improve this question









$endgroup$












  • $begingroup$
    If $f(x) = 1$ then for every tagged partition of the interval [a,b] the finite Riemann sum has the form $sum_{i=1}^n(gamma(x_i) - gamma(x_{i-1}))$ which is a telescoping sum that collapses to $gamma(x_n) - gamma(x_0) = gamma(b) - gamma(a)$. Non-rectifiability only means that partitions can be found that make $sum_{i=1}^n|gamma(x_i) - gamma(x_{i-1})|$ arbitrarily high.
    $endgroup$
    – A.C.
    Dec 14 '18 at 21:05














1












1








1


1



$begingroup$


In chapter 16 of Mathematical Analysis Apostol defines contour integrals in terms of Riemann-Stieltjes integrals, specifically:



$$int_gamma f = int_a^b f[gamma(t)],dgamma(t)$$
whenever the Riemann-Stieltjes integral on the right exists. My question would be "Find necessary and sufficient conditions on a contour $gamma$ to ensure that the Riemann-Stieltjes integral defined above (and thus the contour integral) exists for all continuous complex functions $f$."



It is well-known that requiring $gamma$ to be rectifiable is a sufficient condition for the contour integral to exist. But is it necessary? Is it the case that for every non-rectifiable curve $gamma$ we can find a continuous function $f$ for which $int_gamma f$ (as defined above) does not exist? If it is not a necessary condition, what is?










share|cite|improve this question









$endgroup$




In chapter 16 of Mathematical Analysis Apostol defines contour integrals in terms of Riemann-Stieltjes integrals, specifically:



$$int_gamma f = int_a^b f[gamma(t)],dgamma(t)$$
whenever the Riemann-Stieltjes integral on the right exists. My question would be "Find necessary and sufficient conditions on a contour $gamma$ to ensure that the Riemann-Stieltjes integral defined above (and thus the contour integral) exists for all continuous complex functions $f$."



It is well-known that requiring $gamma$ to be rectifiable is a sufficient condition for the contour integral to exist. But is it necessary? Is it the case that for every non-rectifiable curve $gamma$ we can find a continuous function $f$ for which $int_gamma f$ (as defined above) does not exist? If it is not a necessary condition, what is?







complex-analysis contour-integration






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 14 '18 at 20:23









A.C.A.C.

112




112












  • $begingroup$
    If $f(x) = 1$ then for every tagged partition of the interval [a,b] the finite Riemann sum has the form $sum_{i=1}^n(gamma(x_i) - gamma(x_{i-1}))$ which is a telescoping sum that collapses to $gamma(x_n) - gamma(x_0) = gamma(b) - gamma(a)$. Non-rectifiability only means that partitions can be found that make $sum_{i=1}^n|gamma(x_i) - gamma(x_{i-1})|$ arbitrarily high.
    $endgroup$
    – A.C.
    Dec 14 '18 at 21:05


















  • $begingroup$
    If $f(x) = 1$ then for every tagged partition of the interval [a,b] the finite Riemann sum has the form $sum_{i=1}^n(gamma(x_i) - gamma(x_{i-1}))$ which is a telescoping sum that collapses to $gamma(x_n) - gamma(x_0) = gamma(b) - gamma(a)$. Non-rectifiability only means that partitions can be found that make $sum_{i=1}^n|gamma(x_i) - gamma(x_{i-1})|$ arbitrarily high.
    $endgroup$
    – A.C.
    Dec 14 '18 at 21:05
















$begingroup$
If $f(x) = 1$ then for every tagged partition of the interval [a,b] the finite Riemann sum has the form $sum_{i=1}^n(gamma(x_i) - gamma(x_{i-1}))$ which is a telescoping sum that collapses to $gamma(x_n) - gamma(x_0) = gamma(b) - gamma(a)$. Non-rectifiability only means that partitions can be found that make $sum_{i=1}^n|gamma(x_i) - gamma(x_{i-1})|$ arbitrarily high.
$endgroup$
– A.C.
Dec 14 '18 at 21:05




$begingroup$
If $f(x) = 1$ then for every tagged partition of the interval [a,b] the finite Riemann sum has the form $sum_{i=1}^n(gamma(x_i) - gamma(x_{i-1}))$ which is a telescoping sum that collapses to $gamma(x_n) - gamma(x_0) = gamma(b) - gamma(a)$. Non-rectifiability only means that partitions can be found that make $sum_{i=1}^n|gamma(x_i) - gamma(x_{i-1})|$ arbitrarily high.
$endgroup$
– A.C.
Dec 14 '18 at 21:05










0






active

oldest

votes












Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3039844%2fcontour-integral-over-a-non-rectifiable-contour%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3039844%2fcontour-integral-over-a-non-rectifiable-contour%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

How to change which sound is reproduced for terminal bell?

Title Spacing in Bjornstrup Chapter, Removing Chapter Number From Contents

Can I use Tabulator js library in my java Spring + Thymeleaf project?