SQLAlchemy Relationship with Composite Joins











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I am trying to find the right way to specify a relationship between SQL alchemy tables that join on conditions from two related tables.



I have a SQL statment equivalent to:



select a.id
, b.id
, b.b_val
, c.id
, c.c_dt
, c.c_val
from a
join b
on a.id = b.id
join c
on b.id = c.id
and a.date <-= c.date
and a.date < current_date;


What I am currently getting out of SQLAlchemy is:



print(q)

SELECT schema.a.id AS schema_a_id
, schema.b.id AS schema_b_id
, schema.b.b_val AS schema_b_b_val
, schema.c.id AS schema_c_id
, schema.c.c_dt AS schema_c_c_dt
, schema.c.c_val AS schema_c_c_val
FROM schema.a
JOIN schema.b
ON schema.a.id = schema.b.id
JOIN schema.c
ON schema.a.secondary_id = schema.c.id
-- I'm missing the rest of the join clause here


I'm getting thrown off by the join condition to the c table. In it I want to use a constraint on the date column with two conditions. I attempted to do this using the primaryjoin field in my relationship but so far no luck.



Here's my minimum reproducible example:



Base = declarative_base()

class A(Base):
__tablename__ = 'a'
__table_args__ = {'schema':'schema'}
id = Column(Integer(), primary_key=True)
secondary_id = Column(Integer())
a_dt = Column(Date())
b_rel = relationship('b', uselist=False, back_populates="a")
c_rel = relationship('c', primaryjoin="and_(a.a_dt >= c.c_dt, a.a_dt < func.current_date())")

class B(Base):
__tablename__ = 'b'
__table_args__ = {'schema':'schema'}
id = Column(Integer, ForeignKey(A.id), primary_key=True)
b_val = Column(Integer())

class C(Base):
__tablename__ = 'c'
__table_args__ = {'schema':'schema'}
id = Column(Integer(), ForeignKey(A.secondary_id), primary_key=True)
c_dt = Column(Date())
c_val = Column(Integer())

engine = create_engine('teradatasql://'+user+':'+pswd+'@'+host)

Session = sessionmaker()
Session.configure(bind=engine)
sess = Session()

q = sess.query(A.id, B.id, B.b_val, C.id, C.c_dt, C.c_val).join(B).join(C)

# result is shown above


What am I missing that I could add to cause this relationship to function properly?










share|improve this question
























  • Given an entity Query.join() will attempt to join using natural foreign key relationships between the two, so you'd want to pass A.c_rel instead, but that is not going to work either given your models, which seem to disagree with your desired query.
    – Ilja Everilä
    Nov 14 at 20:02












  • How do the models disagree with the desired query? That is what I am trying to determine.
    – Sledge
    Nov 14 at 21:37










  • The primary join of A.c_rel is slightly different from your desired SQL and in it you join c on b.id, though c and b have no direct foreign key relationship. I'm not entirely sure how you'd have to express having b in the join from A to C in this case.
    – Ilja Everilä
    Nov 15 at 8:38















up vote
0
down vote

favorite












I am trying to find the right way to specify a relationship between SQL alchemy tables that join on conditions from two related tables.



I have a SQL statment equivalent to:



select a.id
, b.id
, b.b_val
, c.id
, c.c_dt
, c.c_val
from a
join b
on a.id = b.id
join c
on b.id = c.id
and a.date <-= c.date
and a.date < current_date;


What I am currently getting out of SQLAlchemy is:



print(q)

SELECT schema.a.id AS schema_a_id
, schema.b.id AS schema_b_id
, schema.b.b_val AS schema_b_b_val
, schema.c.id AS schema_c_id
, schema.c.c_dt AS schema_c_c_dt
, schema.c.c_val AS schema_c_c_val
FROM schema.a
JOIN schema.b
ON schema.a.id = schema.b.id
JOIN schema.c
ON schema.a.secondary_id = schema.c.id
-- I'm missing the rest of the join clause here


I'm getting thrown off by the join condition to the c table. In it I want to use a constraint on the date column with two conditions. I attempted to do this using the primaryjoin field in my relationship but so far no luck.



Here's my minimum reproducible example:



Base = declarative_base()

class A(Base):
__tablename__ = 'a'
__table_args__ = {'schema':'schema'}
id = Column(Integer(), primary_key=True)
secondary_id = Column(Integer())
a_dt = Column(Date())
b_rel = relationship('b', uselist=False, back_populates="a")
c_rel = relationship('c', primaryjoin="and_(a.a_dt >= c.c_dt, a.a_dt < func.current_date())")

class B(Base):
__tablename__ = 'b'
__table_args__ = {'schema':'schema'}
id = Column(Integer, ForeignKey(A.id), primary_key=True)
b_val = Column(Integer())

class C(Base):
__tablename__ = 'c'
__table_args__ = {'schema':'schema'}
id = Column(Integer(), ForeignKey(A.secondary_id), primary_key=True)
c_dt = Column(Date())
c_val = Column(Integer())

engine = create_engine('teradatasql://'+user+':'+pswd+'@'+host)

Session = sessionmaker()
Session.configure(bind=engine)
sess = Session()

q = sess.query(A.id, B.id, B.b_val, C.id, C.c_dt, C.c_val).join(B).join(C)

# result is shown above


What am I missing that I could add to cause this relationship to function properly?










share|improve this question
























  • Given an entity Query.join() will attempt to join using natural foreign key relationships between the two, so you'd want to pass A.c_rel instead, but that is not going to work either given your models, which seem to disagree with your desired query.
    – Ilja Everilä
    Nov 14 at 20:02












  • How do the models disagree with the desired query? That is what I am trying to determine.
    – Sledge
    Nov 14 at 21:37










  • The primary join of A.c_rel is slightly different from your desired SQL and in it you join c on b.id, though c and b have no direct foreign key relationship. I'm not entirely sure how you'd have to express having b in the join from A to C in this case.
    – Ilja Everilä
    Nov 15 at 8:38













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am trying to find the right way to specify a relationship between SQL alchemy tables that join on conditions from two related tables.



I have a SQL statment equivalent to:



select a.id
, b.id
, b.b_val
, c.id
, c.c_dt
, c.c_val
from a
join b
on a.id = b.id
join c
on b.id = c.id
and a.date <-= c.date
and a.date < current_date;


What I am currently getting out of SQLAlchemy is:



print(q)

SELECT schema.a.id AS schema_a_id
, schema.b.id AS schema_b_id
, schema.b.b_val AS schema_b_b_val
, schema.c.id AS schema_c_id
, schema.c.c_dt AS schema_c_c_dt
, schema.c.c_val AS schema_c_c_val
FROM schema.a
JOIN schema.b
ON schema.a.id = schema.b.id
JOIN schema.c
ON schema.a.secondary_id = schema.c.id
-- I'm missing the rest of the join clause here


I'm getting thrown off by the join condition to the c table. In it I want to use a constraint on the date column with two conditions. I attempted to do this using the primaryjoin field in my relationship but so far no luck.



Here's my minimum reproducible example:



Base = declarative_base()

class A(Base):
__tablename__ = 'a'
__table_args__ = {'schema':'schema'}
id = Column(Integer(), primary_key=True)
secondary_id = Column(Integer())
a_dt = Column(Date())
b_rel = relationship('b', uselist=False, back_populates="a")
c_rel = relationship('c', primaryjoin="and_(a.a_dt >= c.c_dt, a.a_dt < func.current_date())")

class B(Base):
__tablename__ = 'b'
__table_args__ = {'schema':'schema'}
id = Column(Integer, ForeignKey(A.id), primary_key=True)
b_val = Column(Integer())

class C(Base):
__tablename__ = 'c'
__table_args__ = {'schema':'schema'}
id = Column(Integer(), ForeignKey(A.secondary_id), primary_key=True)
c_dt = Column(Date())
c_val = Column(Integer())

engine = create_engine('teradatasql://'+user+':'+pswd+'@'+host)

Session = sessionmaker()
Session.configure(bind=engine)
sess = Session()

q = sess.query(A.id, B.id, B.b_val, C.id, C.c_dt, C.c_val).join(B).join(C)

# result is shown above


What am I missing that I could add to cause this relationship to function properly?










share|improve this question















I am trying to find the right way to specify a relationship between SQL alchemy tables that join on conditions from two related tables.



I have a SQL statment equivalent to:



select a.id
, b.id
, b.b_val
, c.id
, c.c_dt
, c.c_val
from a
join b
on a.id = b.id
join c
on b.id = c.id
and a.date <-= c.date
and a.date < current_date;


What I am currently getting out of SQLAlchemy is:



print(q)

SELECT schema.a.id AS schema_a_id
, schema.b.id AS schema_b_id
, schema.b.b_val AS schema_b_b_val
, schema.c.id AS schema_c_id
, schema.c.c_dt AS schema_c_c_dt
, schema.c.c_val AS schema_c_c_val
FROM schema.a
JOIN schema.b
ON schema.a.id = schema.b.id
JOIN schema.c
ON schema.a.secondary_id = schema.c.id
-- I'm missing the rest of the join clause here


I'm getting thrown off by the join condition to the c table. In it I want to use a constraint on the date column with two conditions. I attempted to do this using the primaryjoin field in my relationship but so far no luck.



Here's my minimum reproducible example:



Base = declarative_base()

class A(Base):
__tablename__ = 'a'
__table_args__ = {'schema':'schema'}
id = Column(Integer(), primary_key=True)
secondary_id = Column(Integer())
a_dt = Column(Date())
b_rel = relationship('b', uselist=False, back_populates="a")
c_rel = relationship('c', primaryjoin="and_(a.a_dt >= c.c_dt, a.a_dt < func.current_date())")

class B(Base):
__tablename__ = 'b'
__table_args__ = {'schema':'schema'}
id = Column(Integer, ForeignKey(A.id), primary_key=True)
b_val = Column(Integer())

class C(Base):
__tablename__ = 'c'
__table_args__ = {'schema':'schema'}
id = Column(Integer(), ForeignKey(A.secondary_id), primary_key=True)
c_dt = Column(Date())
c_val = Column(Integer())

engine = create_engine('teradatasql://'+user+':'+pswd+'@'+host)

Session = sessionmaker()
Session.configure(bind=engine)
sess = Session()

q = sess.query(A.id, B.id, B.b_val, C.id, C.c_dt, C.c_val).join(B).join(C)

# result is shown above


What am I missing that I could add to cause this relationship to function properly?







python sqlalchemy






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 at 19:16

























asked Nov 14 at 17:26









Sledge

3551518




3551518












  • Given an entity Query.join() will attempt to join using natural foreign key relationships between the two, so you'd want to pass A.c_rel instead, but that is not going to work either given your models, which seem to disagree with your desired query.
    – Ilja Everilä
    Nov 14 at 20:02












  • How do the models disagree with the desired query? That is what I am trying to determine.
    – Sledge
    Nov 14 at 21:37










  • The primary join of A.c_rel is slightly different from your desired SQL and in it you join c on b.id, though c and b have no direct foreign key relationship. I'm not entirely sure how you'd have to express having b in the join from A to C in this case.
    – Ilja Everilä
    Nov 15 at 8:38


















  • Given an entity Query.join() will attempt to join using natural foreign key relationships between the two, so you'd want to pass A.c_rel instead, but that is not going to work either given your models, which seem to disagree with your desired query.
    – Ilja Everilä
    Nov 14 at 20:02












  • How do the models disagree with the desired query? That is what I am trying to determine.
    – Sledge
    Nov 14 at 21:37










  • The primary join of A.c_rel is slightly different from your desired SQL and in it you join c on b.id, though c and b have no direct foreign key relationship. I'm not entirely sure how you'd have to express having b in the join from A to C in this case.
    – Ilja Everilä
    Nov 15 at 8:38
















Given an entity Query.join() will attempt to join using natural foreign key relationships between the two, so you'd want to pass A.c_rel instead, but that is not going to work either given your models, which seem to disagree with your desired query.
– Ilja Everilä
Nov 14 at 20:02






Given an entity Query.join() will attempt to join using natural foreign key relationships between the two, so you'd want to pass A.c_rel instead, but that is not going to work either given your models, which seem to disagree with your desired query.
– Ilja Everilä
Nov 14 at 20:02














How do the models disagree with the desired query? That is what I am trying to determine.
– Sledge
Nov 14 at 21:37




How do the models disagree with the desired query? That is what I am trying to determine.
– Sledge
Nov 14 at 21:37












The primary join of A.c_rel is slightly different from your desired SQL and in it you join c on b.id, though c and b have no direct foreign key relationship. I'm not entirely sure how you'd have to express having b in the join from A to C in this case.
– Ilja Everilä
Nov 15 at 8:38




The primary join of A.c_rel is slightly different from your desired SQL and in it you join c on b.id, though c and b have no direct foreign key relationship. I'm not entirely sure how you'd have to express having b in the join from A to C in this case.
– Ilja Everilä
Nov 15 at 8:38

















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