Knapsack cover inequalities for a particular covering problem












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$begingroup$


The Knapsack cover inequalities for a constraint $ A_i x geq b$ where $x_{j}in{0,1}$ are:
$$sum_{ j notin S} tilde{ a}_j x_j geq b_i −sum_{ j in S } 1 $$
with $tilde{ a}_j = min {a_j , b_i − sum_{ j in S } 1 }$.
Given a covering polyhedron $P$ given by $ { x : Ax geq b, 0 leq x leq 1 } $ it is known that the integrality gap of $P'$ (given by constraints in $P$ and additional knapsack cover inequalites) and the integral hull of $P$ is at most 2.



Suppose our covering polyhedron is given, that $xin{0,1}^n$ with $n$ even and large, and that the rows of A are all vectors with $n/2$ ones. How would one go about finding a knapsack cover inequality that cuts the point 0.1 * $mathbb{1}$ (with $mathbb{1}$ the all ones vector)? I understand one can do this with iterative Chvátal cuts, but I'm wondering how one would use knapsack cover inequalities to cut such a point.










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    1












    $begingroup$


    The Knapsack cover inequalities for a constraint $ A_i x geq b$ where $x_{j}in{0,1}$ are:
    $$sum_{ j notin S} tilde{ a}_j x_j geq b_i −sum_{ j in S } 1 $$
    with $tilde{ a}_j = min {a_j , b_i − sum_{ j in S } 1 }$.
    Given a covering polyhedron $P$ given by $ { x : Ax geq b, 0 leq x leq 1 } $ it is known that the integrality gap of $P'$ (given by constraints in $P$ and additional knapsack cover inequalites) and the integral hull of $P$ is at most 2.



    Suppose our covering polyhedron is given, that $xin{0,1}^n$ with $n$ even and large, and that the rows of A are all vectors with $n/2$ ones. How would one go about finding a knapsack cover inequality that cuts the point 0.1 * $mathbb{1}$ (with $mathbb{1}$ the all ones vector)? I understand one can do this with iterative Chvátal cuts, but I'm wondering how one would use knapsack cover inequalities to cut such a point.










    share|cite|improve this question











    $endgroup$















      1












      1








      1





      $begingroup$


      The Knapsack cover inequalities for a constraint $ A_i x geq b$ where $x_{j}in{0,1}$ are:
      $$sum_{ j notin S} tilde{ a}_j x_j geq b_i −sum_{ j in S } 1 $$
      with $tilde{ a}_j = min {a_j , b_i − sum_{ j in S } 1 }$.
      Given a covering polyhedron $P$ given by $ { x : Ax geq b, 0 leq x leq 1 } $ it is known that the integrality gap of $P'$ (given by constraints in $P$ and additional knapsack cover inequalites) and the integral hull of $P$ is at most 2.



      Suppose our covering polyhedron is given, that $xin{0,1}^n$ with $n$ even and large, and that the rows of A are all vectors with $n/2$ ones. How would one go about finding a knapsack cover inequality that cuts the point 0.1 * $mathbb{1}$ (with $mathbb{1}$ the all ones vector)? I understand one can do this with iterative Chvátal cuts, but I'm wondering how one would use knapsack cover inequalities to cut such a point.










      share|cite|improve this question











      $endgroup$




      The Knapsack cover inequalities for a constraint $ A_i x geq b$ where $x_{j}in{0,1}$ are:
      $$sum_{ j notin S} tilde{ a}_j x_j geq b_i −sum_{ j in S } 1 $$
      with $tilde{ a}_j = min {a_j , b_i − sum_{ j in S } 1 }$.
      Given a covering polyhedron $P$ given by $ { x : Ax geq b, 0 leq x leq 1 } $ it is known that the integrality gap of $P'$ (given by constraints in $P$ and additional knapsack cover inequalites) and the integral hull of $P$ is at most 2.



      Suppose our covering polyhedron is given, that $xin{0,1}^n$ with $n$ even and large, and that the rows of A are all vectors with $n/2$ ones. How would one go about finding a knapsack cover inequality that cuts the point 0.1 * $mathbb{1}$ (with $mathbb{1}$ the all ones vector)? I understand one can do this with iterative Chvátal cuts, but I'm wondering how one would use knapsack cover inequalities to cut such a point.







      combinatorics linear-programming integer-programming






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      edited Dec 28 '18 at 17:20









      LinAlg

      10.1k1521




      10.1k1521










      asked Dec 14 '18 at 5:08









      Hao SunHao Sun

      155214




      155214






















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