Add time values in Python
I have a list of times that are in following format:
Hour:Minue:Second.Microseconds
File looks like this:
0:06:50.137529
0:08:55.439963
0:06:19.179093
0:07:16.680906
0:31:55.778010
0:16:56.940836
Is there a Python function or set of commands that will let me add all of these values together?
I initially "build" these values with the following code:
optimize_times =
starting_time=(datetime.now())
ending_time=(datetime.now())
optimize_times.append(str(ending_time-starting_time))
python string python-2.7 datetime timedelta
add a comment |
I have a list of times that are in following format:
Hour:Minue:Second.Microseconds
File looks like this:
0:06:50.137529
0:08:55.439963
0:06:19.179093
0:07:16.680906
0:31:55.778010
0:16:56.940836
Is there a Python function or set of commands that will let me add all of these values together?
I initially "build" these values with the following code:
optimize_times =
starting_time=(datetime.now())
ending_time=(datetime.now())
optimize_times.append(str(ending_time-starting_time))
python string python-2.7 datetime timedelta
Yes,timedelta
, but it's not clear to me why you callstr()
on your results.
– roganjosh
Nov 20 '18 at 21:24
Without using the str function the value resulted in a timedelta function being output
– user3299633
Nov 20 '18 at 21:37
add a comment |
I have a list of times that are in following format:
Hour:Minue:Second.Microseconds
File looks like this:
0:06:50.137529
0:08:55.439963
0:06:19.179093
0:07:16.680906
0:31:55.778010
0:16:56.940836
Is there a Python function or set of commands that will let me add all of these values together?
I initially "build" these values with the following code:
optimize_times =
starting_time=(datetime.now())
ending_time=(datetime.now())
optimize_times.append(str(ending_time-starting_time))
python string python-2.7 datetime timedelta
I have a list of times that are in following format:
Hour:Minue:Second.Microseconds
File looks like this:
0:06:50.137529
0:08:55.439963
0:06:19.179093
0:07:16.680906
0:31:55.778010
0:16:56.940836
Is there a Python function or set of commands that will let me add all of these values together?
I initially "build" these values with the following code:
optimize_times =
starting_time=(datetime.now())
ending_time=(datetime.now())
optimize_times.append(str(ending_time-starting_time))
python string python-2.7 datetime timedelta
python string python-2.7 datetime timedelta
edited Nov 20 '18 at 21:50
jpp
101k2163112
101k2163112
asked Nov 20 '18 at 21:22
user3299633user3299633
7972823
7972823
Yes,timedelta
, but it's not clear to me why you callstr()
on your results.
– roganjosh
Nov 20 '18 at 21:24
Without using the str function the value resulted in a timedelta function being output
– user3299633
Nov 20 '18 at 21:37
add a comment |
Yes,timedelta
, but it's not clear to me why you callstr()
on your results.
– roganjosh
Nov 20 '18 at 21:24
Without using the str function the value resulted in a timedelta function being output
– user3299633
Nov 20 '18 at 21:37
Yes,
timedelta
, but it's not clear to me why you call str()
on your results.– roganjosh
Nov 20 '18 at 21:24
Yes,
timedelta
, but it's not clear to me why you call str()
on your results.– roganjosh
Nov 20 '18 at 21:24
Without using the str function the value resulted in a timedelta function being output
– user3299633
Nov 20 '18 at 21:37
Without using the str function the value resulted in a timedelta function being output
– user3299633
Nov 20 '18 at 21:37
add a comment |
1 Answer
1
active
oldest
votes
You can use datetime.timedelta
from the standard library:
from datetime import timedelta
L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']
def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)
res = sum(map(str_to_td, L), timedelta())
# datetime.timedelta(0, 4694, 156337)
Note the output of this is a timedelta
object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.
1
Thank you, that's exactly what I needed.
– user3299633
Nov 20 '18 at 21:48
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use datetime.timedelta
from the standard library:
from datetime import timedelta
L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']
def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)
res = sum(map(str_to_td, L), timedelta())
# datetime.timedelta(0, 4694, 156337)
Note the output of this is a timedelta
object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.
1
Thank you, that's exactly what I needed.
– user3299633
Nov 20 '18 at 21:48
add a comment |
You can use datetime.timedelta
from the standard library:
from datetime import timedelta
L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']
def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)
res = sum(map(str_to_td, L), timedelta())
# datetime.timedelta(0, 4694, 156337)
Note the output of this is a timedelta
object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.
1
Thank you, that's exactly what I needed.
– user3299633
Nov 20 '18 at 21:48
add a comment |
You can use datetime.timedelta
from the standard library:
from datetime import timedelta
L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']
def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)
res = sum(map(str_to_td, L), timedelta())
# datetime.timedelta(0, 4694, 156337)
Note the output of this is a timedelta
object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.
You can use datetime.timedelta
from the standard library:
from datetime import timedelta
L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']
def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)
res = sum(map(str_to_td, L), timedelta())
# datetime.timedelta(0, 4694, 156337)
Note the output of this is a timedelta
object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.
answered Nov 20 '18 at 21:43
jppjpp
101k2163112
101k2163112
1
Thank you, that's exactly what I needed.
– user3299633
Nov 20 '18 at 21:48
add a comment |
1
Thank you, that's exactly what I needed.
– user3299633
Nov 20 '18 at 21:48
1
1
Thank you, that's exactly what I needed.
– user3299633
Nov 20 '18 at 21:48
Thank you, that's exactly what I needed.
– user3299633
Nov 20 '18 at 21:48
add a comment |
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Yes,
timedelta
, but it's not clear to me why you callstr()
on your results.– roganjosh
Nov 20 '18 at 21:24
Without using the str function the value resulted in a timedelta function being output
– user3299633
Nov 20 '18 at 21:37