How to make python count how many files are in a directory?





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Just by the title, you might think that this is a duplicate but it is not. I need to make my program count how many files with a specific ending such as .mp3 or .mp4 are in a directory. So if I have 10 .mp3 files in a directory I want my program to figure that out. After that, I need to list those files with numbers next to them so that the user can enter a number to launch that file. I need help with counting the files.










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  • 1





    Take a look at stackoverflow.com/questions/33635353/…

    – KJH
    Nov 23 '18 at 1:54






  • 1





    for file in glob.glob('/some/directory/*.mp3'):

    – John Gordon
    Nov 23 '18 at 1:57











  • Great for the first part but I still need help with the number part.

    – Hrittik Chatterjee
    Nov 23 '18 at 1:59











  • btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

    – Hrittik Chatterjee
    Nov 23 '18 at 2:17











  • Split the filename on the dot; feed the extensions into collections.Counter.

    – wwii
    Nov 23 '18 at 2:19


















-1















Just by the title, you might think that this is a duplicate but it is not. I need to make my program count how many files with a specific ending such as .mp3 or .mp4 are in a directory. So if I have 10 .mp3 files in a directory I want my program to figure that out. After that, I need to list those files with numbers next to them so that the user can enter a number to launch that file. I need help with counting the files.










share|improve this question




















  • 1





    Take a look at stackoverflow.com/questions/33635353/…

    – KJH
    Nov 23 '18 at 1:54






  • 1





    for file in glob.glob('/some/directory/*.mp3'):

    – John Gordon
    Nov 23 '18 at 1:57











  • Great for the first part but I still need help with the number part.

    – Hrittik Chatterjee
    Nov 23 '18 at 1:59











  • btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

    – Hrittik Chatterjee
    Nov 23 '18 at 2:17











  • Split the filename on the dot; feed the extensions into collections.Counter.

    – wwii
    Nov 23 '18 at 2:19














-1












-1








-1


0






Just by the title, you might think that this is a duplicate but it is not. I need to make my program count how many files with a specific ending such as .mp3 or .mp4 are in a directory. So if I have 10 .mp3 files in a directory I want my program to figure that out. After that, I need to list those files with numbers next to them so that the user can enter a number to launch that file. I need help with counting the files.










share|improve this question
















Just by the title, you might think that this is a duplicate but it is not. I need to make my program count how many files with a specific ending such as .mp3 or .mp4 are in a directory. So if I have 10 .mp3 files in a directory I want my program to figure that out. After that, I need to list those files with numbers next to them so that the user can enter a number to launch that file. I need help with counting the files.







python directory






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share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 2:16







Hrittik Chatterjee

















asked Nov 23 '18 at 1:51









Hrittik ChatterjeeHrittik Chatterjee

2511




2511








  • 1





    Take a look at stackoverflow.com/questions/33635353/…

    – KJH
    Nov 23 '18 at 1:54






  • 1





    for file in glob.glob('/some/directory/*.mp3'):

    – John Gordon
    Nov 23 '18 at 1:57











  • Great for the first part but I still need help with the number part.

    – Hrittik Chatterjee
    Nov 23 '18 at 1:59











  • btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

    – Hrittik Chatterjee
    Nov 23 '18 at 2:17











  • Split the filename on the dot; feed the extensions into collections.Counter.

    – wwii
    Nov 23 '18 at 2:19














  • 1





    Take a look at stackoverflow.com/questions/33635353/…

    – KJH
    Nov 23 '18 at 1:54






  • 1





    for file in glob.glob('/some/directory/*.mp3'):

    – John Gordon
    Nov 23 '18 at 1:57











  • Great for the first part but I still need help with the number part.

    – Hrittik Chatterjee
    Nov 23 '18 at 1:59











  • btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

    – Hrittik Chatterjee
    Nov 23 '18 at 2:17











  • Split the filename on the dot; feed the extensions into collections.Counter.

    – wwii
    Nov 23 '18 at 2:19








1




1





Take a look at stackoverflow.com/questions/33635353/…

– KJH
Nov 23 '18 at 1:54





Take a look at stackoverflow.com/questions/33635353/…

– KJH
Nov 23 '18 at 1:54




1




1





for file in glob.glob('/some/directory/*.mp3'):

– John Gordon
Nov 23 '18 at 1:57





for file in glob.glob('/some/directory/*.mp3'):

– John Gordon
Nov 23 '18 at 1:57













Great for the first part but I still need help with the number part.

– Hrittik Chatterjee
Nov 23 '18 at 1:59





Great for the first part but I still need help with the number part.

– Hrittik Chatterjee
Nov 23 '18 at 1:59













btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

– Hrittik Chatterjee
Nov 23 '18 at 2:17





btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

– Hrittik Chatterjee
Nov 23 '18 at 2:17













Split the filename on the dot; feed the extensions into collections.Counter.

– wwii
Nov 23 '18 at 2:19





Split the filename on the dot; feed the extensions into collections.Counter.

– wwii
Nov 23 '18 at 2:19












1 Answer
1






active

oldest

votes


















1














import os 
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])


make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()






share|improve this answer


























  • I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

    – Hrittik Chatterjee
    Nov 23 '18 at 2:29











  • Also I cant ask any more questions apparently so if you guys could upvote this :)

    – Hrittik Chatterjee
    Nov 23 '18 at 2:30











  • you can use `os.startfile()'

    – wishmaster
    Nov 23 '18 at 2:34











  • do not worry i will edit my answer to complete your answer

    – wishmaster
    Nov 23 '18 at 2:35











  • i should note that programmers start count from 0

    – wishmaster
    Nov 23 '18 at 2:41












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














import os 
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])


make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()






share|improve this answer


























  • I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

    – Hrittik Chatterjee
    Nov 23 '18 at 2:29











  • Also I cant ask any more questions apparently so if you guys could upvote this :)

    – Hrittik Chatterjee
    Nov 23 '18 at 2:30











  • you can use `os.startfile()'

    – wishmaster
    Nov 23 '18 at 2:34











  • do not worry i will edit my answer to complete your answer

    – wishmaster
    Nov 23 '18 at 2:35











  • i should note that programmers start count from 0

    – wishmaster
    Nov 23 '18 at 2:41
















1














import os 
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])


make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()






share|improve this answer


























  • I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

    – Hrittik Chatterjee
    Nov 23 '18 at 2:29











  • Also I cant ask any more questions apparently so if you guys could upvote this :)

    – Hrittik Chatterjee
    Nov 23 '18 at 2:30











  • you can use `os.startfile()'

    – wishmaster
    Nov 23 '18 at 2:34











  • do not worry i will edit my answer to complete your answer

    – wishmaster
    Nov 23 '18 at 2:35











  • i should note that programmers start count from 0

    – wishmaster
    Nov 23 '18 at 2:41














1












1








1







import os 
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])


make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()






share|improve this answer















import os 
i=0
x=
for file in os.listdir():
if file.endswith('.mp3'):
print(file)
x.append(file)
i+=1
print('the total number of files: ' +str(i))
fileNumber=input('enter number')
os.startfile(x[int(fileNumber)])


make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 23 '18 at 2:45

























answered Nov 23 '18 at 2:26









wishmasterwishmaster

35210




35210













  • I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

    – Hrittik Chatterjee
    Nov 23 '18 at 2:29











  • Also I cant ask any more questions apparently so if you guys could upvote this :)

    – Hrittik Chatterjee
    Nov 23 '18 at 2:30











  • you can use `os.startfile()'

    – wishmaster
    Nov 23 '18 at 2:34











  • do not worry i will edit my answer to complete your answer

    – wishmaster
    Nov 23 '18 at 2:35











  • i should note that programmers start count from 0

    – wishmaster
    Nov 23 '18 at 2:41



















  • I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

    – Hrittik Chatterjee
    Nov 23 '18 at 2:29











  • Also I cant ask any more questions apparently so if you guys could upvote this :)

    – Hrittik Chatterjee
    Nov 23 '18 at 2:30











  • you can use `os.startfile()'

    – wishmaster
    Nov 23 '18 at 2:34











  • do not worry i will edit my answer to complete your answer

    – wishmaster
    Nov 23 '18 at 2:35











  • i should note that programmers start count from 0

    – wishmaster
    Nov 23 '18 at 2:41

















I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

– Hrittik Chatterjee
Nov 23 '18 at 2:29





I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

– Hrittik Chatterjee
Nov 23 '18 at 2:29













Also I cant ask any more questions apparently so if you guys could upvote this :)

– Hrittik Chatterjee
Nov 23 '18 at 2:30





Also I cant ask any more questions apparently so if you guys could upvote this :)

– Hrittik Chatterjee
Nov 23 '18 at 2:30













you can use `os.startfile()'

– wishmaster
Nov 23 '18 at 2:34





you can use `os.startfile()'

– wishmaster
Nov 23 '18 at 2:34













do not worry i will edit my answer to complete your answer

– wishmaster
Nov 23 '18 at 2:35





do not worry i will edit my answer to complete your answer

– wishmaster
Nov 23 '18 at 2:35













i should note that programmers start count from 0

– wishmaster
Nov 23 '18 at 2:41





i should note that programmers start count from 0

– wishmaster
Nov 23 '18 at 2:41




















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