Magic variable for entire command, including &&












1















I'm trying to write a little function for bash like so:



alias timesec='/usr/bin/time --format="%C took %e seconds"'



prun() {

    echo $ $@

    timesec $*

}


But when I use it, I get:



mpen@mpen:/topsecret$ prun echo foo && echo bar

$ echo foo

foo

echo foo took 0.00 seconds

bar


I want that first line to say $ echo foo && echo bar and the timesec should also apply to the entirety of the command (echo foo && echo bar) not just the first half.



How would I do this?






bash







share|improve this question


















  • 1





    No way. That's the reason why the time reserved word exists in bash.

    – hek2mgl
    Nov 22 '18 at 3:56
















1















I'm trying to write a little function for bash like so:



alias timesec='/usr/bin/time --format="%C took %e seconds"'



prun() {

    echo $ $@

    timesec $*

}


But when I use it, I get:



mpen@mpen:/topsecret$ prun echo foo && echo bar

$ echo foo

foo

echo foo took 0.00 seconds

bar


I want that first line to say $ echo foo && echo bar and the timesec should also apply to the entirety of the command (echo foo && echo bar) not just the first half.



How would I do this?






bash







share|improve this question


















  • 1





    No way. That's the reason why the time reserved word exists in bash.

    – hek2mgl
    Nov 22 '18 at 3:56














1












1








1


0






I'm trying to write a little function for bash like so:



alias timesec='/usr/bin/time --format="%C took %e seconds"'



prun() {

    echo $ $@

    timesec $*

}


But when I use it, I get:



mpen@mpen:/topsecret$ prun echo foo && echo bar

$ echo foo

foo

echo foo took 0.00 seconds

bar


I want that first line to say $ echo foo && echo bar and the timesec should also apply to the entirety of the command (echo foo && echo bar) not just the first half.



How would I do this?






bash







share|improve this question














I'm trying to write a little function for bash like so:



alias timesec='/usr/bin/time --format="%C took %e seconds"'



prun() {

    echo $ $@

    timesec $*

}


But when I use it, I get:



mpen@mpen:/topsecret$ prun echo foo && echo bar

$ echo foo

foo

echo foo took 0.00 seconds

bar


I want that first line to say $ echo foo && echo bar and the timesec should also apply to the entirety of the command (echo foo && echo bar) not just the first half.



How would I do this?






bash




bash






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 22 '18 at 2:00









mpenmpen

126k177658956




126k177658956








  • 1





    No way. That's the reason why the time reserved word exists in bash.

    – hek2mgl
    Nov 22 '18 at 3:56














  • 1





    No way. That's the reason why the time reserved word exists in bash.

    – hek2mgl
    Nov 22 '18 at 3:56








1




1





No way. That's the reason why the time reserved word exists in bash.

– hek2mgl
Nov 22 '18 at 3:56





No way. That's the reason why the time reserved word exists in bash.

– hek2mgl
Nov 22 '18 at 3:56












1 Answer
1






active

oldest

votes


















1














You can use the TIMEFORMAT variable to customize the output of bash's time builtin:



 cmd="/bin/echo foo && /bin/echo bar"

 # See man bash for the TIMEFORMAT variable

 PREV_TIMEFORMAT="${TIMEFORMAT}"

 TIMEFORMAT="The command ${cmd} took %lR"

 # You could use time eval "${cmd}". I don't recommend that

 time /bin/echo foo && /bin/echo bar


Output:



foo

bar

The command /bin/echo foo && /bin/echo bar took 0m0.00s


Note: The above "solution" doesn't work when you use bash's echo builtin.






share|improve this answer


























  • How does this solution work with variables though? That's the part I'm having trouble with.

    – mpen
    Nov 23 '18 at 19:05












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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














You can use the TIMEFORMAT variable to customize the output of bash's time builtin:



 cmd="/bin/echo foo && /bin/echo bar"

 # See man bash for the TIMEFORMAT variable

 PREV_TIMEFORMAT="${TIMEFORMAT}"

 TIMEFORMAT="The command ${cmd} took %lR"

 # You could use time eval "${cmd}". I don't recommend that

 time /bin/echo foo && /bin/echo bar


Output:



foo

bar

The command /bin/echo foo && /bin/echo bar took 0m0.00s


Note: The above "solution" doesn't work when you use bash's echo builtin.






share|improve this answer


























  • How does this solution work with variables though? That's the part I'm having trouble with.

    – mpen
    Nov 23 '18 at 19:05
















1














You can use the TIMEFORMAT variable to customize the output of bash's time builtin:



 cmd="/bin/echo foo && /bin/echo bar"

 # See man bash for the TIMEFORMAT variable

 PREV_TIMEFORMAT="${TIMEFORMAT}"

 TIMEFORMAT="The command ${cmd} took %lR"

 # You could use time eval "${cmd}". I don't recommend that

 time /bin/echo foo && /bin/echo bar


Output:



foo

bar

The command /bin/echo foo && /bin/echo bar took 0m0.00s


Note: The above "solution" doesn't work when you use bash's echo builtin.






share|improve this answer


























  • How does this solution work with variables though? That's the part I'm having trouble with.

    – mpen
    Nov 23 '18 at 19:05














1












1








1







You can use the TIMEFORMAT variable to customize the output of bash's time builtin:



 cmd="/bin/echo foo && /bin/echo bar"

 # See man bash for the TIMEFORMAT variable

 PREV_TIMEFORMAT="${TIMEFORMAT}"

 TIMEFORMAT="The command ${cmd} took %lR"

 # You could use time eval "${cmd}". I don't recommend that

 time /bin/echo foo && /bin/echo bar


Output:



foo

bar

The command /bin/echo foo && /bin/echo bar took 0m0.00s


Note: The above "solution" doesn't work when you use bash's echo builtin.






share|improve this answer















You can use the TIMEFORMAT variable to customize the output of bash's time builtin:



 cmd="/bin/echo foo && /bin/echo bar"

 # See man bash for the TIMEFORMAT variable

 PREV_TIMEFORMAT="${TIMEFORMAT}"

 TIMEFORMAT="The command ${cmd} took %lR"

 # You could use time eval "${cmd}". I don't recommend that

 time /bin/echo foo && /bin/echo bar


Output:



foo

bar

The command /bin/echo foo && /bin/echo bar took 0m0.00s


Note: The above "solution" doesn't work when you use bash's echo builtin.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 22 '18 at 4:17

























answered Nov 22 '18 at 4:11









hek2mglhek2mgl

109k13148173




109k13148173













  • How does this solution work with variables though? That's the part I'm having trouble with.

    – mpen
    Nov 23 '18 at 19:05



















  • How does this solution work with variables though? That's the part I'm having trouble with.

    – mpen
    Nov 23 '18 at 19:05

















How does this solution work with variables though? That's the part I'm having trouble with.

– mpen
Nov 23 '18 at 19:05





How does this solution work with variables though? That's the part I'm having trouble with.

– mpen
Nov 23 '18 at 19:05




















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