Transformation Law for Tensor of Rank Two












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Okay, I am sorry if this question seems absurd, but I am really having a difficult time understanding it.
In the book by H. Jeffreys chapter Cartesian tensors, he defines a second order tensor as $ omega_{jl},' = a_{ij}, a_{kl},omega_{ik}$.



Then he goes on to demonstrate that we change the variables 'j' and 'l' in the equation , and also shows "dummy indices" can be changed without any trouble, after which he arrives at $ omega_{lj},' = a_{kl}, a_{ij},omega_{ki}$ which makes sense, then in the same line he says that $ omega_{lj},' = a_{ij}, a_{kl},omega_{ki}$.



Which is a bit troubling for me, because $a_{ij}$ and $a_{kl} $ are transformation matrices(like operators), and the order of application is important.










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    $begingroup$


    Okay, I am sorry if this question seems absurd, but I am really having a difficult time understanding it.
    In the book by H. Jeffreys chapter Cartesian tensors, he defines a second order tensor as $ omega_{jl},' = a_{ij}, a_{kl},omega_{ik}$.



    Then he goes on to demonstrate that we change the variables 'j' and 'l' in the equation , and also shows "dummy indices" can be changed without any trouble, after which he arrives at $ omega_{lj},' = a_{kl}, a_{ij},omega_{ki}$ which makes sense, then in the same line he says that $ omega_{lj},' = a_{ij}, a_{kl},omega_{ki}$.



    Which is a bit troubling for me, because $a_{ij}$ and $a_{kl} $ are transformation matrices(like operators), and the order of application is important.










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      Okay, I am sorry if this question seems absurd, but I am really having a difficult time understanding it.
      In the book by H. Jeffreys chapter Cartesian tensors, he defines a second order tensor as $ omega_{jl},' = a_{ij}, a_{kl},omega_{ik}$.



      Then he goes on to demonstrate that we change the variables 'j' and 'l' in the equation , and also shows "dummy indices" can be changed without any trouble, after which he arrives at $ omega_{lj},' = a_{kl}, a_{ij},omega_{ki}$ which makes sense, then in the same line he says that $ omega_{lj},' = a_{ij}, a_{kl},omega_{ki}$.



      Which is a bit troubling for me, because $a_{ij}$ and $a_{kl} $ are transformation matrices(like operators), and the order of application is important.










      share|cite|improve this question









      $endgroup$




      Okay, I am sorry if this question seems absurd, but I am really having a difficult time understanding it.
      In the book by H. Jeffreys chapter Cartesian tensors, he defines a second order tensor as $ omega_{jl},' = a_{ij}, a_{kl},omega_{ik}$.



      Then he goes on to demonstrate that we change the variables 'j' and 'l' in the equation , and also shows "dummy indices" can be changed without any trouble, after which he arrives at $ omega_{lj},' = a_{kl}, a_{ij},omega_{ki}$ which makes sense, then in the same line he says that $ omega_{lj},' = a_{ij}, a_{kl},omega_{ki}$.



      Which is a bit troubling for me, because $a_{ij}$ and $a_{kl} $ are transformation matrices(like operators), and the order of application is important.







      tensor-products






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Dec 3 '18 at 21:59









      Ashutosh SinghAshutosh Singh

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