Estimate probability density from cumulative fraction












0















Can I "backward" estimate the probability density by mutate function in dplyr?



x <- c(0.1, 0.2, 0.3, 0.2, 0.1, 0.1)
df <- as.data.frame(x)
df %>% mutate(cumsum = cumsum(x))









share|improve this question



























    0















    Can I "backward" estimate the probability density by mutate function in dplyr?



    x <- c(0.1, 0.2, 0.3, 0.2, 0.1, 0.1)
    df <- as.data.frame(x)
    df %>% mutate(cumsum = cumsum(x))









    share|improve this question

























      0












      0








      0








      Can I "backward" estimate the probability density by mutate function in dplyr?



      x <- c(0.1, 0.2, 0.3, 0.2, 0.1, 0.1)
      df <- as.data.frame(x)
      df %>% mutate(cumsum = cumsum(x))









      share|improve this question














      Can I "backward" estimate the probability density by mutate function in dplyr?



      x <- c(0.1, 0.2, 0.3, 0.2, 0.1, 0.1)
      df <- as.data.frame(x)
      df %>% mutate(cumsum = cumsum(x))






      r data-manipulation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 20 '18 at 18:54









      Nan-Hung HsiehNan-Hung Hsieh

      174




      174
























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          If



          cs <- cusum(x)


          then x equals



          c(cs[1], diff(cs))





          share|improve this answer























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            If



            cs <- cusum(x)


            then x equals



            c(cs[1], diff(cs))





            share|improve this answer




























              1














              If



              cs <- cusum(x)


              then x equals



              c(cs[1], diff(cs))





              share|improve this answer


























                1












                1








                1







                If



                cs <- cusum(x)


                then x equals



                c(cs[1], diff(cs))





                share|improve this answer













                If



                cs <- cusum(x)


                then x equals



                c(cs[1], diff(cs))






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 20 '18 at 18:58









                G. GrothendieckG. Grothendieck

                150k10132238




                150k10132238
































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