Open Wifi Settings programatically from pop-up notification











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1
down vote

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I'm using the code snippet below, but it does not seem to open the Settings, it opens the Notifications settings of the app.



I need to open the wifi settings to enable the user to switch it off, iOS 12, Swift 4.2



{

if response.actionIdentifier == "action1" {
guard let settingsUrl = URL(string: UIApplication.openSettingsURLString) else {
return
}

if UIApplication.shared.canOpenURL(settingsUrl) {
UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
print("Settings opened: (success)") // Prints true
})
}
}
}









share|improve this question
























  • Have you tried this ? stackoverflow.com/a/34024467/5464805
    – Olympiloutre
    Nov 13 at 9:59










  • You can not open Wifi-Settings directly. Apple only allows to open settings. There are many answers to open Wifi-settings only but then your app will get rejection if the reviewer noticed this behavior.
    – Kamran
    Nov 13 at 10:00












  • Possible duplicate of How to open WIFI setting in Swift 3
    – Kamran
    Nov 13 at 10:01










  • I'm getting this when compiling the code with the suggested link [stackoverflow.com/questions/39764553/…: UIApplicationOpenSettingsURLString' has been renamed to 'UIApplication.openSettingsURLString This opens "Allow AppName to access:" and not the General Settings Page
    – shawn.t
    Nov 13 at 12:51










  • The method in the link opens the App's settings, not the phone's settings. How do I open the phone's settings?
    – shawn.t
    Nov 13 at 13:08















up vote
1
down vote

favorite












I'm using the code snippet below, but it does not seem to open the Settings, it opens the Notifications settings of the app.



I need to open the wifi settings to enable the user to switch it off, iOS 12, Swift 4.2



{

if response.actionIdentifier == "action1" {
guard let settingsUrl = URL(string: UIApplication.openSettingsURLString) else {
return
}

if UIApplication.shared.canOpenURL(settingsUrl) {
UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
print("Settings opened: (success)") // Prints true
})
}
}
}









share|improve this question
























  • Have you tried this ? stackoverflow.com/a/34024467/5464805
    – Olympiloutre
    Nov 13 at 9:59










  • You can not open Wifi-Settings directly. Apple only allows to open settings. There are many answers to open Wifi-settings only but then your app will get rejection if the reviewer noticed this behavior.
    – Kamran
    Nov 13 at 10:00












  • Possible duplicate of How to open WIFI setting in Swift 3
    – Kamran
    Nov 13 at 10:01










  • I'm getting this when compiling the code with the suggested link [stackoverflow.com/questions/39764553/…: UIApplicationOpenSettingsURLString' has been renamed to 'UIApplication.openSettingsURLString This opens "Allow AppName to access:" and not the General Settings Page
    – shawn.t
    Nov 13 at 12:51










  • The method in the link opens the App's settings, not the phone's settings. How do I open the phone's settings?
    – shawn.t
    Nov 13 at 13:08













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I'm using the code snippet below, but it does not seem to open the Settings, it opens the Notifications settings of the app.



I need to open the wifi settings to enable the user to switch it off, iOS 12, Swift 4.2



{

if response.actionIdentifier == "action1" {
guard let settingsUrl = URL(string: UIApplication.openSettingsURLString) else {
return
}

if UIApplication.shared.canOpenURL(settingsUrl) {
UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
print("Settings opened: (success)") // Prints true
})
}
}
}









share|improve this question















I'm using the code snippet below, but it does not seem to open the Settings, it opens the Notifications settings of the app.



I need to open the wifi settings to enable the user to switch it off, iOS 12, Swift 4.2



{

if response.actionIdentifier == "action1" {
guard let settingsUrl = URL(string: UIApplication.openSettingsURLString) else {
return
}

if UIApplication.shared.canOpenURL(settingsUrl) {
UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
print("Settings opened: (success)") // Prints true
})
}
}
}






ios swift unusernotificationcenter






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edited Nov 13 at 10:07

























asked Nov 13 at 9:42









shawn.t

255




255












  • Have you tried this ? stackoverflow.com/a/34024467/5464805
    – Olympiloutre
    Nov 13 at 9:59










  • You can not open Wifi-Settings directly. Apple only allows to open settings. There are many answers to open Wifi-settings only but then your app will get rejection if the reviewer noticed this behavior.
    – Kamran
    Nov 13 at 10:00












  • Possible duplicate of How to open WIFI setting in Swift 3
    – Kamran
    Nov 13 at 10:01










  • I'm getting this when compiling the code with the suggested link [stackoverflow.com/questions/39764553/…: UIApplicationOpenSettingsURLString' has been renamed to 'UIApplication.openSettingsURLString This opens "Allow AppName to access:" and not the General Settings Page
    – shawn.t
    Nov 13 at 12:51










  • The method in the link opens the App's settings, not the phone's settings. How do I open the phone's settings?
    – shawn.t
    Nov 13 at 13:08


















  • Have you tried this ? stackoverflow.com/a/34024467/5464805
    – Olympiloutre
    Nov 13 at 9:59










  • You can not open Wifi-Settings directly. Apple only allows to open settings. There are many answers to open Wifi-settings only but then your app will get rejection if the reviewer noticed this behavior.
    – Kamran
    Nov 13 at 10:00












  • Possible duplicate of How to open WIFI setting in Swift 3
    – Kamran
    Nov 13 at 10:01










  • I'm getting this when compiling the code with the suggested link [stackoverflow.com/questions/39764553/…: UIApplicationOpenSettingsURLString' has been renamed to 'UIApplication.openSettingsURLString This opens "Allow AppName to access:" and not the General Settings Page
    – shawn.t
    Nov 13 at 12:51










  • The method in the link opens the App's settings, not the phone's settings. How do I open the phone's settings?
    – shawn.t
    Nov 13 at 13:08
















Have you tried this ? stackoverflow.com/a/34024467/5464805
– Olympiloutre
Nov 13 at 9:59




Have you tried this ? stackoverflow.com/a/34024467/5464805
– Olympiloutre
Nov 13 at 9:59












You can not open Wifi-Settings directly. Apple only allows to open settings. There are many answers to open Wifi-settings only but then your app will get rejection if the reviewer noticed this behavior.
– Kamran
Nov 13 at 10:00






You can not open Wifi-Settings directly. Apple only allows to open settings. There are many answers to open Wifi-settings only but then your app will get rejection if the reviewer noticed this behavior.
– Kamran
Nov 13 at 10:00














Possible duplicate of How to open WIFI setting in Swift 3
– Kamran
Nov 13 at 10:01




Possible duplicate of How to open WIFI setting in Swift 3
– Kamran
Nov 13 at 10:01












I'm getting this when compiling the code with the suggested link [stackoverflow.com/questions/39764553/…: UIApplicationOpenSettingsURLString' has been renamed to 'UIApplication.openSettingsURLString This opens "Allow AppName to access:" and not the General Settings Page
– shawn.t
Nov 13 at 12:51




I'm getting this when compiling the code with the suggested link [stackoverflow.com/questions/39764553/…: UIApplicationOpenSettingsURLString' has been renamed to 'UIApplication.openSettingsURLString This opens "Allow AppName to access:" and not the General Settings Page
– shawn.t
Nov 13 at 12:51












The method in the link opens the App's settings, not the phone's settings. How do I open the phone's settings?
– shawn.t
Nov 13 at 13:08




The method in the link opens the App's settings, not the phone's settings. How do I open the phone's settings?
– shawn.t
Nov 13 at 13:08












1 Answer
1






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up vote
0
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Open settings, don't open wifi setting. My app was rejected once when i opened wifi setting directly from my app. Avoid using private apis, apple may reject your app.






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    up vote
    0
    down vote













    Open settings, don't open wifi setting. My app was rejected once when i opened wifi setting directly from my app. Avoid using private apis, apple may reject your app.






    share|improve this answer

























      up vote
      0
      down vote













      Open settings, don't open wifi setting. My app was rejected once when i opened wifi setting directly from my app. Avoid using private apis, apple may reject your app.






      share|improve this answer























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        up vote
        0
        down vote









        Open settings, don't open wifi setting. My app was rejected once when i opened wifi setting directly from my app. Avoid using private apis, apple may reject your app.






        share|improve this answer












        Open settings, don't open wifi setting. My app was rejected once when i opened wifi setting directly from my app. Avoid using private apis, apple may reject your app.







        share|improve this answer












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        answered Nov 13 at 10:08









        Viren Malhan

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