Upper and lower bounds - nearest 5
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I am really confused about rounding number to the nearest 5, i was practicing bounds gcse questions and I had a question saying that 135 was rounded to nearest 5m, find the upper and lower bounds. I thought it was going to be 136.5 until my friend told me it was 137.5, I got really confused. Can someone explain how this works? Is there a way a value that nearest 5 is x or something like that? An clear explanation would be helpful.
elementary-number-theory upper-lower-bounds
edited Oct 27 '17 at 1:07
Charles
24k452116
asked Oct 26 '17 at 21:52
jose carlosjose carlos
611
$endgroup$
|
show 1 more comment
$begingroup$
I am really confused about rounding number to the nearest 5, i was practicing bounds gcse questions and I had a question saying that 135 was rounded to nearest 5m, find the upper and lower bounds. I thought it was going to be 136.5 until my friend told me it was 137.5, I got really confused. Can someone explain how this works? Is there a way a value that nearest 5 is x or something like that? An clear explanation would be helpful.
elementary-number-theory upper-lower-bounds
edited Oct 27 '17 at 1:07
Charles
24k452116
asked Oct 26 '17 at 21:52
jose carlosjose carlos
611
$endgroup$
$begingroup$
Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
$endgroup$
– T. Bongers
Oct 26 '17 at 21:52
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It might sound stupid to you but if i was doing i would round it to 138.5
$endgroup$
– jose carlos
Oct 26 '17 at 21:58
$begingroup$
Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
$endgroup$
– T. Bongers
Oct 26 '17 at 21:59
$begingroup$
How is 137 a multiple of 5 then?
$endgroup$
– jose carlos
Oct 26 '17 at 22:00
$begingroup$
It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
$endgroup$
– T. Bongers
Oct 26 '17 at 22:01
|
show 1 more comment
$begingroup$
I am really confused about rounding number to the nearest 5, i was practicing bounds gcse questions and I had a question saying that 135 was rounded to nearest 5m, find the upper and lower bounds. I thought it was going to be 136.5 until my friend told me it was 137.5, I got really confused. Can someone explain how this works? Is there a way a value that nearest 5 is x or something like that? An clear explanation would be helpful.
elementary-number-theory upper-lower-bounds
edited Oct 27 '17 at 1:07
Charles
24k452116
asked Oct 26 '17 at 21:52
jose carlosjose carlos
611
$endgroup$
I am really confused about rounding number to the nearest 5, i was practicing bounds gcse questions and I had a question saying that 135 was rounded to nearest 5m, find the upper and lower bounds. I thought it was going to be 136.5 until my friend told me it was 137.5, I got really confused. Can someone explain how this works? Is there a way a value that nearest 5 is x or something like that? An clear explanation would be helpful.
elementary-number-theory upper-lower-bounds
elementary-number-theory upper-lower-bounds
edited Oct 27 '17 at 1:07
Charles
24k452116
asked Oct 26 '17 at 21:52
jose carlosjose carlos
611
edited Oct 27 '17 at 1:07
Charles
24k452116
asked Oct 26 '17 at 21:52
jose carlosjose carlos
611
edited Oct 27 '17 at 1:07
Charles
24k452116
edited Oct 27 '17 at 1:07
Charles
24k452116
edited Oct 27 '17 at 1:07
Charles
24k452116
24k452116
asked Oct 26 '17 at 21:52
jose carlosjose carlos
611
asked Oct 26 '17 at 21:52
jose carlosjose carlos
611
asked Oct 26 '17 at 21:52
jose carlosjose carlos
611
611
$begingroup$
Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
$endgroup$
– T. Bongers
Oct 26 '17 at 21:52
$begingroup$
It might sound stupid to you but if i was doing i would round it to 138.5
$endgroup$
– jose carlos
Oct 26 '17 at 21:58
$begingroup$
Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
$endgroup$
– T. Bongers
Oct 26 '17 at 21:59
$begingroup$
How is 137 a multiple of 5 then?
$endgroup$
– jose carlos
Oct 26 '17 at 22:00
$begingroup$
It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
$endgroup$
– T. Bongers
Oct 26 '17 at 22:01
|
show 1 more comment
$begingroup$
Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
$endgroup$
– T. Bongers
Oct 26 '17 at 21:52
$begingroup$
It might sound stupid to you but if i was doing i would round it to 138.5
$endgroup$
– jose carlos
Oct 26 '17 at 21:58
$begingroup$
Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
$endgroup$
– T. Bongers
Oct 26 '17 at 21:59
$begingroup$
How is 137 a multiple of 5 then?
$endgroup$
– jose carlos
Oct 26 '17 at 22:00
$begingroup$
It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
$endgroup$
– T. Bongers
Oct 26 '17 at 22:01
$begingroup$
Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
$endgroup$
– T. Bongers
Oct 26 '17 at 21:52
$begingroup$
Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
$endgroup$
– T. Bongers
Oct 26 '17 at 21:52
$begingroup$
It might sound stupid to you but if i was doing i would round it to 138.5
$endgroup$
– jose carlos
Oct 26 '17 at 21:58
$begingroup$
It might sound stupid to you but if i was doing i would round it to 138.5
$endgroup$
– jose carlos
Oct 26 '17 at 21:58
$begingroup$
Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
$endgroup$
– T. Bongers
Oct 26 '17 at 21:59
$begingroup$
Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
$endgroup$
– T. Bongers
Oct 26 '17 at 21:59
$begingroup$
How is 137 a multiple of 5 then?
$endgroup$
– jose carlos
Oct 26 '17 at 22:00
$begingroup$
How is 137 a multiple of 5 then?
$endgroup$
– jose carlos
Oct 26 '17 at 22:00
$begingroup$
It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
$endgroup$
– T. Bongers
Oct 26 '17 at 22:01
$begingroup$
It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
$endgroup$
– T. Bongers
Oct 26 '17 at 22:01
|
show 1 more comment
2 Answers
2
active
oldest
votes
$begingroup$
The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.
answered Jun 10 '18 at 13:57
Ross MillikanRoss Millikan
301k24200375
$endgroup$
add a comment |
$begingroup$
One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
Eg. 135 rounded to the nearest 5
Half 5 to get 2.5
The upper bound is 135 + 2.5=137.5
The lower bound is 135-2.5=132.5
answered Mar 12 at 16:09
AnnaAnna
1
$endgroup$
$begingroup$
A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
$endgroup$
– davidlowryduda♦
Mar 14 at 20:24
add a comment |
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2 Answers
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active
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2 Answers
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$begingroup$
The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.
answered Jun 10 '18 at 13:57
Ross MillikanRoss Millikan
301k24200375
$endgroup$
add a comment |
$begingroup$
The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.
answered Jun 10 '18 at 13:57
Ross MillikanRoss Millikan
301k24200375
$endgroup$
add a comment |
$begingroup$
The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.
answered Jun 10 '18 at 13:57
Ross MillikanRoss Millikan
301k24200375
$endgroup$
The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.
answered Jun 10 '18 at 13:57
Ross MillikanRoss Millikan
301k24200375
answered Jun 10 '18 at 13:57
Ross MillikanRoss Millikan
301k24200375
answered Jun 10 '18 at 13:57
Ross MillikanRoss Millikan
301k24200375
answered Jun 10 '18 at 13:57
Ross MillikanRoss Millikan
301k24200375
301k24200375
add a comment |
add a comment |
$begingroup$
One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
Eg. 135 rounded to the nearest 5
Half 5 to get 2.5
The upper bound is 135 + 2.5=137.5
The lower bound is 135-2.5=132.5
answered Mar 12 at 16:09
AnnaAnna
1
$endgroup$
$begingroup$
A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
$endgroup$
– davidlowryduda♦
Mar 14 at 20:24
add a comment |
$begingroup$
One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
Eg. 135 rounded to the nearest 5
Half 5 to get 2.5
The upper bound is 135 + 2.5=137.5
The lower bound is 135-2.5=132.5
answered Mar 12 at 16:09
AnnaAnna
1
$endgroup$
$begingroup$
A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
$endgroup$
– davidlowryduda♦
Mar 14 at 20:24
add a comment |
$begingroup$
One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
Eg. 135 rounded to the nearest 5
Half 5 to get 2.5
The upper bound is 135 + 2.5=137.5
The lower bound is 135-2.5=132.5
answered Mar 12 at 16:09
AnnaAnna
1
$endgroup$
One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
Eg. 135 rounded to the nearest 5
Half 5 to get 2.5
The upper bound is 135 + 2.5=137.5
The lower bound is 135-2.5=132.5
answered Mar 12 at 16:09
AnnaAnna
1
answered Mar 12 at 16:09
AnnaAnna
1
answered Mar 12 at 16:09
AnnaAnna
1
answered Mar 12 at 16:09
AnnaAnna
1
1
$begingroup$
A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
$endgroup$
– davidlowryduda♦
Mar 14 at 20:24
add a comment |
$begingroup$
A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
$endgroup$
– davidlowryduda♦
Mar 14 at 20:24
$begingroup$
A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
$endgroup$
– davidlowryduda♦
Mar 14 at 20:24
$begingroup$
A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
$endgroup$
– davidlowryduda♦
Mar 14 at 20:24
add a comment |
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$begingroup$
Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
$endgroup$
– T. Bongers
Oct 26 '17 at 21:52
$begingroup$
It might sound stupid to you but if i was doing i would round it to 138.5
$endgroup$
– jose carlos
Oct 26 '17 at 21:58
$begingroup$
Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
$endgroup$
– T. Bongers
Oct 26 '17 at 21:59
$begingroup$
How is 137 a multiple of 5 then?
$endgroup$
– jose carlos
Oct 26 '17 at 22:00
$begingroup$
It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
$endgroup$
– T. Bongers
Oct 26 '17 at 22:01