Data Formatting pandas





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I am trying to enter a line of code that creates a row for the index 31'st January 1995. I am unable to get the row to look like 31/01/1995 and instead the output is 1995-01-31 00:00:00 .



My original data in a dataframe called MainData



I am trying to add a row at the top for 31st January 1995 in the same format as the data below.



enter image description here



My code is



MainData.loc[pd.to_datetime('31/01/1995',format='%d/%m/%Y'),:] = [100 for number in range(7)]
MainData


enter image description here



Please let me know if there is a way to reformat this to 31/01/1995.



Thanks in advance.










share|improve this question

























  • Yes, I need the index to look like "31/01/1995" and not the way it is in the output. How do I do that?

    – AnalysisNerd
    Nov 22 '18 at 20:33











  • I have no idea. Please make an MCVE

    – roganjosh
    Nov 22 '18 at 20:34













  • MainData is the main dataframe where I am trying to add a row with "31/01/1995". There is no df.

    – AnalysisNerd
    Nov 22 '18 at 20:34











  • I think it's better write a function that convert datetime type into string and then apply it on your column.

    – Ali AzG
    Nov 22 '18 at 20:35






  • 1





    Am editing my query to provide further information

    – AnalysisNerd
    Nov 22 '18 at 20:36


















0















I am trying to enter a line of code that creates a row for the index 31'st January 1995. I am unable to get the row to look like 31/01/1995 and instead the output is 1995-01-31 00:00:00 .



My original data in a dataframe called MainData



I am trying to add a row at the top for 31st January 1995 in the same format as the data below.



enter image description here



My code is



MainData.loc[pd.to_datetime('31/01/1995',format='%d/%m/%Y'),:] = [100 for number in range(7)]
MainData


enter image description here



Please let me know if there is a way to reformat this to 31/01/1995.



Thanks in advance.










share|improve this question

























  • Yes, I need the index to look like "31/01/1995" and not the way it is in the output. How do I do that?

    – AnalysisNerd
    Nov 22 '18 at 20:33











  • I have no idea. Please make an MCVE

    – roganjosh
    Nov 22 '18 at 20:34













  • MainData is the main dataframe where I am trying to add a row with "31/01/1995". There is no df.

    – AnalysisNerd
    Nov 22 '18 at 20:34











  • I think it's better write a function that convert datetime type into string and then apply it on your column.

    – Ali AzG
    Nov 22 '18 at 20:35






  • 1





    Am editing my query to provide further information

    – AnalysisNerd
    Nov 22 '18 at 20:36














0












0








0


1






I am trying to enter a line of code that creates a row for the index 31'st January 1995. I am unable to get the row to look like 31/01/1995 and instead the output is 1995-01-31 00:00:00 .



My original data in a dataframe called MainData



I am trying to add a row at the top for 31st January 1995 in the same format as the data below.



enter image description here



My code is



MainData.loc[pd.to_datetime('31/01/1995',format='%d/%m/%Y'),:] = [100 for number in range(7)]
MainData


enter image description here



Please let me know if there is a way to reformat this to 31/01/1995.



Thanks in advance.










share|improve this question
















I am trying to enter a line of code that creates a row for the index 31'st January 1995. I am unable to get the row to look like 31/01/1995 and instead the output is 1995-01-31 00:00:00 .



My original data in a dataframe called MainData



I am trying to add a row at the top for 31st January 1995 in the same format as the data below.



enter image description here



My code is



MainData.loc[pd.to_datetime('31/01/1995',format='%d/%m/%Y'),:] = [100 for number in range(7)]
MainData


enter image description here



Please let me know if there is a way to reformat this to 31/01/1995.



Thanks in advance.







python pandas datetime






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 20:39







AnalysisNerd

















asked Nov 22 '18 at 20:28









AnalysisNerdAnalysisNerd

69111




69111













  • Yes, I need the index to look like "31/01/1995" and not the way it is in the output. How do I do that?

    – AnalysisNerd
    Nov 22 '18 at 20:33











  • I have no idea. Please make an MCVE

    – roganjosh
    Nov 22 '18 at 20:34













  • MainData is the main dataframe where I am trying to add a row with "31/01/1995". There is no df.

    – AnalysisNerd
    Nov 22 '18 at 20:34











  • I think it's better write a function that convert datetime type into string and then apply it on your column.

    – Ali AzG
    Nov 22 '18 at 20:35






  • 1





    Am editing my query to provide further information

    – AnalysisNerd
    Nov 22 '18 at 20:36



















  • Yes, I need the index to look like "31/01/1995" and not the way it is in the output. How do I do that?

    – AnalysisNerd
    Nov 22 '18 at 20:33











  • I have no idea. Please make an MCVE

    – roganjosh
    Nov 22 '18 at 20:34













  • MainData is the main dataframe where I am trying to add a row with "31/01/1995". There is no df.

    – AnalysisNerd
    Nov 22 '18 at 20:34











  • I think it's better write a function that convert datetime type into string and then apply it on your column.

    – Ali AzG
    Nov 22 '18 at 20:35






  • 1





    Am editing my query to provide further information

    – AnalysisNerd
    Nov 22 '18 at 20:36

















Yes, I need the index to look like "31/01/1995" and not the way it is in the output. How do I do that?

– AnalysisNerd
Nov 22 '18 at 20:33





Yes, I need the index to look like "31/01/1995" and not the way it is in the output. How do I do that?

– AnalysisNerd
Nov 22 '18 at 20:33













I have no idea. Please make an MCVE

– roganjosh
Nov 22 '18 at 20:34







I have no idea. Please make an MCVE

– roganjosh
Nov 22 '18 at 20:34















MainData is the main dataframe where I am trying to add a row with "31/01/1995". There is no df.

– AnalysisNerd
Nov 22 '18 at 20:34





MainData is the main dataframe where I am trying to add a row with "31/01/1995". There is no df.

– AnalysisNerd
Nov 22 '18 at 20:34













I think it's better write a function that convert datetime type into string and then apply it on your column.

– Ali AzG
Nov 22 '18 at 20:35





I think it's better write a function that convert datetime type into string and then apply it on your column.

– Ali AzG
Nov 22 '18 at 20:35




1




1





Am editing my query to provide further information

– AnalysisNerd
Nov 22 '18 at 20:36





Am editing my query to provide further information

– AnalysisNerd
Nov 22 '18 at 20:36












1 Answer
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oldest

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#Making the data look more normal by removing the first column index level
MainData = MainData.rename(columns=MainData.iloc[0])
MainData = MainData.iloc[1:]
#Re-adjusting the Index to a datetime format
MainData['DateAdjusted'] = MainData.index
MainData = MainData.reset_index(drop=True)
MainData['DateAdjusted'] = pd.to_datetime(MainData['DateAdjusted'],dayfirst=True)

#Just renaming the Column and converting the index back to Date
MainData.rename(columns={'DateAdjusted':'Date'},inplace=True)
MainData.index = MainData['Date']
del MainData['Date']

#Defining the date for the row I want to add
InitialDate = "31/01/1995"
format_str = '%d/%m/%Y'
datetime_obj = datetime.datetime.strptime(InitialDate, format_str)
print (datetime_obj.date())

MainData.loc[datetime_obj,:] = [100 for number in range(7)]
MainData = MainData.sort_index(ascending=True)





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    1 Answer
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    #Making the data look more normal by removing the first column index level
    MainData = MainData.rename(columns=MainData.iloc[0])
    MainData = MainData.iloc[1:]
    #Re-adjusting the Index to a datetime format
    MainData['DateAdjusted'] = MainData.index
    MainData = MainData.reset_index(drop=True)
    MainData['DateAdjusted'] = pd.to_datetime(MainData['DateAdjusted'],dayfirst=True)

    #Just renaming the Column and converting the index back to Date
    MainData.rename(columns={'DateAdjusted':'Date'},inplace=True)
    MainData.index = MainData['Date']
    del MainData['Date']

    #Defining the date for the row I want to add
    InitialDate = "31/01/1995"
    format_str = '%d/%m/%Y'
    datetime_obj = datetime.datetime.strptime(InitialDate, format_str)
    print (datetime_obj.date())

    MainData.loc[datetime_obj,:] = [100 for number in range(7)]
    MainData = MainData.sort_index(ascending=True)





    share|improve this answer




























      0














      #Making the data look more normal by removing the first column index level
      MainData = MainData.rename(columns=MainData.iloc[0])
      MainData = MainData.iloc[1:]
      #Re-adjusting the Index to a datetime format
      MainData['DateAdjusted'] = MainData.index
      MainData = MainData.reset_index(drop=True)
      MainData['DateAdjusted'] = pd.to_datetime(MainData['DateAdjusted'],dayfirst=True)

      #Just renaming the Column and converting the index back to Date
      MainData.rename(columns={'DateAdjusted':'Date'},inplace=True)
      MainData.index = MainData['Date']
      del MainData['Date']

      #Defining the date for the row I want to add
      InitialDate = "31/01/1995"
      format_str = '%d/%m/%Y'
      datetime_obj = datetime.datetime.strptime(InitialDate, format_str)
      print (datetime_obj.date())

      MainData.loc[datetime_obj,:] = [100 for number in range(7)]
      MainData = MainData.sort_index(ascending=True)





      share|improve this answer


























        0












        0








        0







        #Making the data look more normal by removing the first column index level
        MainData = MainData.rename(columns=MainData.iloc[0])
        MainData = MainData.iloc[1:]
        #Re-adjusting the Index to a datetime format
        MainData['DateAdjusted'] = MainData.index
        MainData = MainData.reset_index(drop=True)
        MainData['DateAdjusted'] = pd.to_datetime(MainData['DateAdjusted'],dayfirst=True)

        #Just renaming the Column and converting the index back to Date
        MainData.rename(columns={'DateAdjusted':'Date'},inplace=True)
        MainData.index = MainData['Date']
        del MainData['Date']

        #Defining the date for the row I want to add
        InitialDate = "31/01/1995"
        format_str = '%d/%m/%Y'
        datetime_obj = datetime.datetime.strptime(InitialDate, format_str)
        print (datetime_obj.date())

        MainData.loc[datetime_obj,:] = [100 for number in range(7)]
        MainData = MainData.sort_index(ascending=True)





        share|improve this answer













        #Making the data look more normal by removing the first column index level
        MainData = MainData.rename(columns=MainData.iloc[0])
        MainData = MainData.iloc[1:]
        #Re-adjusting the Index to a datetime format
        MainData['DateAdjusted'] = MainData.index
        MainData = MainData.reset_index(drop=True)
        MainData['DateAdjusted'] = pd.to_datetime(MainData['DateAdjusted'],dayfirst=True)

        #Just renaming the Column and converting the index back to Date
        MainData.rename(columns={'DateAdjusted':'Date'},inplace=True)
        MainData.index = MainData['Date']
        del MainData['Date']

        #Defining the date for the row I want to add
        InitialDate = "31/01/1995"
        format_str = '%d/%m/%Y'
        datetime_obj = datetime.datetime.strptime(InitialDate, format_str)
        print (datetime_obj.date())

        MainData.loc[datetime_obj,:] = [100 for number in range(7)]
        MainData = MainData.sort_index(ascending=True)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 '18 at 21:50









        AnalysisNerdAnalysisNerd

        69111




        69111
































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