ruby - help need to convert an array to a specific type of array of arrays, duplicating the keys as [key,...











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I want to convert and array into a specific type of array of arrays.



array = ["Project", "Publication"]



into



array_of_arrays =[["Project", "Project"], ["Publication", "Publication"] ]



The array is not just limited to size two. Its a growing list , so looking for some function to convert it to array_of_arrays.



Appreciate any help.










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    You can format your code by indenting it four spaces or by surrounding it with backticks. Typically, use the former for blocks of code, the latter for isolated bits of code within sentences. Also, if you select your code and click on {} it will all be indented four spaces. This is a pure-Ruby question so you should not have the Rails tag. Lastly, in Ruby we speak of methods (OOP-like), not functions.
    – Cary Swoveland
    Nov 15 at 17:47

















up vote
-1
down vote

favorite












I want to convert and array into a specific type of array of arrays.



array = ["Project", "Publication"]



into



array_of_arrays =[["Project", "Project"], ["Publication", "Publication"] ]



The array is not just limited to size two. Its a growing list , so looking for some function to convert it to array_of_arrays.



Appreciate any help.










share|improve this question


















  • 1




    You can format your code by indenting it four spaces or by surrounding it with backticks. Typically, use the former for blocks of code, the latter for isolated bits of code within sentences. Also, if you select your code and click on {} it will all be indented four spaces. This is a pure-Ruby question so you should not have the Rails tag. Lastly, in Ruby we speak of methods (OOP-like), not functions.
    – Cary Swoveland
    Nov 15 at 17:47















up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I want to convert and array into a specific type of array of arrays.



array = ["Project", "Publication"]



into



array_of_arrays =[["Project", "Project"], ["Publication", "Publication"] ]



The array is not just limited to size two. Its a growing list , so looking for some function to convert it to array_of_arrays.



Appreciate any help.










share|improve this question













I want to convert and array into a specific type of array of arrays.



array = ["Project", "Publication"]



into



array_of_arrays =[["Project", "Project"], ["Publication", "Publication"] ]



The array is not just limited to size two. Its a growing list , so looking for some function to convert it to array_of_arrays.



Appreciate any help.







ruby ruby-on-rails-3






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asked Nov 15 at 16:51









user3586935

1




1








  • 1




    You can format your code by indenting it four spaces or by surrounding it with backticks. Typically, use the former for blocks of code, the latter for isolated bits of code within sentences. Also, if you select your code and click on {} it will all be indented four spaces. This is a pure-Ruby question so you should not have the Rails tag. Lastly, in Ruby we speak of methods (OOP-like), not functions.
    – Cary Swoveland
    Nov 15 at 17:47
















  • 1




    You can format your code by indenting it four spaces or by surrounding it with backticks. Typically, use the former for blocks of code, the latter for isolated bits of code within sentences. Also, if you select your code and click on {} it will all be indented four spaces. This is a pure-Ruby question so you should not have the Rails tag. Lastly, in Ruby we speak of methods (OOP-like), not functions.
    – Cary Swoveland
    Nov 15 at 17:47










1




1




You can format your code by indenting it four spaces or by surrounding it with backticks. Typically, use the former for blocks of code, the latter for isolated bits of code within sentences. Also, if you select your code and click on {} it will all be indented four spaces. This is a pure-Ruby question so you should not have the Rails tag. Lastly, in Ruby we speak of methods (OOP-like), not functions.
– Cary Swoveland
Nov 15 at 17:47






You can format your code by indenting it four spaces or by surrounding it with backticks. Typically, use the former for blocks of code, the latter for isolated bits of code within sentences. Also, if you select your code and click on {} it will all be indented four spaces. This is a pure-Ruby question so you should not have the Rails tag. Lastly, in Ruby we speak of methods (OOP-like), not functions.
– Cary Swoveland
Nov 15 at 17:47














2 Answers
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def replicate(arr, n)
arr.map { |e| [e]*n }
end

replicate(["Project", "Publication"], 2)
#=> [["Project", "Project"], ["Publication", "Publication"]]
replicate(["Project", "Publication"], 3)
#=> [["Project", "Project", "Project"], ["Publication", "Publication", "Publication"]]
replicate([["ProjectA", "ProjectB"], "Publication"], 2)
#=> [[["ProjectA", "ProjectB"], ["ProjectA", "ProjectB"]], ["Publication", "Publication"]





share|improve this answer




























    up vote
    0
    down vote













    This is something map can handle quite easily.



    a = ["Project", "Publication"]
    a.map{|x| [x,x]}
    #=> [["Project", "Project"], ["Publication", "Publication"]]





    share|improve this answer























    • a.zip(a) will do the same thing :)
      – engineersmnky
      Nov 15 at 17:08











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    2 Answers
    2






    active

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    2 Answers
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    up vote
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    def replicate(arr, n)
    arr.map { |e| [e]*n }
    end

    replicate(["Project", "Publication"], 2)
    #=> [["Project", "Project"], ["Publication", "Publication"]]
    replicate(["Project", "Publication"], 3)
    #=> [["Project", "Project", "Project"], ["Publication", "Publication", "Publication"]]
    replicate([["ProjectA", "ProjectB"], "Publication"], 2)
    #=> [[["ProjectA", "ProjectB"], ["ProjectA", "ProjectB"]], ["Publication", "Publication"]





    share|improve this answer

























      up vote
      2
      down vote













      def replicate(arr, n)
      arr.map { |e| [e]*n }
      end

      replicate(["Project", "Publication"], 2)
      #=> [["Project", "Project"], ["Publication", "Publication"]]
      replicate(["Project", "Publication"], 3)
      #=> [["Project", "Project", "Project"], ["Publication", "Publication", "Publication"]]
      replicate([["ProjectA", "ProjectB"], "Publication"], 2)
      #=> [[["ProjectA", "ProjectB"], ["ProjectA", "ProjectB"]], ["Publication", "Publication"]





      share|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        def replicate(arr, n)
        arr.map { |e| [e]*n }
        end

        replicate(["Project", "Publication"], 2)
        #=> [["Project", "Project"], ["Publication", "Publication"]]
        replicate(["Project", "Publication"], 3)
        #=> [["Project", "Project", "Project"], ["Publication", "Publication", "Publication"]]
        replicate([["ProjectA", "ProjectB"], "Publication"], 2)
        #=> [[["ProjectA", "ProjectB"], ["ProjectA", "ProjectB"]], ["Publication", "Publication"]





        share|improve this answer












        def replicate(arr, n)
        arr.map { |e| [e]*n }
        end

        replicate(["Project", "Publication"], 2)
        #=> [["Project", "Project"], ["Publication", "Publication"]]
        replicate(["Project", "Publication"], 3)
        #=> [["Project", "Project", "Project"], ["Publication", "Publication", "Publication"]]
        replicate([["ProjectA", "ProjectB"], "Publication"], 2)
        #=> [[["ProjectA", "ProjectB"], ["ProjectA", "ProjectB"]], ["Publication", "Publication"]






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 at 17:41









        Cary Swoveland

        67k53865




        67k53865
























            up vote
            0
            down vote













            This is something map can handle quite easily.



            a = ["Project", "Publication"]
            a.map{|x| [x,x]}
            #=> [["Project", "Project"], ["Publication", "Publication"]]





            share|improve this answer























            • a.zip(a) will do the same thing :)
              – engineersmnky
              Nov 15 at 17:08















            up vote
            0
            down vote













            This is something map can handle quite easily.



            a = ["Project", "Publication"]
            a.map{|x| [x,x]}
            #=> [["Project", "Project"], ["Publication", "Publication"]]





            share|improve this answer























            • a.zip(a) will do the same thing :)
              – engineersmnky
              Nov 15 at 17:08













            up vote
            0
            down vote










            up vote
            0
            down vote









            This is something map can handle quite easily.



            a = ["Project", "Publication"]
            a.map{|x| [x,x]}
            #=> [["Project", "Project"], ["Publication", "Publication"]]





            share|improve this answer














            This is something map can handle quite easily.



            a = ["Project", "Publication"]
            a.map{|x| [x,x]}
            #=> [["Project", "Project"], ["Publication", "Publication"]]






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 15 at 17:08









            engineersmnky

            13.1k12137




            13.1k12137










            answered Nov 15 at 17:03









            Jeff Price

            2,7991723




            2,7991723












            • a.zip(a) will do the same thing :)
              – engineersmnky
              Nov 15 at 17:08


















            • a.zip(a) will do the same thing :)
              – engineersmnky
              Nov 15 at 17:08
















            a.zip(a) will do the same thing :)
            – engineersmnky
            Nov 15 at 17:08




            a.zip(a) will do the same thing :)
            – engineersmnky
            Nov 15 at 17:08


















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