Assigning coordinates in TikZ











up vote
2
down vote

favorite












I use TikZ to draw arrows and labels on maps, generated from other applications.



A minimal example with a global mercator projection might look like this:



documentclass{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
node[anchor=south west,inner sep=0] (image) at (0,0)
{includegraphics[width=18cm]{my_mercator_world_map.jpg}};
begin{scope}[x={(image.south east)},y={(image.north west)}]
draw [->] (0.5,1) -- (0.5421,0.6353);
node[draw] at (0.2,0.05) {a};
end{scope}
end{tikzpicture}
end{document}


enter image description here



It's easy to normalise map coordinates to TikZ coordinates, but sometimes I have many labels or even TikZ generated polygons. It would be very convenient to give the coordinates as geographical coordinates instead of a number between 0 and 1.



Is there a simple way to normalise TikZ coordinates so that they can be given in e.g. decimal lat-lon if I know the exact extent of the map?



In the case above, I'd like to be able to give coordinates as:



draw [->] (0,90) -- (7.578,12.177);
node[draw] at (-108,-81) {a};


I also work with local maps, but we can assume that all have a rectangular grid. Map coordinates to any projection would be fantastic, but I guess that is beyond the scope of TikZ.





EDIT



A partly working answer can be found here: tex.stackexchange.com/a/9562/121799










share|improve this question




















  • 1




    Sure: tex.stackexchange.com/a/9562/121799
    – marmot
    Nov 13 at 1:02










  • Yes. That's the way! As the question is framed differently, I didn't find that answer.
    – Tactopoda
    Nov 13 at 1:07










  • Glad to hear! Is your question answered by that, or do you want to get an official answer, or do you want to get it closed as a duplicate such that people searching for keywords contained in your question get dragged to the original answer?
    – marmot
    Nov 13 at 2:02










  • I'm happy with that answer, but as the linked answer is an answer to a different question, it might be hard to find. Linking this as a duplicate OR a further developed answer to this might be useful for future users.
    – Tactopoda
    Nov 13 at 2:24






  • 1




    Hmmm... the linked answer still use [0..1]x[0..1] as coordinate systems, not [-180..180]x[-90..90]... so an explicit answer could be better, I think!
    – Rmano
    Nov 13 at 13:17















up vote
2
down vote

favorite












I use TikZ to draw arrows and labels on maps, generated from other applications.



A minimal example with a global mercator projection might look like this:



documentclass{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
node[anchor=south west,inner sep=0] (image) at (0,0)
{includegraphics[width=18cm]{my_mercator_world_map.jpg}};
begin{scope}[x={(image.south east)},y={(image.north west)}]
draw [->] (0.5,1) -- (0.5421,0.6353);
node[draw] at (0.2,0.05) {a};
end{scope}
end{tikzpicture}
end{document}


enter image description here



It's easy to normalise map coordinates to TikZ coordinates, but sometimes I have many labels or even TikZ generated polygons. It would be very convenient to give the coordinates as geographical coordinates instead of a number between 0 and 1.



Is there a simple way to normalise TikZ coordinates so that they can be given in e.g. decimal lat-lon if I know the exact extent of the map?



In the case above, I'd like to be able to give coordinates as:



draw [->] (0,90) -- (7.578,12.177);
node[draw] at (-108,-81) {a};


I also work with local maps, but we can assume that all have a rectangular grid. Map coordinates to any projection would be fantastic, but I guess that is beyond the scope of TikZ.





EDIT



A partly working answer can be found here: tex.stackexchange.com/a/9562/121799










share|improve this question




















  • 1




    Sure: tex.stackexchange.com/a/9562/121799
    – marmot
    Nov 13 at 1:02










  • Yes. That's the way! As the question is framed differently, I didn't find that answer.
    – Tactopoda
    Nov 13 at 1:07










  • Glad to hear! Is your question answered by that, or do you want to get an official answer, or do you want to get it closed as a duplicate such that people searching for keywords contained in your question get dragged to the original answer?
    – marmot
    Nov 13 at 2:02










  • I'm happy with that answer, but as the linked answer is an answer to a different question, it might be hard to find. Linking this as a duplicate OR a further developed answer to this might be useful for future users.
    – Tactopoda
    Nov 13 at 2:24






  • 1




    Hmmm... the linked answer still use [0..1]x[0..1] as coordinate systems, not [-180..180]x[-90..90]... so an explicit answer could be better, I think!
    – Rmano
    Nov 13 at 13:17













up vote
2
down vote

favorite









up vote
2
down vote

favorite











I use TikZ to draw arrows and labels on maps, generated from other applications.



A minimal example with a global mercator projection might look like this:



documentclass{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
node[anchor=south west,inner sep=0] (image) at (0,0)
{includegraphics[width=18cm]{my_mercator_world_map.jpg}};
begin{scope}[x={(image.south east)},y={(image.north west)}]
draw [->] (0.5,1) -- (0.5421,0.6353);
node[draw] at (0.2,0.05) {a};
end{scope}
end{tikzpicture}
end{document}


enter image description here



It's easy to normalise map coordinates to TikZ coordinates, but sometimes I have many labels or even TikZ generated polygons. It would be very convenient to give the coordinates as geographical coordinates instead of a number between 0 and 1.



Is there a simple way to normalise TikZ coordinates so that they can be given in e.g. decimal lat-lon if I know the exact extent of the map?



In the case above, I'd like to be able to give coordinates as:



draw [->] (0,90) -- (7.578,12.177);
node[draw] at (-108,-81) {a};


I also work with local maps, but we can assume that all have a rectangular grid. Map coordinates to any projection would be fantastic, but I guess that is beyond the scope of TikZ.





EDIT



A partly working answer can be found here: tex.stackexchange.com/a/9562/121799










share|improve this question















I use TikZ to draw arrows and labels on maps, generated from other applications.



A minimal example with a global mercator projection might look like this:



documentclass{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
node[anchor=south west,inner sep=0] (image) at (0,0)
{includegraphics[width=18cm]{my_mercator_world_map.jpg}};
begin{scope}[x={(image.south east)},y={(image.north west)}]
draw [->] (0.5,1) -- (0.5421,0.6353);
node[draw] at (0.2,0.05) {a};
end{scope}
end{tikzpicture}
end{document}


enter image description here



It's easy to normalise map coordinates to TikZ coordinates, but sometimes I have many labels or even TikZ generated polygons. It would be very convenient to give the coordinates as geographical coordinates instead of a number between 0 and 1.



Is there a simple way to normalise TikZ coordinates so that they can be given in e.g. decimal lat-lon if I know the exact extent of the map?



In the case above, I'd like to be able to give coordinates as:



draw [->] (0,90) -- (7.578,12.177);
node[draw] at (-108,-81) {a};


I also work with local maps, but we can assume that all have a rectangular grid. Map coordinates to any projection would be fantastic, but I guess that is beyond the scope of TikZ.





EDIT



A partly working answer can be found here: tex.stackexchange.com/a/9562/121799







tikz-pgf






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 at 13:47

























asked Nov 13 at 0:31









Tactopoda

115112




115112








  • 1




    Sure: tex.stackexchange.com/a/9562/121799
    – marmot
    Nov 13 at 1:02










  • Yes. That's the way! As the question is framed differently, I didn't find that answer.
    – Tactopoda
    Nov 13 at 1:07










  • Glad to hear! Is your question answered by that, or do you want to get an official answer, or do you want to get it closed as a duplicate such that people searching for keywords contained in your question get dragged to the original answer?
    – marmot
    Nov 13 at 2:02










  • I'm happy with that answer, but as the linked answer is an answer to a different question, it might be hard to find. Linking this as a duplicate OR a further developed answer to this might be useful for future users.
    – Tactopoda
    Nov 13 at 2:24






  • 1




    Hmmm... the linked answer still use [0..1]x[0..1] as coordinate systems, not [-180..180]x[-90..90]... so an explicit answer could be better, I think!
    – Rmano
    Nov 13 at 13:17














  • 1




    Sure: tex.stackexchange.com/a/9562/121799
    – marmot
    Nov 13 at 1:02










  • Yes. That's the way! As the question is framed differently, I didn't find that answer.
    – Tactopoda
    Nov 13 at 1:07










  • Glad to hear! Is your question answered by that, or do you want to get an official answer, or do you want to get it closed as a duplicate such that people searching for keywords contained in your question get dragged to the original answer?
    – marmot
    Nov 13 at 2:02










  • I'm happy with that answer, but as the linked answer is an answer to a different question, it might be hard to find. Linking this as a duplicate OR a further developed answer to this might be useful for future users.
    – Tactopoda
    Nov 13 at 2:24






  • 1




    Hmmm... the linked answer still use [0..1]x[0..1] as coordinate systems, not [-180..180]x[-90..90]... so an explicit answer could be better, I think!
    – Rmano
    Nov 13 at 13:17








1




1




Sure: tex.stackexchange.com/a/9562/121799
– marmot
Nov 13 at 1:02




Sure: tex.stackexchange.com/a/9562/121799
– marmot
Nov 13 at 1:02












Yes. That's the way! As the question is framed differently, I didn't find that answer.
– Tactopoda
Nov 13 at 1:07




Yes. That's the way! As the question is framed differently, I didn't find that answer.
– Tactopoda
Nov 13 at 1:07












Glad to hear! Is your question answered by that, or do you want to get an official answer, or do you want to get it closed as a duplicate such that people searching for keywords contained in your question get dragged to the original answer?
– marmot
Nov 13 at 2:02




Glad to hear! Is your question answered by that, or do you want to get an official answer, or do you want to get it closed as a duplicate such that people searching for keywords contained in your question get dragged to the original answer?
– marmot
Nov 13 at 2:02












I'm happy with that answer, but as the linked answer is an answer to a different question, it might be hard to find. Linking this as a duplicate OR a further developed answer to this might be useful for future users.
– Tactopoda
Nov 13 at 2:24




I'm happy with that answer, but as the linked answer is an answer to a different question, it might be hard to find. Linking this as a duplicate OR a further developed answer to this might be useful for future users.
– Tactopoda
Nov 13 at 2:24




1




1




Hmmm... the linked answer still use [0..1]x[0..1] as coordinate systems, not [-180..180]x[-90..90]... so an explicit answer could be better, I think!
– Rmano
Nov 13 at 13:17




Hmmm... the linked answer still use [0..1]x[0..1] as coordinate systems, not [-180..180]x[-90..90]... so an explicit answer could be better, I think!
– Rmano
Nov 13 at 13:17










1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










Based on the linked answer, and using coordinate transformations, you can do this:



documentclass[tikz]{standalone}
usetikzlibrary{fpu, calc}
begin{document}
begin{tikzpicture}
node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
begin{scope}[x={($1/360*(image.south east)$)},
y={($1/180*(image.north west)$)},
shift={(180,90)},
]
draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
end{scope}
end{tikzpicture}
end{document}


enter image description here



For more complex transformation, you can define your own coordinate system; look at the tikz manual, section 13.2.5 "Defining New Coordinate System" (at pag. 137 in my copy) and at this example.



Then you can use it, like for example:



documentclass[tikz]{standalone}
usetikzlibrary{fpu, calc}
newcommand{showpoint}[3][5,-15]{
path (#2) node[circle, fill=blue, inner sep=1pt]{} coordinate(tmp);
draw [thick, blue, <-] (tmp) -- ++(#1)
node[fill=white,]{#3};
}
begin{document}
begin{tikzpicture}
node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
begin{scope}[x={($1/360*(image.south east)$)},
y={($1/180*(image.north west)$)},
shift={(180,90)},
]
draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
% use them
showpoint{0,90}{North Pole}
showpoint{100,90}{still North Pole}
showpoint{-100,90}{North Pole, again}
showpoint{-3,40}{Madrid}
showpoint{-105,40}{Denver}
showpoint[5,15]{10,44}{Sarzana}
%
showpoint{0,0}{geolocation list bug}
end{scope}
end{tikzpicture}
end{document}


enter image description here






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    up vote
    2
    down vote



    accepted










    Based on the linked answer, and using coordinate transformations, you can do this:



    documentclass[tikz]{standalone}
    usetikzlibrary{fpu, calc}
    begin{document}
    begin{tikzpicture}
    node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
    begin{scope}[x={($1/360*(image.south east)$)},
    y={($1/180*(image.north west)$)},
    shift={(180,90)},
    ]
    draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
    foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
    foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here



    For more complex transformation, you can define your own coordinate system; look at the tikz manual, section 13.2.5 "Defining New Coordinate System" (at pag. 137 in my copy) and at this example.



    Then you can use it, like for example:



    documentclass[tikz]{standalone}
    usetikzlibrary{fpu, calc}
    newcommand{showpoint}[3][5,-15]{
    path (#2) node[circle, fill=blue, inner sep=1pt]{} coordinate(tmp);
    draw [thick, blue, <-] (tmp) -- ++(#1)
    node[fill=white,]{#3};
    }
    begin{document}
    begin{tikzpicture}
    node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
    begin{scope}[x={($1/360*(image.south east)$)},
    y={($1/180*(image.north west)$)},
    shift={(180,90)},
    ]
    draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
    foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
    foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
    % use them
    showpoint{0,90}{North Pole}
    showpoint{100,90}{still North Pole}
    showpoint{-100,90}{North Pole, again}
    showpoint{-3,40}{Madrid}
    showpoint{-105,40}{Denver}
    showpoint[5,15]{10,44}{Sarzana}
    %
    showpoint{0,0}{geolocation list bug}
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer



























      up vote
      2
      down vote



      accepted










      Based on the linked answer, and using coordinate transformations, you can do this:



      documentclass[tikz]{standalone}
      usetikzlibrary{fpu, calc}
      begin{document}
      begin{tikzpicture}
      node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
      begin{scope}[x={($1/360*(image.south east)$)},
      y={($1/180*(image.north west)$)},
      shift={(180,90)},
      ]
      draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
      foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
      foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
      end{scope}
      end{tikzpicture}
      end{document}


      enter image description here



      For more complex transformation, you can define your own coordinate system; look at the tikz manual, section 13.2.5 "Defining New Coordinate System" (at pag. 137 in my copy) and at this example.



      Then you can use it, like for example:



      documentclass[tikz]{standalone}
      usetikzlibrary{fpu, calc}
      newcommand{showpoint}[3][5,-15]{
      path (#2) node[circle, fill=blue, inner sep=1pt]{} coordinate(tmp);
      draw [thick, blue, <-] (tmp) -- ++(#1)
      node[fill=white,]{#3};
      }
      begin{document}
      begin{tikzpicture}
      node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
      begin{scope}[x={($1/360*(image.south east)$)},
      y={($1/180*(image.north west)$)},
      shift={(180,90)},
      ]
      draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
      foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
      foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
      % use them
      showpoint{0,90}{North Pole}
      showpoint{100,90}{still North Pole}
      showpoint{-100,90}{North Pole, again}
      showpoint{-3,40}{Madrid}
      showpoint{-105,40}{Denver}
      showpoint[5,15]{10,44}{Sarzana}
      %
      showpoint{0,0}{geolocation list bug}
      end{scope}
      end{tikzpicture}
      end{document}


      enter image description here






      share|improve this answer

























        up vote
        2
        down vote



        accepted







        up vote
        2
        down vote



        accepted






        Based on the linked answer, and using coordinate transformations, you can do this:



        documentclass[tikz]{standalone}
        usetikzlibrary{fpu, calc}
        begin{document}
        begin{tikzpicture}
        node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
        begin{scope}[x={($1/360*(image.south east)$)},
        y={($1/180*(image.north west)$)},
        shift={(180,90)},
        ]
        draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
        foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
        foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
        end{scope}
        end{tikzpicture}
        end{document}


        enter image description here



        For more complex transformation, you can define your own coordinate system; look at the tikz manual, section 13.2.5 "Defining New Coordinate System" (at pag. 137 in my copy) and at this example.



        Then you can use it, like for example:



        documentclass[tikz]{standalone}
        usetikzlibrary{fpu, calc}
        newcommand{showpoint}[3][5,-15]{
        path (#2) node[circle, fill=blue, inner sep=1pt]{} coordinate(tmp);
        draw [thick, blue, <-] (tmp) -- ++(#1)
        node[fill=white,]{#3};
        }
        begin{document}
        begin{tikzpicture}
        node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
        begin{scope}[x={($1/360*(image.south east)$)},
        y={($1/180*(image.north west)$)},
        shift={(180,90)},
        ]
        draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
        foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
        foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
        % use them
        showpoint{0,90}{North Pole}
        showpoint{100,90}{still North Pole}
        showpoint{-100,90}{North Pole, again}
        showpoint{-3,40}{Madrid}
        showpoint{-105,40}{Denver}
        showpoint[5,15]{10,44}{Sarzana}
        %
        showpoint{0,0}{geolocation list bug}
        end{scope}
        end{tikzpicture}
        end{document}


        enter image description here






        share|improve this answer














        Based on the linked answer, and using coordinate transformations, you can do this:



        documentclass[tikz]{standalone}
        usetikzlibrary{fpu, calc}
        begin{document}
        begin{tikzpicture}
        node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
        begin{scope}[x={($1/360*(image.south east)$)},
        y={($1/180*(image.north west)$)},
        shift={(180,90)},
        ]
        draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
        foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
        foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
        end{scope}
        end{tikzpicture}
        end{document}


        enter image description here



        For more complex transformation, you can define your own coordinate system; look at the tikz manual, section 13.2.5 "Defining New Coordinate System" (at pag. 137 in my copy) and at this example.



        Then you can use it, like for example:



        documentclass[tikz]{standalone}
        usetikzlibrary{fpu, calc}
        newcommand{showpoint}[3][5,-15]{
        path (#2) node[circle, fill=blue, inner sep=1pt]{} coordinate(tmp);
        draw [thick, blue, <-] (tmp) -- ++(#1)
        node[fill=white,]{#3};
        }
        begin{document}
        begin{tikzpicture}
        node[anchor=south west,inner sep=0] (image) at (0,0) {includegraphics[width=0.9textwidth]{example-image}};
        begin{scope}[x={($1/360*(image.south east)$)},
        y={($1/180*(image.north west)$)},
        shift={(180,90)},
        ]
        draw[help lines, red, xstep=45,ystep=30] (-180,-90) grid (180,90);
        foreach x in {-180, -135,...,180} { node [anchor=north] at (x,-90) {x}; }
        foreach y in {-90,-60,...,90} { node [anchor=east] at (-180,y) {y}; }
        % use them
        showpoint{0,90}{North Pole}
        showpoint{100,90}{still North Pole}
        showpoint{-100,90}{North Pole, again}
        showpoint{-3,40}{Madrid}
        showpoint{-105,40}{Denver}
        showpoint[5,15]{10,44}{Sarzana}
        %
        showpoint{0,0}{geolocation list bug}
        end{scope}
        end{tikzpicture}
        end{document}


        enter image description here







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        edited Nov 13 at 16:30

























        answered Nov 13 at 13:53









        Rmano

        7,36721647




        7,36721647






























             

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