tikz grid without top edge












4















In this code from TikZ (finite) grid with character in each cell



documentclass{article}
usepackage{tikz}
usetikzlibrary{matrix}

begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}


I would like to delete the top and left edges of the grid.



I have found solutions using nodes but much prefer this one with a matrix.










share|improve this question























  • Off topic: You have a very nice reputation number :)

    – JouleV
    Mar 25 at 13:35











  • @JouleV Indeed, It won't survive any votes on this question.

    – Ethan Bolker
    Mar 25 at 13:36
















4















In this code from TikZ (finite) grid with character in each cell



documentclass{article}
usepackage{tikz}
usetikzlibrary{matrix}

begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}


I would like to delete the top and left edges of the grid.



I have found solutions using nodes but much prefer this one with a matrix.










share|improve this question























  • Off topic: You have a very nice reputation number :)

    – JouleV
    Mar 25 at 13:35











  • @JouleV Indeed, It won't survive any votes on this question.

    – Ethan Bolker
    Mar 25 at 13:36














4












4








4








In this code from TikZ (finite) grid with character in each cell



documentclass{article}
usepackage{tikz}
usetikzlibrary{matrix}

begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}


I would like to delete the top and left edges of the grid.



I have found solutions using nodes but much prefer this one with a matrix.










share|improve this question














In this code from TikZ (finite) grid with character in each cell



documentclass{article}
usepackage{tikz}
usetikzlibrary{matrix}

begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}


I would like to delete the top and left edges of the grid.



I have found solutions using nodes but much prefer this one with a matrix.







tikz-pgf






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 25 at 13:31









Ethan BolkerEthan Bolker

6,69832453




6,69832453













  • Off topic: You have a very nice reputation number :)

    – JouleV
    Mar 25 at 13:35











  • @JouleV Indeed, It won't survive any votes on this question.

    – Ethan Bolker
    Mar 25 at 13:36



















  • Off topic: You have a very nice reputation number :)

    – JouleV
    Mar 25 at 13:35











  • @JouleV Indeed, It won't survive any votes on this question.

    – Ethan Bolker
    Mar 25 at 13:36

















Off topic: You have a very nice reputation number :)

– JouleV
Mar 25 at 13:35





Off topic: You have a very nice reputation number :)

– JouleV
Mar 25 at 13:35













@JouleV Indeed, It won't survive any votes on this question.

– Ethan Bolker
Mar 25 at 13:36





@JouleV Indeed, It won't survive any votes on this question.

– Ethan Bolker
Mar 25 at 13:36










2 Answers
2






active

oldest

votes


















4














We can use foreach:



documentclass[tikz]{standalone}
usetikzlibrary{matrix}

begin{document}
begin{tikzpicture}
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in {-0.5,0,0.5,1} {
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
}
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}


enter image description here



Honestly I don't think nodes or matrices have any thing to do here.





This approach is based on marmot's creative way, which is nicer and more tricky:



documentclass[tikz]{standalone}
usetikzlibrary{matrix}

begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}


enter image description here






share|improve this answer





















  • 1





    Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

    – Ethan Bolker
    Mar 25 at 13:46











  • @EthanBolker No problem. You are welcome ;)

    – JouleV
    Mar 25 at 13:47











  • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

    – marmot
    Mar 25 at 15:15











  • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

    – JouleV
    Mar 25 at 15:17











  • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

    – marmot
    Mar 25 at 15:18



















3














Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



documentclass[tikz,border=2mm]{standalone}
usetikzlibrary{matrix}

begin{document}
begin{tikzpicture}
matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
end{tikzpicture}
end{document}


enter image description here






share|improve this answer
























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    2 Answers
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    active

    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    We can use foreach:



    documentclass[tikz]{standalone}
    usetikzlibrary{matrix}

    begin{document}
    begin{tikzpicture}
    %draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
    foreach i in {-0.5,0,0.5,1} {
    draw[gray] (-1,-i)--(1,-i);
    draw[gray] (i,-1)--(i,1);
    }
    matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\};
    end{tikzpicture}
    end{document}


    enter image description here



    Honestly I don't think nodes or matrices have any thing to do here.





    This approach is based on marmot's creative way, which is nicer and more tricky:



    documentclass[tikz]{standalone}
    usetikzlibrary{matrix}

    begin{document}
    begin{tikzpicture}
    draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
    matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\};
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer





















    • 1





      Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

      – Ethan Bolker
      Mar 25 at 13:46











    • @EthanBolker No problem. You are welcome ;)

      – JouleV
      Mar 25 at 13:47











    • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

      – marmot
      Mar 25 at 15:15











    • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

      – JouleV
      Mar 25 at 15:17











    • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

      – marmot
      Mar 25 at 15:18
















    4














    We can use foreach:



    documentclass[tikz]{standalone}
    usetikzlibrary{matrix}

    begin{document}
    begin{tikzpicture}
    %draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
    foreach i in {-0.5,0,0.5,1} {
    draw[gray] (-1,-i)--(1,-i);
    draw[gray] (i,-1)--(i,1);
    }
    matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\};
    end{tikzpicture}
    end{document}


    enter image description here



    Honestly I don't think nodes or matrices have any thing to do here.





    This approach is based on marmot's creative way, which is nicer and more tricky:



    documentclass[tikz]{standalone}
    usetikzlibrary{matrix}

    begin{document}
    begin{tikzpicture}
    draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
    matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\};
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer





















    • 1





      Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

      – Ethan Bolker
      Mar 25 at 13:46











    • @EthanBolker No problem. You are welcome ;)

      – JouleV
      Mar 25 at 13:47











    • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

      – marmot
      Mar 25 at 15:15











    • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

      – JouleV
      Mar 25 at 15:17











    • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

      – marmot
      Mar 25 at 15:18














    4












    4








    4







    We can use foreach:



    documentclass[tikz]{standalone}
    usetikzlibrary{matrix}

    begin{document}
    begin{tikzpicture}
    %draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
    foreach i in {-0.5,0,0.5,1} {
    draw[gray] (-1,-i)--(1,-i);
    draw[gray] (i,-1)--(i,1);
    }
    matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\};
    end{tikzpicture}
    end{document}


    enter image description here



    Honestly I don't think nodes or matrices have any thing to do here.





    This approach is based on marmot's creative way, which is nicer and more tricky:



    documentclass[tikz]{standalone}
    usetikzlibrary{matrix}

    begin{document}
    begin{tikzpicture}
    draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
    matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\};
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer















    We can use foreach:



    documentclass[tikz]{standalone}
    usetikzlibrary{matrix}

    begin{document}
    begin{tikzpicture}
    %draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
    foreach i in {-0.5,0,0.5,1} {
    draw[gray] (-1,-i)--(1,-i);
    draw[gray] (i,-1)--(i,1);
    }
    matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\};
    end{tikzpicture}
    end{document}


    enter image description here



    Honestly I don't think nodes or matrices have any thing to do here.





    This approach is based on marmot's creative way, which is nicer and more tricky:



    documentclass[tikz]{standalone}
    usetikzlibrary{matrix}

    begin{document}
    begin{tikzpicture}
    draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
    matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\};
    end{tikzpicture}
    end{document}


    enter image description here







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Mar 25 at 15:25

























    answered Mar 25 at 13:39









    JouleVJouleV

    10.5k22559




    10.5k22559








    • 1





      Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

      – Ethan Bolker
      Mar 25 at 13:46











    • @EthanBolker No problem. You are welcome ;)

      – JouleV
      Mar 25 at 13:47











    • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

      – marmot
      Mar 25 at 15:15











    • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

      – JouleV
      Mar 25 at 15:17











    • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

      – marmot
      Mar 25 at 15:18














    • 1





      Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

      – Ethan Bolker
      Mar 25 at 13:46











    • @EthanBolker No problem. You are welcome ;)

      – JouleV
      Mar 25 at 13:47











    • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

      – marmot
      Mar 25 at 15:15











    • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

      – JouleV
      Mar 25 at 15:17











    • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

      – marmot
      Mar 25 at 15:18








    1




    1





    Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

    – Ethan Bolker
    Mar 25 at 13:46





    Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

    – Ethan Bolker
    Mar 25 at 13:46













    @EthanBolker No problem. You are welcome ;)

    – JouleV
    Mar 25 at 13:47





    @EthanBolker No problem. You are welcome ;)

    – JouleV
    Mar 25 at 13:47













    Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

    – marmot
    Mar 25 at 15:15





    Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

    – marmot
    Mar 25 at 15:15













    @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

    – JouleV
    Mar 25 at 15:17





    @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

    – JouleV
    Mar 25 at 15:17













    @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

    – marmot
    Mar 25 at 15:18





    @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

    – marmot
    Mar 25 at 15:18











    3














    Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



    documentclass[tikz,border=2mm]{standalone}
    usetikzlibrary{matrix}

    begin{document}
    begin{tikzpicture}
    matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\};
    draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer




























      3














      Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



      documentclass[tikz,border=2mm]{standalone}
      usetikzlibrary{matrix}

      begin{document}
      begin{tikzpicture}
      matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
      A & B & C & D \
      E & F & & H \
      I & J & K & L \
      M & N & O & P\};
      draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
      end{tikzpicture}
      end{document}


      enter image description here






      share|improve this answer


























        3












        3








        3







        Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



        documentclass[tikz,border=2mm]{standalone}
        usetikzlibrary{matrix}

        begin{document}
        begin{tikzpicture}
        matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
        A & B & C & D \
        E & F & & H \
        I & J & K & L \
        M & N & O & P\};
        draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
        end{tikzpicture}
        end{document}


        enter image description here






        share|improve this answer













        Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



        documentclass[tikz,border=2mm]{standalone}
        usetikzlibrary{matrix}

        begin{document}
        begin{tikzpicture}
        matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
        A & B & C & D \
        E & F & & H \
        I & J & K & L \
        M & N & O & P\};
        draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
        end{tikzpicture}
        end{document}


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 25 at 16:03









        IgnasiIgnasi

        95.7k4175320




        95.7k4175320






























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