Remove special symbols and extra spaces and replace with underscore using the replace method
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I want to remove all special characters and spaces from a string and replace with an underscore.
The string is
var str = "hello world & hello universe";
I have this now which replaces only spaces:
str.replace(/s/g, "_");
The result I get is hello_world_&_hello_universe, but I would like to remove the special symbols as well.
I tried this str.replace(/[^a-zA-Z0-9]s/g, "_") but this does not help.
javascript
edited Oct 11 '18 at 18:09
Peter Mortensen
14k1987114
asked Oct 22 '12 at 21:34
Do GoodDo Good
4173916
add a comment |
I want to remove all special characters and spaces from a string and replace with an underscore.
The string is
var str = "hello world & hello universe";
I have this now which replaces only spaces:
str.replace(/s/g, "_");
The result I get is hello_world_&_hello_universe, but I would like to remove the special symbols as well.
I tried this str.replace(/[^a-zA-Z0-9]s/g, "_") but this does not help.
javascript
edited Oct 11 '18 at 18:09
Peter Mortensen
14k1987114
asked Oct 22 '12 at 21:34
Do GoodDo Good
4173916
add a comment |
I want to remove all special characters and spaces from a string and replace with an underscore.
The string is
var str = "hello world & hello universe";
I have this now which replaces only spaces:
str.replace(/s/g, "_");
The result I get is hello_world_&_hello_universe, but I would like to remove the special symbols as well.
I tried this str.replace(/[^a-zA-Z0-9]s/g, "_") but this does not help.
javascript
edited Oct 11 '18 at 18:09
Peter Mortensen
14k1987114
asked Oct 22 '12 at 21:34
Do GoodDo Good
4173916
I want to remove all special characters and spaces from a string and replace with an underscore.
The string is
var str = "hello world & hello universe";
I have this now which replaces only spaces:
str.replace(/s/g, "_");
The result I get is hello_world_&_hello_universe, but I would like to remove the special symbols as well.
I tried this str.replace(/[^a-zA-Z0-9]s/g, "_") but this does not help.
javascript
javascript
edited Oct 11 '18 at 18:09
Peter Mortensen
14k1987114
asked Oct 22 '12 at 21:34
Do GoodDo Good
4173916
edited Oct 11 '18 at 18:09
Peter Mortensen
14k1987114
asked Oct 22 '12 at 21:34
Do GoodDo Good
4173916
edited Oct 11 '18 at 18:09
Peter Mortensen
14k1987114
edited Oct 11 '18 at 18:09
Peter Mortensen
14k1987114
edited Oct 11 '18 at 18:09
Peter Mortensen
14k1987114
14k1987114
asked Oct 22 '12 at 21:34
Do GoodDo Good
4173916
asked Oct 22 '12 at 21:34
Do GoodDo Good
4173916
asked Oct 22 '12 at 21:34
Do GoodDo Good
4173916
4173916
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
Your regular expression [^a-zA-Z0-9]s/g says match any character that is not a number or letter followed by a space.
Remove the s and you should get what you are after if you want a _ for every special character.
var newString = str.replace(/[^A-Z0-9]/ig, "_");
That will result in hello_world___hello_universe
If you want it to be single underscores use a + to match multiple
var newString = str.replace(/[^A-Z0-9]+/ig, "_");
That will result in hello_world_hello_universe
answered Oct 22 '12 at 21:36
epascarelloepascarello
155k14138187
add a comment |
Remove the s from your new regex and it should work - whitespace is already included in "anything but alphanumerics".
Note that you may want to add a + after the ] so you don't get sequences of more than one underscore. You can also chain onto .replace(/^_+|_+$/g,'') to trim off underscores at the start or end of the string.
answered Oct 22 '12 at 21:36
Niet the Dark AbsolNiet the Dark Absol
261k57365479
Why call separatereplacewhen you can add+in first regex?
– MBO
Oct 22 '12 at 21:38
Because... good point. I was thinking of something else, I guess. Still, you could chain on atrim-like regex.
– Niet the Dark Absol
Oct 22 '12 at 21:39
add a comment |
It was not asked precisely to remove accent (only special characters), but I needed to.
The solutions givens here works but they don’t remove accent: é, è, etc.
So, before doing epascarello’s solution, you can also do:
var newString = "développeur & intégrateur";
newString = replaceAccents(newString);
newString = newString.replace(/[^A-Z0-9]+/ig, "_");
alert(newString);
/**
* Replaces all accented chars with regular ones
*/
function replaceAccents(str) {
// Verifies if the String has accents and replace them
if (str.search(/[xC0-xFF]/g) > -1) {
str = str
.replace(/[xC0-xC5]/g, "A")
.replace(/[xC6]/g, "AE")
.replace(/[xC7]/g, "C")
.replace(/[xC8-xCB]/g, "E")
.replace(/[xCC-xCF]/g, "I")
.replace(/[xD0]/g, "D")
.replace(/[xD1]/g, "N")
.replace(/[xD2-xD6xD8]/g, "O")
.replace(/[xD9-xDC]/g, "U")
.replace(/[xDD]/g, "Y")
.replace(/[xDE]/g, "P")
.replace(/[xE0-xE5]/g, "a")
.replace(/[xE6]/g, "ae")
.replace(/[xE7]/g, "c")
.replace(/[xE8-xEB]/g, "e")
.replace(/[xEC-xEF]/g, "i")
.replace(/[xF1]/g, "n")
.replace(/[xF2-xF6xF8]/g, "o")
.replace(/[xF9-xFC]/g, "u")
.replace(/[xFE]/g, "p")
.replace(/[xFDxFF]/g, "y");
}
return str;
}Source: https://gist.github.com/jonlabelle/5375315
edited Oct 11 '18 at 18:11
Peter Mortensen
14k1987114
answered Jul 7 '18 at 12:15
Sébastien GicquelSébastien Gicquel
2,25633362
add a comment |
If you have a text as
var sampleText ="ä_öü_ßÄ_ TESTED Ö_Ü!@#$%^&())(&&++===.XYZ"
To replace all special character (!@#$%^&())(&&++= ==.) without replacing the characters(including umlaut)
Use below regex
sampleText = sampleText.replace(/[`~!@#$%^&*()|+-=?;:'",.<>{}/s]/gi,'');
OUTPUT : sampleText = "ä_öü_ßÄ____TESTED_Ö_Ü_____________________XYZ"
This would replace all with an underscore which is provided as second argument to the replace function.You can add whatever you want as per your requirement
answered Nov 23 '18 at 7:40
SitaramSitaram
10923
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your regular expression [^a-zA-Z0-9]s/g says match any character that is not a number or letter followed by a space.
Remove the s and you should get what you are after if you want a _ for every special character.
var newString = str.replace(/[^A-Z0-9]/ig, "_");
That will result in hello_world___hello_universe
If you want it to be single underscores use a + to match multiple
var newString = str.replace(/[^A-Z0-9]+/ig, "_");
That will result in hello_world_hello_universe
answered Oct 22 '12 at 21:36
epascarelloepascarello
155k14138187
add a comment |
Your regular expression [^a-zA-Z0-9]s/g says match any character that is not a number or letter followed by a space.
Remove the s and you should get what you are after if you want a _ for every special character.
var newString = str.replace(/[^A-Z0-9]/ig, "_");
That will result in hello_world___hello_universe
If you want it to be single underscores use a + to match multiple
var newString = str.replace(/[^A-Z0-9]+/ig, "_");
That will result in hello_world_hello_universe
answered Oct 22 '12 at 21:36
epascarelloepascarello
155k14138187
add a comment |
Your regular expression [^a-zA-Z0-9]s/g says match any character that is not a number or letter followed by a space.
Remove the s and you should get what you are after if you want a _ for every special character.
var newString = str.replace(/[^A-Z0-9]/ig, "_");
That will result in hello_world___hello_universe
If you want it to be single underscores use a + to match multiple
var newString = str.replace(/[^A-Z0-9]+/ig, "_");
That will result in hello_world_hello_universe
answered Oct 22 '12 at 21:36
epascarelloepascarello
155k14138187
Your regular expression [^a-zA-Z0-9]s/g says match any character that is not a number or letter followed by a space.
Remove the s and you should get what you are after if you want a _ for every special character.
var newString = str.replace(/[^A-Z0-9]/ig, "_");
That will result in hello_world___hello_universe
If you want it to be single underscores use a + to match multiple
var newString = str.replace(/[^A-Z0-9]+/ig, "_");
That will result in hello_world_hello_universe
answered Oct 22 '12 at 21:36
epascarelloepascarello
155k14138187
answered Oct 22 '12 at 21:36
epascarelloepascarello
155k14138187
answered Oct 22 '12 at 21:36
epascarelloepascarello
155k14138187
answered Oct 22 '12 at 21:36
epascarelloepascarello
155k14138187
155k14138187
add a comment |
add a comment |
Remove the s from your new regex and it should work - whitespace is already included in "anything but alphanumerics".
Note that you may want to add a + after the ] so you don't get sequences of more than one underscore. You can also chain onto .replace(/^_+|_+$/g,'') to trim off underscores at the start or end of the string.
answered Oct 22 '12 at 21:36
Niet the Dark AbsolNiet the Dark Absol
261k57365479
Why call separatereplacewhen you can add+in first regex?
– MBO
Oct 22 '12 at 21:38
Because... good point. I was thinking of something else, I guess. Still, you could chain on atrim-like regex.
– Niet the Dark Absol
Oct 22 '12 at 21:39
add a comment |
Remove the s from your new regex and it should work - whitespace is already included in "anything but alphanumerics".
Note that you may want to add a + after the ] so you don't get sequences of more than one underscore. You can also chain onto .replace(/^_+|_+$/g,'') to trim off underscores at the start or end of the string.
answered Oct 22 '12 at 21:36
Niet the Dark AbsolNiet the Dark Absol
261k57365479
Why call separatereplacewhen you can add+in first regex?
– MBO
Oct 22 '12 at 21:38
Because... good point. I was thinking of something else, I guess. Still, you could chain on atrim-like regex.
– Niet the Dark Absol
Oct 22 '12 at 21:39
add a comment |
Remove the s from your new regex and it should work - whitespace is already included in "anything but alphanumerics".
Note that you may want to add a + after the ] so you don't get sequences of more than one underscore. You can also chain onto .replace(/^_+|_+$/g,'') to trim off underscores at the start or end of the string.
answered Oct 22 '12 at 21:36
Niet the Dark AbsolNiet the Dark Absol
261k57365479
Remove the s from your new regex and it should work - whitespace is already included in "anything but alphanumerics".
Note that you may want to add a + after the ] so you don't get sequences of more than one underscore. You can also chain onto .replace(/^_+|_+$/g,'') to trim off underscores at the start or end of the string.
answered Oct 22 '12 at 21:36
Niet the Dark AbsolNiet the Dark Absol
261k57365479
answered Oct 22 '12 at 21:36
Niet the Dark AbsolNiet the Dark Absol
261k57365479
answered Oct 22 '12 at 21:36
Niet the Dark AbsolNiet the Dark Absol
261k57365479
answered Oct 22 '12 at 21:36
Niet the Dark AbsolNiet the Dark Absol
261k57365479
261k57365479
Why call separatereplacewhen you can add+in first regex?
– MBO
Oct 22 '12 at 21:38
Because... good point. I was thinking of something else, I guess. Still, you could chain on atrim-like regex.
– Niet the Dark Absol
Oct 22 '12 at 21:39
add a comment |
Why call separatereplacewhen you can add+in first regex?
– MBO
Oct 22 '12 at 21:38
Because... good point. I was thinking of something else, I guess. Still, you could chain on atrim-like regex.
– Niet the Dark Absol
Oct 22 '12 at 21:39
Why call separate
replace when you can add + in first regex?– MBO
Oct 22 '12 at 21:38
Why call separate
replace when you can add + in first regex?– MBO
Oct 22 '12 at 21:38
Because... good point. I was thinking of something else, I guess. Still, you could chain on a
trim-like regex.– Niet the Dark Absol
Oct 22 '12 at 21:39
Because... good point. I was thinking of something else, I guess. Still, you could chain on a
trim-like regex.– Niet the Dark Absol
Oct 22 '12 at 21:39
add a comment |
It was not asked precisely to remove accent (only special characters), but I needed to.
The solutions givens here works but they don’t remove accent: é, è, etc.
So, before doing epascarello’s solution, you can also do:
var newString = "développeur & intégrateur";
newString = replaceAccents(newString);
newString = newString.replace(/[^A-Z0-9]+/ig, "_");
alert(newString);
/**
* Replaces all accented chars with regular ones
*/
function replaceAccents(str) {
// Verifies if the String has accents and replace them
if (str.search(/[xC0-xFF]/g) > -1) {
str = str
.replace(/[xC0-xC5]/g, "A")
.replace(/[xC6]/g, "AE")
.replace(/[xC7]/g, "C")
.replace(/[xC8-xCB]/g, "E")
.replace(/[xCC-xCF]/g, "I")
.replace(/[xD0]/g, "D")
.replace(/[xD1]/g, "N")
.replace(/[xD2-xD6xD8]/g, "O")
.replace(/[xD9-xDC]/g, "U")
.replace(/[xDD]/g, "Y")
.replace(/[xDE]/g, "P")
.replace(/[xE0-xE5]/g, "a")
.replace(/[xE6]/g, "ae")
.replace(/[xE7]/g, "c")
.replace(/[xE8-xEB]/g, "e")
.replace(/[xEC-xEF]/g, "i")
.replace(/[xF1]/g, "n")
.replace(/[xF2-xF6xF8]/g, "o")
.replace(/[xF9-xFC]/g, "u")
.replace(/[xFE]/g, "p")
.replace(/[xFDxFF]/g, "y");
}
return str;
}Source: https://gist.github.com/jonlabelle/5375315
edited Oct 11 '18 at 18:11
Peter Mortensen
14k1987114
answered Jul 7 '18 at 12:15
Sébastien GicquelSébastien Gicquel
2,25633362
add a comment |
It was not asked precisely to remove accent (only special characters), but I needed to.
The solutions givens here works but they don’t remove accent: é, è, etc.
So, before doing epascarello’s solution, you can also do:
var newString = "développeur & intégrateur";
newString = replaceAccents(newString);
newString = newString.replace(/[^A-Z0-9]+/ig, "_");
alert(newString);
/**
* Replaces all accented chars with regular ones
*/
function replaceAccents(str) {
// Verifies if the String has accents and replace them
if (str.search(/[xC0-xFF]/g) > -1) {
str = str
.replace(/[xC0-xC5]/g, "A")
.replace(/[xC6]/g, "AE")
.replace(/[xC7]/g, "C")
.replace(/[xC8-xCB]/g, "E")
.replace(/[xCC-xCF]/g, "I")
.replace(/[xD0]/g, "D")
.replace(/[xD1]/g, "N")
.replace(/[xD2-xD6xD8]/g, "O")
.replace(/[xD9-xDC]/g, "U")
.replace(/[xDD]/g, "Y")
.replace(/[xDE]/g, "P")
.replace(/[xE0-xE5]/g, "a")
.replace(/[xE6]/g, "ae")
.replace(/[xE7]/g, "c")
.replace(/[xE8-xEB]/g, "e")
.replace(/[xEC-xEF]/g, "i")
.replace(/[xF1]/g, "n")
.replace(/[xF2-xF6xF8]/g, "o")
.replace(/[xF9-xFC]/g, "u")
.replace(/[xFE]/g, "p")
.replace(/[xFDxFF]/g, "y");
}
return str;
}Source: https://gist.github.com/jonlabelle/5375315
edited Oct 11 '18 at 18:11
Peter Mortensen
14k1987114
answered Jul 7 '18 at 12:15
Sébastien GicquelSébastien Gicquel
2,25633362
add a comment |
It was not asked precisely to remove accent (only special characters), but I needed to.
The solutions givens here works but they don’t remove accent: é, è, etc.
So, before doing epascarello’s solution, you can also do:
var newString = "développeur & intégrateur";
newString = replaceAccents(newString);
newString = newString.replace(/[^A-Z0-9]+/ig, "_");
alert(newString);
/**
* Replaces all accented chars with regular ones
*/
function replaceAccents(str) {
// Verifies if the String has accents and replace them
if (str.search(/[xC0-xFF]/g) > -1) {
str = str
.replace(/[xC0-xC5]/g, "A")
.replace(/[xC6]/g, "AE")
.replace(/[xC7]/g, "C")
.replace(/[xC8-xCB]/g, "E")
.replace(/[xCC-xCF]/g, "I")
.replace(/[xD0]/g, "D")
.replace(/[xD1]/g, "N")
.replace(/[xD2-xD6xD8]/g, "O")
.replace(/[xD9-xDC]/g, "U")
.replace(/[xDD]/g, "Y")
.replace(/[xDE]/g, "P")
.replace(/[xE0-xE5]/g, "a")
.replace(/[xE6]/g, "ae")
.replace(/[xE7]/g, "c")
.replace(/[xE8-xEB]/g, "e")
.replace(/[xEC-xEF]/g, "i")
.replace(/[xF1]/g, "n")
.replace(/[xF2-xF6xF8]/g, "o")
.replace(/[xF9-xFC]/g, "u")
.replace(/[xFE]/g, "p")
.replace(/[xFDxFF]/g, "y");
}
return str;
}Source: https://gist.github.com/jonlabelle/5375315
edited Oct 11 '18 at 18:11
Peter Mortensen
14k1987114
answered Jul 7 '18 at 12:15
Sébastien GicquelSébastien Gicquel
2,25633362
It was not asked precisely to remove accent (only special characters), but I needed to.
The solutions givens here works but they don’t remove accent: é, è, etc.
So, before doing epascarello’s solution, you can also do:
var newString = "développeur & intégrateur";
newString = replaceAccents(newString);
newString = newString.replace(/[^A-Z0-9]+/ig, "_");
alert(newString);
/**
* Replaces all accented chars with regular ones
*/
function replaceAccents(str) {
// Verifies if the String has accents and replace them
if (str.search(/[xC0-xFF]/g) > -1) {
str = str
.replace(/[xC0-xC5]/g, "A")
.replace(/[xC6]/g, "AE")
.replace(/[xC7]/g, "C")
.replace(/[xC8-xCB]/g, "E")
.replace(/[xCC-xCF]/g, "I")
.replace(/[xD0]/g, "D")
.replace(/[xD1]/g, "N")
.replace(/[xD2-xD6xD8]/g, "O")
.replace(/[xD9-xDC]/g, "U")
.replace(/[xDD]/g, "Y")
.replace(/[xDE]/g, "P")
.replace(/[xE0-xE5]/g, "a")
.replace(/[xE6]/g, "ae")
.replace(/[xE7]/g, "c")
.replace(/[xE8-xEB]/g, "e")
.replace(/[xEC-xEF]/g, "i")
.replace(/[xF1]/g, "n")
.replace(/[xF2-xF6xF8]/g, "o")
.replace(/[xF9-xFC]/g, "u")
.replace(/[xFE]/g, "p")
.replace(/[xFDxFF]/g, "y");
}
return str;
}Source: https://gist.github.com/jonlabelle/5375315
var newString = "développeur & intégrateur";
newString = replaceAccents(newString);
newString = newString.replace(/[^A-Z0-9]+/ig, "_");
alert(newString);
/**
* Replaces all accented chars with regular ones
*/
function replaceAccents(str) {
// Verifies if the String has accents and replace them
if (str.search(/[xC0-xFF]/g) > -1) {
str = str
.replace(/[xC0-xC5]/g, "A")
.replace(/[xC6]/g, "AE")
.replace(/[xC7]/g, "C")
.replace(/[xC8-xCB]/g, "E")
.replace(/[xCC-xCF]/g, "I")
.replace(/[xD0]/g, "D")
.replace(/[xD1]/g, "N")
.replace(/[xD2-xD6xD8]/g, "O")
.replace(/[xD9-xDC]/g, "U")
.replace(/[xDD]/g, "Y")
.replace(/[xDE]/g, "P")
.replace(/[xE0-xE5]/g, "a")
.replace(/[xE6]/g, "ae")
.replace(/[xE7]/g, "c")
.replace(/[xE8-xEB]/g, "e")
.replace(/[xEC-xEF]/g, "i")
.replace(/[xF1]/g, "n")
.replace(/[xF2-xF6xF8]/g, "o")
.replace(/[xF9-xFC]/g, "u")
.replace(/[xFE]/g, "p")
.replace(/[xFDxFF]/g, "y");
}
return str;
}var newString = "développeur & intégrateur";
newString = replaceAccents(newString);
newString = newString.replace(/[^A-Z0-9]+/ig, "_");
alert(newString);
/**
* Replaces all accented chars with regular ones
*/
function replaceAccents(str) {
// Verifies if the String has accents and replace them
if (str.search(/[xC0-xFF]/g) > -1) {
str = str
.replace(/[xC0-xC5]/g, "A")
.replace(/[xC6]/g, "AE")
.replace(/[xC7]/g, "C")
.replace(/[xC8-xCB]/g, "E")
.replace(/[xCC-xCF]/g, "I")
.replace(/[xD0]/g, "D")
.replace(/[xD1]/g, "N")
.replace(/[xD2-xD6xD8]/g, "O")
.replace(/[xD9-xDC]/g, "U")
.replace(/[xDD]/g, "Y")
.replace(/[xDE]/g, "P")
.replace(/[xE0-xE5]/g, "a")
.replace(/[xE6]/g, "ae")
.replace(/[xE7]/g, "c")
.replace(/[xE8-xEB]/g, "e")
.replace(/[xEC-xEF]/g, "i")
.replace(/[xF1]/g, "n")
.replace(/[xF2-xF6xF8]/g, "o")
.replace(/[xF9-xFC]/g, "u")
.replace(/[xFE]/g, "p")
.replace(/[xFDxFF]/g, "y");
}
return str;
}edited Oct 11 '18 at 18:11
Peter Mortensen
14k1987114
answered Jul 7 '18 at 12:15
Sébastien GicquelSébastien Gicquel
2,25633362
edited Oct 11 '18 at 18:11
Peter Mortensen
14k1987114
edited Oct 11 '18 at 18:11
Peter Mortensen
14k1987114
edited Oct 11 '18 at 18:11
Peter Mortensen
14k1987114
14k1987114
answered Jul 7 '18 at 12:15
Sébastien GicquelSébastien Gicquel
2,25633362
answered Jul 7 '18 at 12:15
Sébastien GicquelSébastien Gicquel
2,25633362
answered Jul 7 '18 at 12:15
Sébastien GicquelSébastien Gicquel
2,25633362
2,25633362
add a comment |
add a comment |
If you have a text as
var sampleText ="ä_öü_ßÄ_ TESTED Ö_Ü!@#$%^&())(&&++===.XYZ"
To replace all special character (!@#$%^&())(&&++= ==.) without replacing the characters(including umlaut)
Use below regex
sampleText = sampleText.replace(/[`~!@#$%^&*()|+-=?;:'",.<>{}/s]/gi,'');
OUTPUT : sampleText = "ä_öü_ßÄ____TESTED_Ö_Ü_____________________XYZ"
This would replace all with an underscore which is provided as second argument to the replace function.You can add whatever you want as per your requirement
answered Nov 23 '18 at 7:40
SitaramSitaram
10923
add a comment |
If you have a text as
var sampleText ="ä_öü_ßÄ_ TESTED Ö_Ü!@#$%^&())(&&++===.XYZ"
To replace all special character (!@#$%^&())(&&++= ==.) without replacing the characters(including umlaut)
Use below regex
sampleText = sampleText.replace(/[`~!@#$%^&*()|+-=?;:'",.<>{}/s]/gi,'');
OUTPUT : sampleText = "ä_öü_ßÄ____TESTED_Ö_Ü_____________________XYZ"
This would replace all with an underscore which is provided as second argument to the replace function.You can add whatever you want as per your requirement
answered Nov 23 '18 at 7:40
SitaramSitaram
10923
add a comment |
If you have a text as
var sampleText ="ä_öü_ßÄ_ TESTED Ö_Ü!@#$%^&())(&&++===.XYZ"
To replace all special character (!@#$%^&())(&&++= ==.) without replacing the characters(including umlaut)
Use below regex
sampleText = sampleText.replace(/[`~!@#$%^&*()|+-=?;:'",.<>{}/s]/gi,'');
OUTPUT : sampleText = "ä_öü_ßÄ____TESTED_Ö_Ü_____________________XYZ"
This would replace all with an underscore which is provided as second argument to the replace function.You can add whatever you want as per your requirement
answered Nov 23 '18 at 7:40
SitaramSitaram
10923
If you have a text as
var sampleText ="ä_öü_ßÄ_ TESTED Ö_Ü!@#$%^&())(&&++===.XYZ"
To replace all special character (!@#$%^&())(&&++= ==.) without replacing the characters(including umlaut)
Use below regex
sampleText = sampleText.replace(/[`~!@#$%^&*()|+-=?;:'",.<>{}/s]/gi,'');
OUTPUT : sampleText = "ä_öü_ßÄ____TESTED_Ö_Ü_____________________XYZ"
This would replace all with an underscore which is provided as second argument to the replace function.You can add whatever you want as per your requirement
answered Nov 23 '18 at 7:40
SitaramSitaram
10923
answered Nov 23 '18 at 7:40
SitaramSitaram
10923
answered Nov 23 '18 at 7:40
SitaramSitaram
10923
answered Nov 23 '18 at 7:40
SitaramSitaram
10923
10923
add a comment |
add a comment |
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