Draw an little arc to indicate an angle in tikzpicture












2















How would you modify the following code so that I insert the arc indicated by the blue line in the diagram?
In the normal tikzpicture environment this seems to be quite straightforward, but I am unsure when it comes to graphs.



Thanks



documentclass{article}
usepackage[margin=0.5in]{geometry}
usepackage{pgfplots}
renewcommand{thesection}{arabic{section}}
usepackage{mathtools}
usepackage{cancel}
usepackage{pgfplots}
usepackage{amsmath}
newtheorem{theorem}{THEOREM}
newtheorem{proof}{PROOF}
usepackage{tikz}
usepackage{amssymb}
usetikzlibrary{patterns}
usepackage{fancyhdr}
usepackage{bigints}
usepackage{color}
usepackage{tcolorbox}
usepackage{color,xcolor}
usepackage{booktabs,array}
usepackage{hyperref}
usepackage{graphicx}
usetikzlibrary{arrows}
usepackage{polynom}
usepackage{wallpaper}
usetikzlibrary{shapes.geometric}
usepgfplotslibrary{fillbetween}
newenvironment{tightcenter}{
setlengthtopsep{0pt}
setlengthparskip{0pt}
begin{center}}{end{center}}
begin{document}
begin{tikzpicture}
begin{axis}[
axis x line=middle, % put the x axis in the middle
axis y line=middle, % put the y axis in the middle
axis line style=thick,
axis line style={->}, % arrows on the axis
xlabel={$x$}, % default put x on x-axis
ylabel={$y$}, % default put y on y-axis
ticks=none,
xmin=-7,xmax=7,
ymin=-7,ymax=7,
clip=false
]
%
draw[black,thick](axis cs:0,0) circle (1.7cm);
%
%
node [above] at (axis cs: +0.4,0){$O$};
node [left,scale=0.9] at (axis cs: -0.5,-0.4){$theta$};
%
node [left,scale=0.9] at (axis cs: -2.4,-3.4){$(x,y)$};
%node [left] at (axis cs: 0,+1.5){$1$};
%node [left] at (axis cs: 0,-5.5){$-5$};
draw[black,thick](axis cs:0,0) -- (axis cs:-2.4,0) -- (axis cs:-2.4,-2.95) --cycle;
draw[black,thick](axis cs:-2.4,0) rectangle (axis cs:-2,-0.4);
draw[fill=black](axis cs:-2.4,-2.97) circle (0.4mm);
%
draw [thick](axis cs:0.92,2) ++(0:1) arc (185:264:0.5);
%draw [thick](axis cs:2.18,0) ++(0:1) arc (0:95:0.5);
end{axis}
end{tikzpicture}
end{document}


desired output










share|improve this question


















  • 4





    There is the angles library for that. (Or just draw the arc by using draw [thick](axis cs:-0.5) arc (180:222:0.5); and if you use a reasonably recent version of pgfplots, pgfplotset{compat=1.16}, you can drop all the axis cs:.)

    – marmot
    Mar 28 at 22:40








  • 2





    Observe that the bullet is not exactly over the circle.

    – Sigur
    Mar 28 at 22:47
















2















How would you modify the following code so that I insert the arc indicated by the blue line in the diagram?
In the normal tikzpicture environment this seems to be quite straightforward, but I am unsure when it comes to graphs.



Thanks



documentclass{article}
usepackage[margin=0.5in]{geometry}
usepackage{pgfplots}
renewcommand{thesection}{arabic{section}}
usepackage{mathtools}
usepackage{cancel}
usepackage{pgfplots}
usepackage{amsmath}
newtheorem{theorem}{THEOREM}
newtheorem{proof}{PROOF}
usepackage{tikz}
usepackage{amssymb}
usetikzlibrary{patterns}
usepackage{fancyhdr}
usepackage{bigints}
usepackage{color}
usepackage{tcolorbox}
usepackage{color,xcolor}
usepackage{booktabs,array}
usepackage{hyperref}
usepackage{graphicx}
usetikzlibrary{arrows}
usepackage{polynom}
usepackage{wallpaper}
usetikzlibrary{shapes.geometric}
usepgfplotslibrary{fillbetween}
newenvironment{tightcenter}{
setlengthtopsep{0pt}
setlengthparskip{0pt}
begin{center}}{end{center}}
begin{document}
begin{tikzpicture}
begin{axis}[
axis x line=middle, % put the x axis in the middle
axis y line=middle, % put the y axis in the middle
axis line style=thick,
axis line style={->}, % arrows on the axis
xlabel={$x$}, % default put x on x-axis
ylabel={$y$}, % default put y on y-axis
ticks=none,
xmin=-7,xmax=7,
ymin=-7,ymax=7,
clip=false
]
%
draw[black,thick](axis cs:0,0) circle (1.7cm);
%
%
node [above] at (axis cs: +0.4,0){$O$};
node [left,scale=0.9] at (axis cs: -0.5,-0.4){$theta$};
%
node [left,scale=0.9] at (axis cs: -2.4,-3.4){$(x,y)$};
%node [left] at (axis cs: 0,+1.5){$1$};
%node [left] at (axis cs: 0,-5.5){$-5$};
draw[black,thick](axis cs:0,0) -- (axis cs:-2.4,0) -- (axis cs:-2.4,-2.95) --cycle;
draw[black,thick](axis cs:-2.4,0) rectangle (axis cs:-2,-0.4);
draw[fill=black](axis cs:-2.4,-2.97) circle (0.4mm);
%
draw [thick](axis cs:0.92,2) ++(0:1) arc (185:264:0.5);
%draw [thick](axis cs:2.18,0) ++(0:1) arc (0:95:0.5);
end{axis}
end{tikzpicture}
end{document}


desired output










share|improve this question


















  • 4





    There is the angles library for that. (Or just draw the arc by using draw [thick](axis cs:-0.5) arc (180:222:0.5); and if you use a reasonably recent version of pgfplots, pgfplotset{compat=1.16}, you can drop all the axis cs:.)

    – marmot
    Mar 28 at 22:40








  • 2





    Observe that the bullet is not exactly over the circle.

    – Sigur
    Mar 28 at 22:47














2












2








2


0






How would you modify the following code so that I insert the arc indicated by the blue line in the diagram?
In the normal tikzpicture environment this seems to be quite straightforward, but I am unsure when it comes to graphs.



Thanks



documentclass{article}
usepackage[margin=0.5in]{geometry}
usepackage{pgfplots}
renewcommand{thesection}{arabic{section}}
usepackage{mathtools}
usepackage{cancel}
usepackage{pgfplots}
usepackage{amsmath}
newtheorem{theorem}{THEOREM}
newtheorem{proof}{PROOF}
usepackage{tikz}
usepackage{amssymb}
usetikzlibrary{patterns}
usepackage{fancyhdr}
usepackage{bigints}
usepackage{color}
usepackage{tcolorbox}
usepackage{color,xcolor}
usepackage{booktabs,array}
usepackage{hyperref}
usepackage{graphicx}
usetikzlibrary{arrows}
usepackage{polynom}
usepackage{wallpaper}
usetikzlibrary{shapes.geometric}
usepgfplotslibrary{fillbetween}
newenvironment{tightcenter}{
setlengthtopsep{0pt}
setlengthparskip{0pt}
begin{center}}{end{center}}
begin{document}
begin{tikzpicture}
begin{axis}[
axis x line=middle, % put the x axis in the middle
axis y line=middle, % put the y axis in the middle
axis line style=thick,
axis line style={->}, % arrows on the axis
xlabel={$x$}, % default put x on x-axis
ylabel={$y$}, % default put y on y-axis
ticks=none,
xmin=-7,xmax=7,
ymin=-7,ymax=7,
clip=false
]
%
draw[black,thick](axis cs:0,0) circle (1.7cm);
%
%
node [above] at (axis cs: +0.4,0){$O$};
node [left,scale=0.9] at (axis cs: -0.5,-0.4){$theta$};
%
node [left,scale=0.9] at (axis cs: -2.4,-3.4){$(x,y)$};
%node [left] at (axis cs: 0,+1.5){$1$};
%node [left] at (axis cs: 0,-5.5){$-5$};
draw[black,thick](axis cs:0,0) -- (axis cs:-2.4,0) -- (axis cs:-2.4,-2.95) --cycle;
draw[black,thick](axis cs:-2.4,0) rectangle (axis cs:-2,-0.4);
draw[fill=black](axis cs:-2.4,-2.97) circle (0.4mm);
%
draw [thick](axis cs:0.92,2) ++(0:1) arc (185:264:0.5);
%draw [thick](axis cs:2.18,0) ++(0:1) arc (0:95:0.5);
end{axis}
end{tikzpicture}
end{document}


desired output










share|improve this question














How would you modify the following code so that I insert the arc indicated by the blue line in the diagram?
In the normal tikzpicture environment this seems to be quite straightforward, but I am unsure when it comes to graphs.



Thanks



documentclass{article}
usepackage[margin=0.5in]{geometry}
usepackage{pgfplots}
renewcommand{thesection}{arabic{section}}
usepackage{mathtools}
usepackage{cancel}
usepackage{pgfplots}
usepackage{amsmath}
newtheorem{theorem}{THEOREM}
newtheorem{proof}{PROOF}
usepackage{tikz}
usepackage{amssymb}
usetikzlibrary{patterns}
usepackage{fancyhdr}
usepackage{bigints}
usepackage{color}
usepackage{tcolorbox}
usepackage{color,xcolor}
usepackage{booktabs,array}
usepackage{hyperref}
usepackage{graphicx}
usetikzlibrary{arrows}
usepackage{polynom}
usepackage{wallpaper}
usetikzlibrary{shapes.geometric}
usepgfplotslibrary{fillbetween}
newenvironment{tightcenter}{
setlengthtopsep{0pt}
setlengthparskip{0pt}
begin{center}}{end{center}}
begin{document}
begin{tikzpicture}
begin{axis}[
axis x line=middle, % put the x axis in the middle
axis y line=middle, % put the y axis in the middle
axis line style=thick,
axis line style={->}, % arrows on the axis
xlabel={$x$}, % default put x on x-axis
ylabel={$y$}, % default put y on y-axis
ticks=none,
xmin=-7,xmax=7,
ymin=-7,ymax=7,
clip=false
]
%
draw[black,thick](axis cs:0,0) circle (1.7cm);
%
%
node [above] at (axis cs: +0.4,0){$O$};
node [left,scale=0.9] at (axis cs: -0.5,-0.4){$theta$};
%
node [left,scale=0.9] at (axis cs: -2.4,-3.4){$(x,y)$};
%node [left] at (axis cs: 0,+1.5){$1$};
%node [left] at (axis cs: 0,-5.5){$-5$};
draw[black,thick](axis cs:0,0) -- (axis cs:-2.4,0) -- (axis cs:-2.4,-2.95) --cycle;
draw[black,thick](axis cs:-2.4,0) rectangle (axis cs:-2,-0.4);
draw[fill=black](axis cs:-2.4,-2.97) circle (0.4mm);
%
draw [thick](axis cs:0.92,2) ++(0:1) arc (185:264:0.5);
%draw [thick](axis cs:2.18,0) ++(0:1) arc (0:95:0.5);
end{axis}
end{tikzpicture}
end{document}


desired output







tikz-pgf






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 28 at 22:38









Will KimWill Kim

792519




792519








  • 4





    There is the angles library for that. (Or just draw the arc by using draw [thick](axis cs:-0.5) arc (180:222:0.5); and if you use a reasonably recent version of pgfplots, pgfplotset{compat=1.16}, you can drop all the axis cs:.)

    – marmot
    Mar 28 at 22:40








  • 2





    Observe that the bullet is not exactly over the circle.

    – Sigur
    Mar 28 at 22:47














  • 4





    There is the angles library for that. (Or just draw the arc by using draw [thick](axis cs:-0.5) arc (180:222:0.5); and if you use a reasonably recent version of pgfplots, pgfplotset{compat=1.16}, you can drop all the axis cs:.)

    – marmot
    Mar 28 at 22:40








  • 2





    Observe that the bullet is not exactly over the circle.

    – Sigur
    Mar 28 at 22:47








4




4





There is the angles library for that. (Or just draw the arc by using draw [thick](axis cs:-0.5) arc (180:222:0.5); and if you use a reasonably recent version of pgfplots, pgfplotset{compat=1.16}, you can drop all the axis cs:.)

– marmot
Mar 28 at 22:40







There is the angles library for that. (Or just draw the arc by using draw [thick](axis cs:-0.5) arc (180:222:0.5); and if you use a reasonably recent version of pgfplots, pgfplotset{compat=1.16}, you can drop all the axis cs:.)

– marmot
Mar 28 at 22:40






2




2





Observe that the bullet is not exactly over the circle.

– Sigur
Mar 28 at 22:47





Observe that the bullet is not exactly over the circle.

– Sigur
Mar 28 at 22:47










1 Answer
1






active

oldest

votes


















4














Sorry, there was a typo in my comment, it should have been draw [thick](axis cs:-0.5,0) arc (180:222:0.5);, i.e. a ,0 was missing. Here is the version using the angles library.



documentclass{article}
usepackage[margin=0.5in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usetikzlibrary{angles,quotes}
begin{document}
begin{tikzpicture}
begin{axis}[
axis x line=middle, % put the x axis in the middle
axis y line=middle, % put the y axis in the middle
axis line style=thick,
axis line style={->}, % arrows on the axis
xlabel={$x$}, % default put x on x-axis
ylabel={$y$}, % default put y on y-axis
ticks=none,
xmin=-7,xmax=7,
ymin=-7,ymax=7,
clip=false
]
%
draw[black,thick](0,0) coordinate (O) circle (1.7cm);
%
%
node [above] at ( +0.4,0){$O$};
%
node [left,scale=0.9] at ( -2.4,-3.4){$(x,y)$};
%node [left] at ( 0,+1.5){$1$};
%node [left] at ( 0,-5.5){$-5$};
draw[black,thick](0,0) -- (-2.4,0) coordinate (X) --
(-2.4,-2.95) coordinate (xy) --cycle;
draw[black,thick](-2.4,0) rectangle (-2,-0.4);
draw[fill=black](-2.4,-2.97) circle (0.4mm);
%
draw [thick](0.92,2) ++(0:1) arc (185:264:0.5);
%draw [thick](2.18,0) ++(0:1) arc (0:95:0.5);
path pic [draw,angle radius=0.5cm,"{$theta$}",angle eccentricity=1.5] {angle =
X--O--xy};
end{axis}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer



















  • 1





    Thank you so much! :)

    – Will Kim
    Mar 29 at 5:20












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1 Answer
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active

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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









4














Sorry, there was a typo in my comment, it should have been draw [thick](axis cs:-0.5,0) arc (180:222:0.5);, i.e. a ,0 was missing. Here is the version using the angles library.



documentclass{article}
usepackage[margin=0.5in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usetikzlibrary{angles,quotes}
begin{document}
begin{tikzpicture}
begin{axis}[
axis x line=middle, % put the x axis in the middle
axis y line=middle, % put the y axis in the middle
axis line style=thick,
axis line style={->}, % arrows on the axis
xlabel={$x$}, % default put x on x-axis
ylabel={$y$}, % default put y on y-axis
ticks=none,
xmin=-7,xmax=7,
ymin=-7,ymax=7,
clip=false
]
%
draw[black,thick](0,0) coordinate (O) circle (1.7cm);
%
%
node [above] at ( +0.4,0){$O$};
%
node [left,scale=0.9] at ( -2.4,-3.4){$(x,y)$};
%node [left] at ( 0,+1.5){$1$};
%node [left] at ( 0,-5.5){$-5$};
draw[black,thick](0,0) -- (-2.4,0) coordinate (X) --
(-2.4,-2.95) coordinate (xy) --cycle;
draw[black,thick](-2.4,0) rectangle (-2,-0.4);
draw[fill=black](-2.4,-2.97) circle (0.4mm);
%
draw [thick](0.92,2) ++(0:1) arc (185:264:0.5);
%draw [thick](2.18,0) ++(0:1) arc (0:95:0.5);
path pic [draw,angle radius=0.5cm,"{$theta$}",angle eccentricity=1.5] {angle =
X--O--xy};
end{axis}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer



















  • 1





    Thank you so much! :)

    – Will Kim
    Mar 29 at 5:20
















4














Sorry, there was a typo in my comment, it should have been draw [thick](axis cs:-0.5,0) arc (180:222:0.5);, i.e. a ,0 was missing. Here is the version using the angles library.



documentclass{article}
usepackage[margin=0.5in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usetikzlibrary{angles,quotes}
begin{document}
begin{tikzpicture}
begin{axis}[
axis x line=middle, % put the x axis in the middle
axis y line=middle, % put the y axis in the middle
axis line style=thick,
axis line style={->}, % arrows on the axis
xlabel={$x$}, % default put x on x-axis
ylabel={$y$}, % default put y on y-axis
ticks=none,
xmin=-7,xmax=7,
ymin=-7,ymax=7,
clip=false
]
%
draw[black,thick](0,0) coordinate (O) circle (1.7cm);
%
%
node [above] at ( +0.4,0){$O$};
%
node [left,scale=0.9] at ( -2.4,-3.4){$(x,y)$};
%node [left] at ( 0,+1.5){$1$};
%node [left] at ( 0,-5.5){$-5$};
draw[black,thick](0,0) -- (-2.4,0) coordinate (X) --
(-2.4,-2.95) coordinate (xy) --cycle;
draw[black,thick](-2.4,0) rectangle (-2,-0.4);
draw[fill=black](-2.4,-2.97) circle (0.4mm);
%
draw [thick](0.92,2) ++(0:1) arc (185:264:0.5);
%draw [thick](2.18,0) ++(0:1) arc (0:95:0.5);
path pic [draw,angle radius=0.5cm,"{$theta$}",angle eccentricity=1.5] {angle =
X--O--xy};
end{axis}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer



















  • 1





    Thank you so much! :)

    – Will Kim
    Mar 29 at 5:20














4












4








4







Sorry, there was a typo in my comment, it should have been draw [thick](axis cs:-0.5,0) arc (180:222:0.5);, i.e. a ,0 was missing. Here is the version using the angles library.



documentclass{article}
usepackage[margin=0.5in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usetikzlibrary{angles,quotes}
begin{document}
begin{tikzpicture}
begin{axis}[
axis x line=middle, % put the x axis in the middle
axis y line=middle, % put the y axis in the middle
axis line style=thick,
axis line style={->}, % arrows on the axis
xlabel={$x$}, % default put x on x-axis
ylabel={$y$}, % default put y on y-axis
ticks=none,
xmin=-7,xmax=7,
ymin=-7,ymax=7,
clip=false
]
%
draw[black,thick](0,0) coordinate (O) circle (1.7cm);
%
%
node [above] at ( +0.4,0){$O$};
%
node [left,scale=0.9] at ( -2.4,-3.4){$(x,y)$};
%node [left] at ( 0,+1.5){$1$};
%node [left] at ( 0,-5.5){$-5$};
draw[black,thick](0,0) -- (-2.4,0) coordinate (X) --
(-2.4,-2.95) coordinate (xy) --cycle;
draw[black,thick](-2.4,0) rectangle (-2,-0.4);
draw[fill=black](-2.4,-2.97) circle (0.4mm);
%
draw [thick](0.92,2) ++(0:1) arc (185:264:0.5);
%draw [thick](2.18,0) ++(0:1) arc (0:95:0.5);
path pic [draw,angle radius=0.5cm,"{$theta$}",angle eccentricity=1.5] {angle =
X--O--xy};
end{axis}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer













Sorry, there was a typo in my comment, it should have been draw [thick](axis cs:-0.5,0) arc (180:222:0.5);, i.e. a ,0 was missing. Here is the version using the angles library.



documentclass{article}
usepackage[margin=0.5in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
usetikzlibrary{angles,quotes}
begin{document}
begin{tikzpicture}
begin{axis}[
axis x line=middle, % put the x axis in the middle
axis y line=middle, % put the y axis in the middle
axis line style=thick,
axis line style={->}, % arrows on the axis
xlabel={$x$}, % default put x on x-axis
ylabel={$y$}, % default put y on y-axis
ticks=none,
xmin=-7,xmax=7,
ymin=-7,ymax=7,
clip=false
]
%
draw[black,thick](0,0) coordinate (O) circle (1.7cm);
%
%
node [above] at ( +0.4,0){$O$};
%
node [left,scale=0.9] at ( -2.4,-3.4){$(x,y)$};
%node [left] at ( 0,+1.5){$1$};
%node [left] at ( 0,-5.5){$-5$};
draw[black,thick](0,0) -- (-2.4,0) coordinate (X) --
(-2.4,-2.95) coordinate (xy) --cycle;
draw[black,thick](-2.4,0) rectangle (-2,-0.4);
draw[fill=black](-2.4,-2.97) circle (0.4mm);
%
draw [thick](0.92,2) ++(0:1) arc (185:264:0.5);
%draw [thick](2.18,0) ++(0:1) arc (0:95:0.5);
path pic [draw,angle radius=0.5cm,"{$theta$}",angle eccentricity=1.5] {angle =
X--O--xy};
end{axis}
end{tikzpicture}
end{document}


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 29 at 4:51









marmotmarmot

116k5146277




116k5146277








  • 1





    Thank you so much! :)

    – Will Kim
    Mar 29 at 5:20














  • 1





    Thank you so much! :)

    – Will Kim
    Mar 29 at 5:20








1




1





Thank you so much! :)

– Will Kim
Mar 29 at 5:20





Thank you so much! :)

– Will Kim
Mar 29 at 5:20


















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